Engineering Analysis with Ansys Software Episode 2 Part 13 doc

... matrix of 2n by 2n as shown in Equation (1.94): 12 ·· 2I − 12I ··· 2J − 12J ··· 2K − 12K ··· 2n − 12n [K (e) ]{δ}= 1 2 . . . 2I − 1 2I . . . 2J − 1 2J . . . 2K − 1 2K . . . 2n − 1 2n ⎡ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎣ 00··· ... description 24 2 5.3 .2 Create a model for analysis 24 2 5.3 .2. 1 Select kind of analysis 24 2 5.3 .2. 2 Select elemen...

Ngày tải lên: 17/08/2013, 11:58

... 0.15 A 921 17 21 17 0.8 0.7 2. 2–3.0 0 .20 0 .20 –0.50 0.10 0 .25 A 921 24 21 24 0 .20 0.30 3.8–4.9 0.30–0.9 1 .2 1.8 0.10 0 .25 0.15 A 922 18 22 18 0.9 1.0 3.5–4.5 0 .20 1 .2 1.8 0.10 1.7 2. 3 0 .25 A 922 19 22 19 0 .20 ... Ϫ4,6 42. 01 H 2 O 23 7,000 69.9 10.669 42. 284 Ϫ6.903 18.54 23 9,483 Al 0 28 . 325 20 .67 12. 38 0 24 .79 Ϫ1,040.43 Al(OH) 3 Ϫ1 ,136 ,5 42 0 Ϫ1 ,136 ,5 42 A...

Ngày tải lên: 05/08/2014, 09:20

... 0.35 1.0 0 .25 A 021 30 21 3.0 l.0–30 1 .2 6.0–8.0 0.6 0.10 0.35 2. 5 0 .25 A 022 20 22 2.0 2. 0 1.5 9 .2 10.7 0.50 0.15–0.35 0.50 0.8 0 .25 A 022 40 22 4.0 0.06 0.10 4.5–5.5 0 .20 –0.50 0.35 A 023 80 23 8.0 3.5–4.5 ... 0.15 A 920 36 20 36 0.50 0.50 2. 2–3.0 0.10–0.40 0.30–0.6 0.10 0 .25 0.15 A 921 17 21 17 0.8 0.7 2. 2–3.0 0 .20 0 .20 –0.50 0.10 0 .25 A 921 24 21 24 0 .20 0.3...

Ngày tải lên: 05/08/2014, 09:20

... 25 5 bearings, 29 6 -29 8 reciprocating, 3, 25 5 -26 4 ,28 6- 326 booster, 25 4, 27 6, 28 6 high-speed, 25 8 -25 9 capacity control devices, 3 02 low-speed, 25 9 -26 4 casinghead gas, 25 4 process considerations, ... considerations, 27 6 -28 0 centrifugal, 3, 26 7 -27 0, 28 6 rod, 29 4, 310-311 centr i fugal proces s considerations, rotary ,3 ,25 5...

Ngày tải lên: 06/08/2014, 02:20

... angle close enough to x* = π and N2 within limits? Apply reformation condition Apply finite difference equation with relaxation Calculate DHDX, DHDY, D2HDX2, D2HDY2, F and G Start iteration for ... parameter ‘G’ of the Vogelpohl equation, i.e.: = h* 1.5 ∂ 2 M v ∂x* 2 + ( R L ) 2 ∂ 2 M v ∂y* 2 = FM v + G FM v + ∂h* ∂x* + 2w* (5.100) Damping coefficients are computed in a simi...

Ngày tải lên: 05/08/2014, 09:19

... shown in Figure 7 .20 [7]. 100 20 0 500 1000 20 00 5000 10 4 2 × 10 4 5 × 10 4 10 5 2 × 10 5 5 × 10 5 10 6 2 × 10 6 5 × 10 6 10 7 20 0 500 1000 20 00 5000 10 4 2 × 10 4 5 × 10 4 10 5 2 × 10 5 5 × 10 5 10 6 100 50 20 10 Piezoviscous-elastic Piezoviscous-rigid Lubrication ... p max = 3W 2 ab = 3 × 50 2 (2. 32 × 10 −4 ) × (1.75 × 10 −4 ) = 588.0 [MPa] p average = W πa...

Ngày tải lên: 05/08/2014, 09:19

... 43, 20 00, pp. 26 9 -27 4. 133 W. Liu, E.E. Klaus and J.L. Duda, Wear Behaviour of Steel-on-Si 3 N 4 and Systems with Vapor Phase Lubrication of Oleic Acid and TCP, Wear , Vol. 21 4, 1998, pp. 20 7 -21 1. TEAM ... 121 -131 . 42 J.J. Frewing, The Heat of Adsorption of Long-Chain Compounds and their Effect on Boundary Lubrication, Proc. Roy. Soc., London, Series A, Vol. 1 82, 1944, pp...

Ngày tải lên: 05/08/2014, 09:19

... Elsevier, 20 00. 45 G.W. Stachowiak and P. Podsiadlo, Surface Characterization of Wear Particles, Wear, Vol. 22 5 -22 9, 1999, pp. 1171-1185. 46 P. Podsiadlo and G.W. Stachowiak, 3-D Imaging of Wear Particles ... given in the form: p crit = φ 2 λK IIC 2 / (D ab 2 Hµ 2 ) (11 .13) where: φ 2 is a geometrical factor relating to the effectiveness of the shape of the abrasive particl...

Ngày tải lên: 05/08/2014, 09:19

... = ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎦ ⎤ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎣ ⎡ − +−−−−− −−+−−−−− −− −−−−−−+− −−−−−+ EK L EK C L EK S-EK L EK C L EK S L EK C L EK C L EA S L EK L EA CS L EK C L EK C L EA S L EK L EA CS L EK S L EK L EA CS L EK S L EA C L EK S L EK L EA CS L EK S L EA C EK L EK C L EK SEK L EK C L EK S L EK C L EK C L EA S L EK L EA CS L EK C L EK C L EA S L EK L EA CS L EK S L...

Ngày tải lên: 05/08/2014, 09:20

... 17.63 0 42. 98 σ due to axial force (kN/cm 2 ) 0.0 72 0.0 72 0.088 0.088 0. 125 0. 124 σ due to moment (kN/cm 2 ) 0 0.006 0 0. 013 0 0.0 32 Total σ (kN/cm 2 ) 0.0 72 0.078 0.088 0.101 0. 125 0.156 Error ... the above table: P L /2 L /2 w L L /2 L /2 L 0.2L0.2L 0.6L h h b a 0.2L0.8L h h b a 0.2L0.2L 0.3L c 0.2L0.8L h h b a h h 0.3L 100 kN 10 kN/m w P Other Topics by S. T....

Ngày tải lên: 05/08/2014, 09:20