Advances in Analog Circuits Part 5 ppt
... T6(s) X4 1 354 167 189 1.87 92 1.82 89 3.97 44 3.79 2 737 152 391 1.88 83 1.83 187 3.94 40 3.80 3 192 39 1 05 1.82 22 1.77 52 3.69 11 3 .54 4 55 15 31 1.77 9 1.67 14 3.93 4 3. 75 5 1,1 05 127 57 0 1.93 ... and U is the input excitation in the frequency domain. When 112 Advances in Analog Circuitsi It can be seen that minimizing the inter-PE communication overhead (T comm ) is...
Ngày tải lên: 20/06/2014, 06:20
... = 5. 802 151 e-01 V BE2 = 7.020994e-01 V CE1 = 6.432040e-01 V BE1 = 2 .50 9425e+00 V RC2 = 2. 054 483e+00 I C2 = 4.343896e-04 R C2 = 4.72 958 7e+03 WinSpice 4 -> Advances in Analog Circuits ... relatively new elements in circuit theory; and the rules of Advances in Analog Circuits 26 growth of the voltage or current in the pairing norator. In fac...
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... 2.48e-07 2 .50 e-03 2 .50 e-03 V BE3 0 .58 9 -0.014 0 .57 5 V CE3 9.40 0 .51 9.91 I B3 8.80e-07 -3.27e-07 5. 53e-07 Q 3 I C3 8.80e- 05 -3.69e- 05 5.11e- 05 V BE4 -0.728 0.377 -0. 351 V CE4 9 .58 0.32 ... be included in ,,inrms V or ,,inrms I . ,, ,. in S inrms onrms in RR VV AR + = (6) ,, ,. in S inrms onrms in S RR IV AR R + = (7) AC V Out V in I i...
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Advances in Analog Circuits Part 6 pptx
... = 0. 05. Then the interval transmittance is done as [ ] [ ] [][] 1s 15. 3, 85. 2s10 25. 1,90 25. 0 1s1.2,9.1s10 25. 1,90 25. 0 U U )s(K 2 2 1 2 ++ ++ == . 0.6 0. 65 0.7 0. 75 0.8 0. 85 0.9 0. 95 1 Real ... analysis of linear analog circuits using sensitivity bands, IEEE Trans. Circuits Syst. –I, Vol. 47, No. 8, pp.1138-11 45, ISSN: 1 057 -7122. Linear Analog Circuits...
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Advances in Analog Circuits Part 11 pptx
... Universitaet Muenchen Germany 1. Introduction Analog circuits form an important part in integrated circuits and in particular in ASICs (Application Specific Integrated Circuits) . However, due to the ... is 304 Advances in Analog Circuitsi Algorithm 2: Modified Branch and Bound(d inc ,D N , ˆ D N rel ) Input: incumbent d inc , parameter domain D N , relaxed domain ˆ D N rel...
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Advances in Optical Amplifiers Part 5 pptx
... shown in Fig .5 as inset (ii). 154 0.0 154 2 .5 154 5.0 154 7 .5 155 0.0 155 2 .5 -50 -40 -30 -20 -10 0 Optical power (dBm) Wavelength (nm) 1.25nm/D Converted signal 17dBm 154 3 .5 154 5.0 154 6 .5 154 8.0 154 9. 5 -60 - 45 -30 - 15 0 Optical ... 10Gb/s TDS-684 AWG 154 2.0 154 3 .5 154 5.0 154 6 .5 154 8.0 -50 -40 -30 -20 -10 0 Optical power (dBm) Wavelength (nm) 0.75nm...
Ngày tải lên: 19/06/2014, 23:20
Advances in Spacecraft Technologies Part 5 pptx
... determined as follows. If the plane of i-facet of Sc does not cross the planet: 4 cos 1 sin 1 23 ( ) (1 sin 2 sin ln ); 2 4 2 sin 1 sin 22 cos (3 sin ) 1 sin () ln 3 16 sin 1 sin 2 (1 sin ) ... (84) 1234 0 llll eA e A eA e A μμνν μμ νν −− − +− = ( 85) Inserting (67) and (69) into (51 ) and then inserting the obtained results into (78)~(81), we have 1234 BBBB DP+++=− (86) 1234 0B...
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Advances in Analog Circuits Part 1 pdf
... February, 2011 Printed in India A free online edition of this book is available at www.intechopen.com Additional hard copies can be obtained from orders@intechweb.org Advances in Analog Circuits, Edited ... experience and insights to introduce advances in analog circuit design, mod- eling, simulation and optimization. That way, this book summarizes recent advances in analo...
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Advances in Analog Circuits Part 4 pdf
... 3. 91 Behavioral Modeling of Mixed-Mode Integrated Circuits New Port Modeling and Local Biasing of Analog Circuits 83 introduced; and many properties of H-modeling including power management in the circuit ... find R M1 = 51 KΩ, R M2 = 51 KΩ, and R M4 = 4 .5 KΩ to best fit the specs. Locally biasing Sources W/L μm V DS V GS V SB I D pMOS-1 15/ 2 -5. 55 -1. 65...
Ngày tải lên: 20/06/2014, 06:20
Advances in Analog Circuits Part 7 docx
... 2000 mesh points and the 184 Advances in Analog Circuitsi 10 M 100 M 1 G 10 G 100 G 1 T Frequency [Hz] 5 10 15 20 25 30 Current Gain [dB] 0.0V, 0.0V 0.5V, 0.5V 1.0V, 1.0V -0.5V, -0.5V -1.0V, -1.0V -1 -0 .5 0 0 .5 1 Bias ... Mixed-Signal CMOS Integrated Circuits 0 0.1 0.2 0.3 0.4 0 .5 Back Gate Bias [V], V BGp =V BGn 3 5 7 10 30 50 70 Frequency [MHz] 0.4V; 0.5nA 0.5V; 0.5n...
Ngày tải lên: 20/06/2014, 06:20