100 STATISTICAL TESTS phần 1 pdf

... book. GOKA: “FM” — 2006/6 /15 — 15 : 21 — PAGE iii — #3 10 0 STATISTICAL TESTS 3rd Edition Gopal K. Kanji GOKA: “CHAP02” — 2006/6 /10 — 17 : 21 — PAGE 10 — #6 10 10 0 STATISTICAL TESTS Test 15 χ 2 -test for a ... first GOKA: “FM” — 2006/6 /15 — 15 : 21 — PAGEi— #1 10 0 STATISTICAL TESTS GOKA: “CHAP 01 — 2006/6 /10 — 17 : 21 — PAGE4—#4 4 10 0 STATISTICAL T...

Ngày tải lên: 23/07/2014, 16:21

... 11 1 11 0 10 9 10 8 10 8 0. 01 105 10 3 10 2 10 0 99 99 98 98 13 0.05 13 8 13 5 13 3 13 2 13 0 12 9 12 9 12 8 0. 01 125 12 3 12 1 12 0 11 9 11 8 11 7 11 7 14 0.05 16 1 15 8 15 5 15 4 15 3 15 2 15 1 15 0 0. 01 147 14 4 14 2 14 1 14 0 ... 11 3 12 5 28 86 10 0 11 8 13 0 29 90 10 6 12 6 13 8 30 95 11 1 13 1 14 5 31 99 11 7 13 7 15 1 32...

Ngày tải lên: 23/07/2014, 16:21

... 810 1 012 50 14 16 18 20 15 9 9 11 11 55 15 17 19 21 16 810 1 212 56 14 16 18 20 17 9 9 11 13 59 15 17 19 21 18 810 1 212 60 14 18 20 22 19 911 111 3 65 15 17 21 23 20 10 10 12 14 66 16 18 20 22 21 911 1 313 69 15 ... –– 36 12 14 16 18 7 777 – 37 11 13 17 17 8 6888 38 12 14 16 18 9 7799 39 13 15 17 17 10 8 8 10 10 40 12 14 16 18...

Ngày tải lên: 23/07/2014, 16:21

... 0.0823 1. 2 0 .11 51 0 .11 31 0 .11 12 0 .10 93 0 .10 75 0 .10 56 0 .10 38 0 .10 20 0 .10 03 0.0985 1. 1 0 .13 57 0 .13 35 0 .13 14 0 .12 92 0 .12 71 0 .12 51 0 .12 30 0 .12 10 0 .11 90 0 .11 70 1. 0 0 .15 87 0 .15 62 0 .15 39 0 .15 15 0 .14 92 0 .14 69 ... 1. 90 1. 85 1. 81 1.75 1. 70 1. 64 30 2 .16 2.09 2. 01 1.93 1. 89 1. 84 1. 79 1. 74 1. 68 1. 62 40 2.08 2.00 1. 92...

Ngày tải lên: 23/07/2014, 16:21

... Total 1 7.8 11 .1 11. 7 (16 .5) (23 .1) ( 21. 7) 61. 3 8.7 12 .0 10 .0 2 8.0 11 .3 9.8 (17 .2) ( 21. 9) ( 21. 7) 60.8 9.2 10 .6 11 .9 3 4.0 9.8 11 .7 (10 .9) (19 .9) (24.3) 55 .1 6.9 10 .1 12.6 4 10 .3 11 .4 7.9 (19 .7) ... couples W t +1 W t +1 H t 10 1 0 1 76 10 0 80 63 0 79 200 43 39 β 1 = log e 76 × 200 79 × 10 0 = 0.654; β 2 = log e 80 ×39 43 × 63 = 0 .14...

Ngày tải lên: 23/07/2014, 16:21

... 10 10 10 +10 + 1 = 200 20 + 1 = 11 σ 2 K = 2 10 10 (2 × 10 × 10 10 10 ) (10 +10 ) 2 (10 +10 1) = 4.74, σ K = 2 .18 Z = 11 − 11 + 1 2 2 .18 = 0.23. Critical value at α = 0.05 is 1. 96 [Table 1] . Hence ... 23 21 13 14 16 5 Mean 16 .5 16 .5 16 .5 16 .5 16 .5 16 .5 16 .5 16 .5 16 .5 16 .5 16 5 Difference 0.5 1. 5 0.5 −8.5 −0.5 1. 5 6.5 4.5 −3.5 −2.5 GOKA: “CH...

Ngày tải lên: 23/07/2014, 16:21

... 6 .1 7.3 7.3 8.5 Rank 14 58 912 1 316 1720 Sample xxxxxyxyyy Value 8.8 9.4 9.8 10 .1 10.l 11 .7 12 .6 13 .1 15.3 16 .5 Rank 19 18 15 14 11 10 7632 n 1 = n 2 = 10 R x = 1 + 13 + 16 +20 + 19 +18 + 15 + 14 +11 ... calculation n 1 = 5, n 2 = 5, α = 0.05 x i 11 .79 11 . 21 13.20 12 .66 13 .37 y i 10 .34 11 .40 10 .19 12 .10 11 .46 Rearrangement gives the follo...

Ngày tải lên: 23/07/2014, 16:21

... 77 No. 12 345678 910 111 213 14 x i 5 14 24 57 11 1 19 7 278 378 418 4 61 433 413 358 219 cu(x i ) 5 19 43 10 0 211 408 686 10 64 14 82 19 43 2376 2789 314 7 3366 S n (x i ) 0.0 01 0.005 0. 012 0.029 0.062 0 .12 1 ... calculation a = 15 , b = 85, c = 4, d = 77 a + b = 10 0, c + d = 81, a + c = 19 , b +d = 16 2 α = 0 .10 , ν = 1, χ 2 1; 0 .10 = 2.7, n = 18 1 [Table 5] χ...

Ngày tải lên: 23/07/2014, 16:21

... first sample Z 1 = 1 2 log e  1 + r 1 1 − r 1  = 1. 1 513 log 10  1 + r 1 1 − r 1  which has mean µ Z 1 = 1 2 log e [ (1 + ρ 1 )/ (1 − ρ 1 )] and variance σ Z 1 = 1/ √ n 1 − 3, where n 1 is the size ... 19 0 × 805 15 1 +2 (15 1) 3 19 0 18 9 18 8 = 0.5799445 K 4 = 2 795 4 21 924 19 0 18 9 18 8 × 18 7 = 2. 214 280 GOKA: “CHAP05A” — 2006/6 /10 — 17 :2...

Ngày tải lên: 23/07/2014, 16:21

... 2006/6 /10 — 17 :22 — PAGE 41 — # 21 THE TESTS 41 Numerical calculation r = 0.75, ρ 0 = 0.50, n = 24 µ Z 1 = 1. 1 513 log 10 3 = 0.5493, Z 1 = 1. 1 513 log 10  1 + 0.75 1 − 0.75  = 0.9730 [Table 4] σ Z 1 = ... standard deviation σ Z 1 where µ Z 1 = 1 2 log e  1 + ρ 0 1 − ρ 0  = 1. 1 513 log 10  1 + r 1 − r  σ Z 1 = 1 √ n − 3 . The test statisti...

Ngày tải lên: 23/07/2014, 16:21