Metal Machining - Theory and Applications Episode 1 Part 1 potx
Metal Machining - Theory and Applications Episode 2 Part 1 potx
... 19 5
Fig. 6 .18 The dependence of
η
c
on (a)
λ
s
and (b)
r
n
, for machining a carbon steel (after Usui and Hirota, 19 78)
(a)
Childs Part 2 28:3:2000 3 :13 pm Page 19 5
19 93; Ceretti et al., 19 96) and ... 3 :14 pm Page 211
Kudo, H. (19 65) Some new slip-line solutions for two-dimensional steady-state machining. Int. J.
Mech. Sci. 7, 43–55.
Lee, E. H. and Shaffer, B. W...
Metal Machining - Theory and Applications Episode 2 Part 11 ppt
... [W/mK]
P 01 10 50 16 20 6 8 < 2 6900 16 .2 1. 2 20
P05–25 49 16 15 8 12 < 2 7000 14 .2 1. 8 20
P 01 15 48 16 20 5 11 –* 7000 15 .7 –* 20
P05 Total carbide: 94 Total metal: 6 –* 610 0 17 .2 1. 8 –*
P10 ... [10
-6
K
-1
]
– 97 3 4000 16 .2 0.55 8.7 380 –
K10 96.5 3.5 4020 17 .0 0.7 – – –
P/K 01 10 96 4 4000 17 .0 0.7 – – –
– √* √* 4000 18 .6 0.8 – – –
P 01 15 80...
Metal Machining - Theory and Applications Episode 2 Part 10 pot
... [GPa] [10
–6
K
1
]
P/K 01 05 95 5 1 6800 18 .1 1.3 11 410 6.7
P10–P15 86 14 1 710 0 15 .5 1. 65 12 400 7.2
P/K05 15 89 11 < ;1 7000 16 .5 1. 65 14 410 7.6
P10–P25 85 15 < ;1 7000 15 .2 2.0 19 390 ... 23 15 10 6.5 4.5
0.04–0.25C 14 16 11 13 8.6–9.3 6 .1 6.4 4.2–4.3
0.25–0.8C 14 15 11 12 8 .1 8.7 5.7–6 .1 4.2–4.3
0.8 1. 2C 12 14 10 11 7.6–8 .1 5.6–5.7 3.9–4...
Metal Machining - Theory and Applications Episode 2 Part 9 doc
... u˘
y
c
l
+ u˘
z
d
l
hD
ikj
211 0
+ ——
[
12 10
]
12
11 20
0000 (A2.26)
and
11 1
q*V
e
1
qD
ikj
1
hT
0
D
ikj
1
{F}
e
= ———
{}
– ———
{}
– ———
{}
(A2.27)
4
1
3
1
3
1
10 0
Global assembly of equations ... [H]
e
{T} = {F
e
} (A2.30)
∂t
with
rCV
e
211 1
[C]
e
= ———
|
12 11
|
20
11 21
111 2
([C] is given here for a four-node tetrahedron).
Numerical (finite element) method...
Metal Machining - Theory and Applications Episode 2 Part 8 pptx
... 339
Fig. A1.8 Metal machining slip-line fields (left) and their velocity diagrams (right), due to (1) Lee and Shaffer (19 51) ,
(2–4) Kudo (19 65) and (5) Dewhurst (19 78)
Childs Part 3 31: 3:2000 10 : 41 am ... (A1.48a)
where, from equation (A1.42)
1 – nn n
——— ——— ——— 0 0 0
1 – 2n 1 – 2n 1 – 2n
n 1 – nn
——— ——— ——— 0 0 0
E 1 – 2n 1 – 2n 1 – 2n
[D
e
] = ———
[
00...
Metal Machining - Theory and Applications Episode 2 Part 7 ppt
... infrared and thermocouple data. Trans. ASME, J. Eng. Ind. 11 3, 12 1 12 8.
Stephenson, D. A. and Agapiou, J. S. (19 97) Metal Cutting Theory and Practice. New York: Marcel
Dekker, p. 6 01.
Takata, S. (19 93) ... Trans. on Auto. Cont. 19 ,
716 –722.
ASM (19 90) Classification and designation of carbon and low-alloy steels. In ASM Handbook 10 th
edn. Vol. 1, 14 0 19 4. Ohi...
Metal Machining - Theory and Applications Episode 2 Part 6 pot
... [mm]
SVVBN2525M16 VBMM160404 53 P10 49 0 .10 0.33 5 12 17 35 0.4
MVVNN2020M16 VNMG160404 53 P10 45 0.20 0.48 4 11 17 35 0.4
MVVNN2020M16 VNMG160408 53 P10 38 0.40 0.70 4 11 17 35 0.8
Childs Part 3 31: 3:2000 ... length of cut: (10 0 mm, inch)
(3.9) diameter of the workpiece: (25 mm, inch)
(3 .10 ) cost
(3 .10 .1) machining cost with overhead: (1 2 $/min)
(3 .11 ) time factor
(3 .11...
Metal Machining - Theory and Applications Episode 2 Part 5 ppsx
... in
modern machining systems, leading to:
(C1) g
1
( f, d) ≤ g
1c
(9 .18 a)
If depth of cut affects chip breakability independently of the feed, (C1) becomes
(C1′) d
1
≤ d ≤ d
u
(9 .18 b)
(C1″) f
1
≤ f ... the
Optimization of machining conditions 283
Childs Part 3 31: 3:2000 10 :38 am Page 283
t
mach
t
mach
t
total
= t
load
+ ——— + t
ct
———
f
mach
T
}
(9 .16 d)
pDLd
a
1 V
1/ n...
Metal Machining - Theory and Applications Episode 2 Part 4 pptx
... J. Manuf. Sci. and Engng. 12 1, 16 3 17 2.
Williams, J. E., Smart, E. F. and Milner, D. (19 70) The metallurgy of machining, Part 2. Metallurgia
81, 51 59.
Yamaguchi, K. and Kato, T. (19 80) Friction ... speed
machining. Int. J. Machining Sci. and Tech. 2, 343–353.
Shaw, M. C., Usui, E. and Smith, P. A. (19 61) Free machining steel (part III). Trans ASME J. Eng.
Ind. 82,...
Metal Machining - Theory and Applications Episode 2 Part 3 pot
... 0.0 315 + 0.000 016 T
N = 0 .19 e
–0.0005T
+ 0.085e
–0.000 015 (T–430)
2
a = 0.00032, m = 0.0 018
Steel L A = 910 e
–0.0 011 T
+ 19 0e
–0.00 011 (T 13 5)
2
+ 15 0e
–0.00002(T–330)
2
+ 10 0e
–0.00 01( T–650)
2
M ... 0.000 014 T
N = 0 .18 e
–0.0005T
+ 0.1e
–0.000 015 (T–430)
2
a = 0.00020, m = 0.0052
Steel Y A = 920e
–0.0 011 T
+ 12 0e
–0.00003(T 16 0)
2
+ 11 0e
–0.00004(T–340)...
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