SAT practise test 20000 part 5 ppsx
SAT practise test 20000 part 5 ppsx
... definition of a meter. ( 15) (20) ( 25) (30) ( 35) (40) ( 45) (50 ) (55 ) (60) ( 65) (70) ( 75) (80) ( 85) (90) 38 Copyright © 20 05 Thomson Peterson’s, a part of The Thomson Corporaton SAT is a registered ... important, or influential, or of great merit? (5) (10) ( 15) (5) (10) ( 15) (20) 36 Copyright © 20 05 Thomson Peterson’s, a part of The Thomson Corporaton SAT i...
Ngày tải lên: 22/07/2014, 10:22
SAT practise test 20000 part 4 ppsx
... 1200 (D) 2000 (E) 2400 2. If Z 5 2x 5 and Z 5 3, then x 5 (A) 5 3 (B)2 (C )5 (D) 19 3 (E) 15 2 30 Copyright © 20 05 Thomson Peterson’s, a part of The Thomson Corporaton SAT is a registered trademark ... otherwise. Reference Information w b h h w h b a c 3x r r 2x 30 60 45 45 2s s s x A 5pr 2 C 5 2prA5 ,w A 5 1 2 bh V 5 ,wh V 5pr 2 hc 2 5 a 2 1 b 2 Special Right Tr...
Ngày tải lên: 22/07/2014, 10:22
SAT practise test 20000 part 11 pot
... Worksheet MATH Number Correct Number Incorrect 5 Raw Score Section 2 2 (. 25 3 ) 5 Section 5 2 (. 25 3 ) 5 Section 7 2 (. 25 3 ) 5 CRITICAL READING Sections 1, 4, and 6 2 (. 25 3 ) 5 WRITING Section 3 2 (. 25 3 ) 5 Section 8 Go ... 5 Section 8 Go to www.petersons.com/satessayedge/ for instant online scoring and feedback. 81Copyright © 20 05 Thomson Peterson’s, a part o...
Ngày tải lên: 22/07/2014, 10:22
SAT practise test 20000 part 10 docx
... information you can solve for y using the equation: 80 2 y 4 5 14 ~ 4 ! 80 2 y 4 5 14 ~ 4 ! 80 2 y 5 56 80 2 56 2 y 5 56 2 56 24 2 y 5 0 24 5 y 8. Since the triangle is a right triangle, you can use ... product. 7. If x is the sum of the five numbers, you know: sum number of items 5 Average x 5 5 16 ~ 5 ! x 5 5 16 ~ 5 ! x 5 80 Make y the number taken away from the s...
Ngày tải lên: 22/07/2014, 10:22
SAT practise test 20000 part 9 pptx
... substitution problem. If Z 5 3 and Z 5 2x 5 , then you substitute the value of 3 for Z in the second equation to get: Z 5 2x 5 3 5 2x 5 ~ 5 ! 3 5 2x 5 ~ 5 ! 15 5 2x 15 2 5 2x 2 15 2 5 x (E) is the answer. 67Copyright ... about this problem as a method of solving for y. a 2 1 b 2 5 c 2 y 2 1 5 2 5 10 2 y 2 1 25 5 100 y 2 1 25 2 25 5 100 2 25 y 2 5 75...
Ngày tải lên: 22/07/2014, 10:22
SAT practise test 20000 part 8 potx
... DE. It has sides of 2 .5 and 6. Placing those values into the Pythagorean theorem yields: a 2 1 b 2 5 c 2 2 .5 2 1 6 2 5 c 2 6. 25 1 36 5 c 2 42. 25 5 c 2 = 42. 25 5 = c 6 .5 5 c It’s choice (B). 20. ... 4b 2 21 2 2b 2 2 12b 2 10 2b 2 52 b 2 2 16b 2 31 2b 2 1 b 2 52 b 2 1 b 2 2 16b 2 31 0 52 16b 2 31 0 1 16b 52 16b 1 16b 2 31 16b 52 31 16b 16 5 231 16 b 52 31 16 52 1 15...
Ngày tải lên: 22/07/2014, 10:22
SAT practise test 20000 part 7 ppt
... is 100 (1 950 2 1 850 ), so what percent of 1, 850 is 100? S n 100 D 1 850 5 100 ~ 100 ! S n 100 D 1 850 5 100 ~ 100 ! 1 850 n 5 10000 1 850 n 1 850 5 10000 1 850 n 5 5.4 100 is 5. 4 percent of 1 850 , which ... just leave the 3f as is, and monkey with the formula this way: 3f 1 15 5 27 3f 1 15 2 15 5 27 2 15 3f 5 12 3f 2 6 5 12 2 6 3f 2 6 5 6 Whichever path you take, if...
Ngày tải lên: 22/07/2014, 10:22
SAT practise test 20000 part 6 pot
... answer 3 1 5 must be gridded as 16 /5 or 3.2. If is gridded, it will be read as 31 5 , not 3 1 5 . 31 /5 O / Þ O . O . O . O . O 0 O 0 O 0 O 1 Þ O 1 O 1 O 2 O 2 O 2 O 2 Þ O 3 O 3 O 3 O 4 O 4 O 4 O 4 O 5 O 5 O 5 Þ Decimal ... 1/3 Þ O / O . O . O . O . O 0 O 0 O 0 Þ O 1 O 1 O 1 O 2 O 2 O 2 O 2 O 3 O 3 Þ O 3 O 4 O 4 O 4 O 4 O 5 O 5 O 5 O 5 O 6 O 6 O 6 O 6 .333 O / O / Þ O...
Ngày tải lên: 22/07/2014, 10:22
SAT practise test 20000 part 3 doc
... a Frenchman wrote four centuries back. (5) (10) ( 15) (20) ( 25) (30) ( 35) (40) 20 Copyright © 20 05 Thomson Peterson’s, a part of The Thomson Corporaton SAT is a registered trademark of the College ... protests were even __________. (A) disliked organized (B) espoused planned (C) discouraged theorized (D) bolstered. .analyzed (E) detested negotiated 24 Copyright © 20 05 Thomson P...
Ngày tải lên: 22/07/2014, 10:22
SAT practise test 20000 part 2 pptx
... one? (A)46 (B )51 (C )55 (D )57 (E )58 19. What is the distance from the midpoint of DE to the origin, if D(0,12) and E (5, 0)? (A )5 (B) 6 .5 (C) 8.2 (D)12 (E)13 20. If 2b 2 5 (b 2 7)(b 1 3) 2 (2b 1 2)(b 1 5) , then ... otherwise. Reference Information w b h h w h b a c 3x r r 2x 30 60 45 45 2s s s x A 5pr 2 C 5 2prA5 ,w A 5 1 2 bh V 5 ,wh V 5pr 2 hc 2 5 a 2 1 b 2 Special...
Ngày tải lên: 22/07/2014, 10:22