Tyre and Vehicle Dynamics part 10 ppt
Tyre and Vehicle Dynamics part 10 ppt
... 101 5202530
0
0
0.5
ψ
1
o
o
[Hz]
x10
5
N/m
2.4
1.2
1.8
4
9
4
0246 810 x10
0
10
20
30
40
60
40
30
=50m/s
=10m/s
60
2
1
[Hz]
3
5
[N/m]
20
10
0
-1
4
2
0
1m
0.5
δ
01 2
= 20m/s
[s]
σ
=
0
-2.5
10
5
012
0
1m
0.5
δ ... 1.5
[N/mm]
ω/ω
Ωο
57Hz
=
40m/s
10
10
40
-120
o
-180
-240
o
o
φ
α
10 1550
o
[ ]
10 1550
o
[ ]
[N]
[Nm]
6000
2000
100 0
0
120
0
-80
2000 N
3000 N
5000 N
4000...
Tyre and Vehicle Dynamics part 8 ppt
...
α
ψ
0
50
4 010 20 30
[Hz]
0
oo
100 60
[m/s]
8040200
Ω
=
ω
0
5
1
90
180
0
φ
ψ
[ ]
o
α
ψ
0
50
10 100
oo
4 010 20 30
[Hz]
10
10m/s
10
20
20 20
20
60
60m/s
60
5
5
40m/s
40
40
40
40
5
5
20
20m/s
10
10
0
1
90
0
experiments
0
50Hz
5
0
5
10
15
20
25
0
-1
1
2
3
4
5
0
30
60
90
120
150
180
0.5
...
_
_
_
0
5
-2
012345
ψ
_
_
5
10
20
5
5
10
10
=
_
20
20
2.5
2.5
20
20
2.5
2.5...
Tyre and Vehicle Dynamics part 11 ppt
...
0.00 rad
0.08 rad
0.16 rad
o
01 23
-1
10 10 10 10 10
α
φ
Nm
rad
ω
[rad/m]
2
3
4
5
0
-30
-90
-60
10
10
10
10
o
o
o
o
λ
=0.2m
01 23
-1
10 10 10 10 10
analytic solution
simulation model
α
= ...
α
ω
[rad/m]
N
rad
10
0
10
1
10
2
10
3
1/
ω
[rad/m]
0
10
0
10
-1
10
-2
-90
o
-45
o
~
κ
~
κ
φ
κ
analytic solution
approx. 1st order
1/
σ
10
0
10
1
10
2...
Tyre and Vehicle Dynamics Part 14 ppt
...
1
δ
ϕ
10
50 100 0
[km/h ]
α
2
α
1
δ
50 100
=
0
0
0.2
-0.2
approx.
exact
=
-1500N
ϕ
10
Tyre and Vehicle Dynamics part 2 ppsx
... class="bi x0 y12 w3 h10" alt=""
Ω
-
-
ψ
α
tangential distortion
and slip
radial deflection
rolling radius variation
rolling resistance
wheel
Ω
~
~
non-uniformity
lateral distortion
and slip
torsional ... resistance
wheel
Ω
~
~
non-uniformity
lateral distortion
and slip
torsional deflections
turn and camber slip
tyre inertia
-
ψ
γ
~
~
Tyre and Vehicle Dynamics part 3 ppsx
...
µ
0
0
α
1
α
σ
α
tan
α
0
500
20000
20
25
27.5
15
10
5
14
12
10
8
6
4
2
10
15
20
25
30
40
50
80
100 00
[N]
[Nm]
0
250
5
0
20000
100 00
0
5
10
15
20
25
30
40
50
14
12
10
8
6
4
2
400200
20
25
15
10
5
[kN]
[mm]
[deg]
α ... scale
tyre test data
by regression
techniques
distorting,
rescaling and
combining
basic
characteristics
using simple
mechanical
representation,
possibly...
Tyre and Vehicle Dynamics part 4 pps
... y1bd w4 h5c" alt=""
-20 -10
20
0
γ
[deg]
α
[deg]
-1
1
-20
-10
20
010
-0.2
γ
[deg]
-20
-10
10
20
0
µ
µ
(1-
ε
)
γ
=
θ
= 5
1
3
0
-1
1
0.2
γ
[deg]
-20
-10
20
0
10
0
1
2
3
4
6
-1
-2
-3
-4
-5
-6
5
α ... 5
1
3
α
-40
0
40
-20 -10 0 10 20
oo oo
[Nm]
0
κ
=
=
0.03
µ
1 row
flexible
γ
=
ϕ
=
0
-0.2
-3
0
3
α
-20 -10 0 10 20
oo oo
[kN]
-0.2
1 row
flexible
=
0.03
µ
γ
=10...
Tyre and Vehicle Dynamics part 5 doc
...
0246 810
0
0.2
0.4
0.6
0.8
1
= 0.8
= -100 , -10, -2, 0, 0.7, 1
= 2
0 2 4 6 8 10
0
0.2
0.4
0.6
0.8
1
= 1.0
= -100 , -10, -2, 0, 0.7, 1
= 2
0246 810
0
0.2
0.4
0.6
0.8
1
= 1.3
= -100 , -10, -2, ... 1
= 2
0246 810
0
0.2
0.4
0.6
0.8
1
= 1.6
= -100 , -10, -2, 0, 0.7, 1
= 2
0246 810
0
0.2
0.4
0.6
0.8
1
= 2.0
= -100 , -10, -2, 0, 0.7, 1
= 2
0246 810
-1
0
1
= 2.4
= -100 ,...
Tyre and Vehicle Dynamics part 6 doc
... class="bi x0 y34 w5 h18" alt=""
I
1
2
2
1
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