... -0. 71 -1. 00 -3.40 -4.806 -56 .56 17 ,680 -3.20 1. 00 0.94 -3.20 -3.007 40.00 25, 000 1. 60 -0. 71 0.33 -1. 14 0 .53 8 -56 .56 17 ,680 -3.20 0.00 -0.47 0.00 1. 50 9 -40.00 25, 000 -1. 60 -0. 71 -0.33 1. 14 ... is α =5 (10 -6)/oC.Problem 5- 3. 1 24m3m33m 1 23 1. 0 kN0 .5 kN 1 234 5 6 1 234 5 67894m3@4m =12 m 1 234 5 6 1 234 5 67894m3@4m =12 m Truss Analysis: Force Method, Part II ... (kN-mm) 1 80.00 25, 000 3.20 0.00 -0.33 0.00 -1. 062 80.00 25, 000 3.20 -0. 71 -0.33 -2.26 -1. 063 40.00 25, 000 1. 60 0.00 0.33 0.00 0 .53 4 -11 3 .13 17 ,680 -6.40 0.00 0.47 0.00 -3.00 5 12 0.00 25, 000...