Friction and Lubrication in Mechanical Design Episode 1 Part 7 pdf

... 62 76 90 97 10 0 10 0 10 0 10 5 11 1 11 3 11 3 11 4 11 5 11 6 11 8 12 1 12 1 12 1 12 3 12 7 13 5 14 2 15 8 16 1 16 1 18 7 209 230 246 24. Traction Drives: Selection and Application, ... 1 1 .1 Introduction 11 .2 Frictional Noise Due to Rubbing 11 .3 Effect of Lubrication on Noise Reduction 11 .4 Frictional Noise in Gears 1 1. 5 Friction- Ind...

Ngày tải lên: 05/08/2014, 09:20

... on Gear Lubrication, ” Bull. JSME, 19 61, Vol. 4 (14 ), p. 3 82. 26 6( 1 17 0), pp. 1- 33. p. 57. 2 15 -23 6. 17 (4), pp. 2 71- 27 9. 24 Chapter 2 U = horizontal displacement and w ... was given by Boussinesq [I] as: 22 18 Chapter 1 22 . 23 . 24 . 25 . 26 . 27 . 28 . 29 . 30. 31. 32. 33. 34. 35. 36. 37. 38. 39. 40. 41. 42....

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... 10 3 10 2 10 1 0 .1 H,=5 in. - - - - h K 2 10 -2 10 -3 - t, - 10 4 10 -5 10 -6 1 I I I 111 11 I I I 111 111 1 I 11 Ill 11 I I I1 11 111 1 I I I LLU EXAMPLE 4. In ... given in Refs 21- 39 . REFERENCES 1. 2. 3. 4. 5. 6. 7. 8. 9. 10 . 11 . 12 . 13 . 14 . 15 . 16 . 17 . Timoshenko, S.P., Theory of Elasticity, McGraw H...

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... The rigid body movement (0.6 619 6 x 10 -4 in. ) was also found to compare favorably with Mindlin's prediction (0.67 13 9 x 10 -4 in. ) with a deviation of 1. 41 O/O. EXAMPLE 2: Circular ... 20,OOOpsi, P2 = 10 ,OOOpsi and the tangential load is 800 lbf applied at 45 " inclination. 800 lbf applied at 45 " inclination. 12 00 lbf applied at 45 &q...

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... machining Planing, shaping Sawing Forging Snagging Hot rolling Flame cutting Sand casting 2-8 2 -16 4 -16 4-32 4-63 8 -16 8-32 16 - 250 32-63 32 -12 5 32 -1 25 32 -12 5 32- 250 63 -1 25 ... 63- 250 63- 250 63- 250 63 -50 0 63 -10 00 12 5- 500 250 -1 000 50 0- 10 00 50 0- 10 00 50 0- 10 00 literature [ 1- 18]. Although various factors affect...

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... the interface. 1. 2. 3. 4. 5. 6. 7. Albrecht, A. B., “How to Secure Surface Finish in Turning Operations,” Am. Machin., 19 56, Vol. 10 0, pp. 13 3 -13 6. Chandiramani, K. L., and Cook, ... Res., Zhang, G. M., and Kapoor, S. G., “Dynamic Generation of Machined Surfaces,” J. Indust. Eng., ASME, Parts I and 11 , 19 91, Vol. 11 3, pp. 13 7 -15 9. Olgac, N., a...

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... (5 .12 ): and where (5 .18 ) and The percentage of heat flowing to the upper solid can be predicted by sub- stituting Eq. (5 . 17 ) into Eq. (5 .15 ) to get: (5 .19 ) 44 - c1) AI Y1 = and ... as: 1 a= and accordingly: (5 .10 ) (5 .1 1) Blok [2] derived an identical equation for the flash temperature. The contact in Blok's equation is determined anal...

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... (rolling velocity = 2000 in. /sec, 1= .02 in. , K~=K~~, K~~=K*=.I K~, H,,,=~o~ in. ). Thermal Considerations in Tribology 15 9 4. 5. 6. 7. 8. 9. 10 . 11 . 12 . 13 . 14 . 15 . 16 . 17 . ... Rolling/sliding Contacts,” Proc. Inst. Mech. Engrs, 19 67 -1 9 68, Vol. 19 82 , Pt. 1, No. 41, p. 81 3 . Conry, T. F., “Thermal Effects on Traction in EHD Lubricati...

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... 19 4 Chapter 6 9x1 o8 8x1 O8 7x1 O8 6x1 0" 5x1 0" 4x10" 3x106 n * B 2x1 o8 1 OS 0 20 40 60 80 10 0 12 0 14 0 16 0 18 0 200 220 240 260 ... 80 10 0 12 0 14 0 16 0 18 0 200 220 240 260 280 AT (OF) Figure 6.20 Bearing chart for P = 500 psi. 9E-6 8E-6 7E-6 6E-6 5E-6 2E-6 1 E-6 0 20 40 60 80 10 0 12 0 14 0 16 0 18 0 ....

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... rotor at 5500 rpm. 19 4 Chapter 6 9x1 o8 8x1 O8 7x1 O8 6x1 0" 5x1 0" 4x10" 3x106 n * B 2x1 o8 1 OS 0 20 40 60 80 10 0 12 0 14 0 16 0 18 0 200 220 240 260 ... 57.67 0.006 1. 53 x 10 -6 0. 014 2 15 5. 81 26.6 44 55.6 0. 012 1. 61 x 10 -6 0.00375 8 12 .00 32 68 92 19 6 Chapter 6 O.OO0 0.002 0.004 0.006 0.008 0. 01...

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... Constants SAE 10 1. 18 x 10 -5 2 .18 x 10 -6 1. 58 x 10 -8 1 15 7.5 SAE 20 1. 95 x 10 -’ 3 .15 x 10 -6 1. 36 x 10 -* 12 71. 6 SAE 30 3.35 x 10 -’ 4.60 x 10 -6 1. 41 x 10 -’ 13 60.9 SAE ... loss 1 1 10 -~ 3.4 10 -~ 0.36 3.77 4.88 7600 0 .14 7 5 1 x 10 -7 2.55 x 10 -3 0.325 11 .00 2 .15 8500 0 .17 5 10 1 x 10 -7 1. 5...

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... smaller increases in the mineral content ratio resulted from the lower compressive loads. This result is interesting in view of the finding of Radin et al. [88] that increased calcification and ... I Torque =22 .6*(1 -cos (2& apos;pi'Pt)) /2 N-m =20 0'( 1 -cos (2& apos;pi'f9)) /2 Ib -in - f=100 HZ Figure 9. 37 The heat flux at four key points under t...

Ngày tải lên: 05/08/2014, 09:20

... I Torque =22 .6*(1 -cos (2& apos;pi'Pt)) /2 N-m =20 0'( 1 -cos (2& apos;pi'f9)) /2 Ib -in - f=100 HZ Figure 9. 37 The heat flux at four key points under the fretting contact ... Torque =22 .6‘( 1 -cos (2* pi’ft)) /2 N-m =20 0’(1 -ws(P*pi’ft))l2 Ib -in 0 0 0.1 0 .2 0.3 0.4 0.5 0.6 0 .7 0.8 0.9 1 Time (sec) Figure 9.41 Fretting wear p...

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... Loading,” Surface Engineering Volume 11: Engineering Applications, Dotta, P. K. et al. (eds), Royal Society of Chemistry, Cambridge, England, 19 92. Mort, J., “Diamond and Diamond-like Coatings,” ... Rickerby, D. S., and Matthews, A., Advanced Surface Coatings: A Handbook of Surface Engineering, Blackie and Son, New York, NY, 1991. Sander, H., and Petersohn, D., Friction a...

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... data: h2 = 0.000 6in. , m = 0.000 9in. /in. , 18 spm, SAE 5 oil, 25 °C. at four different instances in time, as indicated by (a), (b), (c), and (d) in Fig. 13 .20 . The corresponding instantaneous ... 10 15 20 SpHd (in/ s) Figure 13 .24 m = 0.001 1 in. /in. , SAE 20 oil, 25 °C. Pressure-speed characteristic of slider bearing: h2 = 0.0010 in. , st...

Ngày tải lên: 05/08/2014, 09:20