Architectural design and practice Phần 5 doc

Architectural design and practice Phần 5 doc

Architectural design and practice Phần 5 doc

... (DL)=1. 35 ␥ f (LL)=1 .5 Design vertical loading (Fig. 5. 16) Loading from above (W 1 )=1. 35 1 05+ 1 .5 19=170.25kN/m Load from left (W 2 ) dead load only=1. 35 4.1 =5. 535kN/m imposed load =5. 5 35+ 1 .5 2.2=8.835kN/m ... Design vertical loading (Fig. 5. 18) Load from above=1. 35 21.1+1 .5 2.2=31.785kN/m Self-weight of wall=1. 35 17=22.95kN/m Total vertical design load W...

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Architectural design and practice Phần 2 doc

Architectural design and practice Phần 2 doc

... types of sand:sand type S and sand type G. Both types of sand will produce satisfactory mortars. However, the grading of sand type G, which falls between the lower limits of sand S and sand G, may ... order to compensate for this and for free flowing of the mix to fill the space and the void, a slump of 75 mm and 175mm for concrete mix has been recommended in BS 56 28: Part 2. In...

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Architectural design and practice Phần 4 doc

Architectural design and practice Phần 4 doc

... with slenderness ratio and eccentricity was shown previously in Fig. 4.4 and further details of the method used for calculating ß are given in sections 5. 6.2 and 5. 9. 5. 3.2 ENV 1996–1–1 A similar ... the bearing area. (a) BS 52 68 In BS 56 28 two design checks are suggested: • At the bearing, assuming a local design bearing strength of either 1.25f k / ␥ m or 1.5f k / ␥ m...

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Architectural design and practice Phần 7 docx

Architectural design and practice Phần 7 docx

... G k =5kN/m 2, Q k =1.5kN/m 2 and L a =4m. Then F t =40kN/m width =[40 (5+ 1 .5) ×4]/(7 .5 5) = 35. 5kN/m width Therefore design for 40kN/m both ways unless steel already provided as normal slab ... 2F t =80kN/m length (h/2 .5) F t =(3.0/2 .5) ×40=48kN/m length (which governs) Shear strength is found using Clause 25 of BS 56 28, f v =0. 35+ 0.6g A (max. 1. 75) or f v...

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Architectural design and practice Phần 8 docx

Architectural design and practice Phần 8 docx

... G k =3 .5 21×10 .5+ 6×4.8×21×10 .5 +(12×2.6×4. 25 2. 85+ 4×2×2.42×4. 25 2. 85 +2×21×2.6×2. 85+ 21×2×2×2.42×2. 85) ×7 =17643kN 12 .5 WIND LOADING 12 .5. 1 General stability To explain the method, only walls A and ... finishings and partition, 4.8kN/m 2 (see section 12.10 for sample calculation) • Imposed load, 1.5kN/m 2 • Wall: 102.5mm with 13mm plaster both sides, 2.6kN/m 2 102.5mm a...

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Architectural design and practice Phần 1 pdf

Architectural design and practice Phần 1 pdf

... Introduction 5. 2 Wall and column behaviour under axial load 5. 3 Wall and column behaviour under eccentric load 5. 4 Slenderness ratio 5. 5 Calculation of eccentricity 5. 6 Vertical load resistance 5. 7 Vertical ... basis and structure of BS 56 28: Part 1 4.3 BS 56 28: Part 2—reinforced and prestressed masonry 4.4 Description of Eurocode 6 Part 1–1 (ENV 1996–1–1:19 95) 5 D...

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Architectural design and practice Phần 3 ppt

Architectural design and practice Phần 3 ppt

... components and workmanship. In general, these should be in accordance with the relevant British Standard (e.g. BS 56 28: Part 3; Materials and components, design and workmanship and BS 53 90; Stone ... built in brickwork and the other in blockwork. 4.2.3 Sections 3 and 4: design Sections 3 and 4 contain the main design information, starting with a statement of the basis...

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Architectural design and practice Phần 6 ppsx

Architectural design and practice Phần 6 ppsx

... of design loads and are to be compared with the design strengths of the material in compression and shear. The design of the beam would be carried out in accordance with the relevant code of practice. 8.2 ... introduced by Wood for design purposes and M p is the effective plastic moment given by Z σ y / ␥ ms . For design purposes the design strength must be equal to or gr...

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Architectural design and practice Phần 9 ppsx

Architectural design and practice Phần 9 ppsx

... considered in the design. ©2004 Taylor & Francis • Windward side • Leeward side Hence, most unfavourable action is 1.35G kj +1.35Q ki +1. 35 W ki and the design load=3.17×102 .5 10 3 /10 3 =324.9kN/m. 12.7.1 ... floor C f qA e ×h/2=1.1×(1269/10 3 )×21×3×3/2=131.9kNm • 5th floor 1.1×(1269/10 3 )×21×6×3 =52 7.6kNm • 4th floor (1.1×1269×21/10 3 )×9×9/2=1187.20kNm • 3rd floor 29....

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Architectural design and practice Phần 10 pps

Architectural design and practice Phần 10 pps

... construction. Assuming 50 % saturation at this stage reversible movement may be 0 .5 0.0004×24×10 3 =+4.8mm. Table 13.2 Elastic and creep deformations ©2004 Taylor & Francis From equations (12 .57 ) and (12 .58 ) ... to racking—with design recommendations, Structural Engineer, 55 (6) June, 263–8 Roberts, J.J., Tovey, A.K., Cranston, W.B. and Beeby, A.W. (1983) Concrete Masonry...

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