Introduction to Fracture Mechanics phần 2 pptx
Introduction to Fracture Mechanics phần 2 pptx
...
are:
.
1
1
u
u
u
r
,
1
,
u
r
r
u
r
u
rr
rr
19
.
1
2
1
r
u
r
u
u
r
r
r
The strain compatibility equation in polar coordinates is:
.0
111 12
2
2
22
2
2
2
rrrrrrrrr
rrrr
rr
Modes ... ):
0
zz
,
rr
E
,
rrrr
E
.
2...
Business Process Modeling Introduction to ARIS Methodolgy PHẦN 2 pptx
... Management
Process Performance Monitoring
Process Performance Monitoring
Effect
Effect
Page 15
Methodology & tools
z A modeling tool is more than a drawing tool
Aris is a framework for describing ... optimization.
Page 12
The Process Repository foundation
Strategic Management
Measures
&
Standards
Process
Best
Practices
Process Dictionary
Process Repository
Operational
Data
Store(...
Introduction to Fracture Mechanics phần 1 ppsx
... elastic plate with an edge crack of length
as shown below:
,
a
9
Introduction to Fracture Mechanics
1
Introduction to Fracture Mechanics
From Suresh: Fatigue of Materials
Using the results of ... The total system energy is then given by
.4
'
22
SSP
aB
E
Ba
WWU
6
Griffith noted that the critical condition for the onset
of crack growth is:
, 02
'
2
...
Introduction to Fracture Mechanics phần 3 docx
... satisfies
the biharmonic equation:
.
11
,0
2
2
22
2
222
rrrr
The boundary conditions for this plane crack problem
22
The boundary conditions for this plane crack ... be bounded.
0
ij
2
2
2
r
2coscos 12
11
BAr
rx
rr
r
1
25
2sin2sin1
11
...
Introduction to Fracture Mechanics phần 4 ppt
... applied to the first
11
aK
I
33
crack of length 2a
2
. A stress
σ
1
is applied to the first
plate, and a stress σ
2
is applied to the second plate. If
we choose σ
1
, σ
1
, σ
2
and σ
2
so ... which is very important in
fracture mechanics as it allows results from laboratory
scale tests to be applied to large scale fracture problems.
)2( )1(
II
KK
Si
3
N...
Introduction to Fracture Mechanics phần 5 docx
... B
Substitute in to the Mises yield condition:
Plane strain:
2
2
2
2
2cos 121 sin
2
3
2
ys
I
r
K
7
2
2
r
Plane stress:
22
2
2cossin
2
3
1
2
ys
I
r
K
Plastic ...
find that:
2
sin1
2
cos
2
1
r
K
I
K
6
(plane strain); σ
3
= 0 (plane stress).
2
cos
2
2
3
r
K
I
...
Introduction to Fracture Mechanics phần 6 ppt
... strain and anti-plane
strain loading:
22
22
1
1
K
EE
KK
17
For the plane stress case (combination Mode I and
Mode II):
E
KK
22
...
measurement?
m
20
Example Problem
Size Requirements
K
Ic
Test
ASTM standard E399 (1974) for K
Ic
testing (specimen
dimensions large compared to plastic zone):
2
5
.
2
,
,
Ic
K
B
b
a
21
5
.
2...
Tài liệu Ôn thi ĐH Toán đại số tổ hợp_Chương 5 (Phần 2) pptx
... n1 2
nn
2C 2C 3
−−
++
Đại học Kinh tế Quốc dân 20 00
1n1 2n 22 3n33 nn
n n n n
C2 x C2 x C2 x Cx
−− −
+ + ++
ha c
1n1 2n2 23 n3 n1n
nn n n
C2 2xC2 3xC2 nx C
−− −−
++ ++
n x ợc
n1 1 n1 2 ... x)dx+
∫
=
n3 n2 n1
21 2 (21 )21
n3 n2 n1
+++
− −−
−+
+ ++
=
n1
441 21
2
n3n2 n1 n2 n3n
+
⎛⎞⎛
−+ + −−
⎜⎟⎜
+++ +++
⎝⎠⎝
1
1
⎞
⎟
⎠
=
2
n1
nn2 2
2
(n 1)(n
+
++
++
=
2) (n 3)...
Introduction to Fracture Mechanics pdf
... http://www.simpopdf.com
Substitute in to the Mises yield condition:
Plane strain:
2
2
2
2
2cos 121 sin
2
3
2
ys
I
r
K
7
2
2
r
Plane stress:
22
2
2cossin
2
3
1
2
ys
I
r
K
Simpo ... singular term (λ = 1 /2 and thus B
1
=A
1
/3)
we find that:
29
we find that:
2
5
2...