phai ld KL)
Citu2. Nguy€n tu cria hainguy6n t6 A va B thuQc haichu kj,li6n titip c6 t6ng s6 proton trong haihat nh6n ld 25. Nguydn
t6 A tao v6i hidro mQt hqp ch6t khf c6 c6ng thilc phdn tí la H2Ạ Hai nguy6n tO A vd B c6 sri diQn tich hat nhdn tucrng ld:Giiri: A vd B chua chdc phdi ó I nh6nt n€n khdng bidn htQn ch|nh t€ch 8 hay I8ẹ A tqo v6'i hidro ntQt hóp chtit khi Giiri: A vd B chua chdc phdi ó I nh6nt n€n khdng bidn htQn ch|nh t€ch 8 hay I8ẹ A tqo v6'i hidro ntQt hóp chtit khi c6c6ngthrlrcphdntirtdH1An€nAthtt6cnhdmVIẠ lrl6uAftuOcchttk)2thicdZ:8thiBc6Z:lTsdthtt1cCK3.A thuoc CK3 thi A cd Z : l6 tlti B c6 Z : 9, tir gia dinh A thuQc CK4 tró di ld v6 lỵ
Ciu 3. Cho h5n họp A chría 0,15 mol d6ng vd 0,15 rrrol s6t phan fng vila du vdi dung dich HNO3 lo6ng, thu dugc sdn
phArn khríduy nhAt ld 0,2 mol khi X kh6ng mdu d6 đng h6a ndu do khi g?p kh6ng khị Khdi luọng mu6i thu dugc khi c6 can dung dich sau phdn ríng bing.
Giai:KhitdNOv6'is6molenhQn:0,2x3:0,6.|,t€uchitqonntdish@)siintotecho:0,15x2+0,15x2:0,6
vira bdngsii ntol e nhan. Dtmg dich c6 Cn(l,lO j)2vd Fe(NO j)2vdi dng KL - 55,2 gam.
CAu 4. Nguoita đ trOn dung dich C chría 0,1 molNa*,0,2 moll(*, 0,05 mol SOa2', vir OH'v6'idung dich D chria 0,05 mol
Bả*,0,2 mol I(*, 0,1 mol Cl-vd HCO:- thi thu duo-c 200 mldung dich E c6 pH (cho bi€t ion CO32'dA blthuy phAn trong
dung dich).
Giiri: Bao toitn diQn tlch ta c6 0,2 ntol OH trong clung dlch C, 0,2 mol HCO; vira dri ldc dung tao ra CO12-BaSO, ket n)a cdn lqi ion CO32' thuy phdn tao ra m6i tnrdng c6 pH>7,
C6g S. Cho 4 lo hoa chAt bi rn6t phdn dung 4 dr-rng dich trong sudt, khdng miu chira cic h6a chAt ri6ng biet: NaOH, H:SOr, HCl vd NaCt. O6 nnan fi6t timg ch6t colrong tilng lo dung.dich cAn ft nhAt si5 hOa ch6t la . Chi cdn BăHCO:)z ld phdn
'oiQt duọ c 4 dung dlch. Nhung co-n dung ajcn NaCt atjnnan bi€t thi cAn thdm dung dich ndy bing miru ngon lua nhAn ra ion natri hay nhfn ra ion clo bdng phirn ung lt€t tua tao AgCl
Giii: N6u dii phdn bi€t cdc clung clich thi chi cdn 1 chrit ld clung dich BăHCO)2, nhtrng đ nhdn bih ting chtil cd troyg timg tp thi cdn'nh(m bi6t nijt wait (tong lp kh6ng c6 hiQn ttqng gi khi cho phdn *ng v6i BăHCO)) bdng dung
dich AglttrO j chdng han.
C6u 6. OOt cnay ho2rn roirn 26,8 gam h6n hqp I g6rn c6 3 kim lo4i Fe, Al vd Zn thu dugc 41 ,4 gan h6n hop Y chi chria 3
oxit. Th6 tfch dung dich HzSOq 1M cin dirng dt3 vira hda tan h6t luọng hdn hqp Y d trdn bdng
Gidi:Sd molaxit:s6ntoloxi:(41,4*26,8)/16:0,9125ntoln€nthdtichdungdichaxit--0,9125 l{t.
CAu 7. D6t ch6y hoirn todn a gam h6n hgp X g6m 3 kirn loai Mg, Fe vd Al thu duo-c 34,5 gam h6n hqp Y g6m c6 3 oxit.
OC hoantun frA f'an hgp Y cAn"dtrng it nhdt a00 ml dung dich HCI 2M. a c6 gi6 tri bdng
Ciai:d8 molaxitHCt{rngv6i0,4ntoloxitrotrgoxitvdya:34,5-0,4x16:28,1 gam.
CAu 8. Cho tu tu dung dich h6n hgp chfia 0,02 molNa2QO3 vi 0,012 mol K2CO3 vdo dung dich h6n họp chira 0,02 mol HCI vd 0,02 mol NaHSOạ fne ticntni CO, ihu dugc d di€u kiQn ti€u chuAn bdng.
^'!' n: i mol COj2' : 0,032 mol. sd mot rt : 0,04 mol. Phan rbng tao ra CO2 ngay vd tinh theo s6 mol H' ural: ,l ong so I
n€n s6 ntol CO2 : 0,02 vbi thii fich : 0,448 lit.
cau g. oot cnay ho2rn ro2rn m6t hidrocacbon A, đn todn b0 siin pham ch6y qua binh dung.dung dich nu6c v6i trong (du) ,rrav ittaii".;;g J""g dlch trong binh giim 2,48 g vir trong binh xu6t hi6n 7 gam k6t tuạ c6ng thric ph6n tri cua hidrocacbon l2r
Gitti: Chri y khtii tup.ng dtutg dich gidm c6 nghTa ld khoi tryng CO2 vd nfíc hdp thi so v6'i khdi lupng kdt ilạ T{nh duqp khiji 6qng nt'róc vd COt.-56 mol ntr6'c - 0,08> s6 mol CO2:0,07 n1n A ld HC no suy ra C7H 16
Ciu 10. s5 anken t6i da dugc tao thdnh khi tach nudc c6c ancol b6c 2 m4chho c6 5 nguydn tri cacbon trong phAn tu bing
Gidi: V6'i 3 d6ng phdn ancol bqc 2 n,n vto ra 5 anken ftd ca 2 dong phdn hinh hpc.
C6u 11. Cho 15,4 gam h5n họp ancoletylic vd etilenglicol (etylen glicol) tac dungvila dir vdinatrithu tluọc 4,48 lit khi
hidro(do6dktc)uạgu*"iriịin.*rogiaffi baG QhaylHbinglNav6'tkhiiilusngtdng22gam/lmolH.Nanm:
I 5,4 + 22x2x4,48/22,4 : 24,2gam) (adsbygoogle = window.adsbygoogle || []).push({});
C6iu lZ.Chuy6n h6a hodn toa; 4,6 gam mQr h6n hqp X gdm 2 ankanol b?c 1 c6 cirng s6 mol d6 thu dugc ankanal đ dilng
h6,0,1n,';i 6uỌ Cfro todn b0 ankinal thu dugc tt'ur t,iqn phin fng trdng guong thu dúo-c 0,3 mol Ag. Hai ankanol đ
dilng ld
Giai: Sd mol Clo =0,1 tqro ra 0,1 ntol anclehit n'ong khi d6 tqto 0,3 mol Ag chirng to co HCHO Vdy c6 I nrou la rretanol. T* d6 tim ra rlt.óu kia ld CsHQH
CAu 13. H6a hoj hoirn toirn mQt axit hiiu co X dugc th6 tich hoi bing rha tfch khi hidro (do d cing di6u ki6n) thudugc khi
cho cirng lu-ong axit trdn t6c drlng h6t v6'i natrị ICri trung hda 9 gam axit X cAn 100 gam dung dich NaOH 8% X c6 c6ng
thric
GiAi c6 2 n1t6m axit. Tir sij mol NaOH stty ra M: 90 ld axit oxalic.
Ciu 14. Cho mQt amin X phdn iffrg vdi dung dich HzSƠ lodng thu dugc muiii c6 cdng.thric (RNH3)2SO4. Cho a gani X
ph6n ung voi dung dich mu6i tit 1tf clorua du (kh6ng c6 khdng khf thi thu dugc a gam k6t tua- X li
Giiti: tir c6ng thdrc ctia ntu6i sny ra amiu dón ch{rc. Xtlt I mol amin suy ra M amin : Mr,(tu)z : 90 + C2H5N-H2
CAu 15. oot cnay nJn toan mQt amin no, don chf'c, mach hd. Sdn phAm chdy sau khi ngung tu hoi nuoc con lai h6n hqp
khi c6 ti kh5iso v6ihi dro la 19,333' Amin c6 cdng th0'c ld
Gi6i: Di bdi hdm y kh6ng da oxi thi h6n ho;p khi satt khi ngrng ttt hói nu6'c chi cdn CO2 vd N2 ta c6 CnH,n+31'l chdy tc.to ra nCO2+0,5N, nin (44n+0,5x28)/(n+0,5) : 19,333x2 vd n:1. Amin ld CH3NH2.
CAu 16. Nhfln xet ndo sau đy vA ancol thom ld dring ?
Ạ C6ng thríc chung cira ancol thom la C6H6-"(OH)' vdi n> 6 (sai vi naphtalen kh6ng dilngv6'i CT ndy)
B. Do anh huong cua vong benzen ndn ancol thom phdn ríng dugc vdi dung dich ki€m (sai vi ancol thom chi phan
t?ng dtrq'c v6i kittt loai manh th6i)