... occur?
C) Find the generator matrix for the (7 ,3) block code based on the above generator. (note
that a (7 ,3) code has 3 information bits and 4 check bits).
D) Using the generator matrix from ... MASSACHUSETTS INSTITUTE OF TECHNOLOGY
Department of Aeronautics and Astronautics
16 .36 : Comm. Sys. Engineering Date Issued: April 17
Problem Set No. 8 Date Due: April ... code?
Probl...
... can be used to represent 4
∆
quantization levels
– Soon we will learn that you only need H(Q) bits
∆
− ∆
R
1
R
2
R
3
R
4
q
1
= -3 /2
q
4
= 3 /2
q
2
=∆/2
q
3
=∆/2
Eytan Modiano
Slide ...
A
2
A
2
[] =
2 A
∫
− A
xdx =
3
A
2
/
3
A
2
/
3
SQNR =
∆
2
/
12
=
(
2
AN)
2
/
12
= N
2
,(∆ =
2
A / N)
/
Eytan Modiano
Slide 5
Lecture 4: Quantization
Eyt...
... 3dB = 7dB
– => Pb = 5x10
-4
from table 7.55 or 7.58
• Regenerator: P
b
(up) = P
b
(down) = 3x10
-6
– (from table with (E
b
/N
0
)
d
= 10dB)
– Hence P
b
(up/down) ~ 2 P
b
(up) ~ 6x3x10
-6 ...
– Hence a doubling of the diameter D increases gain by a factor of 4
Eytan Modiano
Slide 4
Repeaters
Tx
P
T2
+ A
P
T3
+ A
+ Rx
P
N
P
N
P
N
• A repeater simply amplifies the sig...