Advances in Analog Circuits Part 1 pdf

... February, 2 011 Printed in India A free online edition of this book is available at www.intechopen.com Additional hard copies can be obtained from orders@intechweb.org Advances in Analog Circuits, ... 9 Chapter 10 Chapter 11 Part 3 Chapter 12 Chapter 13 Chapter 14 Chapter 15 Chapter 16 Fig. 2. Simulation-based design flow using genetic algorithms. 4. gm/I D methodology...

Ngày tải lên: 20/06/2014, 06:20

... low voltage amplifier. V in1 1 gm2 go2 1 3 9 gm4 go4 10 6 gm3 7 in2 1 28 gm5 go5 12 V 4 gm1 gm7 14 13 gm6 go6 gm9 17 gm8 16 Cp1 Cp2 CLgo7 go9 go8 5 11 15 18 O1 P1 O10 P10 O2 P2 O3P3 O4 P4 O5 P5 O6 P6 O7 ... (14 ). R 3 = R 4 , ω o = 1  R 1 R 2 (C 1 + C m1 )(C 2 + C m2 ) (14 ) C 1 R m1 (s) + R m2 (s) + C 2 R 3 R 1 1 2 3 4 5 6 R 4 R 2 1 1 R m1 (s) C 1 1 1...

Ngày tải lên: 20/06/2014, 06:20

... 10 −9 ⎞ ⎟ ⎟ ⎟ ⎟ ⎠ 0.0000769737 ⎛ ⎜ ⎜ ⎜ ⎜ ⎝ 0.000293665 0.000 014 219 9 5.70282 10 10 9 .12 6 21 10 −9 ⎞ ⎟ ⎟ ⎟ ⎟ ⎠ 0.00 012 5976 ⎛ ⎜ ⎜ ⎜ ⎜ ⎝ 0.000409046 0.0000948249 4 .14 6 71 10 −9 2.8 413 6 10 −8 ⎞ ⎟ ⎟ ⎟ ⎟ ⎠ 0.000280898 ⎛ ⎜ ⎜ ⎜ ⎜ ⎝ 0.0 010 119 7 0.00 011 1354 7 .14 833 10 −9 2.625 91 ... test RS 0.000 012 5623 ⎛ ⎜ ⎜ ⎜ ⎜ ⎝ 0.0000350975 0.000 015 1476 3.06034 10 10 3.59774 10...

Ngày tải lên: 20/06/2014, 06:20

... 700μm, β = 10 −4 , the threshold density N th = 1. 5 × 10 18 cm −3 , v g = 8.5 × 10 9 cm/s, optical confinement 10 Advances in Optical Amplifiers Part 1 Chapter 1 Chapter 2 Chapter 3 Part 2 Chapter ... published February, 2 011 Printed in India A free online edition of this book is available at www.intechopen.com Additional hard copies can be obtained from orders@intech...

Ngày tải lên: 19/06/2014, 23:20

... (b) (c) 413 KΩ 10 0 KΩ 10 KΩ 1 KΩ 10 0 KΩ 5 KΩ V CC = 5 V Q 2 Q 1 413 K Ω 10 0 KΩ 10 KΩ 1 KΩ 10 0 KΩ V CC Q 2 Q 1 R C2 Fx(0, I B1 ) V BB = 5 V 413 KΩ 10 0 KΩ 10 KΩ 1 K Ω 10 0 KΩ V CC Q 2 Q 1 R C2 Fx(0, ... the fixator. V BE1 = 5.789974e- 01 V CE1 = 7. 619 999e- 01 V BE2 = 6.398944e- 01 V CE2 = 2.206873e+ 01 I B1 = 4.405491e-07 R C2 = -3 .11 725e+...

Ngày tải lên: 20/06/2014, 06:20

... Supplies V BE1 0.667 -08 71 -0.204 V CE1 4 .17 5.35 9.52 I B1 1. 18e-05 -1. 18e-05 -1. 61e -12 Q 1 I C1 1. 63e-03 -1. 63e-03 1. 24e -11 V BE2 0.437 0.248 0.685 V CE2 9.66 -9. 61 5 .16 e-02 I B2 ... be included in ,,inrms V or ,,inrms I . ,, ,. in S inrms onrms in RR VV AR + = (6) ,, ,. in S inrms onrms in S RR IV AR R + = (7) AC V Out V in I in...

Ngày tải lên: 20/06/2014, 06:20

... T6(s) X4 1 354 16 7 18 9 1. 87 92 1. 82 89 3.97 44 3.79 2 737 15 2 3 91 1.88 83 1. 83 18 7 3.94 40 3.80 3 19 2 39 10 5 1. 82 22 1. 77 52 3.69 11 3.54 4 55 15 31 1.77 9 1. 67 14 3.93 4 3.75 5 1, 105 12 7 570 1. 93 ... analysis. Equation 11 is rewritten in the following partitioned form  AX 1 + BX 2 = V 1 CX 1 + DX 2 = V 2 . (12 ) From the first equation in Equa...

Ngày tải lên: 20/06/2014, 06:20

... 1sC)RR(sCRCR 1 U U )s(K 2 21 2 2 211 1 2 +++ == . Assuming R 1 C 1 = R 2 C 2 /2= RC = [1- ε, 1+ ε], ε = 0 .1, we have [][] 1s3.3,7.2s42.2,62 .1 1 U U )s(K 2 1 2 ++ == { } ]42.2,62 .1[ xfor,x1)j(GRe 22 ωω=−∈ω ... process. 16 7 Analog Design Issues for Mixed-Signal CMOS Integrated Circuits Linear Analog Circuits Problems by Means of Interval Analysis Techniques...

Ngày tải lên: 20/06/2014, 06:20

... points and the 18 4 Advances in Analog Circuitsi 10 M 10 0 M 1 G 10 G 10 0 G 1 T Frequency [Hz] 5 10 15 20 25 30 Current Gain [dB] 0.0V, 0.0V 0.5V, 0.5V 1. 0V, 1. 0V -0.5V, -0.5V -1. 0V, -1. 0V -1 -0.5 0 0.5 1 Bias ... [Hz] -60 -50 -40 -30 -20 -10 0 Gain [dB] - 1. 0V - 0.5V 0.0V 0.5V 1. 0V -1 0 12 Vsetn [V] 1 10 10 0 10 00 BW [MHz] IDDG SDDG Vsetp =1. 0V V...

Ngày tải lên: 20/06/2014, 06:20

... fitting. Hence, we have: M=f(E) (7) 0 1 Inputs [V] 0 1 F 1 [V] 0 1 0 5 10 15 20 25 Time [ns] 0 1 Vsum Vsum Vsum 000000 01 00000 011 0000 011 1 000 011 11 00 011 111 0 011 111 1 011 111 11 111 111 11 F 2 ... [ns] 0 1 F out [V] AND OR MAJ Vsum Vsum Vsum 000000 01 00000 011 0000 011 1 000 011 11 00 011 111 0 011 111 1 011 111 11 111 111 11 b) F V SUM x p3 x n3 x...

Ngày tải lên: 20/06/2014, 06:20