Pro Entity Framework 4 0 Depositfiles 8 ppt

... ',@12 =45 . 20, @13=5,@ 14= N'S ',@15=N'M ',@16=N'M ',@17=1,@ 18= 129,@19=' 200 9 -09 -07  12 :07 :26. 04 3 9 48 2',@ 20= &apos ;00 000 000 -00 00- 000 0 -00 00- 000 000 000 000 ',@21=' 200 9 -09 -07  ... datetime2(7)', @0= N'Inverted Kayaba',@1=N'IKAYA-R 209 ', @2=1,@3=1, @4= N'Red',@5=2 50, @6=2...

Ngày tải lên: 18/06/2014, 16:20

... Microsoft.Data .Entity. Ctp assemblies in your UI project (CodeOnlyUI) are located here: C:\Program Files(x86)\Reference Assemblies\Microsoft \Framework\ .NetFramework\v4 .0\  Profile\Client The client profile ... project. Your System.Data component in your data project (CodeOnlyData) points to the following location: C:\Program Files(x86)\Reference Assemblies\Microsoft \Framewor...

Ngày tải lên: 18/06/2014, 16:20

... names would not gain anything. Figure 12 -4. EntityType and EntitySet properties We can also verify that the navigation properties were set properly as well, based on the previous pluralization ... connection string found in the app.config looks like this: res://*/EF40Model.csdl|res://*/EF40Model.ssdl|res://*/EF40Model.msl The * in the line means that schema files are included...

Ngày tải lên: 18/06/2014, 16:20

... the EF40Entities data model from the EF40Data project. The second variable defines the ProductModel entity to which you add a record. Last is CHAPTER 13 ■ DATABINDING WITH THE ENTITY FRAMEWORK ... (nameTextBox.Text.Length > 0) { productModelBindingSource.EndEdit(); prodMods = new EF40Data.ProductModel(); prodMods.Name = nameTextBox.Text; context.ProductModels.AddObject...

Ngày tải lên: 18/06/2014, 16:20

... AdventureWorks 200 8Entities1): try { CHAPTER 5 ■ WORKING WITH ENTITIES 88 using (var context = new AdventureWorks 200 8Entities1()) { ProductModel prodModel = new ProductModel(); prodModel.Name ... ([BusinessEntityID] = @2) ',N' @0 nvarchar (8) ,@1 datetime2(7),@2 int', @0= N'Mr.',@1=' 200 9 -09 -07 11 :41 :25.1656711',@2=2 28 One la...

Ngày tải lên: 20/06/2014, 08:20

... ',@12 =45 . 20, @13=5,@ 14= N'S ',@15=N'M ',@16=N'M ',@17=1,@ 18= 129,@19=' 200 9 -09 -07  12 :07 :26. 04 3 9 48 2',@ 20= &apos ;00 000 000 -00 00- 000 0 -00 00- 000 000 000 000 ',@21=' 200 9 -09 -07  ... datetime2(7)', @0= N'Inverted Kayaba',@1=N'IKAYA-R 209 ', @2=1,@3=1, @4= N'Red',@5=2 50, @6=2...

Ngày tải lên: 20/06/2014, 08:20

... EF40Data.EF40Entities context; EF40Data.ProductModel prodMods; bool isNew; The next step is to implement the isNew variable, which must be placed in the AddingNew event of the productModelBindingSource. ... (nameTextBox.Text.Length > 0) { productModelBindingSource.EndEdit(); prodMods = new EF40Data.ProductModel(); prodMods.Name = nameTextBox.Text; context.ProductModels....

Ngày tải lên: 20/06/2014, 08:20

... field, 116 Product class, 90 Product Model Binding Navigator, 244 Product Model ID, 244 Production.Product table, 87 Production.ProductModel table, 87 ProductModel class, 88 , 236, 244 ProductModel ... 239, 242 – 243 ProductModelID column, 90, 244 ProductModelID property, 236 ProductModelID value, 90 91 ProductModelName column, 241 Products class, 2 38 239, 244 Products enti...

Ngày tải lên: 20/06/2014, 08:20

... a new AdventureWorks 200 8Entities object. /// </summary> public AdventureWorks 200 8Entities(EntityConnection connection) : base(connection, "AdventureWorks 200 8Entities") { ... new AdventureWorks 200 8Entities object. /// </summary> public AdventureWorks 200 8Entities(string connectionString) : base(connectionString, "AdventureWorks 200 8Entities"...

Ngày tải lên: 18/06/2014, 16:20

... AdventureWorks 200 8Entities1): try { CHAPTER 5 ■ WORKING WITH ENTITIES 88 using (var context = new AdventureWorks 200 8Entities1()) { ProductModel prodModel = new ProductModel(); prodModel.Name ... ([BusinessEntityID] = @2) ',N' @0 nvarchar (8) ,@1 datetime2(7),@2 int', @0= N'Mr.',@1=' 200 9 -09 -07 11 :41 :25.1656711',@2=2 28 One la...

Ngày tải lên: 18/06/2014, 16:20