Friction and Lubrication in Mechanical Design Episode 2 Part 12 pdf
Friction and Lubrication in Mechanical Design Episode 2 Part 1 potx
... x (10 6) SP, x (10 6) ratio x 10 6 (N/m2) x 10 6 (N/m2) 1 2 3 4 5 6 7 8 9 10 11 12 13 0. 025 1 0.03 61 0. 025 1 0.036 1 0. 025 1 0.036 1 0 .2 19 8 0 .2 19 8 0 .2 19 8 ... 0.0 31 I 0.0 31 1 0 .26 49 0 .26 49 3. 72 4 .25 7.44 8.50 14 .88 17 .00 3.54 7.09 14 .17 2. 853 5.705 0 .1 17 0 .23 4 0.0933 0 .15 34 0 .18 67 0.3069 0.3734 0. 613 7 0.779 1. 557 3 .11 5 0.089 ... 6. 7. 8. 9. 10 . 11 . 12 . 13 . 14 . 15 . 16 . 17 . 18 . 19 . 20 . 21 . 22 . Badgley, R. H., and Booker, J. F., “Rigid-Body Rotor Dynamics: Dynamic Unbalance and Lubrication Temperature...
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Friction and Lubrication in Mechanical Design Episode 2 Part 1 docx
... 95 -1 02. Vol. 19 9(C2), pp. 10 3 -1 11 . 29 8-307. Vol. 2, pp. 52- 58. 19 68, pp. 23 3 -23 9. Design of Fluid Film Bearings 24 7 6. 7. 8. 9. 10 . 11 . 12 . 13 . 14 . 15 . 16 . 17 . 18 . 19 . ... x (10 6) SP, x (10 6) ratio x 10 6 (N/m2) x 10 6 (N/m2) 1 2 3 4 5 6 7 8 9 10 11 12 13 0. 025 1 0.03 61 0. 025 1 0.036 1 0. 025 1 0.036 1 0 .2 19 8 0 .2 19 8 0 .2 19 8 ... 0.0 31 I 0.0 31 1 0 .26 49 0 .26 49 3. 72 4 .25 7.44 8.50 14 .88 17 .00 3.54 7.09 14 .17 2. 853 5.705 0 .1 17 0 .23 4 0.0933 0 .15 34 0 .18 67 0.3069 0.3734 0. 613 7 0.779 1. 557 3 .11 5 0.089...
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Friction and Lubrication in Mechanical Design Episode 2 Part 2 docx
... 1 .22 , k = 0. 026 . Drozdov and Gavrikov [ 171 investigated friction and scoring under conditions of simultaneous rolling and sliding with a roller test machine. The formula for determination ... 94,703, 189,406 ,28 4,109, and 378,8 12 N/m; the slide/roll ratios were 0,0.08,0.154,0 .22 2,0.345; the rolling speeds varied from 0.3 to 2. 76 m/s, and the sliding speeds were in the range 0 ... coefficient of friction in pure rolling conditions and in the isothermal, the nonlinear, and the thermal regimes. The coefficient of friction always decreases with increasing rolling speed. The rate...
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Friction and Lubrication in Mechanical Design Episode 2 Part 2 doc
... 1 .22 , k = 0. 026 . Drozdov and Gavrikov [ 171 investigated friction and scoring under conditions of simultaneous rolling and sliding with a roller test machine. The formula for determination ... 7 .2 Material Properties Steel 43 7800 473 20 3.4 Copper 40 1 8930 386 103 Chromium 94 7135 450 25 0 Tin 67 728 0 22 2 46 10W30 0.145 888 1880 - Rolling/ Sliding Contacts 25 7 ... be within 15%. Ku et al. [21 ] conducted sliding-rolling disk scuffing tests over a wide range of sliding and sum velocities, using a straight mineral oil and three aviation gas turbine synthetic...
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Friction and Lubrication in Mechanical Design Episode 2 Part 3 docx
... 0. 03 pm (12pin.), W = 37 8,812N/m (21 601bf /in. ), 10W30 oil, U1 = 3 .2 m/sec ( 126 in. /sec), R = 0. 0 23 4 m (0. 92 in. ). Figure 7 .38 shows calculated coefficient of friction versus sliding/ ... and Es for AT, K1, c1, p1, El and K2, c2, p2, E2 in Eqs. (7 .27 ) and (7 .28 ), where f is replaced byf,, L is replaced by L = 32 J'm. 2. U1 + U2 3. Mean rolling ... Drozdov. 30 4 Chapter 7 19. 20 . 21 . 22 . 23 . stokes), substitute ml, Tl and m2, T2 into Eq. (7. 32 ) , respec- tively, and solve these two linear equations simultaneously to get a and 6....
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Friction and Lubrication in Mechanical Design Episode 2 Part 4 ppsx
... alloys Invar “36” annealed H,M,80 annealed Monel C 27 0 29 6 22 4 25 2 27 0 27 0 22 4 29 6 I99 46 8 27 0 397 3 59 160 I80 3 84 27 6 24 2 26 0 22 0 21 6 746 22 0 22 6 26 2 340 27 0 29 6 ... Dry 32 1 Dry 44 0 c Dry 0. 54 0.09 0. 54 0.15 0. 54 0.1 1 0. 54 0.60 0. 54 0 .27 0. 54 0 .27 0 .20 0.70 0 .20 0 .22 0. 54 0.19 0 .20 0.78 0 .20 0 .23 0. 54 0.13 0 .20 0. 72 0 .20 0.18 ... 0. 54 0.16 Brass vs. steel 1 045 Dry 0 .20 0.66 A 0 .20 0 .20 B 0 .20 0. 12 41 40 LL Dry 0 .20 0.73 A 0 .20 0 .22 B 0 .20 0 . 24 521 00 Dry 0 .20 0.80 A 0 .20 0 .26 B 0. 54 0 .20 ...
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Friction and Lubrication in Mechanical Design Episode 2 Part 4 ppsx
... alloys Invar “36” annealed H,M,80 annealed Monel C 27 0 29 6 22 4 25 2 27 0 27 0 22 4 29 6 I99 46 8 27 0 397 3 59 160 I80 3 84 27 6 24 2 26 0 22 0 21 6 746 22 0 22 6 26 2 340 27 0 29 6 ... 0. 54 0.15 0. 54 0.1 1 0. 54 0.60 0. 54 0 .27 0. 54 0 .27 0 .20 0.70 0 .20 0 .22 0. 54 0.19 0 .20 0.78 0 .20 0 .23 0. 54 0.13 0 .20 0. 72 0 .20 0.18 0. 54 0.16 Brass vs. steel 1 045 ... Polyethylene 0. 54 0.89 0. 54 0. 14 0. 54 0. 14 0 .20 0.83 0. 54 0. 14 0. 54 0. 14 0 .20 0.93 0. 54 0.15 0. 54 0. 14 0 .20 1.33 0 .20 0.16 0 .20 0.19 0 .20 0.99 0 .20 0.15 0 .20 0.15 Dry 0 .20 1.16...
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Friction and Lubrication in Mechanical Design Episode 2 Part 5 doc
... radial roller bearings. As outlined by Jones [39], the centrifugal Wear 33 7 13. 14. 15. 16. 17. 18. 19. 20 . 21 . 22 . 23 . 24 . 25 . 26 . 27 . 28 . 29 . 30. 31. 32. 33. 34. Blok, ... 20 0 SINK TEMPERATURE 4oo 120 0 - f 1400- 1600- v) 1800- W a 5 20 00- w (3 22 00 - 24 00 - 26 00 - 28 00 - 3000 Figure 9 .2 Design chart for gear lubrication. 9.1 .5 Most ... inclusions in the surface region. 9 .2 ROLLING ELEMENT BEARINGS Rolling element bearings represents some of the most critical components in rotating machinery. Because of the ever-increasing...
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Friction and Lubrication in Mechanical Design Episode 2 Part 6 pot
... in. 2. 565 8 in. 2. 563 7 in. 2. 5 62 0 in. 0.5 766 in. 0 .65 9 in. 12 0.1719 in. 0.3 0.0 021 in. 0.0038 in. Brass Mild steel 8-10 pin rms (10.99947 cm) (4.99 922 8 cm) (2. 6 924 cm) ... (2. 6 924 cm) (9.44 62 cm) (6. 5171 32 cm) (6. 51 1798 cm) (6. 50478 cm) (1. 464 564 cm) (1 .67 3 86 cm) (0.4 36 62 6 cm) (0.005334 cm) (0.00 965 3 cm) Load Figure 9.1 2 Diagrammatic representation ... condition (2) = 0 .25 (2) = 0.50 (2) = 0.75 I. Uniform thickness and external loading 73,4 56. 4 70,378.9 50,5 06. 1 2. Uniform thickness and internal loading 27 2 ,28 3.7 137,739.3 67 ,039.4...
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Friction and Lubrication in Mechanical Design Episode 2 Part 6 doc
... Outer and inner race material Surface finish for rollers and races 4.3305 in. 1. 96 82 in. 1. 06 in. 3.719 in. 2. 565 8 in. 2. 563 7 in. 2. 5 62 0 in. 0.5 766 in. 0 .65 9 in. 12 0.1719 in. ... 0.0 021 in. 0.0038 in. Brass Mild steel 8-10 pin rms (10.99947 cm) (4.99 922 8 cm) (2. 6 924 cm) (9.44 62 cm) (6. 5171 32 cm) (6. 51 1798 cm) (6. 50478 cm) (1. 464 564 cm) (1 .67 3 86 ... loading 27 2 ,28 3.7 137,739.3 67 ,039.4 3. Uniform thickness and equal load sharing 13 1, 164 .9 54,8 46. 1 19 ,6 16. 8 4. Uniform thickness and optimal load sharing 50 ,28 3.1 33,954 .6 16, 393.5...
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Friction and Lubrication in Mechanical Design Episode 2 Part 7 pdf
... smaller increases in the mineral content ratio resulted from the lower compressive loads. This result is interesting in view of the finding of Radin et al. [88] that increased calcification and ... I Torque =22 .6*(1 -cos (2& apos;pi'Pt)) /2 N-m =20 0'( 1 -cos (2& apos;pi'f9)) /2 Ib -in - f=100 HZ Figure 9. 37 The heat flux at four key points under the fretting contact ... Equations (9.36) and (9. 37) in the wedging condition are plotted in normal- ized form as shown in Figs 9.31 and 9. 32, respectively. The change of the c value with increasing ramp angle...
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Friction and Lubrication in Mechanical Design Episode 2 Part 11 pdf
... Loading,” Surface Engineering Volume 11: Engineering Applications, Dotta, P. K. et al. (eds), Royal Society of Chemistry, Cambridge, England, 19 92. Mort, J., “Diamond and Diamond-like Coatings,” ... Rickerby, D. S., and Matthews, A., Advanced Surface Coatings: A Handbook of Surface Engineering, Blackie and Son, New York, NY, 1991. Sander, H., and Petersohn, D., Friction and Wear Behavior ... “Coatings: Key Factor in Cutting Tool Performance,” Mach. Tool Blue Bk., Vol. 81(1), pp. 62- 64. Kane, G. E., “Modern Trends in Cutting Tools,” Society of Manufacturing Engineering, 19 82, ...
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Friction and Lubrication in Mechanical Design Episode 2 Part 12 pdf
... data: h2 = 0.000 6in. , m = 0.000 9in. /in. , 18 spm, SAE 5 oil, 25 °C. at four different instances in time, as indicated by (a), (b), (c), and (d) in Fig. 13 .20 . The corresponding instantaneous ... 10 15 20 SpHd (in/ s) Figure 13 .24 m = 0.001 1 in. /in. , SAE 20 oil, 25 °C. Pressure-speed characteristic of slider bearing: h2 = 0.0010 in. , steel plate and the loading screws ... 1 .25 1 SO Location (in) Figure 13 .22 Pressure distribution along the central line in the direction of motion: h2 = 0.001 0in. , m = 0.0011 in. /in. , V = 18.01 in. /sec., p = 1.986...
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Friction and Lubrication in Mechanical Design Episode 2 Part 12 potx
... data: h2 = 0.000 6in. , m = 0.000 9in. /in. , 18 spm, SAE 5 oil, 25 °C. at four different instances in time, as indicated by (a), (b), (c), and (d) in Fig. 13 .20 . The corresponding instantaneous ... sures ranging from 125 0 to 21 40 MPa (1.8 1 x 10’ - 3.10 x 10’ psi) and slid- ing speeds from 0.4 to 1.3 m/sec (943-3 1 42 in. /min). Temperature and wear 5 18 30 25 20 = ... I 7 DbpIacament Scab (in) - 0 128 46 Loading Rata - 0. 122 61bf/s SeCOndr 111111111111111111111 (a) Time (8) 4 - 012a4s second8 Loading Rate 0. 42 Ibfh I1111 IIIIIII 3 Figure...
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