Advanced Microwave Circuits and Systems Part 6 pot
... t SiN ranging from 30 to 50nm and L FP ranging from 0.4 and 0 .6 m. Advanced Microwave Circuits and Systems1 98 Asano K., Miyoshi Y., Ishikura K., Nashimoto Y., Kuzuhara M., and Mizuta M. (1998) “Novel ... plated devices are obtained with t SiN ranging from 30 to 50nm and L FP ranging from 0.4 and 0 .6 m. Advanced Microwave Circuits and Systems1 78 pointing out that beside i...
Ngày tải lên: 20/06/2014, 11:20
... R 3,ratio = 0 .6 OBO = 4.4dB = 0.5 OBO = 6dB = 0.4 OBO = 8dB Fig. 16. R 3,ratio as function of for different OBO () values. Advanced Microwave Circuits and Systems1 24 4. Advanced DPA ... R 3,ratio = 0 .6 OBO = 4.4dB = 0.5 OBO = 6dB = 0.4 OBO = 8dB Fig. 16. R 3,ratio as function of for different OBO () values. Advanced Microwave Circuits and System...
Ngày tải lên: 20/06/2014, 11:20
... 5.37-4.84 -124.2 at 5.33GHz -1 .67 15 .69 001 5. 16- 4 .69 -122.1 at 5.13GHz -1.72 15 .69 010 4.80-4.43 -121.8 at 4.78GHz -2.77 15.83 011 4 .67 -4.55 -124.4 at 4 .64 GHz -2 .68 15.90 100 4.15-3.91 -128.8 ... -128.8 at 4.13GHz -5.97 15.78 101 4.07-3.84 -1 26. 4 at 4.05GHz -6. 06 15.85 110 3.89-3 .69 -1 26. 3 at 3.88GHz -6. 92 15.83 111 3.82-3 .64 -122.8 at 3.81GHz -6. 78 15.84 Table 2...
Ngày tải lên: 20/06/2014, 11:20
Advanced Microwave Circuits and Systems Part 8 docx
... phones or other handheld wireless products. The choice 13 Advanced Microwave Circuits and Systems2 66 good dielectric material should have a high dielectric constant, a high band gap to limit ... energies stored in the magnetic and electric fields and lost can be expresses in eqation (3.8 to 3.10) respectively. Advanced Microwave Circuits and Systems2 68 size (Wu J. C. & Z...
Ngày tải lên: 20/06/2014, 11:20
Advanced Microwave Circuits and Systems Part 11 ppt
... 66 6 0 0 464 161 464 161 1 65 663 6 00 66 33 00 565 3 00 00 565 3 454434 464 3 00 151 131 161 3 00 454434 00 464 3 151131 00 161 3 6 3 6 3 6 3 Pr Px : Px Pr : Pr Pr Pr P P ... ...
Ngày tải lên: 20/06/2014, 11:20
Advanced Microwave Circuits and Systems Part 13 pptx
... 0. 368 89 0. 568 05 0 .60 21 0 .62 818 0 .65 4 0 .66 92 Lung 0.2 761 3 0.3855 0.42109 0.45158 0.48429 0.50 462 Bone 0.0841 46 0.102 56 0.11585 0.12845 0.14185 0.15009 Heart 0.22405 0.41127 0.47134 0.5 261 7 0.58 769 ... 0 .66 92 Lung 0.2 761 3 0.3855 0.42109 0.45158 0.48429 0.50 462 Bone 0.0841 46 0.102 56 0.11585 0.12845 0.14185 0.15009 Heart 0.22405 0.41127 0.47134 0.5 261 7 0.58 769...
Ngày tải lên: 20/06/2014, 11:20
Advanced Microwave Circuits and Systems Part 14 doc
... to 26. 5 501.39 75.70 26. 5 to 40 34. 76 8.78 33 to 50 101.95 13 .68 SWW 18 to 26. 5 139 .66 35.48 26. 5 to 40 84. 26 7. 96 33 to 50 100.94 12. 36 Rice 18 to 26. 5 180.97 46. 34 26. 5 to 40 61 .54 ... -45 -43 -41 -39 -37 -35 -33 -31 -29 -27 -25 5.4 5 .6 5.8 6 6.2 6. 4 6. 6 6. 8 7 7.2 7.4 Without impairments Without impairments With impairments With impairments...
Ngày tải lên: 20/06/2014, 11:20
Advanced Microwave Circuits and Systems Part 15 ppt
... 10, 20 06. Advanced Microwave Circuits and Systems4 84 exciting monopole antenna is positioned at the top of the silo’s lid below the microwave source. (a) (b) Fig. 11. Design and simulation ... stored products”, US Patent No.: 6, 192,598 B1, 27 Feb. 2001. Advanced Microwave Circuits and Systems4 86 0 10 20 30 40 50 0 20 40 60 80 100 Time (min) Mortality Rate (%)...
Ngày tải lên: 20/06/2014, 11:20
Expert Systems for Human Materials and Automation Part 6 pot
... 0.3 0.3 Yield stress (MPa) 354 425 66 4 Tangent modulus (MPa) 763 763 763 β 1 1 1 C (s -1 ) 40 100 10.99 p 5 5 2.5 Obtained depth (mm) 16. 14 16. 14 15. 96 Relative error 1.5% 1.5% 0.38% Table ... calculations. For example, to activate AM for PART #1 the following command must be written: EDADAPT, 1, ON AM activation command is placed just before SOLVE command, and does not...
Ngày tải lên: 19/06/2014, 10:20
Advanced Radio Frequency Identification Design and Applications Part 6 potx
... thickness is T, and the size of the metal plate is M. The spacing between the antenna and the metal plate is S. The equivalent electric and magnetic currents are I and J, respectively. E θ and E φ ... 0.0790 0.2378 0 .63 80 0.9548 -4.7911 N = 5 H = 0.02λ Sim. 0.2537 0.5 862 0.8399 -5.1988 Eq. 0.0790 0. 065 6 0.8008 0.9453 -8.1554 N = 15 H = 0.02λ Sim. 0.1987 0.7988 0.9975...
Ngày tải lên: 19/06/2014, 23:20