Applied Computational Fluid Dynamics Techniques - Wiley Episode 1 Part 3 pptx

... 211 11 .8Projectivepredictionofpressureincrements 212 11 .9Examples 2 13 11 .9 .1 vonKarmanvortexstreet 2 13 11 .9.2 NACA0 012 wing . 216 11 .9 .3 LPD -1 7 topsideflowstudy 218 11 .9.4 DARPASUBOFFmodel 2 23 11 .9.5 ... 13 1 5 .3. 3 Higherderivatives 13 2 6 DISCRETIZATION IN TIME 13 3 6 .1 Explicitschemes 13 3 6.2 Implicitschemes 13 5 6.2 .1 Situationswhereimplicitschemespa...

Ngày tải lên: 27/06/2014, 08:20

... 211 11 .8Projectivepredictionofpressureincrements 212 11 .9Examples 2 13 11 .9 .1 vonKarmanvortexstreet 2 13 11 .9.2 NACA0 012 wing . 216 11 .9 .3 LPD -1 7 topsideflowstudy 218 11 .9.4 DARPASUBOFFmodel 2 23 11 .9.5 ... ICL > ;10 3 3-D FEFLO30 19 85 Forebody Cyber-205 > ;10 4 2-D FEFLO27 19 86 Train Cray-XMP > ;10 5 3- D FEFLO72 19 89 Train Cray-2 > ;10 6 3- D FEFL...

Ngày tải lên: 27/06/2014, 14:20

... forces r AB ecos θ () aesin θ () + b− ⎛ ⎜ ⎜ ⎝ ⎞ ⎟ ⎟ ⎠ = F 1v F 1 r AB r AB = F 1v 38 10 3. 8 10 1.4− ⎛ ⎜ ⎜ ⎝ ⎞ ⎟ ⎟ ⎠ N= r AC c ad− b− ⎛ ⎜ ⎜ ⎝ ⎞ ⎟ ⎟ ⎠ = F 2v F 2 r AC r AC = F 2v 11 9.4 19 .9− 15 9.2− ⎛ ⎜ ⎜ ⎝ ⎞ ⎟ ⎟ ⎠ N= Add the ... magnitude of force F 3 ? Given: F 1 500 N= F 2 400 N= F R 10 00 N= a 1m= b 2m= c 2m= d 3m= Solution: Initial Guesses F 3 1N= x 1m= y 1m= Given F R...

Ngày tải lên: 21/07/2014, 17:20

... EXPLANATIONS Quick-Score Answers 1. A 2. B 3. E 4. D 5. D 6. C 7. E 8. B 9. B 10 . D 11 . B 12 . A 13 . C 14 . E 15 . B 16 . E 17 . A 18 . D 19 . E 20. B 21. D 22. B 23. C 24. B 25. C 26. D 27. B 28. B 29. D 30 . A 31 . ... D 27. B 28. B 29. D 30 . A 31 . D 32 . C 33 . D 34 . C 35 . B 36 . B 37 . C 38 . C 39 . B 40. D 41. B 42. C 43. A 44. D 45. D 46. B 47. D 48....

Ngày tải lên: 22/07/2014, 10:22

... 'Vibro-acoustic effects of friction in gears: an experimental investigation. 1 A.S.M.E., paper 200 1- 0 1- 1 516 , 20 01. 4. Roark's Formulas. 6th edition. Young, W.C., McGraw-Hill, ... version) Maag, CH80 23, Zurich, Switzerland. 3. Harris, S.L., 'Dynamic loads on the teeth of spur gears. 1 Proc. Inst. Mech. Eng., Vol 17 2, 19 58, pp 8 7 -1...

Ngày tải lên: 05/08/2014, 09:20

... 'Vibro-acoustic effects of friction in gears: an experimental investigation. 1 A.S.M.E., paper 200 1- 0 1- 1 516 , 20 01. 4. Roark's Formulas. 6th edition. Young, W.C., McGraw-Hill, ... version) Maag, CH80 23, Zurich, Switzerland. 3. Harris, S.L., 'Dynamic loads on the teeth of spur gears. 1 Proc. Inst. Mech. Eng., Vol 17 2, 19 58, pp 8 7 -1...

Ngày tải lên: 05/08/2014, 09:20

... 5 71. 90 19 16.49 79 38 . 31 1420. 71 1407.69 30 16 .70 5 91. 04 19 10.67 80 38 .66 14 34 . 71 139 3. 41 31 17.22 610 .12 19 04.67 81 39 . 01 1448.57 13 79.00 32 17 .74 629 . 13 18 98.47 82 39 .35 14 62.29 13 64.44 33 18 .26 ... 424 10 61 10 210 16 2 14 8 13 5 96 38 2 955 11 19 1 14 8 13 5 12 3 87 34 7 868 12 17 5 13 5 12 3 11 3 80 31 8 796 1...

Ngày tải lên: 05/08/2014, 12:20

... y0 w0 h1" alt=""

Ngày tải lên: 05/08/2014, 12:20

... 1 1 0 -3 0 20 0.025 2 3 0-7 0 50 0.027 3 7 0-9 0 80 0. 039 4 9 0 -1 50 12 0 0.066 5 15 0 -1 90 17 0 0.095 6 19 0-2 10 200 0 .11 5 7 21 0-2 90 250 0 .12 6 8 29 0-4 10 35 0 0 .12 4 9 41 0-4 90 450 0 .11 3 10 49 0-6 10 550 ... 60 1. 5 27.5 27.5 8.5e-04 50 1. 7 27.5 27.5 8.6e-04 25 1. 83 26 26 8.7e-04 15 2.52 25.4 25.4 8.8e-04 CFD Calculated at...

Ngày tải lên: 28/06/2014, 16:20

... as a vverage= + = + = + == 812 3 8 415 1 4 12 8 99 8 4 61 4 12 99 61 12 16 0 12 13 11 3 .  e correct answer is A. 15 . 0 .1 + (0 .1) 2 + (0 .1) 3 = (A) 0 .1 (B) 0 .11 1 (C) 0 .12 11 (D) 0. 23 41 (E) 0 .3 Arithmetic ... an integer. A 10 0 1 1 10 1 1 1 01 + == Integer B 10 0 2 2 10 2 2 51 + == Integer C 10 0 3 3 10 3 3 34 33 3 + ==. NOT an i...

Ngày tải lên: 22/07/2014, 14:20