INTRODUCTION TO COMPUTER SCIENCE - PART 2 pot

... cell.46••319 42 LM INTRODUCTION TO COMPUTER SCIENCE HANDOUT #2. SET THEORYK5 & K6, Computer Science Department, Vaên Lang UniversitySecond semester Feb, 20 02 Instructor: Traàn Ñöùc QuangMajor ... NULL */else if (L->element == M->element)return assemble(L->element, L->next, M->next);else if (L->element < M->element)return assemble(L->element, L->next, M);else ... T• T contains S 2. S ⊂ T means:• S is a proper subset of T• T is a proper superset of SRegion 1Region 2 Region 3 Region 4S T16 INTRODUCTION TO COMPUTER SCIENCE: HANDOUT #2. SET THEORYCode:...

INTRODUCTION TO COMPUTER SCIENCE - PART 0 pot

... Trí tuệ nhân tạo. INTRODUCTION TO COMPUTER SCIENCE HANDOUT #0. COURSE INFORMATIONK5 & K6, Computer Science Department, Văn Lang UniversitySecond semester Feb, 20 02 Instructor: Trần Đức Quang0.1 ... opportunities to get an English-working skill and a betterknowledge in computer science. 0 .2 TEXTBOOK AND HANDOUTSThere is one required text for this course: Foundations of Computer Science (C ... allaspects of the design and use of computers.Information Technology: Coõng ngheọ Thoõng tin. An applied science, the study of the4 INTRODUCTION TO COMPUTER SCIENCE: HANDOUT #0. COURSE INFORMATIONpractical...

INTRODUCTION TO COMPUTER SCIENCE - PART 3 pot

... GradeCS101CS101EE200EE200CS101PH100 123 4567890 123 45 22 222 3333367890ABCB+A−C+Course StudentId GradeCS101CS101CS101 123 456789033333ABA−18 INTRODUCTION TO COMPUTER SCIENCE: HANDOUT ... two tables CDH and CR as follows:The table CDH.StudentId 123 4567890 22 222 33333Course Day HourCS101CS101CS101EE200EE200EE200MWFTuWTh9AM9AM9AM10AM1PM10AM >< Ai=Bj3.3 ... chéo).Course RoomCS101EE200PH100Turing Aud. 25 Ohm HallNewton Lab.Course Room Day HourCS101CS101CS101EE200EE200EE200Turing Aud.Turing Aud.Turing Aud. 25 Ohm Hall 25 Ohm Hall 25 Ohm HallMWFTuWTh9AM9AM9AM10AM1PM10AM...

INTRODUCTION TO COMPUTER SCIENCE - PART 8 pot

... INTRODUCTION TO COMPUTER SCIENCE HANDOUT #8. REGULAR EXPRESSIONSK5 & K6, Computer Science Department, Vaên Lang UniversitySecond semester Feb, 20 02 Instructor: Traàn Ñöùc ... QuangMajor themes:1. Introduction 2. Algebraic Laws for Regular ExpressionsReading: Sections 10.5 and 10.7.8.1 INTRODUCTION In the previous handout, we have studied a finite automaton which is, in ... regular-expressionalgebra is exactly the same set of patterns that can be described by automata. Forexample, the regular expression a | bc* can express the patterns described by the fol-lowing...

INTRODUCTION TO COMPUTER SCIENCE - PART 9 potx

... INTRODUCTION TO COMPUTER SCIENCE HANDOUT #9. GRAMMARSK5 & K6, Computer Science Department, Vaên Lang UniversitySecond semester Feb, 20 02 Instructor: Traàn Ñöùc QuangMajor ... ;<StatList> → ε<StatList> → <StatList> <Statement> 52 INTRODUCTION TO COMPUTER SCIENCE: HANDOUT #9. GRAMMARS9 .2 LANGUAGES FROM GRAMMARSA grammar is essentially an inductive definition ... expression to get a newexpression. 2. E + E. That is, two expressions connected by a plus sign is an expression.3. E − E. This and the next two rules are analogous to (2) with the other operators.4....

An introduction to multiagent systems - part 2 potx

... =2s10u1dv 2 +102s1u1dv 2 =2s10(v1− s1)dv 2 +102s10dv 2 =2s10(v1− s1)dv 2 = (v1− s1)v1|2s10= 2v1s1− 2s 2 1Now we have a closed form function ... Figure 7.3.1 depictsbeforeSell: 5@$1 3@ $2 6@$4 2@ $6 4@$9Buy: 6@$9 4@$5 6@$4 3@$3 5@ $2 2@$1↑afterSell: 2@ $6 4@$9Buy: 2@ $4 3@$3 5@ $2 2@$1Figure 7 .2: A call-market order b ook, before and after ... that all-or-nothing bids give rise to subtle tie-breaking problems. For example, imagine that at the end of the pre-vious auction the highest bids are as follows, all of them all-or-nothing:...

An introduction to predictive maintenance - part 2 pot

... CONDITIONERCPTR RM 16PRD-PROD PERMT100% 12 3-5 551Freon, A/C Charge Kit6035 52 5/30/00$ 12. 75 $ 12. 75$ 12. 75CURRMETER6/1/00REQUESTEDBY:ORDER#: 1 926 PAD#: 45 524 DEPARTMENTTYPE:WORK ORDERDESCRIPTION ... to monitor the mean-time-between-failures (MTBF). These data provide the means to determine the mostcost-effective time to replace machinery rather than continue to absorb high mainte-nance ... havefailures to ﬁx. 52 An Introduction to Predictive Maintenancemachine-train components is that the looseness or slack in the chain tends to modu-late and amplify the tooth-mesh energy. Most...

INTRODUCTION TO COMPUTER SCIENCE - PART 1 ppsx

... of C.10 02 50num831001 2 3 INTRODUCTION TO COMPUTER SCIENCE HANDOUT #1. REVIEWSK5 & K6, Computer Science Department, Vaên Lang UniversitySecond semester Feb, 20 02 Instructor: Traàn ... pointer pt is 68. 2. Statements. We use statements to direct a computer to do some task. A state-ment may indicate the flow of control or an operation to be performed in pro-grams. In C,• Flow ... specified by asingle computer instruction or high-level statement (2) Any defined action. to operate: thao tác, hoạt động.operator: người điều hành, to n tử.operand: to n hạng.Execution:...

INTRODUCTION TO COMPUTER SCIENCE - PART 4 pdf

... xếp. top: Đỉnh (chồng xếp). INTRODUCTION TO COMPUTER SCIENCE HANDOUT #4. THE LIST DATA MODELK5 & K6, Computer Science Department, Vaên Lang UniversitySecond semester Feb, 20 02 Instructor: ... = pQ->front;}else {pQ->rear->next = (LIST) malloc(sizeof(struct CELL));pQ->rear = pQ->rear->next;}pQ->rear->element = x;pQ->rear->next = NULL;return TRUE;}4.4 ... hàng.4 .2 STACKS 25 A smart way to implement a stack by an array is to create a structure consisting of:1. An array to hold the elements, and 2. A variable top to keep track of the top of stack.In...

INTRODUCTION TO COMPUTER SCIENCE - PART 5 pps

... INTRODUCTION TO COMPUTER SCIENCE HANDOUT #5. THE TREE DATA MODELK5 & K6, Computer Science Department, Vaên Lang UniversitySecond semester Feb, 20 02 Instructor: Traàn Ñöùc ... than theroot, move to the parent of n, to the parent of the parent of n, and so on, weeventually reach the root of the tree.rn1n 2 n3n4n530 INTRODUCTION TO COMPUTER SCIENCE: HANDOUT ... course.rn1n 2 n3n4n5n6 32 INTRODUCTION TO COMPUTER SCIENCE: HANDOUT #5. THE TREE DATA MODELin the left subtree of x have keys less than the key of x, and all nodes in the right sub-tree have...

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