, If^ Ldl GIAJ 0^ THI HOC SINH GIOIHOA HQC
5. Sau khi phdn dng ket thuc, dugc chdt khi vd dungdich K Chia dung dich K Idm 2 phdn:
• Sue tii til khi CO2 den du vdo phdn 1 thdy tqo thdnh ket tuạ
• Sue tlX tii khi HCI vdo phdn 2 cdng thdy tqo ket tua, sau do ket tda tan khi HCI dU tqo dung dich Y trong sudt. Nhd tiep dung dich NaOH tii tii vdo Y thdy ket tua tqo thdnh, sau do tan trong NaOH dỤ
ibu rV. Hgp chdt hQu ca B (chiia cdc nguyen to C, H, O) c6 khdi lugng mol bdng 90 gam. Hoa tan B vdo dung moi tra roi cho tdc diLng vai lugng dU Na thu dugc so mol H2 bdng so mol B phdn dng.
»Ldp ludn xdc dinh cong thdc phdn tii B vd viet cong thiic cdu tqo tat cu cdc chdt mqch lid thod mdn dieu kien cho tren.
Cuu V. Dot chdy hodn todn 0,2 niol mot anken A, todn bo sdn phdm chdy dugc hap thu vdo 295,2 gam dung dicli NaOH 20%. Sau thi nghiem, nSug do dung dieh NaOH dU Id 8,45%. Biet cdc phdn iCng xdy ra hodn todn. 1. Xdc dinh cong thiCc phdn ti2 cua Ạ
2. Hon hap X gom A vd H2 c6 tl khoi hai cua X doi vdi khi hidro la 6,2
Dun nong X vai Ni xuc tdc defi phdn i2ng hodn todn thu dUgc hon hap y a) Chiing minh rdng Y khong Idm mat mdu dung dieh brom.
b) Dot chdy liodn todn Y diiqe 25,2 gam H2Ọ Tinh the tich moi kin trong hon hap X a dktc.
Cau Vl.Cho 18,5 gam hSn hap Z gom Fe vd Fe304 tdc dung 200 ml d ; / / , , .
dieh HNO3 lodng, dun nong, khudy deụ Sau khi phdn j2ng xdy ra lioun todn thu dugc 2,24 lit khi NO duy nhdt (dktc), dung dieh Zi vd con Lu 1,46 gam kim logị
1. Viet cdc phuang trinh phdn iCng xdy rạ 2. Tinh nong do moi dung dieh HNO3 đ diing. 3. Tinh khoi lugng muoi trong dung dieh Zị
Cho: H = 1, C = 12, O = 16, Na = 23, Fe = 56.
Ldl GIAl
Cdu I .
1. X: NaOH; Y: NaHCOa; Z = NasCOg NaOH + CO2 > NaHCOa
2NaHC03 — N a a C O s + COzt + H2O CO2 + H2O + NaaCOg > 2NaHC03
NaOH + NaPICOg > NâCOs + H2O
2. A: CaCOg; B: CO2; C: NaHCOg; D: Na2C03; E: Că0H)2; F: CaCla C a c phan ufng:
A ^ B: CaCOa — ^ C a O + CO2
C ^ A: 2NaHC03 + Că0H)2 > CaCOa + NagCOg + 2H2O
D -> A: NaaCOs + CaCl2 > CaCOg + 2NaCl
B -> C: CO2 + NaOH > NaHCOg
B -> D: CO2 + 2 N a O H > Na2C03 + H2O
C D: NaHC03 + NaOH > NazCOa + H2O
D -> C: Na2C03 + HCl > NaHC03 + NaCl
ifii r.\kt TMI u n r Q I U U n i n i unA u n r 9
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