Machinery Components Maintenance And Repair Episode 2 Part 1 pps
Gear Noise and Vibration Episode 2 Part 1 ppsx
... Fig. 9. 12 ) with 19 :29 at input and 23 : 31 at output. For a complete meshing cycle the layshaft would have to do 19 x 31 revs and 589 revs would take rather a long time and require ... of waveform. Analysis Techniques 14 9 1 0.8 0.6 0.4 0 .2 0 -0 .2 -0.4 -0.6 -0.8 -1 6 8 window length L 10 12 Fig 9.7 Finite length records showing end effects....
Ngày tải lên: 05/08/2014, 09:20
Metal Machining - Theory and Applications Episode 2 Part 5 ppsx
... regenerative 28 2 Process selection, improvement and control Fig. 9.9 Unconditional chatter limit Childs Part 3 31: 3 :20 00 10 :38 am Page 28 2 f mach (1 – n 1 ) n 1 1 C c t ct + C t n 1 C opt = C c t load + ... C p (x) 29 2 Process selection, improvement and control Fig. 9. 12 Fuzzy optimization of cutting conditions; only three constraints 1, 4 and 10 are considered...
Ngày tải lên: 21/07/2014, 17:20
Metal Machining - Theory and Applications Episode 2 Part 1 potx
... cutting process (Part 1) . Trans. ASME J. Eng. Ind. 10 0, 22 2 22 8. Usui, E. and Hirota, A. (19 78) Analytical prediction of three dimensional cutting process (Part 2) . Trans. ASME J. Eng. Ind. 10 0, 22 9 23 5. Usui, ... 19 5 Fig. 6 .18 The dependence of η c on (a) λ s and (b) r n , for machining a carbon steel (after Usui and Hirota, 19 78) (a) Childs Part 2 28:3 :20...
Ngày tải lên: 21/07/2014, 17:20
Bearing Design in Machinery Episode 2 Part 1 pps
... 0:877 DT m ¼ 8:3P½R=Cðf Þ 10 6 Q nRCL 1 Àð0:5ÞQ s =Q ¼ 8:3 25 Â0:877 3 :29 Â0: 519 5 ¼ 10 6 C b. Maximum and Average Oil Temperatures: Maximum temperature: T max ¼ T in þ DT ¼ 20 10 6 ¼ 12 3 C Average temperature: T av ¼ ... highly dependent on the film thickness, particularly under high loads. For turbulent fluid films, the equation is T max À T 1 ¼ f p 2 N 2 D 3 2gc p...
Ngày tải lên: 21/07/2014, 17:20
Gear Noise and Vibration Episode 2 Part 1 docx
... Fig. 9. 12 ) with 19 :29 at input and 23 : 31 at output. For a complete meshing cycle the layshaft would have to do 19 x 31 revs and 589 revs would take rather a long time and require ... resulting Fourier analysis and add bands in groups. If the original record was for 10 s the bandwith would be 0 .1 Hz and adding 10 bands would widen the band...
Ngày tải lên: 05/08/2014, 09:20
Gear Noise and Vibration Episode 2 Part 4 pps
... there is a 20 8 Chapter 12 end for th = 1: 8; % rotate for other 8 teeth xl((th *2* N +l):(th+l) *2* N) = xl(l :2* N)*cos(0.69 813 *th)+yl(l :2* N)*sin(0.69 813 *th); yl((th *2* N +l):(th+l) *2* N) =- xl(l :2* N)*sin(0.69 813 *th)+yl(l :2* N)*cos(0.69 813 *th); end saveteeth9 ... tip relief and deflections for contact ratio of 2. 21 2 Chapter 12 50 10 0 15...
Ngày tải lên: 05/08/2014, 09:20
Gear Noise and Vibration Episode 2 Part 5 pps
... noise. 22 8 Chapter 14 1. 08: 1. 06 1. 04 1. 02 tangent from -0 .1 position base circle 0.98 L •- < 1 -— — - — -0. 12 -0 .1 -0.08 -0.06 -0.04 -0. 02 0 Fig 14 .5 Expanded view of involute near ... Monitoring 23 9 at c c o 2 * 4> 0 U 0) £ .*: (0 4) 0, n u -50 -10 0 -15 0 -20 0 -25 0 -300 -350 Tooth Tooth Tooth Tooth Tooth Tooth Tooth Tooth Tooth Tooth...
Ngày tải lên: 05/08/2014, 09:20
Dictionary of Engineering Episode 2 Part 1 ppsx
... handle. 2. An nance and repair of machinery or equipment. arm with a striking head for sounding a bell or { handho ¯ l} gong. [ MECH ENG ] A power tool with a metal hand lance [ ENG ] A hand-held ... to 1/ 4 U.S. liquid pint, or to getter sputtering [ ELECTR ] The deposition of 1. 1 829 411 825 ϫ 10 Ϫ4 cubic meter. 2. A unit of high-purity thin films at ordinary vacuum levels...
Ngày tải lên: 21/07/2014, 15:20
Process Selection - From Design to Manufacture Episode 2 Part 1 ppsx
... transferring the partly 6.1F Manual assembly process. 18 0 Selecting candidate processes //SYS 21/ //INTEGRAS/B&H/PRS/FINALS_07-05-03/0750654376-CH0 02- 1. 3D – 16 5 – [35 24 8 / 21 4] 9.5 .20 03 2: 05PM 5 .2 Electrochemical ... depending on part complexity, typically Æ0.5 mm. 1 82 Selecting candidate processes //SYS 21/ //INTEGRAS/B&H/PRS/FINALS_07-05-03/0750654376-CH0 02-...
Ngày tải lên: 21/07/2014, 16:21
Engineering Mechanics - Statics Episode 2 Part 1 ppsx
... d+() T BC db−() 2 i 2 + c 2 + + A x + 0= i− T DE ak−() 2 i 2 + j 2 + i T BC db−() 2 i 2 + c 2 + − A y + 0= j T DE ak−() 2 i 2 + j 2 + c T BC db−() 2 i 2 + c 2 + + W− 0= M Ax T DE j i ak−() 2 i 2 + j 2 + + ... are T BC 10 0 lb= T BD 10 0 lb= A x 10 0 lb= A y 10 0 lb= A z 10 0 lb= Given F 1 cos θ () F 2 + () cT BC a c a 2 b 2 + c 2 + ⎛ ⎜ ⎝ ⎞ ⎟...
Ngày tải lên: 21/07/2014, 17:20