Computational Physics - M Jensen Episode 2 Part 2 doc

... wood for a distance of . 024 5m. Stating the equations: and but an Vgd Vad VV f f 2 0 2 2 0 2 2 2 = =− = dd m/ s m 2 . 024 5m m/s 2 298 2 800 2 •• •− =− . 26 .26 . 26 .26 . 26 . The corThe cor The ... a conservation of momentum question. Since the momentum before an event must equal the momentum after an event, the momentum must be 12, 500 kg • m/ s. 20 .2...

Ngày tải lên: 22/07/2014, 10:22

... 90/95 Series Number of terms in series 0.0 0.100000E+01 0.100000E+01 1 10.0 0.453999E-04 0.453999E-04 44 20 .0 0 .20 6115E-08 0.487460E-08 72 30.0 0.935762E-13 -0 .3 421 34E-04 100 40.0 0. 424 835E-17 -0 .22 1033E+01 ... n sumsq2 =0. DO i =1 , 127 sumsq2=sumsq2 +( x ( i ) xbar ) 2 ENDDO sigma2=SQRT( sumsq2 / 1 26 .) WRITE( , ) xbar , sigma1 , sigma2 END PROGRAM sta n dar d_d e via...

Ngày tải lên: 17/03/2014, 14:25

... AND AND THERMODTHERMOD THERMODTHERMOD THERMOD YNYN YNYN YN AMICSAMICS AMICSAMICS AMICS TEMPERATURE The atoms and molecules of which matter is made are constantly in motion. The more energy they ... image. Solution 111 11 1 36 1 37 1 27 7 027 fpq fpq q =+ −= −= − rearranges to 1 cm cm cm cm . 1 cm 4cm = == q q 1 025 . The image is located 4 cm from the mirror. The object is outside...

Ngày tải lên: 22/07/2014, 10:22

... called power MOMENTUMMOMENTUM MOMENTUMMOMENTUM MOMENTUM • The symbol P is used to represent momentum. • mv also represents momentum. • Ft is an impulse. It produces a change in momentum m v. • The ... www.petersons.com 97 Work Nm PE kg m/ s m Nm KE 1 2 kg m 2 =• =• = = =• • =• = = =• Fs Joule mgh Joule mv 2 22 2 s Nm=• = Joule It should be pointed out that the Work and PE equati...

Ngày tải lên: 22/07/2014, 10:22

... Both magnitude and direction must be included in operations with vectors. CHAPTER 1 Peterson’s: www.petersons.com 67 CHAPTER SUMMARYCHAPTER SUMMARY CHAPTER SUMMARYCHAPTER SUMMARY CHAPTER SUMMARY • ... quadrant. y x =∴+ =∴+ positive N positive N 19 4 52 . . CHAPTER 1 Peterson’s SAT II Success: Physics 48 This leads to: V f 2 – V o 2 = 2as Then we divide both sides by 2s: VV s as s f 2...

Ngày tải lên: 22/07/2014, 10:22

... the circuit. EXAMPLE In the diagram above, = 9 V, = 5 , = 5 , and = 20 . What are the values measured by the ammeter and the voltmeter? WHAT DOES THE AMMETER READ? Since the ammeter is not connected ... create miniscule magnetic fields. In most materials, these tiny fields all point in different random directions, so the bulk material does not have a magnetic field. But in permanent magne...

Ngày tải lên: 22/07/2014, 10:22

... steadily so that it goes from a velocity of 20 m/ s to a velocity of 40 m/ s in 4 seconds. What is its acceleration? (A) 0 .2 m/ s 2 (B) 4 m/ s 2 (C) 5 m/ s 2 (D) 10 m/ s 2 (E) 80 m/ s 2 Questions 7 and 8 relate ... Uniform Acceleration If you’ve got the hang of 1-D motion, you should have no trouble at all with 2- D motion. The motion of any object moving in two dimensi...

Ngày tải lên: 22/07/2014, 10:22

... is above an activation minimum. (D) the momentum of the photon is below the activation minimum. (E) the momentum of the impacted electron is above the activation mini- mum. PRACTICE TEST 1 Peterson’s: ... gravita- tional acceleration on the asteroid to be (A) less than 2. 4 m/ s 2 . (B) toward him at 2. 4 m/ s 2 . (C) downward at 2. 4 m/ s 2 . (D) greater than 2. 4 m/ s 2 . (E...

Ngày tải lên: 22/07/2014, 10:22

... 10 23 atoms of helium in one mole. Multiply the energy from the formation of one helium atom by the number of atoms in one mole of helium. (6. 022 × 10 23 ) (25 .7 MeV) = 1.55 × 10 25 MeV That ... 23 5.043 923 1 The mass of is 139.9 23 5 140 Uu Ba 1105995 The mass of is 91. 926 1 528 92 u Kr u 1 0 23 5 92 140 56 92 36 4 1 0 1 008665 23 5 043 923 1 139 9 nU BaKrn uu +→ ++ +→...

Ngày tải lên: 22/07/2014, 10:22

... be x = (x max − x min )/nsubx y = (y max − y min )/nsuby z = (z max − z min )/nsubz, DATA STRUCTURES AND ALGORITHMS 27 1 1 3 4 2 2 3 1 4 Root x y x 1 Root x y 2 1 1 2 2 31 1 32 1 3 54 2 2 3 1 4 5 1 3 54 6 2 2 3 1 4 5 6 Figure ... edges ipoi1=inpoel(lpoed(1,iedel),ielem) ipoi2=inpoel(lpoed (2, iedel),ielem) ipmin=min(ipoi1,ipoi2) ipmax=max(ipoi1,ipoi2) ! Loop over the edges em...

Ngày tải lên: 06/08/2014, 01:21