- Th* nhdt ld ld ndng gidi bdt phuong trinh hdm cila hgc sinh chua t6t.
ld 1,458692994 vit 1,69476a971 i ,
Vfi gAf Utf, S0 ngUC fUAy finn CA1U tnV ... TREN TH&TT
nnu noan.uAo
(HV tdp Li' luQn & Phtong phdp dqy hqc bQ m6n Todn' K21' DH Cdn Thtt)
O bei vi6t ,,Su dyne m6V tinh cAm tay giiri TrCn thpc t6, ching ta c6 th6 ding chric nSngphuong trinh bgc b6n, 5p dung gi6i phuong 1rinil, MODE 7: TABLE cin mity CASIO fr-570ES phuong trinh bgc b6n, 5p dung gi6i phuong 1rinil, MODE 7: TABLE cin mity CASIO fr-570ES
?flflf"ffi.T#,};dTff;;fl.f;T5#Jl: (vh cdc roqi m6y tuong duong) dc tim si6 t4
,a r"oitre ,i6 +e+ p.zorc1, ffang 30-32), tbc cltng cria S, vd P, nhu sau:
eie fa NguyAn Duy dd trinh bdy c6ch xu li lchi . Tim gi6 tri dirng ctra St =0,236067917 tong hoflc tich cua c6c nghiem do clugc khong ^, -
. .
o B6m MODE, chgn 7: TABLE
phdi so hiru ti nhu sau:
ifr,iau i. ?i tai in r,,nsiiint - - -
i o Nhdp vho mdn hinh
l x* + 4x3 + 3-r1 -12x- 16 = 0.
$nep: Dtng m6y tinh b6 tui dd <tugc 2 nghi€ni
ld -1,458692994 vit 1,69476a971. i,i ,i Nhfn x6t: sr: -1,458692994 + 1,694760971 : i ! i : 0,23606'7977. i F (X) = (0,236067 97 7 + X)2
o B6m :,rn|y hoi Start? chqn 1
o B6m :,ttby h6i End? chqn 10
o B6m :,ttby h6i End? chqn 10
o Dd trong b6ng kiit quii ndy ta th6y v6i
kA q* f6n kh6ng phai li sO trtu tj', n6n ta dd sd X =2 th\ F(2) = 4,gggg9ggg8 p 5 . Vfly
,t
i,u * * Ji fi len vi th6v J5 =2,236067977i; F(z)=5 e (S, +2)z =5 = S, = JS -Z .
l* * E =0,236067977: JS -z i o Tim gi6 tri dring cira pt = -2,4i2135955i Pr = -1,458692994 x 1,694760971 i o Ta co i Pr = -1,458692994 x 1,694760971 i o Ta co
: = -2,472t35g55 i Pr=-2,472135955= -(2+0,472135955)
iVnA, *e,' Vi i o fa chi .in tim eiiL fti dring cita
ri
t4,236067g77 x2 = -0,472135954, n6n i * =0'472135955
I '
' n t' o B6m MODE' chon 7: TABLE' nhiP vdoip, = -2,+72135955 = -a(Ji -z)-z =2-2J5. i - -'-' " ip, = -2,+72135955 = -a(Ji -z)-z =2-2J5. i - -'-' "
: i mdn hinh F(X) = (0,472135955 + X)2
i - -(F:h-gorytar-iic11- - - - - -, -i o B5m :, miyhoi Start? chon 1; b5m :,
Song theo t6i thi dopn "n6n ta do sti vd tf tu J7 mdy hoi End? chon 10; b6m :, may hoi Step?
trO l€n vd th6y...suy ra S, = ... = J5 -2 ", cf,ng chgn 1; b6m :, m6y hi6n bang k6t qui
nhu nhpn x6t md titc gittnou ra sau d6 cl6 tim gi6 o Dd trong bang k6t qui ndy ta th6y v6i
tri dirng cua P, tl€u chua thflt sU tu nhi0n. N6u X = 4 thi F(4) = 20 'Yly
gap bdi to6n nhy trong gid ki6m tra, qu6 ld rAt F(4)=Vgo(m+4)2=)fiavn=^|2-A-4=2J5-4'
kh6 cho hqc sinh (vd ci gi6o vi0n) c6 th6 binh o Cho n6n,tinh nghi ra dugc c6ch xu li nhu tr6n. tinh nghi ra dugc c6ch xu li nhu tr6n.
^ -- TORN l-loc
30 -qtudiu@