ADVANCED THERMODYNAMICS ENGINEERING phần 8 doc
... –1261 48 0.021 0.0527 310.2 334.7 –22 588 7 O 2 9.75 0 0.2057 0.5141 205.1 210.7 –62 781 N 2 36.66 0 0.7733 1.933 191.6 186 .1 –554 28 CO 2 4 –360470 0. 081 8 0.205 269.3 282 .52 –444302 H 2 O(g) 5 –21 584 9 ... = – 393546 +79399 – 180 0 × 302 .89 2 = -85 9355 kJ kmole –1 , and ∆G o = (1)×(–519650)+(1/2)×(–42 480 0)+(–1)×( 85 9355)= 127305 kJ. (If one uses the “g’ values in Tables A -8,...
Ngày tải lên: 08/08/2014, 15:21
ADVANCED THERMODYNAMICS ENGINEERING phần 10 docx
... 592.30 48. 08 2.71 787 -1352.346 82 0 84 3. 98 52.59 6 08. 59 44 .84 2.74504 -1406.95 28 840 86 6. 08 57.60 624.95 41 .85 2.77170 -1462.1 48 860 88 8.27 63.09 641.40 39.12 2.79 783 -1517 .86 38 880 910.56 68. 98 657.95 ... 11.2 11.197 11.192 11. 182 11.172 11.162 0.55 0.115 9.9 48 9.946 9.942 9.935 9.9 28 9.921 0.6 0.0 78 8 .82 8 8. 826 8. 823 8. 817 8. 811 8. 806 0.65 0.05...
Ngày tải lên: 08/08/2014, 15:21
Advanced Biomedical Engineering Part 8 doc
... Advanced Biomedical Engineering 150 The Raman scattering in CdSe QDs has been studied efficiently during last two decades (Alivisatos et al., 1 989 ; Baranov et al., 2003; ... the process of any substance applied on a given phantom, being highly useful Advanced Biomedical Engineering 1 48 transition dynamics of band-edge emission can be quantitatively understood ... 2006;...
Ngày tải lên: 19/06/2014, 12:20
ADVANCED THERMODYNAMICS ENGINEERING phần 1 ppt
... 0.94 78 pe specific potential energy Q heat transfer kJ BTU 0.94 78 q heat transfer per unit mass kJ kg –1 BTU lb –1 0.4299 q c charge R gas constant kJ kg –1 K –1 BTU lb –1 R –1 0.2 388 R universal ... constant kJ kmole –1 BTU lbmole –1 0.2 388 K –1 R –1 S entropy kJ K –1 BTU R –1 0.5266 s specific entropy (mass basis) kJ kg –1 K –1 BTU lb –1 R –1 0.2 388 s specific entropy (mole...
Ngày tải lên: 08/08/2014, 15:21
ADVANCED THERMODYNAMICS ENGINEERING phần 2 ppsx
... c vo /R)/(1 + c vo /R). (F) Using R = R /M = 8. 314 ÷ 28. 97 = 0. 287 kJ kg –1 K –1 , T 2 /T 1 = (200÷100 + 0.7÷0. 287 ) ÷ (1 + 0.7 ÷ 0. 287 ) = 1.29, or T 2 = 387 K. Substituting this result in Eq. (E), V 2 /V 1 ... Composition Species Mole % Mass % Ar 0.934 1. 288 CO 2 0.033 0.050 N 2 78. 084 75.521 O 2 20.946 23.139 Rare gases 0.003 0.002 Molecular Weight: 28. 96 kg kmole –1 . 2. Pr...
Ngày tải lên: 08/08/2014, 15:21
ADVANCED THERMODYNAMICS ENGINEERING phần 3 pdf
... 4 387 1 + 0.06 × 26799 = 3362 .8 kJ, U 1 = 0.04 × 34455 + 0.06 × 2 181 5 = 2 687 .1 kJ, and Q 12 = 3362 .8 – 2 687 .1 + 65.3 = 741 kJ. q R = 288 .88 kJ kg –1 . The heat loss to the ambient is q 0 = 288 .88 ... (53) with T 2 = T W and 1.046 1.0 48 1.05 1.052 1.054 1.056 1.0 58 1.06 1.062 280 300 320 340 360 380 400 420 440 460 T A , K S iso , kJ/K 280 300 320 340 360 380 400 42...
Ngày tải lên: 08/08/2014, 15:21
ADVANCED THERMODYNAMICS ENGINEERING phần 4 potx
... – 2 98 × (1 × ln (673/2 98) ) = 430.2 kJ kg –1 , ψ a,e = 473 – 2 98 × 1 × ln (473/2 98) = 335.3 kJ kg –1 , ψ w,i = 419 – 2 98 × 1.31 = 28. 6 kJ kg –1 , and ψ w,e = 2676.1 – 2 98 × 7.35 = 485 .8 kJ ... 2 98 × (205.0 – 8. 314 × ln (0.21/1)) + 100 × (0. 083 14 × 2 98/ 0.21) = –46 981 kJ kmole –1 . Likewise, φ N 2 ,∞ (T 0 ,p N2 , ∞ ) = 6190 – 2 98 × (191.5 – 8. 314 × ln (0.79/1)) +...
Ngày tải lên: 08/08/2014, 15:21
ADVANCED THERMODYNAMICS ENGINEERING phần 5 potx
... with w RK SRK VW a´ 0.42 187 5 0.42 187 5 0.45724 0.4572 0.427 48 0.427 48 0.42 187 5 b´ 0.125 -0.02 0.07 78 0.07 78 0. 086 64 0. 086 64 0.125 c´ 0 0.145 0. 187 826 0. 187 826 0. 086 64 0. 086 64 0 d´ 0 0.375 -0.03223 ... as ( 28. 85×ln (87 3÷273)+0.01206× (87 3–273) – (100600+2) (87 3 –2 –273 –2 )) – (8. 314×ln(250÷0.006) = 41. 38 – 88 .30 = –46.92 kJ kmole –1 K –1 . On a mass basis...
Ngày tải lên: 08/08/2014, 15:21
ADVANCED THERMODYNAMICS ENGINEERING phần 6 ppt
... 169.59 A o 30.54 22.54 16.7 78 17.229 29.75 28. 58 29.1519 26.765 † B o 0.01030 0.1141077 0. 286 5 0.4757 .025 .00377 –.001573 0.17594 † C o 0.0 130196.35 0 0 –15 480 8. 502 08 0.292×10 –6 –.27 10 –7† D o 0.0 –0.329×10 –4 –2.276×10 –4 2 .89 3×10 –4 0.0 ... NH 3 N 2 CO 2 W m 18. 015 86 .476 102.03 66.05 17.03 28. 013 44.01 120.92 P c (bar) 220.9 49.775 40.67 45.20 112 .8 33.9 73.9 41.2...
Ngày tải lên: 08/08/2014, 15:21
ADVANCED THERMODYNAMICS ENGINEERING phần 7 ppt
... (–96 38. 8)) ÷593 = 0. 183 k kmole -1 K - . -4000 -3500 -3000 -2500 -2000 -1500 -1000 -500 0 500 1000 0 0.05 0.1 0.15 0.2 0.25 0.3 v, m 3 /kmole a, kJ/kmole 0 20 40 60 80 100 120 140 160 180 200 P, ... that ¯s = 149 .83 kJ kmole –1 . The state is represented by point D in the figure, and the extensive 146 146.5 147 147.5 1 48 1 48. 5 149 149.5 150 150.5 151 0.04 0.05 0.06 0.07 0. 08...
Ngày tải lên: 08/08/2014, 15:21