Friction and Lubrication in Mechanical Design Episode 2 Part 2 doc

... semi-infinite elastic solid. a, = horizontal stress at any point I = P((1 2n - 2v)[$ - z v2 (E 2n ~3( ,2~ 2)-5 /2) -”~] - 3r2Z(r2 + 22 )-5 /2 az = vertical stress at any point ... was given by Boussinesq [I] as: 22 18 Chapter 1 22 . 23 . 24 . 25 . 26 . 27 . 28 . 29 . 30. 31. 32. 33. 34. 35. 36. 37. 38. 39. 40. 41. 42. Seireg, A., and Wei...

Ngày tải lên: 05/08/2014, 09:20

... + sin 21 q= k1z1 =- sinh /!?x sin /!?.U [ (cosh 2i- COS 2A) - (sinh 2; 1+ sin 2A) - sinh Bx cos Px + cosh Bx sin Bx where (2. 12) A = ge q = the load intensity ... comes into play and the constant stiffness model can no longer be justified. An empirical method 54 Chapter 2 18. 19. 20 . 21 . 22 . 23 . 24 . 25 . 26 . 27 . 28 . 29 . 30...

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... applied at 45" inclination. 800 lbf applied at 45" inclination. 120 0 lbf applied at 45" inclination. The coefficient of friction on both regions 1 and 2 is assumed to ... and is used to obtain the solution. 3 Traction Distribution and Microslip in Frictional Contacts Between Smooth Elastic Bodies 3.1 INTRODUCTION Frictional joints attained...

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... Damage 9.1 Surface Failure in Gears 9 .2 Rolling Element Bearings ix 25 1 25 1 25 2 25 3 25 6 26 0 26 4 27 0 300 304 307 310 3 10 31 1 3 12 317 327 328 3 32 3 32 333 333 334 335 ... 7 Friction and Lubrication in Rolling/Sliding Contacts 7.1 Rolling Friction 7 .2 Hydrodynamic Lubrication and Friction 7.3 Elastohydrodynamics in Rollin...

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... Flame cutting Sand casting 2- 8 2- 16 4-16 4- 32 4-63 8-16 8- 32 16 -25 0 32- 63 32- 125 32- 1 25 32- 125 32- 250 63-1 25 63 -25 0 63 -25 0 63 -25 0 63-500 63-1000 125 -500 25 0-1 000 500- ... Die casting Cold rolling, drawing Extruding Reaming Milling Mold casting Drilling Chemical milling Elect. discharge machining Planing, shaping Sawing Forgi...

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... plotted in Fig. 5.1 for steel. I20 Chapter 4 26 . 27 . 28 . 29 . 30. 31. 32. 33. Rao, P. N., Rao, U. R. K., and Rao, J. S., “Towards Improved Design of Boring Bars Part I and ... presented by Greenwood and Tripp discussed in this chapter provides a rational proce- 124 Chapter 5 24 20 I 4 0 0 4 8 12 16 20 24 28 32 Time - t (min)...

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... Let: 0. 627 (5 .25 a) then: and let: then: To - Ts - = CB 41 (5 .25 b) (5 .26 a) (5 .26 b) Equations (5 .23 b)-(5 .26 b) are valid for the following range of operating conditions and thermal ... also used in developing the following dimensionless equations for maximum solid and surface layer temperatures. Let: -0.788 (5 .23 ) then: (5 .23 ) and let: (5 .24 a)...

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... 20 . 21 . 22 . 23 . 24 . 25 . 26 . 27 . 28 . 29 . Klaus, E. E., “Thermal and Chemical Effects in Boundary Lubrication, ” Lubrication Challenges in Metalworking and Processing, Proc. 1 st Int. ... Cry =z -21 .1 I + 27 .88 Cyv == 22 .24 -i- 28 .43 - 1647S6S+ 7078.46S2 + 739.865 - 705,62S + 23 27 .28 S2 + 353.02D - 6 72. 00s + 23 29.06S2 + 337....

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... 120 140 160 180 20 0 22 0 24 0 26 0 28 0 AT (OF) Figure 6 .20 Bearing chart for P = 500 psi. 9E-6 8E-6 7E-6 6E-6 5E-6 2E-6 1 E-6 0 20 40 60 80 100 120 140 160 180 20 0 22 0 ... 5x1 0" 4x10" 3x106 n * B 2x1 o8 1 OS 0 20 40 60 80 100 120 140 160 180 20 0 22 0 24 0 26 0 28 0 AT (OF) Figure 6 .26 Bearing design chart: applica...

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... = 0.00 022 7 kg-sec2). 9E-6 8E-6 7E-6 6E-6 5E-6 a 3E-6 2E-6 1 E-6 Ud m 0.2s ud 10.5 P = SO0 p.1 Udml.O 0 20 40 60 80 100 120 140 160 180 20 0 22 0 24 0 26 0 28 0 AT (OF) ... Figure 6 .20 Bearing chart for P = 500 psi. 9E-6 8E-6 7E-6 6E-6 5E-6 2E-6 1 E-6 0 20 40 60 80 100 120 140 160 180 20 0 22 0 24 0 26 0 28 0 AT (OF) Figu...

Ngày tải lên: 05/08/2014, 09:20