L t= tn tn t= tr?,li *{i t)
Trudng.hq {t 56 c6 10 cht s6 5: Chi c 61 s
duy nh6t.
Trudng hW 2.56 c6 9 chft s5 5 vd 1 chir s6 2.
Xi5p 9 s6 5 thenh hing: C6 I c6ch. Khi d6 t4o n6n 10 vi tri dC xep s6 2.XCp s6 2: C6Clo c6ch'
Nhu v6y trudng hW 2 c6 Clo s6.
Trudng 4W 3. 56 c6 8 chft sd 5 vd2 chrt sd 2.
X€p 8 s6 5 thhnh hing: C6 1 c6ch. Khi d6 tao
nOn 9 vi tri d0 x6p sO Z. xcp s,i z: C6 Cl c6ch.
Nhu vdy truong hqp 3 c6 C; s6.
Trudng hqp 4. So c6 7 cht sO 5 vh 3 cht s5 2:
X6p 1 sO S tnann hang:.C6 1 cdch. Khi d6 tao
n6n 8 vi tri dO x6p sO Z. Xep sO 2: C6 Cl c6ch.
Nhu vdy tru&ng hqp 4 c6 Cl s6.
Trudng hW 5. 56 c6 6 cht s6 5 vh 4 chfr s6 2: Xtip 6 sO 5 tnenh hhng: C6 i c6ch. Khi d6 tao
n6n 7 vi trf d6 xOp rO Z. Xiip td Z: C6 Cl cdch.
Nhu vdy truong hqp 5 c6 Cl s6.
Trudng hW 6. SO c6 5 cht s5 5 vh 5 cht sti 2.
Xep 5 sO S tna* hhng: C6 1 c6ch. Khi cl6 tao
nOn 6 vi tri de xCp sO Z. XOp s5 2: C6 Cl c6ch.
Nhu v6y truong ho-p 6 c6 Cl s6.
-- tKet qua co
1+ Clo +C$ +C! + Cf + C; = 144 (s6). D
DANG 4. Phuong ph6p "buQC' cilcphin tri
O6t ngdu v6i phuong phdp tao ."vrich ngdn"
ld phuong phdp "buQc" cdc phdn tú. Cdc bdi tQp dqng ndy ỷu cdu x€p hai ho(c nhi1u
phdn tir dtrng cqnh nhaụ W vQy ta "buQc"
llAN(; 3. Íhuolg ph6p t4o "vdch ngin"
Khi bdi totin yAu ,du ."dp hai hofic nhiiu cdc phAn fíklt\ng dung canh nhaụ Chiing ta cd
thd t(to ra ccic "vdch ngdn" cdc phdn fi ndy
traoc khi xAp chting.
*Thi dq 5. Cd 6 hpc sinh vd 2 thdy gidoctvq'c xAp thdnh,hdng ngang. .Hdi c6 bao ctvq'c xAp thdnh,hdng ngang. .Hdi c6 bao
nhiAu cdch sdp xAp sao cho 2 thdy gido kh\ng
drt'ng cqnh nhaủ
Ldi gitiị Trudc h6t, x6p 6 hgc sinh thdnh m6t
hlng: C6 6l c6ch. Khi d6 m5i hgc sinh d6ng
TORN HO(