... node 2 by Av, we obtainDenoting the voltage gain from node 1 to node 2 by Av, we obtain (11 .21 ) (11 .22 )Thus,and (11 .23 ) (11 .24 )Called Miller’s theorem, the results expressed by (11 .22 ) ... dissipation of 2 mW? Assume VCC= 2, 5V and neglect the Early effect and other.Fig. 11. 6114Example 11. 12 Identify all of the capacitances in the circuit shown in Fig. 11 .22 (a).Figure 11 .22 SolutionFrom ... Eqs. (11. 58) and (11. 59) yield (11. 85) (11. 86)• (b) The transfer function in Eq. (11. 70) gives a zero at gm/CGD= 2 x(13,3 GHz). Also, a =2, 12. 10- 20 s -2 and b=6,39.10-10s. Thus, (11. 87) (11. 88)Note...