... problem, Duke Math J 62 ( 19 91 ) , 13 1 15 5 [30] J Sylvester and G Uhlmann, A global uniqueness theorem for an inverse boundary value problem, Ann of Math 12 5 ( 19 87), 15 3 16 9 [ 31] H Triebel, Interpolation ... de Janeiro, 19 80 [12 ] M Cheney, D Isaacson, and J C Newell, Electrical impedance tomography, SIAM Rev 41 ( 19 99 ), 85 10 1 ´ CALDERON’S INVERSE CONDUCTIVITY PROBLEM IN THE PLANE 299 [13 ] A Dijkstra, ... (8 .1) µ = (∂fµ ) 1 ∂fµ and σ = 1 µ 1+ µ Next, let u1 = h+ − ih− and u2 = i(h+ + ih− ) be defined as in (1. 14) From Lemma 2 .1 and (1. 7) we see that u1 , u2 satisfy the conductivity equations (1. 15)...
Ngày tải lên: 16/02/2014, 05:20
... costs (then-year $M) 1, 000 10 0 F/A -18 E/F F/A -18 A/B/C/D F -14 A/D F -15 A/B/C/D/E F -16 A/B/C/D F-5E/F F-22 10 19 70 19 75 19 80 19 85 19 90 19 95 2000 2005 2 010 Fiscal year RAND MG 696 -2 .1 in subsequent years, ... Fiscal Year, 19 74 to 2005 Average unit costs (then-year $M) 1, 000 10 0 E-2C E-3A E-8B E-8C RC -12 TR -1/ U2 EA-6B 10 19 70 19 75 19 80 19 85 19 90 19 95 2000 2005 2 010 Fiscal year RAND MG 696 -2.2 aircraft, ... Fiscal Years 19 60 and 2008 Procurement outlays (FY08 $B) 14 0 12 0 10 0 80 60 40 20 19 60 19 70 19 80 19 90 Fiscal year RAND MG 696 -1. 1 2000 2 010 The Escalation of Aircraft Costs through the early 19 70s, increased...
Ngày tải lên: 17/02/2014, 23:20
Tài liệu Báo cáo khoa học: "HOW DO WE COUNT? THE PROBLEM OF TAGGING PHRASAL VERBS IN PARTS" docx
... 0 .90 0.7 0.86 0 .92 0.87 0 .97 0.36 0.8 1 0 .96 0.85 0 .9 0 .95 0.85 0 .96 0.87 0.77 0.86 0. 79 0 .96 0.80 0.83 0 .92 0 .93 0. 41 0 .94 0. 91 0.84 0.60 0.65 0.63 0 .94 0 .92 0.57 0. 91 0 .96 0.77 0. 79 0. 91 0. 89 ... 0 .9 0.84 0.58 0.02 0 .90 0.85 0.02 0.84 0 .95 0.48 0.25 0. 89 0.48 1 0.02 1 0 .92 0.04 0 .95 0. 29 0.33 0.42 0. 61 0.62 0. 81 1 0.07 0.57 0.60 0 .90 0 .9 0 .92 0.87 0 .97 0 .90 0.85 1 0 .96 0 .95 0 .93 0 .95 ... VB/8 narrow JJ/ 61 NN /1 VB /1 close J J/ 81 NN /16 QL /1 RB /95 VB/40 drive NN/ 49 VB/46 cry NN/ 31 VB / 19 average J J/64 NN/60 VB/6 head J J/4 NN/404 VB /14 end NN/3 59 VB/ 41 account NN/ 89 VB/28 double...
Ngày tải lên: 20/02/2014, 21:20
Báo cáo khoa học: "Case markers and Morphology: Addressing the crux of the fluency problem in English-Hindi SMT" pot
... words) F 2.63 1. 92 1. 62 Baseline A E 2.84 1. 30 2.00 2.23 1. 69 4.00 F 3.30 2.32 1. 86 Reorder A E 3.52 0.74 2.43 2.05 1. 73 3.36 F 3.66 2.62 1. 86 Stanford A E 3.75 0.62 2.46 1. 74 1. 86 2.82 Table ... syntactic syntactic Fluency 2 .14 2.6 2.88 Adequacy 2.26 2. 71 2.82 #errors 2 .16 1. 79 1. 44 Table 6: Subjective Evaluation: The impact of reordering and semantic relations Small ( < 19 words) Medium (20-34 ... + stanford Reordering distortion lexicalized syntactic syntactic BLEU 24.42 28.75 31. 57 31. 49 NIST 5.85 6 . 19 6.40 6.34 Table 5: Results: The impact of reordering and semantic relations Model...
Ngày tải lên: 08/03/2014, 00:20
Báo cáo khoa học: "Words and Echoes: Assessing and Mitigating the Non-Randomness Problem in Word Frequency Distribution Modeling" ppt
... Repubblica corpus) References Baayen, Harald 19 92 Quantitative aspects of morphological productivity Yearbook of Morphology 19 91 , 10 9 -15 0 Baayen, Harald 20 01 Word frequency distributions Dordrecht: ... William A Gale 19 95 Poisson mixtures Journal of Natural Language Engineering 1, 16 3 - 19 0 Evert, Stefan 2004 A simple LNRE model for random character sequences Proceedings of JADT 2004, 411 422 Evert, ... 3N0 10 rMSE for E[V1] vs V1 on test set (REPUBBLICA) 50 rMSE for E[V1] vs V1 on test set (DEWAC) 50 rMSE for E[V1] vs V1 on test set (BNC) ZM fZM GIGP fZM echo Figure 3: rMSEs of predicted V1 on...
Ngày tải lên: 17/03/2014, 04:20
Báo cáo khoa học: "PARASESSION ON TOPICS IN INYEZRACIXVE DISCOURSE INFLUENCE OF THE PROBLEM CONTEXT*" potx
... CIS 5 91 in Fall 19 797 presumes that CIS 5 91 was offered in Fall 19 79 If ~his ~as not the case then a response None by the system would be misleading; rather the response should be that CIS 5 91 was ... offered in Fall 19 79 This is an instance of an extensional failure An example of intensional failure is as follows A user's question: How man7 under~aduates taught courses in Fall 19 797 pr~su~es ... asking f o P Thus in asking the question Who is r~istered in CIS 5 91 ? the user is interested in knowing who is registered in CIS 5 91 The user is normally not interested in how the syst~n got the...
Ngày tải lên: 17/03/2014, 19:20
Báo cáo khoa học: " THE KEY TO THE SELECTION PROBLEM IN NATURAL LANGUAGE GENERATION" ppt
... MS-CIS- 81- I, -1- echnicaz ~eproc 19 81 Mann, W and Moore, J "ComPuter Generation of Multiparagraph Text", American Journal of Computational Linguistics, 7 :1, Jan-Mar 19 81, pp 17 - 29, 19 81 Parma, ... Artificial Intelligence; also available as Heuristic Programming Project Report 81- 17, Stanford University, November 19 81 the picture house, fence, sculpture, street, and grassy patch) are arrayed ... locally developed version of KL-ONE The paragraphs are modify realized using MUMBLE [McDonald 19 81, 19 82], which is responsible for all low-level linguistic decisions and for carrying out sky is...
Ngày tải lên: 17/03/2014, 19:21
Lund University International Master’s Programme in Environmental Science (LUMES): Assessment of Efforts to Solve the Water Pollution Problem in Kaunas pdf
... (20 09, 80.0), (2 010 , 17 .0), (2 011 , 17 .0), (2 012 , 17 .0), (2 013 , 17 .0), (2 014 , 17 .0) WW_flow = GRAPH(time) ( 19 91 , 2 . 19 ), ( 19 92 , 1. 62), ( 19 93 , 1. 78), ( 19 94 , 1. 54), ( 19 95 , 1. 37), ( 19 96 , 1. 04), ( 19 97 , ... {m3/s} WW_BOD_conc = GRAPH(time) ( 19 91 , 222), ( 19 92 , 18 3), ( 19 93 , 17 0), ( 19 94 , 16 7), ( 19 95 , 14 9) , ( 19 96 , 14 0), ( 19 97 , 18 0), ( 19 98 , 19 2), ( 19 99 , 80.0), (2000, 80.0), (20 01, 80.0), (2002, 80.0), (2003, ... in 19 91 - 19 97 is shown in figure 3.2 tons / day BOD7 40 35 30 25 20 15 10 19 91 199 2 19 93 19 94 19 95 19 96 19 97 Figure 3.2 Biochemical oxygen demand (BOD7) of Kaunas wastewater in 19 91 - 19 97 (Data...
Ngày tải lên: 23/03/2014, 00:20
A Bayesian network approach to the database search problem in criminal proceedings docx
... of 17 N 10 10 0 10 00 0 10 0 N 10 10 0 10 00 0 10 0 H H1 H2 H3_N 50.25 00.50 49. 25 0. 01 0 .1 H H1 H2 H3_N 50. 51 49. 49 10 0 X2 X2 _ X2 M1 M1 _ M1 10 0 98 .50 1. 50 (i) M1 M1 _ M1 0. 01 0 .1 X2 X2 _ X2 10 0 10 0 ... http://www.investigativegenetics.com/content/3 /1/ 16 N 10 0 10 00 H1 H1 _ H1 10 0 H H1 H2_n Hn +1_ N M1 M1 _ M1 Page 14 of 17 N 10 0 10 00 10 0 n 10 0 10 00 10 0 0 10 0 0. 01 0 .1 X 2& &X n X 2& &X n _ X 2& &X n 10 0 10 0 36 .97 63.03 (i) H1 H1 _ H1 10 0 ... | H1 ) = Pr(X2 & &Xn | H2 n )Pr(H2 n | H1 ) ¯ +Pr(X2 & &Xn |Hn +1 N )Pr(Hn +1 N | H1) = × (n − 1) /(N − 1) + (1 − γ )n 1 × (N − n)/(N − 1) (1 − γ )n 1 N 1 N (1 − γ )n 1 1 −n = 0 .99 99 × 90 0 /99 9 =...
Ngày tải lên: 23/03/2014, 12:20
john derbyshire - prime obsession bernhard riemann and the greatest unsolved problem in mathemati
... from 99 9 ,9 01 to 1, 000,000) If I took it to a trillion, there would be just four in the last hundred-block (Here they are: 99 9 ,99 9 ,99 9 ,93 7; 99 9 ,99 9 ,99 9 ,95 9; 99 9 ,99 9 ,99 9 ,9 61; and 99 9 ,99 9 ,99 9 ,98 9.) ... 2 71 3 59 443 5 41 6 19 7 19 8 21 91 1 59 12 7 19 7 277 367 4 49 547 6 31 727 823 91 9 61 1 31 199 2 81 373 457 557 6 41 733 827 92 9 11 67 13 7 211 283 3 79 4 61 563 643 7 39 8 29 937 13 71 1 39 223 293 383 463 5 69 ... 9 71 31 97 16 7 2 41 3 31 4 19 499 599 677 773 877 97 7 37 10 1 17 3 2 51 337 4 21 503 6 01 683 787 8 81 98 3 41 103 17 9 257 347 4 31 5 09 607 6 91 797 883 9 91 43 10 7 18 1 263 3 49 433 5 21 613 7 01 8 09 887 99 7...
Ngày tải lên: 05/06/2014, 11:08
the problem of evil the gifford lectures delivered in the university of st andrews in 2003 aug 2006
... and index ISBN -13 : 97 8-0 - 19 -92 4560-4 (alk paper) ISBN -10 : 0 - 19 -92 4560-6 (alk paper) God—Proof Good and evil—Religious aspects—Christianity Theodicy BT103.V35 2006 214 —dc22 200600 615 3 Typeset by ... in Great Britain on acid-free paper by Biddles Ltd., King’s Lynn, Norfolk ISBN 0 19 92 4560–6 97 8–0 19 92 4560–4 10 I Title For Lisette This page intentionally left blank Preface These lectures ... Local Argument from Evil 95 Lecture The Sufferings of Beasts 11 3 Lecture The Hiddenness of God 13 5 Notes Works Cited Index 15 2 17 7 18 1 This page intentionally left blank Detailed Contents L E C...
Ngày tải lên: 10/06/2014, 21:29
university of toronto press the problem of evil in early modern philosophy dec 2001
... 3-5 , 19 99 ISBN 0-8020-3552-3 Good and evil - Congresses Theodicy - History of doctrines 17 th century-Congresses I Kremer, Elmar J II Latzer, Michael John, 19 61- III Series BJ14 01. P7620 01 111 '.84 ... axioms, see DM 22.2.47- 51 See DM 19 .2 Suarez's argument against the possibility of a passive faculty's being free can be found at DM 19 .2 . 19 -20 34 Alfred J Freddoso 10 See DM 19 .4.2-7 There Suarez ... NY: Cornell University Press, 19 88) Also, the interested reader should look at DM 19 .2 and DM 19 .4 -9 for Suarez's extensive discussion of free agency 12 See Part 11 of Molina's Liberi Arbitrii...
Ngày tải lên: 11/06/2014, 15:59
Báo cáo hóa học: " Review on solving the inverse problem in EEG source analysis" pot
... Surface 38. 49 ± 1. 70 30 .92 ± 1. 34 19 .32 ± 0 .94 9. 91 ± 0.40 39. 39 ± 2.04 37 .90 ± 81 29 .13 ± 1. 39 18 .28 ± 0 .92 37.65 ± 3 .18 37 .16 ± 3 .11 31. 80 ± 2. 71 28. 79 ± 2. 21 Surface 21. 35 ± 1. 25 12 .13 ± 0. 81 4.85 ... 0. 41 0.44 ± 0.05 25.50 ± 1. 59 21. 06 ± 1. 51 11. 15 ± 0.83 0.83 ± 0 .15 Deep 24 .90 ± 2.60 23.22 ± 2. 31 15.57 ± 1. 90 0.65 ± 0. 31 Surface 33.45 ± 1. 16 27 .10 ± 1. 05 19 . 31 ± 0.80 8.56 ± 0. 29 Middle 32 .17 ... 0.04 2 .16 ± 0.03 2. 21 ± 0.02 Middle 1. 51 ± 0 .13 1. 15 ± 0.08 0 .95 ± 0.07 1. 05 ± 0.06 Deep 2.30 ± 0. 21 1. 81 ± 0 .13 1. 59 ± 0 .11 1. 53 ± 0. 09 Surface 5.27 ± 0.30 4.50 ± 0.28 3. 81 ± 0.20 2 .98 ± 0 .13 Middle...
Ngày tải lên: 19/06/2014, 08:20
báo cáo hóa học: " Review on solving the forward problem in EEG source analysis" pot
... http://www.jneuroengrehab.com/content/4 /1/ 46 90 91 92 93 94 95 96 97 98 99 10 0 10 1 10 2 10 3 10 4 10 5 10 6 10 7 10 8 10 9 11 0 11 1 11 2 11 3 Brain Journal of Medical Engineering and Technology 19 95 , 19 (23):84-87 Lemieux L, ... clinical Neurophysiology 19 98 , 10 7(2) :15 9 -17 3 11 8 Chang N, Gulrajani R, Gotman J: Dipole localization using simulated intracerebral EEG Clin Neurophysiol 2005, 11 6 (11 ):2707-2 716 11 9 De Clercq W, Vergult ... =1 X(2i +1) 3 i b [id r Pi (cos ) + d t Pi1(cos )], g i (i +1) i ( 21) with gi given by: g i = [(i + 1) X + i][ iX i + 1] + (1 X )[(i + 1) X + i]( f1i1 f 21 ) i (1 X ) 2( f1 / f ) i1 i +1...
Ngày tải lên: 19/06/2014, 10:20
báo cáo hóa học:" Research Article Entire Solutions for a Quasilinear Problem in the Presence of Sublinear and Super-Linear Terms" potx
... t 1/ p 1 t 1 N / p 1 N 1 s r dt ≤ C3 a s ds C4 t 3−N−p / p 1 t s N 1 / p 1 a s 1/ p 1 ds dt A .12 Computing the above integral, we obtain r t 1 N t / p 1 1/ p 1 dt ≤ C3 sN 1 a s ds r C5 t1/ p 1 ... t 1/ p 1 dt A .13 dt A .14 Similar calculations show that r t t 1 N / p 1 1/ p 1 N 1 s dt ≤ C6 b s ds r C7 t1/ p 1 b t 1/ p 1 So, by H3 , 0
Ngày tải lên: 21/06/2014, 20:20
Báo cáo hóa học: " Research Article On the Problem of Bandwidth Partitioning in FDD Block-Fading Single-User MISO/SIMO Systems" docx
... 41, no 16 4, pp 607– 611 , 19 83 [ 21] R M Corless, G H Gonnet, D E G Hare, D J Jeffrey, and D E Knuth, “On the Lambert W function,” Advances in Computational Mathematics, vol 5, no 1, pp 3 29 3 59, 19 96 ... in Communications, vol 16 , no 8, pp 14 23 14 36, 19 98 [4] R M Gray and D L Neuhoff, “Quantization,” IEEE Transactions on Information Theory, vol 44, no 6, pp 2325–2383, 19 98 [5] R W Heath Jr and ... to have a large log2 1+ SNRDL log2 1+ SNRUL opt · where SNRDL β = log2 (e)· B DL T 1 + SNRDL , ( 49) , where N →∞ log2 N Tη (N − 1) /N 1+ (B DL Tη/N)· SNRDL / 1+ SNRDL log2 1+ SNRUL N SNRDL α = B...
Ngày tải lên: 21/06/2014, 22:20
Báo cáo hóa học: "Research Article Target Localization by Resolving the Time Synchronization Problem in Bistatic Radar Systems" potx
... (A .10 )– (A .14 ) as follows From (A.4) we have H − 1, 1 w2 s1 ,1 = 1, 1 − 1, 1 1 R1 s1 ,1 − sH R1 s1 ,1 1 R1 s1 H 1 s1 R1 s1 + 1, 1 1 = − 1, 1 2 H 1 1 s1 ,1 R1 s1 ,1 + H s1 ,1 2 − 1, 1 1 sH R1 s1 ,1 ... s1 1, 1 N2 snr ⎫ + N 1, 1 snr ≈ sH s1 snr 1, 1 N = N 1, 1 sH s1 ,1 N ⎬ | 1, 1 | snr2 sH s1 ,1 ≈ 2 2 σn + N 1, 1 1 sH s1 snr 1, 1 1, 1 1 1, 1 1, (A . 19 ) − 1, 1 1 sH R1 s1 ,1 − sH R1 s1 ⎧ 2 1 1, 1 ... 1, 1 1 w1 s1 ,1 sH w2 + w2 s1 ,1 sH w1 1, 1 1, 1 √ , M H + 1, 1 w2 s1 sH w1 1, 1 ⎞ (A.56) H H 1 w1 s1 sH w2 + w2 s1 sH w1 1 √ , M √ ⎛ 1 11 s1 ,1 sH ⎠ 1 σ n 1, 1 ≈ O √ · ⎝IN − u + Nρ2 β M σn σn 11 ...
Ngày tải lên: 21/06/2014, 22:20
Báo cáo toán học: "On the Dimer Problem and the Ising Problem in Finite 3-dimensional Lattices" pps
... 37:2 796 , 19 96 [17 ] T Regge and R Zecchina Combinatorial and topological approach to the 3d ising model J Phys A, 33:7 41 7 61, 2000 [18 ] J.K Roberts Proc Roy Soc (London) A, 16 1 :14 1, 19 35 [ 19 ] G ... 90 :273– 290 , 20 01 [8] V.L Girko Random Matrices Handbook of Algebra 1, North Holland, Amsterdam, 19 96 [9] O.J Heilmann and E.H Lieb Monomers and dimers Phys Rev Letters, 24 :14 12– 14 14, 19 70 [10 ] ... = (r1 , , r2g ) We let c(r(D)) equal the product of ci , i = 0, , g 1, where ci = c(r2i +1 , r2i+2 ) and c (1, 1) = c (1, 1) = c( 1, 1) = 1/ 2 and c( 1, 1) = 1/ 2 Observe that c(r(D)) = ( 1) n 2−g...
Ngày tải lên: 07/08/2014, 06:23
Báo cáo y học: "AIT test has no problem in the detection of anti-ribosomal P" ppsx
... Korean J Lab Med 19 99 , 19 (Suppl):S366 Sung YK, Hur NW, Sinskey JL, Park D, Bae SC: Assessment of damage in Korean patients with systemic lupus erythematosus J Rheumatol 2007, 34 :98 7 -9 91 Page of (page ... Arthritis Res Ther 2008, 10 :R1 31 Kim TY, Chang SY, Kim SY: A new substrate (IT -1) for the antinuclear antibody (ANA) test [abstract] Arthritis Rheum 19 94 , 37(Suppl):S 317 Kim TY: An external quality ... Arthritis Research & Therapy Vol 11 No Jearn and Kim colleagues’ article We agree that anti-Rib-P, just like anti-Sm or anti-nDNA,...
Ngày tải lên: 09/08/2014, 14:21