A Methodology for the Health Sciences - part 1 doc
... Nisei < ;10 6 0.098 0. 015 0. 015 10 6 11 4 0 .12 2 0.087 0.085 11 6 12 4 0 .15 1 0 .18 6 0 .18 6 12 6 13 4 0 .16 2 0 .12 5 0.222 13 6 14 4 0 .13 5 0 .15 6 0.222 14 6 15 4 0 .11 7 0 .14 4 0 .12 9 15 6 16 4 0.074 0.087 0.070 > ;16 6 0 .14 1 ... Washington, 19 76 19 77 Age Interval Number of Age Interval Number of (days) Deaths (days) Deaths 1 30 6 211 –240 1 31 60 13 2 41 270 0...
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... 3 .10 Graph Number Y 12 345678 11 1 811 142 810 −22283 511 1424 −355889 910 14 − 410 9 811 14 6 810 −5 16 15 8 14 11 3 7 9 −62024 815 8267 −7 16 15 8 14 11 3 5 6 − 810 9 811 14 6 4 4 −955889932 10 2283 511 21 11 118 111 411 Total8888888888888888 a 4 3.03 ... If Y 1 and Y 2 are statistically independent random variables, then for any two constants a 1 and a 2 , the...
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... Birth Gender1234567Total Males 2846 2554 216 2 16 67 13 41 987 666 12 ,223 Females 26 31 23 61 1996 16 76 12 30 914 668 11 ,476 Total 5477 4 915 415 8 3343 25 71 19 01 1334 23,699 (a) Find the p-value for testing the ... Let A denote the dominant gene and a denote the recessive gene. The two parents are Aa. The offspring should be Genotype Probability AA 1/ 4 Aa...
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A Methodology for the Health Sciences - part 4 pot
... 8 .1 Patient C A B Patient C A B 1 185 14 8 13 2 10 18 0 13 2 13 6 2 16 0 12 8 12 0 11 17 6 14 0 13 5 3 19 0 14 4 11 8 12 200 16 5 14 4 4 19 2 15 8 11 5 13 18 8 14 0 11 5 5 218 15 2 14 8 14 200 14 0 12 6 6 200 13 5 13 4 15 ... populations. 510 15 46 810 12 510 15 46 810 12 510 15 46 810 12 510 15 46 810 12 6 8 10 12 14 2 10 1 2 3 6 8 10 12...
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A Methodology for the Health Sciences - part 5 pdf
... Fluorescence 10 Days (j = 1) 12 Days (j = 2) 14 Days (j = 3) Control (i = 1) 14 3 17 9 76 16 9 16 0 40 95 87 11 9 11 1 11 5 72 13 2 17 1 16 3 15 0 14 6 78 14 1 — — Exposed (i = 2) 15 2 14 1 11 9 83 13 2 10 4 91 2 01 125 86 ... VARIANCE 359 10 .2 ONE-WAY ANALYSIS OF VARIANCE 10 .2 .1 Motivating Example Example 10 .1. To motivate the one-way analysis of variance,...
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A Methodology for the Health Sciences - part 6 potx
... Difference 11 2. 71 203 .11 303. 91 412 . 21 503. 31 603. 31 704. 01 804. 91 903. 81 10 0 3. 61 Mean 3.74 2.45 1. 29 11 1 5 .12 12 1 5.22 13 1 4.42 14 0 5.62 15 1 4.02 16 0 7.72 17 1 5 .12 18 1 6.02 19 1 4.62 20 1 ... accept the quadratic equation as appropriate. Figure 11 .5 is a scatter diagram of the data as well as the linear and quadratic curv...
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A Methodology for the Health Sciences - part 7 potx
... 14 0 14 8 0 1 10 15 1 99 0 10 1 1 1 14 14 1 15 1 149 0 1 16 18 4 14 0 10 2 0 1 32 240 24 7 0 15 0 0 1 17 18 10 17 0 10 3 0 1 23 18 2 17 1 1 51 0 1 38 9 7 11 0 10 4 0 1 26 16 2 13 0 15 2 0 1 12 18 2 13 ... 15 7 1 1 52 48 3 15 1 110 0 1 34 96 1 10 0 15 8 1 1 26 48 13 16 1 111 0 1 15 12 2 10 0 15 9 0 0 38 15 1 16 0 11 2...
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A Methodology for the Health Sciences - part 8 ppt
... significantly different from the case rate at age 2? 15 .9 The data in Table 15 .9 come from a paper by Friis et al. [19 81] . The mortality among male Hispanics and non-Hispanics was as shown. Table 15 .9 ... 8,990 .13 13 ,19 7. 41 10 14 334.64 17 2. 81 65–69 11 ,476. 21 13,909.34 15 19 412 .14 350.73 70–74 9,962. 91 18,087.20 20–24 926.09 511 .66 75–79 7,0 41. 03 11 ,590...
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A Methodology for the Health Sciences - part 9 pps
... 11 ). The variance Table 18 .4 Variance Inflation Factors nρ Cluster Size 0.0 01 0. 01 0.02 0.05 0 .1 2 1. 0 01 1. 01 1.02 1. 05 1. 10 5 1. 004 1. 04 1. 08 1. 20 1. 40 10 1. 009 1. 09 1. 18 1. 45 1. 90 10 0 1. 099 1. 99 ... 10 .90 10 00 1. 999 10 .99 20.98 50.95 10 0.90 EXPLORATORY DATA ANALYSIS 735 0 500 10 00 15 00 10 20 30 40 12 35 10 22 10 20 30 40 18...
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A Methodology for the Health Sciences - part 10 pps
... 91 96 10 2 10 5 11 2 15 10 99 10 6 11 1 11 7 12 1 12 9 18 8 96 10 3 10 8 11 4 11 8 12 6 15 11 10 8 11 5 12 1 12 8 13 2 14 1 18 9 10 7 11 4 12 0 12 6 13 1 13 9 15 12 11 7 12 5 13 1 13 8 14 3 15 2 18 10 11 8 12 5 13 2 13 9 14 3 15 3 15 ... 14 7 15 5 16 0 17 0 14 11 10 2 10 8 11 4 12 0 12 4 13 2 17 13 14 2 15 1 15 8 16 6 17 2 1...
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