A textbook of Computer Based Numerical and Statiscal Techniques part 5 ppsx
A textbook of Computer Based Numerical and Statiscal Techniques part 5 ppsx
... 0 .55 55e1, b = 0. 454 5e1, c = 0. 453 5e1 then(b – c) = 0.0010e1 = 0.1000e – l a( b – c) = (0 .55 55e1) × (0.1000e – 1)= (0. 055 5e0) = 0 .55 50e – 1ab = (0 .55 55e1) × (0. 454 5e1) = 0. 252 4e2ac = (0 .55 55e1) ... roots of the equation, obtained byx1= 22244 and 22bb ac bb acaa−+ − −− −=xThese are called closed form solution. Similar formulae are also available for cubic and biquadratic polynomial ... of the normalized floating-point representation theassociative and the distributive laws of arithmetic are not always valid. The example given belowproves the above statement:Let a = 0 .55 55e1,...
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A textbook of Computer Based Numerical and Statiscal Techniques part 2 ppsx
... problems. A majoradvantage for numerical technique is that a numerical answer can be obtained even when a problem has no analytical solution. However, result from numerical analysis is an approximation,in ... significant figures at each step of computation. At each step of computations, retain at least one more significant figurethan that given in the data, perform the last operation, and then round off.3. ... in numerical methods is also a critically important part of the study of numerical technique.1.2 ACCURACY OF NUMBERS(i) Exact Number: Number with which no uncertainly is associated to no approximation...
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A textbook of Computer Based Numerical and Statiscal Techniques part 3 ppsx
... 0.00 05 because −×=3110 0.00 05 214 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES ∂×100uu= −δ×− 5 612 5 100 25 VVVV= −××=−×=−−(12 5) 70. 05 100 5 11.667%(2 5) ... seconddecimal places.Example 4. If 0.333 is the approximate value of 13, then find its absolute, relative and percentageerrors.Sol. Given that True value ()13x=, and its Approximate value ... 11 11 (1)12 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Example 20. It is required to obtain the roots of X2 – 2X + log10 2 = 0 to four decimal places. Towhat accuracy should log10...
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A textbook of Computer Based Numerical and Statiscal Techniques part 14 ppsx
... 122 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Example 22. Evaluate: ∆n [sin (ax + b)]Sol. We know f∆(x) = f(x + h) – f (x) therefore∆sin (ax + b) = sin [a (x + h)+b] – sin)(ax ... hD hDhD116 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Example 14. Evaluate the following:I. ∆2 (cos 2x)II. ∆2 (3ex)III. ∆ tan–1 xIV. ∆(x + cos x)the interval of differencing ... f(x)∴∆(e a + bx)= e a( x + 1)+b – eax + b = eax + b (e a – 1)∴∆2 (e a + bx)= ∆ (∆e a + bx) = ∆ {eax + b (e a –1)}= (e a – 1) (∆ eax + b)= (e a – 1) eax + b (e a –1)= (e a –1)2...
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A textbook of Computer Based Numerical and Statiscal Techniques part 16 ppsx
... given a set of equidistant values of arguments and its corresponding value of f(x). Supposefor n + 1 equidistant argument values x = a, a + h, a + 2h, , a + nh, are given.140 COMPUTER BASED NUMERICAL ... 0f−+×−×+=138 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES i.e., 4f(3) = 124i.e., f(3) = 31(function values are 3n type and this is not a polynomial)Example 7. Find the missing value of the data:12 ... 2212nnnan bn c n a n b n a n−−++−∆+∆+∆142 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES 9. Evaluate the production of wool in the year 19 35 from the given data: ( ) 1931...
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A textbook of Computer Based Numerical and Statiscal Techniques part 17 ppsx
... R.H.S.3.9 FACTORIAL NOTATIONSThe product of n consecutive factors each at a constant difference and the first factor being x iscalled a factorial function or a factorial polynomial of degree n and ... L.H.S. 150 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES CorCorCorCorCorollary:ollary:ollary:ollary:ollary:To show that,()nnx∆= n! hn and 1n+∆ x(n) = 0We know that,()nx∆= ... 1 and 2 by 1 and add them to get the sum –1 which is to bewritten below 3. The remainder –10 is the value of D.4. Add the terms of corresponding columns of (a) and get 2, –1 and 2 of (b) 5. ...
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A textbook of Computer Based Numerical and Statiscal Techniques part 25 ppsx
... −2 .5 1 0 .5 4 1 0 .5 4 2 .5 0 .5 4 2 .5 14 7 .5 13 17 .5 1 .5 3 4 .5 1 .5 1 .5 3 3 1 .5 1 .5 4 .5 3 1 .5 f (5) = 5 15 65 1 75 20. 25 6. 75 6. 75 20. 25 −++ = 0.246913 – 2.2222 + 9.62962 + 8.6419 75 f (5) = 18 .51 850 831 ... 4, and x3 = 5. 5f(x0) = 4, f(x1) = 7 .5, f(x2) = 13 and f(x3) = 17 .5 also, find the value of f (5) 232 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Example 8. Prove that Lagrange’s ... −f( 35) = – 10 .5 + 50 .4 75 + 42. 05 + 4.72f( 35) = 77.4 05 (ii) By using Lagrange’s formula, we havef(x) = ()()()()()()()()( )()()( )2 .54 5 .5 1 45. 547 .5 12 .51 4 15. 5 2 .51 2 .54 2 .55 .5 xxx xxx−−−...
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A textbook of Computer Based Numerical and Statiscal Techniques part 26 ppsx
... . 65 .39 .342 .39 .423 .39 .5 30 35 .5 .342 .5 .423 .5 . 65 . 65 .342 . 65 .423 . 65 .5 −−− −−−+−−− − − −= 22.84 057 797. Ans.238 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Sol. sin6π ... using Lagrange’s inverse interpolation formula.()0 5 10 15 16. 35 14.88 13 .59 12.46xfx[Ans. 8.337]242 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Example 7. Find the value of x correct ... life. [Ans. 15. 67]13. Find the value of tan 33° by Lagrange’s formula if tan 30° = 0 .57 74, tan 32° = 0.6249, tan 35 = 0.7002, tan 38° = 0.7813. [Ans. 0.64942084]14. Apply Lagrange’s formula to...
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A textbook of Computer Based Numerical and Statiscal Techniques part 29 ppsx
... co-efficients a 1, a 2 a n will produce littleerror for small x near zero. But probably substantial error near the ends of the interval268 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES 7. Apply ... approximation to a given function.For evaluating a function f(x) on a computer it is generally more efficient of space and timeto have an analytic approximation to f(x) rather than to store a table ... polynomial. Therefore all the interpolation formulae shouldgive the same functional value.274 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Example 2. Obtain the best lower degree approximation...
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A textbook of Computer Based Numerical and Statiscal Techniques part 51 ppsx
... 0 .52 7 1.407 0 .54 5 1. 455 3. 858 1.710 6.006 0.443 1 .55 7 24 0.612 0.632 0. 157 0.9684 0 .53 8 1.399 0 .55 5 1.4 45 3.3 95 1. 759 6.031 0. 452 1 .54 8 25 0.600 0.619 0. 153 0.9696 0 .54 8 1.392 0 .56 5 1.4 35 3.931 ... juice drained from cans immediately after filling for 20 samples are takenby a random method (at an interval of every 30 minutes). Each of the samples includes 4 cans. Thesamples are tabulated ... concern has an average sale of Rs. 10000/- daily estimated over a longperiod. A salesman claims that he will increase the average sales by Rs. 700/- a day. The concernis interested in an increased...
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Từ khóa: a culture of creativity design education and the creative industriesa study of perceptual learning styles and achievementa period of slow economic growth and high inflationa period of robust economic growth and high employmenthistory of computer based control systemsstructure and interpretation of computer programs abelson and sussman mit pressa summary of the first two and a half partspath—a foundation of file based i othe morality of hiv aids a comparison of russian orthodox church and secular ngo approachessusceptibility testing protocols for antibiograms and preventive surveillance a continuum of data collection analysis and presentationa tradition of authoritarian rule centralization and big governmenta database of microrna sequences targets and nomenclaturea tale of two models implan and remi on the economics of everglades restorationa meeting of troop contributing states and an informal security council meetinga unification of the arrow kurz and keynesian theoriesNghiên cứu vật liệu biến hóa (metamaterials) hấp thụ sóng điện tử ở vùng tần số THzNghiên cứu tổ chức chạy tàu hàng cố định theo thời gian trên đường sắt việt namGiáo án Sinh học 11 bài 13: Thực hành phát hiện diệp lục và carôtenôitGiáo án Sinh học 11 bài 13: Thực hành phát hiện diệp lục và carôtenôitGiáo án Sinh học 11 bài 13: Thực hành phát hiện diệp lục và carôtenôitPhát triển mạng lưới kinh doanh nước sạch tại công ty TNHH một thành viên kinh doanh nước sạch quảng ninhPhát triển du lịch bền vững trên cơ sở bảo vệ môi trường tự nhiên vịnh hạ longPhát hiện xâm nhập dựa trên thuật toán k meansNghiên cứu, xây dựng phần mềm smartscan và ứng dụng trong bảo vệ mạng máy tính chuyên dùngNghiên cứu về mô hình thống kê học sâu và ứng dụng trong nhận dạng chữ viết tay hạn chếĐịnh tội danh từ thực tiễn huyện Cần Giuộc, tỉnh Long An (Luận văn thạc sĩ)Tìm hiểu công cụ đánh giá hệ thống đảm bảo an toàn hệ thống thông tinThiết kế và chế tạo mô hình biến tần (inverter) cho máy điều hòa không khíTăng trưởng tín dụng hộ sản xuất nông nghiệp tại Ngân hàng Nông nghiệp và Phát triển nông thôn Việt Nam chi nhánh tỉnh Bắc Giang (Luận văn thạc sĩ)Tranh tụng tại phiên tòa hình sự sơ thẩm theo pháp luật tố tụng hình sự Việt Nam từ thực tiễn xét xử của các Tòa án quân sự Quân khu (Luận văn thạc sĩ)chuong 1 tong quan quan tri rui roGiáo án Sinh học 11 bài 14: Thực hành phát hiện hô hấp ở thực vậtGiáo án Sinh học 11 bài 14: Thực hành phát hiện hô hấp ở thực vậtBÀI HOÀN CHỈNH TỔNG QUAN VỀ MẠNG XÃ HỘIĐổi mới quản lý tài chính trong hoạt động khoa học xã hội trường hợp viện hàn lâm khoa học xã hội việt nam