Sé?
Chieu doi cd thB vogc cho vd chñn nou dupe tinh IN’ d‹nh gou dgn chot duoi. Vooc cho vd ch6n ndu thub'ng cd chldu ddi co thd gdp 2 Idn chidu ddi du6i cua chdng.
Neu mot con vooc ch6 vo chñn nou c6 duol d6i 30 cm thi cd thé can vooc dd doi khoong .?. cm. Chuyén doi gdn v] (theo
mau). Mou: 6 cm 8 mm - 68 mm a) 1 cm 7 mm = .?. mm 3 cm 2 mm = .?. mm 8 cm 6 mm = .*. mm 6 cm = 60 mm 6D mm + 8 mm = 68 mm b) 1 m4cm .?.cm 5 m 2 cm = .?. cm 7 m 9 cm = .?. cm
Moi chu ki6n n6u ddi 6 mm. Con
séu doi 2 cm 5 mm. 4 chu kiln nou
Khoi Iu'Onq qgo trong moi boo 12 kg 10 kp .?. kp 6 kp
So bao goo S baa 10 boo 8 bao .?. bao
Khdi Iu'ong ggo a' tot co coc
xép noi duoi thonh met hong doc thi c6 doi hon con sou noy khong? 70
2 phut 13 [g U
boo nhiéu ph6L.
8 gid' 4 phut B gib.16 phut 8 god 28 phut
B gio' 33 phs 8 gib' J7 phut 8 gid 59 phdt
hay 9 gif' kém27 phut hay 9 gif' kRW 13 phut hay 9 gid kRm 1 phut Mai ddng h6 chi m6y glb'?
Mau:
Co Idn tâ' d•đ ngéim 1
phut t4 phdt ?. phut *. phut ?. phut O6m thdm 1
d¥ biét kim phut chT
9 gld 39 phđ't hay 10 gif' kém-Z1 phdt,
71 2
Xooy kim dong ho dé ddng hé chi:
ci) 3 gicr 21 ph ut. b,' 7 gif' S4 ph uL c’i 11 gif‘ kém IB phut.
Chon déng hd phu ho'p vé'i cdch dec.
A
Ming xucin mâi,
ttu’o”
B D
ng em tâ chic the ve thonh vâi chs dé ’Dât nu'é'c em’.
2B
a } Chung em bot dou ve luc .?. giâ.
b,' Lé'p 2A vé Xong lu c .?. gié' .*. phd t.
Lip 2B ve xo ng luc .?. gid .?. phut.
c' Thai gian Ié'p 2A vé nho nh ho‘n I é'p 2B Io .?. phut. B. 3 gié' 1B phut
A. 3 gif' kém ¥2 phut
136 16 136 : 4 - 34 362 : 3 - .?. 0
• 13 chio 4 du’oc 3, viet 3.
3 nhcin 4 bong 12; 13 trL/' 12 bong 1, • Ha 6, du'oc 16; 16 chio 4 dLroc 4, viet 4. , 4 nh6n 4 bong 16; \6 try 16 bonq 0.
362 3 362 : 3 = t20 (du’ 2) 02
3 chia 3 du‘o'c 1, viét 1.
1 nhon 3 bo ng 3; 3 trđ' 3 bong 0 • Hg 6; 6 chio 3 du'o'c 2, viét 2.
2nhon 3 bong 6; 6 Art 6 bong 0.
• Ha 2; 2 chio 3 du' c 0, viét 0. 0 nhon 3 bong 0; 2 trñ' 0 bong 2.
Dot tinh roi tinh. c\ 632 . 7 407 : 8 bt 840 . 6 720 : 4 120 Xep déu 136 quyén soch Mo ngan co
73 Tfnh (theo rn&u). Mau: a) 816 : 8 b) 620 : 6 Tinh nhom. a) 210 : 7 100 • 9 o) .Kdm=1m 320 dm = .?. m b) 540 : 9 B00 x 0 c) 360 : 6 4B0 : B c) = .?. phdt 5 gid = .?. phdt Hodn thdnh cdoe6 i: dt ol Ben .?. vé ldu hpnt›gn„?. lb.?. .
Tfnh rdi cho tKdt ph4p cñta n6a duUldby eé thuoytg l6 s6trbn chya
a) 720 : 7 hl 633 : 9 c} 004 :5 881: 8 180 : 6 196 : 4 Tfnh. o) (615 - 234) : 7 c) 190 x 0 : 8 b) 109 x 9 + \8 dl 444 : (3 s 2)
Bg trong trf cdc hip qud, Nggc cut 6 m ddy thdnh 8 sol d0y cd d0 ddi
Hoi m6i sgi df›y ddi boo
Chi trtri lgnh pid, nhiéu Iod/ chim sé bag nd nor
dm dpfion. Chim hbi 8u I 'hdnh
udchimthi&inga
Gidp hloi vd Bonh Um bo I& 15 : 6 7S 32 : 4
Ong Bay tho deu 188 con cd via 5 be cd o cd con du', ong tho lu6n v6o bG cudi cung. H6i cu6i cdng c6 boo nhiéu con c6?
S6i cdnh
• Ouon sot hai bong pidy.
B6ng gioy mou xanh dii gap moy Ion bdnq pioy mou com?
2 cm /@p Gop ,t jml 1 5 lan. Gdp 6 Ibn. 10 cm •”
• Dung thu'é'c thong ktém tro xem cou tro Ié'i cuo em co dđ ng khong.
10 : 2 • 5 chia cho s6 bé.
Sd chom tr6n m6u d6 gop mdy Idn so ch6m tron mou xonh?
ot e aee e e b! e o a« o e c) a o aa a o
o) SO lOn. hl So Ian: 40 kg
So be So be B kg
Gioi b6i toon theo tom tot sou.
c Soon: 72cm 5o bé: 9 cnn 76 Me: 3 6 Fuoi Con9 tuoi.
Thg Thuy
A, O, B la bo diém thong hung. 0 Id diem é' g/đ'o hoi diém A vd B.
• Trung diém cuo dogn
B6 dbi doon th
Ounn sdt hinh va bén. 'm t ng Eng
Trong bo d /m vLI'o r›éu, giém
Id diem 6' giñ'o hoi diém con
lgi?
b) D co Id trung diém cda doo,n thong CE kh6ng?
G cd lo trung diém cdo doon thong
HE kh6ng?
a) Du'â'i doy Id coch xdc dinh trung diém cuo mot doon thing.
Giai thich toi soo N Id trung diem cdo dogn thing ST. b) Vé doc)n thang AB d ñi 10 cm.
X6c di,nh trung diem mdc doon thing AB, BC, CD. DA cdo IN' gioy
hinh ch0' nh§t (hinh vg).
- G8p tb gidy hinh chñ' nhdt ABCD sao cho cgnh AD trdng v6'i cgnh BC, danh dau trung diem M cdo conh AB vo trung diem N cua conh CD.
— Thuc hien tu'ong tu', to sé xdc dinh du'a c trung diem I vo K cuo cdc cgnh AD vo BC.
A M B
Csu mo dung, edu noo soi? ccc
D N C
a) 0 Io trung diém cuo dogn thang AB.
b) PI Id trung diém cuo doon th6ng
CD.
A O B
c) K Io diem é' gii a hol ‹flém P vo D
d) K lo trung diem cdo doo,n thing PQ. E CM
a) V! trf cdc
ld,u , , .,
theo thu' tu' Id trung digm cdo cdc doon thing AD, BC, DC, AB. b) Leu ! trf trung diém cuo doon thong SU.
CA s6 hinh trdn!
A
Hinh tron fam
O, bân hinh
OM, duâng kind AB.
Ddng thu'bc do rdi so sdnh doi cdc
doon thong
OM, OA, OB.
Trong mot hinh tron: • Cdc bon kfnh dol bang nhou.
• Tdm Id trung diem Duo du't›'ng kfnh. • Bu’dng kfnh ddi gdp hoi Ion bdn kfnh.
N6u t6n t6m. c6c bdn kfnh, du'dng kfnh cd trong mli hinh tr6n sau.
bl
79 ’
Thgc hdnh v8 hinh trbn bang com-pa. a) SO' dung com-pa d6 v0 h\nh tr6n.
I id' com-pa. b) Vé em bé vd dng mdt trdi.
Hinh 6nh trén lo ct Olympic
(Thé n hoi)
E—20
Do nhi§t d§ bang cach ndo?
Doc r6i vi6t nhi t d§ (theo mou).
Mau: u) Nhiét dE trong mot phong hoc. NhQtdo nuéc dong béng. 28 ’C
Do nhi§t do trong ph6ng hoc, ngodi ph6ng hoc.
Trao doi vé'i ngu'é'i than vé dung cu vo coch do nhiét duo cd the ngu'@i.
8J Ddng nhiet ke dé do
nhiét d6
Do'n vi do nhiât d6 Io °C (doc lo do xé)
Nhiét ke dong chi 20 'C
d ting nd
966
616
gidm di.6.l6n
Chon bg ba s6 thfch hg'p d/ndi cdc ph4p tfnh trong cdc bdng nhdn, chio dd hqc (theo mou).
Mou: 3, 18, 6 3 • 6 = \8 1B : 3 = 6 6 x 3 = 18 18 : 6 = 3 Ddng hay sal? a) 4s b) 128 cl 2 3 d) 869 6 B 16 069 90 364 5 b) Chgn ddng hg!phd hp'p vd'l'ed’ch d c. A.15'g\é' 6 phdt
hay 3 git›' 6 phut chiéu B.10 gid' 53 phdt
hay 11 gid kém 7 phut
C.\8 gid' 22 phdt
hay 6 gid' 22 phdt chiéu
D.16 gif' 45 phñt
hay 17 gib' kém 15 phut
1 0
350 bbt.1.6
0
b) Trong bo ! i m sou, noi Ignh nhAt I6: A.Mbu Son (Long Son) (Th a ThT4n — Hué} (Ldmoângl M P A. PN B. ON
Tr6 ohD{ d6nh cho hol n 0}.
Chudn b# M§t con x c xcc vb ho i vbt nh6 (vf du c0c do) d6
Idm qudn di.
C. fdN
— Mai hoc sinh ldn \u'ot
tung r6I ddng cue to dl chuy n rnb,t theo s6 chdm trdn d mdt trén dén met h\nh trdn. xc x6c, sd bu’dc x‹ic x6c
• Néu s6 trong hinh tron chs her who
sd chdm trt›n â' rndt I én xucxdc via
tung tht cdc do d' vi trf dd.
• Néu s6 trong hinh trbn khong chio
hdt cho so chdm tr6n d rndt tr0n xdc 1 5 32 35 30 # 5 28 16 36 2010 2 5 B. Bach told
xdc v0'o tung the @t cdc do vé v| trf c6.
— Tr6 choi kdt thee khi c6 ngu'd'i din dupe 6 cu6i cung (vg
GIS GITC - THD'I TINT
1. Tro chdi load mand - load dzzng Tro cho'i donh cho hoi
Chuon b|• Mot mñ hinh diong ho, mot can xuc xoc vo hoi vot nhâ (vi du cue do) dé Idm qudn di.
—Noi hoc sinh lan luo't tung xuc xoc r6i dung cuc do di chuyén theo sd chom trond mot trén xuc xoc, dén mot o vuong vo thu'c hién
theo yéu cou ghi trong o. Vo'i coc o co ghi giO, dung mo hinh dong ho
thé him gio'.
• Xooy kim chi dung gif' ghi trong 6 thi cuc do nom â' o dé.
• Xooy kim Lhong chi Kdng gig' ghl trong o thi dot cIdC oO Ve *! Ui Cu. - N6u sd chdm tr6n nhiéu ho'n s6 6 dd dl chuy0n the bi mdt lu'ot. - Tro choi ket thdc khi cd m§t hpc sinh ve dén dich.
2. Em top lom ngu'cri don chu'ong trinh "D ' boo thâ'i tiet"
Hogt dong nhorn. Chu6n b|:
Moi nhom chon mot bong dir boo tiét trong nqoy (xem bong bén du’c/i).
—Thoo luo n coc noi dun g con trinh boy: • Gi cri thieu ndi sé du’ boo thai tiet.
• Thong boo vé nhiét do thop nhot, nhiét do coo nhot cua noi do. • N hon g lu’u y ve trong phuc phu hop véi Fhc/i ti et.
THOI TIET CAC D!^ PHUONG
Trin h boy tru'â'c IUp:
- Doi dién moi nhorn trinh boy cé c noi dun g do churn bi.
ON 1fIP CflC SO TRONG PHflfn VI 1000
› Doc s6: 275. 609, J2J, 584. 930.
b,• Vi6t s6.
• Bon trom béy mcit.
• Tim trom linh mot. • Séu mu’ i lom. • Mot nghin,
c, Viet coc s6 748, 805, 160 thdnh t6nq coc trom, chi¿c, ddn v!.
574 .?. 702 236 .?. 98 4 65 .?. 461 157 .?. 170 683 .*. 600 + 80 + 3 1000 .?. 900 + 90 + 9
h’i Sop xép coc so 401, 325, 329, 87 theo the tu‘ ID' bộ din Ibn.
:,ã Tim so Ibn nhõL, tôn so bé nhdt trong coc so 725, 275, 257, 752. Dd t6
mou
1
hinh n6o? 2
H’inh A Hinh b H”inh C
Lam tron so 384 dén h b}Lc‹m
tr6n so gén h
Lam tron so
Lam tron so 9
a9S Sq, Neu INm two n so den
hong tro m th’i to noi:
O
aJ Lom trt›n s6 dén hong chuc.
• Lom tron so 17 den hung chuc thi du'oc so .?. • Lom tron so 435 dén hong chuc thi du'oc so .?.
O SO*
c›) 387 gom .?. try m, .?. chuc vo .?. don vi.
b! So lién sau cña 799 la: .?.
‹:! So tron chuc Ibn ho'n 25 nhu'ng bé hon 35 la. .?.
d) So co hoi ch? so, lom tron dén hon g chuc th”i du’ c so 30 Io: . ?. orto st o vuang cua h’inh bon g
icnu .?.
Hinh sou co boo nhiéu mdnh ghép?
Ué'c Iu^p'ng: C6 khodng .?. mdnh ghép. D6m: C6 .?. mdnh ghép. Tro chat B6 ng nhon vâ thu
ctz’ng Chon mot bong nhon do
hgc.
•Lqn Iu'o't £0'ng bon trong lé'p, moi bgn goi tén m{at so, bat dou IO' 1, roi 2, 3, ..., so sau cunq lo tich cudi trong bong nhon dong cho'i,
•Neu ban noo goi den st lo tich trong bong nhon, bon do phoi gio tieng kéu mot con vot.
Vi d u: Tim thu cu’ng cdng bong nho n 4.
du'czc nhan cuc éo, to tinh .?.
Ting hay hi§u?
a)
Oé tim tdt co so cuc do, to tfnh .?.
b)
Biet so cue oo co hai mou xanh, do vet bidt sâ cdc oo mou dâ. Oe tim so cuc do
mou xonh, to tinh .?.
c)
B6' Um s6 cdc ao mtiu
xonh nhieu hewn s6 cuc
do mou vong, to tfnh .?.
Tfch hOy thu'o'ng?
Oé tim tot eg s‹s ctic No, to nén tinh .?.
b)
Chio deu so cuc do cho
céc bgn. Be bi at moi bon
du'gc boo nhiéu cuc do, to
tfnh .?.
a) b)
So bé:
• S6 lé'n:
a) So bé gdp tén .?. Ion thi du'a s6 lé'n.
b) So Ion giom di .?. Idn tfi\'"du’pc,s6 bé. \
c) Sd Ibn gdp .?. Idn s6 b6.
Chgn y tré lé'i dGnp
S6 ldn gdp 3 ldñ sd.bé vb s6 IO'.n hontS6 bé B,do'n v! S6 I 'n vâ sd bé.l6n’T ugt’lb: A. 6 vo 2 8...... 1..0 v..d 2.’.’ C. 12 va 4 a) 20 + 530 ’’ c) 90 x 6 Det tfnh rdi tfnh. a) 172 x 4 o ° b) 785 : B c) .?. : 3 - 70 S¿j. hgc.sinh khdi Gdp. 245
S6 hoc sinh kh6i Idp 3 .280
S6 hoc sinh cd hai khdi .?.
Sd hocsinh kh8i 2 R hon
khdi 3 .?.
So hgc sinh Duo Idp 34 S6 hoc sinh 6' 1bon 2
Sd hoc sinh d' 8
b6n .?.
Sd hoc sinh é/ 17 .?.
a) 610 + .?. = 970
Tfnh gid * ! •*• bidu thi? c.
b) 4 • .?. = 80
o) 493 - 328 + 24d b) 210 : 6 x 5
ng
co hoon conh khé kh0n, rn§t td\.’qu6 g6m 2 quydn sdch vd!’5 ctgyén vd'. Sd
sdch sg' Engl6 52. quyén, H6l. dé
boo nhiéu quydñ? Chpn y trs lé'i ddng.
a) Not so khi nhdn vé'i 1 thi bang:
A. 1 B. 0 C. chfnh so
db. b) Not so khi nhon vd'i 0 the bdnq:
A. 1 B. 0 C. chfnh s6
dé.
c) Gio tr4 cua bi/u thLI'c 2 x (27 - 27) la:
A. 1 B. O C. 54
d) Ld'p em st' dung laoi b6n 2 cho ng6i (moi bon c6 T haoc 2 bon). Dé 35 bon dd ch0 ngdi the cdn it nhdt Id:
A. 17 cdi bon. B. 18 cdi bdn. C. 35 cdi bon.
Tro chdi AIthy§c bdng.nhdw*
Bdy Id tr6 chol dtirih’cho tđ'.hoi boñ.try lén. .
- Bgn d6u tién ’nâ'I rñ I phép’nhdn trong”cdc”b‹2ng ’nhan do hoc r6i
chi dinh mot bgn.
• Bgn du'o'c chi d!nh sé noi mot phép nhon (trong bong) mo thu’o so th0' nhdt la c hñ' sd hong den v! Cuo tich trén, r6i chi dinh IgI
mot bin khac.
• Khi xudt hien phép nhon co tich bong 0 thi IrAYt choi két
ON TCP HINH HOC VgOO rvaNs
Quon s6t coc hinh bén. O! Ggi tén coc h’inh.
Ia\ Coc hinh noa co dung 4 dinh,
4 conh?
c :› Coc h”inh noo co )2 cgnh, 6 mot? j Vé hinh. Chu gé con SO* ?. dm = 1 m 1 km = .?. m *. cm = 1 dm 1 m = .?. cm ?. mm —— 1 cm 1 m = .?. mm
Nén do coc chiéu doi sou theo don •! noo (ki-I6-mét, mét, xdng-ti-mét, mi-li-mét)?
- Chiéu doi son bong ro. — Chiéu doi cuo con kien.
- Chiéu coo cuo em.
— Khoong Loch giñ’a ha i thonh pho.
Em hoy so sink chiéu vOtOmfii.
Too nhâ my ct 2 ton g, moi tâ »g To mo i châu P hi c o tile cao 9 m
ca a 360 cm, mdi nho coo 200 cm.
2 .•' I* 1;2
Die gib' bin Eng hé rdi cho bi6t d6ng h6 the’ ndm chi m6y gi?¥'.
Dgc nhi t d6 d’ cdc nhi4t kg. Chon nh\ t kg phu hop vd'i hinh 6nh.
H!hh2
Hinh 4
Th6ng kâ cdc dyng cy hgc t§p.
a) Thu th§p
Du'é'i ddy l6 m6t so dung cu vé tronh cola bgn L6m.
b) Phdn logi Co the phdn looi nhu' sou:
But chi - But sip - Dung cu ggt but chi — Cuc tdy (cue gom). c) Klgm dim Bém so dung cu moi lock i.
d) Bidu dd tronh
Dgng cy vg trom cdo L6m
M6i thd hién met dung cu.
So sdnh s6 lu‘o'ng cdc logi dung cu trén bang cdch sñ' dung cdc t