Tyre and Vehicle Dynamics part 8 ppt
Tyre and Vehicle Dynamics part 8 ppt
... * velocity * 0 o λ 1 16 1 8 1 4 1 2 ρ ρ ρ sin(2 π λ ) o ρ o ρ 0 0 .8 1 3.15 ρ 1 2 1 4 1 8 1 16 0 o λ = periodic lift off periodic lift off α _ α o 1 0.5 0 tyre vertical deflection average ... 3 o =15 ρ periodic lift off periodic lift off α _ α o 1 0.5 0 0 0 .8 1 1 3.15 ρ o ρ 0 o λ 1 16 1 8 1 4 1 2 ρ ρ ρ sin(2 π λ ) o 1 2 1 4 1 8 1 16 0 o λ = tyre vertical defle...
Ngày tải lên: 11/08/2014, 06:20
Tyre and Vehicle Dynamics part 10 ppt
... 0 1m 0 1m 0.5 10 0 012 σ = [Hz] δ 0 - 180 -90 o o = 20m/s 0 1m 0.5 0 1m σ = 012 [Hz] 0 15 0 - 180 -90 δ o o = 20m/s 012 0 1m 0.5 0 1m 0 1.5 0 - 180 -90 [Hz] σ = β δ o o = 20m/s 3 6 0.6 5 ... = x 315 310 305 320 310 320 310 300 [mm] [mm] [mm] 290 40002000 155 20 150 20 126 68 163 20 0 [N] [km/h ] radial steel belted bias ply tread depth: 7 mm = 1.5 bar bias ply...
Ngày tải lên: 11/08/2014, 06:20
Tyre and Vehicle Dynamics part 11 ppt
... x0 y1c w5 h13" alt=""
Ngày tải lên: 11/08/2014, 06:20
Tyre and Vehicle Dynamics Part 14 ppt
... 5 0 50 -10 imaginary part eigenvalues [rad/s] real part eigenvalues [1/s] wobble weave capsize 040 80 120 160 [km/h] imaginary part eigenvalues [rad/s] 60 40 20 0 wobble weave capsize 040 80 120 160 [km/h] 0 5 -5 -10 real ... /1.2 α,γ 2 -0.1m, +0.1m -0.1m, -0.1m 8: =10 δ Nms rad 0 40 80 120 160 [km/h] 0 5 -5 -10 real part eigenvalues [1/s] 5 0 1 2 3 6 7 4 7 6 8 8 7:...
Ngày tải lên: 11/08/2014, 06:21
Tyre and Vehicle Dynamics part 2 ppsx
... distortion and slip radial deflection rolling radius variation rolling resistance wheel Ω ~ ~ non-uniformity lateral distortion and slip torsional deflections turn and camber slip tyre inertia - ψ γ ~ ~
Ngày tải lên: 11/08/2014, 06:20
Tyre and Vehicle Dynamics part 3 ppsx
... alt="" α =8 o α = - 4 α =+4 o o α =8 o α =4 o 0 -100Nm 2000N 2000N radius 1.1 κ = - 0 . 0 2 - 0 . 0 4 - 0 . 0 8 0 . 0 8 0 . 0 6 0 . 0 4 0 . 0 2 α =2 o 4 o 6 o 8 o 12 o 01000N ... scale tyre test data by regression techniques distorting, rescaling and combining basic characteristics using simple mechanical representation, possibly closed form solu...
Ngày tải lên: 11/08/2014, 06:20
Tyre and Vehicle Dynamics part 4 pps
... 1 0 0.1 0.2 0.30.4 0.5 0.6 0.7 0 .8 ϕ α [deg] µ 1 -1 θ = 5 -10 0 10 α [deg] 0.33 µ -0.3 -0.2 -0.1 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0 .8 0 0.1 ϕ θ = 5 4000 80 00 12000 0 =20000N 400 80 0 1200 0 04 [m] 8 4 [1/m] ... = -50 0 40 [Nm] -3 0 3 [kN] 0 -2 α = 24 68 o =0.03 µ 1 row flexible γ = ϕ = 0 -3 0 3 κ -0 .8 -0.4 0 0.4 0 .8 o [kN] 8 1 row flexible = 0.03 µ o -2 α...
Ngày tải lên: 11/08/2014, 06:20
Tyre and Vehicle Dynamics part 5 doc
... y113 w6 h 48" alt="" 024 681 0 0 0.2 0.4 0.6 0 .8 1 = 0 .8 = -100, -10, -2, 0, 0.7, 1 = 2 0 2 4 6 8 10 0 0.2 0.4 0.6 0 .8 1 = 1.0 = -100, -10, -2, 0, 0.7, 1 = 2 024 681 0 0 0.2 0.4 0.6 0 .8 1 = 1.3 ... =-2 1 2 0 α γ α -60 0 60 κ 1 0.05 0.1 0.2 0.4 0 .8 1.6 κ 0, κ -1 -0.5 0 0.5 1 1 0,2, 5 10 20 40 80 α α α -60 0 60 0.05 1 0.1 0.2 0.4 0 .8 1.6 κ 0 α κ κ -1 -0.5 0 0.5 1 10 1 2...
Ngày tải lên: 11/08/2014, 06:20
