... 10 46. 7 104 466 .21000.3 1 062 6 .6 Ehc 6 J20-sm8sJ34−−×=×××==•λSolve:Example 7.7- Calculate the wavelength of light emitted when the hydrogen electron transitions from n = 6 to ... 1049 .6 1 062 .4 1000.3c71-s14-1sm8−×=××==•νλnm 1049 .6 m 10nm 1m 1049 .6 297×=××−−Chemistry, Julia Burdge, 2nd e., McGraw Hill.Tro, Chemistry: A Molecular Approach 64 Practice ... 104 466 .2 6 151J 1018.2E202218atom−−×−=−×−=∆Ephoton = -(-2 .66 44 x 10-20 J) = 2 .66 44 x 10-20 Jthe unit is correct, the wavelength is in the infrared, which is appropriate...