Designing Capable and Reliable Products Episode 2 Part 6 ppsx
Designing Capable and Reliable Products Episode 2 Part 6 ppsx
... Occurrence, Severity and Detectability
29 6 Appendix III
distribution for comparison:
y
Nw
2
p
exp
ÿ
x ÿ
2
2
2
50 Â 18
23 :45
2
p
exp
ÿ
x ÿ 457: 76
2 23 :45
2
2
To ®nd ... ÿ49:98
2
7 Â49:97 ÿ49:98
2
10 Â49:98 ÿ49:98
2
8 Â49:99 ÿ 49:98
2
6 Â50 ÿ49:98
2
2 Â50:01 ÿ49:98
2
1 Â50: 02 ÿ49:98
2
40
v
u
u
u
u
u
t...
Designing Capable and Reliable Products Episode 2 Part 1 ppsx
... below and involve all three principal stresses (Dowling, 1993):
C
1
1
2
s
1
ÿ s
2
jj
Su
c
ÿ 2Su
Su
c
s
1
s
2
!
4:59
C
2
1
2
s
2
ÿ s
3
jj
Su
c
ÿ 2Su
Su
c
s
2
s
3
!
4 :60
C
3
1
2
s
3
ÿ ...
2lnnÿ0:5lnlnnÿ1 : 26 55
2lnn
p
45
350 40
2ln1000ÿ0:5lnln1000ÿ1 : 26 55
2ln1000
p
45
474 :66 MPa
and
Â
...
Designing Capable and Reliable Products Episode 2 Part 9 ppsx
... () and standard deviation ()
Lognormal distribution
exp
2
2
exp 2 2
2
ÿexp 2
2
0:5
2- parameter Weibull distribution
% Á ÿ
1
1
!
% Á
ÿ0: 9 26
See ... 1:5Â1:05
0:0 32 mm
The standard deviation for one half of the tolerance can be estimated by:
H
b
%
T
2
Á q
2
m
12
0: 025 Â 2: 5
2
12
0:013 mm
Using the algebra of...
Designing Capable and Reliable Products Episode 2 Part 10 ppsx
...
2
x
i
1
2
n
i 1
@
2
@x
2
i
2
Á
4
x
i
0:5
Therefore, substituting in values gives:
L
66 6 :66
2
 10 000
2
1
2
6 :25 Â10
ÿ10
2
 10 000
4
2: 2 26 Â10
9
2
 0:0003
2
1
2
1:4839 ... problem
3 72 Appendix XI
@
2
L
@b
2
68 870 523 64 599 483 2 66 66 6 66 6
0:00 16
2
5:3388 Â 10
10
The variance equation with secon...
Designing Capable and Reliable Products Episode 2 Part 2 pptx
...
L
(MPa)
14 22 5.0 98 .2
15 1 96. 0 85.7
16 1 72. 2 75.1
17 1 52. 6 66. 6
18 1 36. 1 59.4
19 122 .1 53.3
20 110 .2 48.1
21 100.0 43 .6
22 91.1 39.7
23 83.4 36. 6
24 76. 6 33.4
25 70.5 30.8
Case studies 21 9
From ... 0. 865 4 6 . 26 34 0 .69 59
555 2. 7 27 893 0.8 923 6. 3190 0.8013
585 2. 2 22 915 0.9143 6. 37 16 0.8989
61 5 1.8 18 933 0.9 323 6. 421 6 0.9905
64...
Designing Capable and Reliable Products Episode 2 Part 3 docx
... 0 .64 8 724 0.330391
30 60 Â 6 26 4 .2 39 .2 29 7.0 43 .6 0.918951 0.715319
50 65 Â 5 21 1.1 31 .2 26 4.8 38.8 0.99 929 9 0.91 864 8
50 65 Â 6 183.0 27 .0 22 5.9 32. 9 0.999995 0.9 961 12
50 65 Â 8 148 .2 22. 0 ... 0 .6 129 0 .28 7
150.3 20 0 .64 52 0.3 72
151.3 21 0 .67 74 0. 460
1 52. 8 22 0.7097 0.5 52
1 52. 8 23 0.7419 0 .64 9
1 52. 8 24 0.77 42 0.753
1 52. 8 25...
Designing Capable and Reliable Products Episode 2 Part 4 ppt
... the ÿ3
standard deviations limit, therefore:
emin
e
ÿ 3
e
1 36: 6 ÿ 311; 1103:6MPa
Therefore:
d
0 :63 6 62 28 0 Â10
3
103 :6 Â10
6
s
0:0415 ... 19 96) :
. Gather and present facts about products and processes
. Clarify and analyse relationships between products and processes
. Measure performance
. Highlight streng...
Designing Capable and Reliable Products Episode 2 Part 5 doc
... gives:
407, 415, 420 , 424 , 4 26 , 428 , 433, 433, 4 36, 438, 440, 4 42, 443, 444, 445, 447, 447, 449,
450, 450, 451, 4 52, 4 52, 453, 453, 454, 455, 4 56, 459, 460 , 4 62 , 466 , 466 , 469 , 470, 471,
4 72, 474, 477, ... 424 , 444, 455, 4 62 ,
495, 4 26 , 5 02, 447, 438, 4 36, 498, 474, 515, 483, 454, 453, 447, 485, 4 56, 443, 449, 466 ,
445, 4 52, 478, 407, 433, 466 , 428 , 4 52, 440, 450...
Designing Capable and Reliable Products Episode 2 Part 7 pdf
... gives a Handling Ratio Total Ratings/Essential Parts 2. 5
. Fitting analysis gives a Fitting Ratio Total Ratings/Essential Parts 2. 5.
Bene®ts
The potential bene®ts of DFA/DFM are:
. Reduced part ... stages 3 and 4 have the following measures of performance
which are accepted as an indication of good design:
. Functional analysis gives a Design Eciency Essential Parts/Total Parts !6...
Designing Capable and Reliable Products Episode 2 Part 8 pdf
... FF4 76 m
p
1 Â 1 :2 1 :2
g
p
1 Â1 Â 1 Â 1 Â1 Â1 :2 1 :2
Adjusted tolerance
Design tolerance
m
p
 g
p
Æ0 :25
1 :2 Â 1 :2
Æ0:174
t
p
6 Â 1 6
s
p
1 Â 1 1
q
m
t
p
 s
p
6 Â 1 6
Material ... Calculation of q
m
Drawing number FQ21 86 m
p
1 Â 1 :2 1 :2
g
p
1 Â1 Â 1:7 Â 1 Â1 Â1 :2 2: 04
Adjusted tolerance
Design tolerance
m
p
 g
p
Æ0 :25...
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