Gear Noise and Vibration Episode 1 Part 1 ppt

... frequency band stop filter frequency Fig 9 .15 Response of analog notch and band stop filters. Analysis Techniques 14 3 1. 5 1 0.5 -0.5 -1 -1. 5 0.5 1. 5 2.5 3.5 time Fig 9.2 Build up of saw-tooth ... Fig. 9 .12 ) with 19 :29 at input and 23: 31 at output. For a complete meshing cycle the layshaft would have to do 19 x 31 revs and 589 revs would take ra...

Ngày tải lên: 05/08/2014, 09:20

... resulting Fourier analysis and add bands in groups. If the original record was for 10 s the bandwith would be 0 .1 Hz and adding 10 bands would widen the bandwidth to 1 Hz. The addition ... result is a small amplitude random "white noise& quot; vibration. Analysis Techniques 14 9 1 0.8 0.6 0.4 0.2 0 -0.2 -0.4 -0.6 -0.8 -1 6 8 window length L 10 12...

Ngày tải lên: 05/08/2014, 09:20

... In Fig. 10 .6, curve A is what we would expect from a spur gear and curve B is typical for a helical gear. T.E A - spur gear C - gear with base pitch problem 1 rev Fig 10 .6 Different ... of contact. References 1. Newland, D.E.N., 'Random vibrations, spectral and wavelet analysis.' Longman, Harlow, UK and Wiley, New York, 19 93. 2. R...

Ngày tải lên: 05/08/2014, 09:20

... In Fig. 10 .6, curve A is what we would expect from a spur gear and curve B is typical for a helical gear. T.E A - spur gear C - gear with base pitch problem 1 rev Fig 10 .6 Different ... of contact. References 1. Newland, D.E.N., 'Random vibrations, spectral and wavelet analysis.' Longman, Harlow, UK and Wiley, New York, 19 93. 2. R...

Ngày tải lên: 05/08/2014, 09:20

... Multiple paths for vibration via the four bearing housings. 242 Chapter 15 S3 1 1 1 1 1 1 1 1 1 1 time 1 revolution Fig 15 .5 Expected trace from ball bearing with single inner track pit. ... pinion Fig 16 .3 Separate vibrator excitations on gears so that the vibrator mass does not affect the results.

Ngày tải lên: 05/08/2014, 09:20

... (sl-s2 +te!2) - D12 (V1-V2) rearranges to 11 Al + Dl VI + k!2 (sl-s2+te!2) + D12 (V1-V2) = Q and similarly 12 A2 + D2 V2 - k!2 (sl-s2+te!2) - D12 (V1-V2) = - F23 r2 13 A3 + D3 V3 ... short and high force so the contact will be right across the full facewidth and so a constant stiflhess assumption is reasonable. 2000 15 00 10 00 - 500 -500 - -...

Ngày tải lên: 05/08/2014, 09:20

... short and high force so the contact will be right across the full facewidth and so a constant stiflhess assumption is reasonable. 2000 15 00 10 00 - 500 -500 - -1 000 11 6 11 8 12 0 12 2 ... (sl-s2 +te!2) - D12 (V1-V2) rearranges to 11 Al + Dl VI + k!2 (sl-s2+te!2) + D12 (V1-V2) = Q and similarly 12 A2 + D2 V2 - k!2 (sl-s2+te!2) - D12 (V1-V...

Ngày tải lên: 05/08/2014, 09:20

... flank. xl=zeros (18 *N,l); yl=zeros (18 *N,l); for i = 1: 15 % root circle xl(i) = -5 + 5*cos (1. 4488 -(i-l)*0 .1) ; yl(i) - 40.784 - 5*sin (1. 4488 -(i-l)*0 .1) ; end fori =16 :N; % involute ra = (i -16 )*0.02; xl(i)=40.784*(sin(raHi -16 )*0.02*cos(ra)); yl(i)=40.784*(cos(ra)+(i -16 )*0.02*sin(ra)); end for ... planet gears are very inaccessible and are highly loade...

Ngày tải lên: 05/08/2014, 09:20

... there are 12 and two-thirds cycles of 200 Chapter 11 Reference 1. Romax Ltd., 67 Newgate, Newark NG24 1HD. www.romaxtech.com Planetary and Split Drives 211 (see section 9 .10 ). All ... flank. xl=zeros (18 *N,l); yl=zeros (18 *N,l); for i = 1: 15 % root circle xl(i) = -5 + 5*cos (1. 4488 -(i-l)*0 .1) ; yl(i) - 40.784 - 5*sin (1. 4488 -(i-l)*0 .1) ; end fo...

Ngày tải lên: 05/08/2014, 09:20

... take over as another 14 Low Contact Ratio Gears 14 .1 Advantages Conventional industrial gears tend to use the standard 20° pressure angle and standard proportions and thus encounter ... noise. 228 Chapter 14 1. 08: 1. 06 1. 04 1. 02 tangent from -0 .1 position base circle 0.98 L •- < 1 -— — - — -0 .12 -0 .1 -0.08 -0.06 -0.04 -0.02 0 Fig 14 .5...

Ngày tải lên: 05/08/2014, 09:20