VMware vFabric Application Director API Programming vFabric Application Director 5 0 docx
VMware vFabric Application Director API Programming vFabric Application Director 5.0 docx
... Applications REST API.
VMware vFabric Application Director API Programming
10 VMware, Inc.
Example URI syntax:
https://
ApplicationDirectorServerIP
:8443/darwin /api/ 1 .0 /application- versions / 50 1/page /0/ page-
size/2
Response
Table ... "uri":"https://192 .0. 2. 255 /api/ vApp/vm-d 553 51 70- 03bc-4f8f-8f32-8669a392c3a4",
"index":-1,
"...
vCloud API Programming Guide vCloud Director 1.5 doc
... id="urn:vcloud:vapp:490af534-1491- 452 e-8ed6-a5eb54447dac"
type=" ;application/ vnd .vmware. vcloud.vApp+xml"
href="https://vcloud.example.com /api/ vApp/vapp-490af534-1491- 452 e-8ed6-a5eb54447dac"
... the
vCloud API that vCloud Director supports, object IDs are universal unique identifiers (UUIDs) as defined
by RFC 4122, for example vapp-f5e185a4-7c 00-...
Programming Languages - Application and Interpretation pot
... . . . . . 200
20 .5 Testing . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 202
VIII Memory Management 207
21 Automatic Memory Management 209
21.1 Motivation ... . . . . . . . . . . . . . . . . . . . . . 2 80
30 .5. 1 The Unification Algorithm . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 2 80
30 .5. 2 Example of Unification...
inductrial robotics - vol. 2 technology, programming, and application
... class="bi x0 y0 w0 h1" alt=""
Tài liệu Chapter 3 - Application Layer Functionalityand Protocols CCNA Exploration 4.0 docx
... (FTP) is another commonly used Application layer
protocol.
• FTP was developed to allow for file transfers between a client and a server. An
FTP client is an application that runs on a computer ... and printer access.
– Allow an application to send or receive messages to or from another device.
Học viện mạng Bách khoa - Website: www.bkacad.com
– Allow an application to send or rece...
Tài liệu APPLICATION OF REMOTE SENSING IN:" FOREST SECTOR OF VIETNAM" docx
... 1/ 2 50 ,00 0 with
the support of digital classification methods;
200 1- 20 05 : conducted 3rd cycle of NFI with the use of
Landsat ETM to make forest cover maps at provincial
levels 1/ 100 ,00 0 and ... derived from
QuickBird image
200 6- 201 0: is now implementing 4th cycle
of NFI with the use of SPOT 5 to make
forest cover maps at provincial levels
1/ 25, 00 0 – 1 / 50 ,00 0...
Tài liệu ActuateOne on VMware® vSphere™ 5.0 and vCloud Director 1.5 docx
... 100 0. 19/4. 45 3144.36 352 2 .56 56 78 .03 52 32 .58 0. 03 2.93 0 0 0. 01 0. 64
iServer -03 80. 83 100 0. 29 /0 .51 5 2988.71 34 40. 64 2 152 .98 2 05 4 .69 0. 76 4 .5 0 0 0. 63 2.97
iServer -04 83 .55 100 0. 22 /0 .56 301 9.43 ... 3399.68 2 107 .48 20 25. 37 1.38 143.87 0. 06 3. 35 0. 09 2.24
iServer- 05 83 .52 100 0. 28 /0. 92 30 45. 49 352 2 .56 207 8.78 201 7.47...
Web Client Programming with Perl-Chapter 5: The LWP Library- P1
... $ARGV [0] ;
$parsed_html = HTML::Parse::parse_html($html);
for (@{ $parsed_html->extract_links( ) }) {
$link=$_-> [0] ;
$url = new URI::URL $link;
$full_url = $url->abs($ARGV [0] ); ... HTTP, LWP,
MIME, URI, and WWW. Figure 5- 1 sketches out the top-level hierarchy
within LWP.
Figure 5- 1. The top-level LWP hierarchy
The File module parses directory listings.
T...
Web Client Programming with Perl-Chapter 5: The LWP Library- P2
...
RC_UNSUPPORTED_MEDIA_TYP
E (4 15)
RC_SEE_OTHER ( 303 )
RC_INTERNAL_SERVER_ERROR
( 50 0)
RC_NOT_MODIFIED ( 304 ) RC_NOT_IMPLEMENTED ( 50 1)
RC_USE_PROXY (3 05 ) RC_BAD_GATEWAY ( 50 2)
RC_BAD_REQUEST ( 400 )
RC_SERVICE_UNAVAILABLE ...
$response->header('content-length' => 2);
RC_UNAUTHORIZED ( 401 ) RC_GATEWAY_TIMEOUT ( 50 4)
RC_PAYMENT_REQUIRED ( 402 )
RC_HTTP_VER...
Tài liệu MATLAB® 7 Programming: How to Contact The MathWorks docx
... condition
A> ;0 .5
, and uses the positions of ones in
B
to
index into
A
.Thisiscalledlogical indexing:
A = rand (5) ;
B = A > 0 .5;
A(B) = 0
A=
0. 29 20 0. 356 7 0. 1133 0 0. 05 9 5
0 0.4983 0 0. 200 9 0. 08 90
0.3 358 ... elements
1
,
3
,
6
,
7
,and
10
of array
A
:
A = 5: 5 : 50
A=
51 0 152 0 253 0 354 0 455 0
B=[1367 10] ;
2- 35
Comma — ,
3- 100
Cu...
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