A textbook of Computer Based Numerical and Statiscal Techniques part 7 potx
A textbook of Computer Based Numerical and Statiscal Techniques part 7 potx
... 1.4036 0.10203 = Since, x 3 and x 4 are approximately the same upto four places of decimal, hence the required root of the given equation is 1.4036. 48 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Using ... 4 .79 77 – 4.8446 = – 0.0469 Thus, the root lies between 1.6866 and 2. 50 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES and f(3) = (3...
Ngày tải lên: 04/07/2014, 15:20
A textbook of Computer Based Numerical and Statiscal Techniques part 28 potx
... 0.42 073 5 + 0.445605 + 0.00 675 375 – 0.005 67 sin (1.05) = 0.8 674 2. Ans. Example 4. A switching path between parallel railroad tracks is to be a cubic polynomial joining positions (0,0) and (4,2) and ... (x) and vi(x) are polynomials in x of degree ≤ 2n + 1 and satisfy. (i) u i (x i ) = 0, 1, ij ij ≠ = ( 3a) 260 COMPUTER BASED NUMERICAL AND STATISTICA...
Ngày tải lên: 04/07/2014, 15:20
A textbook of Computer Based Numerical and Statiscal Techniques part 38 potx
... the previous evaluation of y and () 1 , yfxy = at a certain number of evenly spaced pivotal point (discrete points of 1 x of x-axis) in the neighbourhood of 0 . x In general the Predictor-Corrector ... differential equation () , dy yfxy dx ′ == by this method we first obtain the approximate value of 1n y + by Predictor formula and then improve the value of 1n y +...
Ngày tải lên: 04/07/2014, 15:20
A textbook of Computer Based Numerical and Statiscal Techniques part 39 potx
... error. NUMERICAL SOLUTION OF ORDINARY DIFFERENTIAL EQUATION 371 Inherent stability is determined by the mathematical formulations of the problem and is dependent on the eigen values of Jacobian Matrix ... complex ()aib=+ , then it is stable if () [1 ] 1aibh += < i.e., ()() 22 11 ah bh ++ < 374 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES 11 12 13 1 ax ay...
Ngày tải lên: 04/07/2014, 15:20
A textbook of Computer Based Numerical and Statiscal Techniques part 42 potx
... the values of x ∑ , etc. and calculated by means of above table in the normal equations. We get, 5 .75 36 = 5A + 34B and 40.8862 = 3 4A + 300B On solving these equations we obtain, A = 0. 976 6; ... the values in the normal equations, we obtain 3 .73 93 8 36AB=+ and 22 .73 85 36 204AB=+ ⇒ 0.1406B = and A = 1.8336 ⇒ log 1.38banti B== and log 0.68.aanti A= = Thus th...
Ngày tải lên: 04/07/2014, 15:20
A textbook of Computer Based Numerical and Statiscal Techniques part 54 potx
... 0 (Samples are large) 522 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES 7. 1,000 apples are taken from a large consignment and 100 are found to be bad. Estimate the percentage of bad apples ... Rejected at both level 1% and 5%] 16. A normal population has a mean of 0.1 and standard deviation of 2.1. Find the probability that mean of a sample of size 90...
Ngày tải lên: 04/07/2014, 15:20
A textbook of Computer Based Numerical and Statiscal Techniques part 55 potx
... E(c)= accd N ++ bgbg and E(d)= bdcd N ++ bgbg abab cdcd ac bd N + + ++ ∴ χ 2 = aEa Ea bEb Eb cEc Ec dEd Ed –––– af af af af af af af af 2222 +++ (2) a – E (a) =a – abac N ++ bgbg = a a b c d a ac ... 11. 07. Calculated value of χ 2 is less than the tabulated value, it is not significant at 5% level of significance and hence the null hypothesis of equal probability for ma...
Ngày tải lên: 04/07/2014, 15:20
A textbook of Computer Based Numerical and Statiscal Techniques part 56 potx
... store. After an advertising campaign the mean weekly sales in 22 stores for a typical week increased to 153 .7 and showed a standard deviation of 17. 2. Was the advertising campaign successful? Sol. We are ... may take the product conforming to specifications. Example 17. A random sample of size 16 has 53 as mean. The sum of squares of the derivation from mean is 135. Can thi...
Ngày tải lên: 04/07/2014, 15:20
A textbook of Computer Based Numerical and Statiscal Techniques part 62 docx
... the Range Lower limit a = 0 Upper limit b = 6 Enter the number of subintervals = 6 Value of the integral is: 1.3 571 598 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Enter the value of y2 ... ALGORITHM FOR TRAPEZOIDAL RULE Step 1. Start of the program for numerical integration Step 2. Input the upper and lower limits a and b Step 3. Obtain the number of s...
Ngày tải lên: 04/07/2014, 15:20
A textbook of Computer Based Numerical and Statiscal Techniques part 1 ppt
... This page intentionally left blank This page intentionally left blank A TEXTBOOK OF COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Anju Khandelwal M.Sc., Ph.D. Department of Mathematics SRMS ... Based Numerical and Statistical Techniques is primarily written according to the unified syllabus of Mathematics for B. Tech. II year and M.C .A. I year students of...
Ngày tải lên: 04/07/2014, 15:20