tai liệu hiệu suất hóa lớp 8

Ngày tải lên: 13/12/2013, 10:15

... Systems: A Model-Based Approach Boudewijn R Haverkort Copyright © 19 98 John Wiley & Sons Ltd ISBNs: 0-471-972 28- 2 (Hardback); 0-470 -84 192-3 (Electronic) Chapter Introduct I ion N this chapter we discuss ... that might yet be uncertain is the number of outgoing lines In addition there is uncertainty about at which times (call) arrivals take place and how long calls last These uncertainties distribution ... was introduced by Haverkort [120]; variants of it, tailored towards specific application areas, can be found in the literature [127, 180 , 211, 2 581 Interesting general guidelines for the construction...

Ngày tải lên: 15/12/2013, 08:15

... importance or information on detailed probabilities regarding certain events in the system (e.g., the probFor these cases a more detailed and ability that a buffer contains at least k customers) ... to be able to the topic of Chapter  28 Little’s law and the MIMI1 queue lOE[S] WSI WSI 7E[Sl 6Jwl 5-wSl 4EPl WSI 2Jwl EPI 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0 .8 0.9 P Figure 2.4: The mean waiting ... (measured in queueing model reading law was originally presented in 1961 [ 186 ] Other proofs of Little’s results can be found in [81 , 150, 193, 269, 2701 The analysis of the MIMI1 queue as presented...

Ngày tải lên: 15/12/2013, 08:15

... derivative of (3 .8) , we obtain that a renewal occurs in the interval [t, t + E) (3.10) 36 Stochastic where fjyn)(t) is the derivative of F$‘(t), 4) and consequently, the reciprocal we obtain the renewal ... would still mean an expected down-time 24 x 365) of 48. 7 hours a year ((1 - 0.99444) x 3.6 Semi-Markov chains 51 1.000 0.995 0.990 0. 985 P31@) 0. 980 0.975 0.970 0.965 0.960 Figure 3.6: Transient ... (3.62) 58 Stochastic Multiplying both sides of this equation with T-j $+‘)T = (-l)j+l = -(j processes we obtain (j + l)jcuT-j + 1) \(-l)j(j)!&T+ ” z(j) - / = -(j (3.63) + l)@, that is, we have obtained...

Ngày tải lên: 15/12/2013, 08:15

... wL(K)I P(K) X(K) 2.00 0.167 0. 084 5.92 0 .88 0 0.440 2.33 2.76 0.324 0.470 0.162 0.235 7.21 0.930 0.963 0.465 0. 482 3.30 0.602 0.301 10 0. 982 0.492 3. 98 4 .85 0.715 0 .80 8 0.3 58 0.404 11 12 0.992 0.997 ... 0. 183 7 0.4737 0.2 989 0.0064 0.0993 0.0013 0.2120 0.1602 0.0003 0.0000 0.0562 0.0326 0.1260 0.0000 0.0000 0.0192 0.0114 0.1019 0. 084 0 0.00 68 0.0703 0.0000 10 0.0000 0.0041 0.0024 0.0595 0.05 08 ... queueing models Solving (4 .8) and setting again p = X/p, we obtain Pi = PO&$ i = 0, 1, , m, (4.47) where po follows from the normalisation: mpi PO = -’ J&oT (4. 48) * ( *) The probability pm...

Ngày tải lên: 15/12/2013, 08:15

... truyền liệu điều dẫn tới tốc độ truyền liệu từ ổ mạng tới ổ cứng SP1 nhanh Trong nhiều trường hợp hiệu suất truyền liệu File nhỏ phản ánh lại việc truyền liệu File lớn , hiệu suất giảm Copy liệu ... nghiệm truyền liệu qua mạng khác kiểm tra Copy File khác Việc Copy liệu từ ổ cứng tới ổ mạng SP1 thực chậm Trong việc lấy liệu từ ổ mạng tới ổ cứng SP1 nhanh cách đáng kể Hiệu suất nhanh cách ... Duo E6750, 2.66GHz 2GB OCZ Reaper PC -85 00 , 80 0MHz 4-4-4-12-1T Nvidia GeForce 88 00 GT 2x Western Digital Raptor 150GB WD1500AHFD ( non-RAID) Ổ Plextor PX-708A DVD-RW Icy Box IB-MP303S-B với ổ...

Ngày tải lên: 22/12/2013, 22:17

... p/s In a similar way we obtain we find p = ~~=, Xaii/pi = 0.6 48 Applying p2 = 104/200 = 50 p/s For th e utilisation the formula for the service time variance, we obtain 0: = 0.3164 msec, whereas ... for E[W] 6.404 x 1O-4 = 36.39 msec 2(1 - 0.6 48) and E[N] we obtain: (5.7) 5.2 An intuitive Applying Little’s proof of the MIG11 result 99 law we obtain E[N] = p + XE[W] If we would have modelled ... models we obtain: f-w+7 34 = fz(z)fy,z(y~z) Kfx(4 = E[Xlz fx O

Ngày tải lên: 24/12/2013, 15:15

... disciplines E[Tp] 0.1540 0.0222 0.4 0.004 0.6 0.15 0.0 188 0.0222 0.0 188 0.3 080 0.4620 0.0542 0.1046 0 .8 1.2 0.0 08 0.012 1.2 1 .8 0.30 0.45 0.03 78 0.0570 0.0547 0.1059 0.0375 0.0563 0.6160 0.7700 0.1953 ... 0.0 188 0.0222 0.3 080 0.03 78 0.4620 0.0570 0.6160 0.0763 0.0547 0.1059 0.1 987 0.00004 0.0567 0.7700 0.09 58 0.4164 0.00010 0.4215 0.9240 0.1154 1.5 183 0.00012 1.5244 0.00006 0.1090 0.000 08 0.20 28 ... 0.1953 0.4076 1.6 2.0 0.016 0.020 2.4 3.0 0.60 0.75 0.0763 0.09 58 0.1 987 0.4164 0.0750 0.09 38 0.9240 1. 480 3 2.4 0.024 3.6 0.90 0.1154 1.5 183 0.1126 Table 6.2: The waiting The non-preemptive priority...

Ngày tải lên: 24/12/2013, 15:15

... 0.75 0 .85 0.95 2.06 1. 28 1. 98 7.02 1.52 2.61 3.93 5.46 7.16 9.01 x x x x x x x x x x WV wv lo-’ 1O-3 1O-2 1O-2 10-l 10-l 10-l 10-l 10-l 10-l 2.06 x 1.29 x 2.02 x 7.55 x 1.79 x 3 .83 x 6. 48 x 1.20 ... 3 .83 x 6. 48 x 1.20 2.52 9.17 lo-’ 1O-3 1O-2 1O-2 10-l 10-l 10-l 5.26 x 1.77 x 3.33 x 5.39 x 8. 18 x 1.22 1 .86 3.00 5.67 1.90 x 1O-2 10-l 10-l 10-l 10-i lOi Table 7.1: Comparing the expected waiting ... a Dirac impulse at t = l/X (see Appendix B) As Laplace transform we find fi(s) = e -8/ X, so that we have to obtain from This nonlinear equation cannot be solved explicitly, so that we have to resort...

Ngày tải lên: 24/12/2013, 15:15

... 0.219 0.12 788 0.263 0.1 680 0 0.306 0.210 18 0.350 0.25406 0.394 10 13 16 19 0.436 0.569 0.700 0 .83 1 0.34560 0. 481 0.613 0.744 0. 382 88 12 0.525 0.53927 0.69117 15 0.656 0.64000 11 14 17 0.299 28 0.44097 ... equals 2k 162 PHIPHIl queueing models 18. 8 18. 6 w,J 18. 4 18. 2 18. 0 10 Figure 8. 4: E[N,] Erlang 15 20 25 lc 30 35 40 45 50 service time distribution A few special 8. 4 of the number special cases of ... 0.53927 0.69117 15 0.656 0.64000 11 14 17 0.299 28 0.44097 0. 589 36 18 0. 786 0.74 282 0.79495 20 0 .87 5 0 .84 752 21 0.919 0.90051 0. 489 79 Table 8. 3: The values of v against p for the EzIH2 11 queue deterministic...

Ngày tải lên: 24/12/2013, 15:15

... 0 .8 10.6 2.33 55.7 2.31 9.67 2.23 0.3 0.442 0.444 0.317 0.5 58 1.20 0.399 0. 989 0.506 0.5 1. 38 1.16 0 .86 1 1. 38 0 .8 7.52 5.60 10.72 8. 30 6.91 6.22 Table 9.2: Comparison of the expected waiting ... 3.070 2.793 0.25 0.35 0 .86 67 1.062 0.9000 1.115 0.9310 1.179 0 .89 53 1.119 0.75 0 .85 3.400 5.933 3.700 6.500 5. 286 15.00 4.690 12.27 0.45 1.327 1.409 1.535 1.4 28 0.95 18. 60 20.50 - - Table 9.1: ... M(N - p)) ’ (9.16) 182 Polling P E[WE] E[WG] E[WL] J?@%] 0.05 0.6000 0.6053 0.6 085 0.6031 p -@[WE] 0.55 E[WG] 1.711 B[WL] 1 .83 3 models E[b] 2. 089 1.931 0.15 0.7176 0.7353 0.7 485 0.7302 0.65 2.314...

Ngày tải lên: 24/12/2013, 15:15

... 7.2 QNA 3.972 E[W4] E[W~] E[l&] E[W7] E[W8] E[V&] 3.0 08 1.377 1.091 1 .83 0 0 .82 0 20.22 2.931 1.301 0. 985 1.695 0.7 58 18. 40 2.6 5 .8 10 .8 7.9 8. 2 9.9 9. 189 1.596 1.372 5.604 3.273 34.51 QNA 6.111 ... 5.257 12.29 6.719 113.1 SIM RE 3.220 23.4 10.97 -16.2 1.559 2.4 1. 282 7.0 6.026 -7.5 2. 685 21.9 70.25 -50.9 SIM RE 6.2 28 -1.9 22.92 -8. 4 6.591 -9.7 5.956 -11.7 13.31 -7.7 7.597 -11.6 100.2 12.9 Table ... Systems: A Model-Based Approach Boudewijn R Haverkort Copyright © 19 98 John Wiley & Sons Ltd ISBNs: 0-471-972 28- 2 (Hardback); 0-470 -84 192-3 (Electronic) Chapter Open 10 queueing networks I N the previous...

Ngày tải lên: 24/12/2013, 15:15

... 12. 480 4 8. 6491 5. 788 9 3.9074 2.7 580 2. 084 4 1.6 987 1. 480 5 1.3 580 1. 289 5 1.2513 13.3333 8. 1005 4.6711 2.7219 1.7137 1.2201 0. 985 1 0 .87 46 0 .82 27 0.7 983 0. 786 8 0. 781 2 30.0000 39.4192 46.67 98 51. 489 2 ... approximations E[&@O)] 21.0000 17.6667 13. 480 4 9.6491 6. 788 9 4.9074 3.7 580 3. 084 4 2.6 987 2. 480 5 2.3 580 2. 289 5 42.0000 28. 6667 18. 2009 11.3423 7.44 38 5.4274 4.4402 3.9703 3.7492 3.6455 3.5967 ... 0.07 58 19.0 08 (11 .8) that station is empty can be calculated as 10. 088 0 0 .83 + 1 .83 + 0 .8( 1 .82 ) + 0 .82 (1 .8) 19.0 08 = ~19.0 08 = 0.5307 = 0) = (11.9) Consequently, we have ~~(3) = 1- 0.5307 = 0.4693,...

Ngày tải lên: 24/12/2013, 15:15

... Hierarchical 286 K X(K) 0.0950 X(K) 0.0945 queueing networks states 0.4731 0.4731 56 11 16 21 1.0343 1.0343 364 1.49 48 1.94 68 1.49 48 1.94 68 969 2002 26 2. 387 5 2. 387 5 3157 31 2 .81 33 2 .81 33 4312 36 ... 2 .81 33 2 .81 33 4312 36 3.2191 3.5 980 3.9416 5467 51 3.2191 3.5 981 3.9419 4.2409 4.2397 89 32 56 4. 486 1 4. 483 0 10 087 41 46 6622 7777 Table 12.1: Comparing the throughputs obtained via a decomposition ... for the aggregated subnetwork, as follows: 12 Hierarchical 282 k I G(d4 1.0 2.6 5.32 10. 088 queueing networks G(LW 1.0 3.6 8. 92 19.0 08 The second column is then computed by standard convolution...

Ngày tải lên: 24/12/2013, 15:15

... Queueing (arrivals brO;i,T network class and solution per chain/class)) 295 As a result of this, one obtains the throughputs & for open chains and the visit ratios V& for closed chains (both per node ... load-independent R pi(Ed =r&-J and in the load-dependent case I& nz,r E ,) ’ ( (13.7) case (13 .8) Notice that the load-dependent cases we have addressed here refer to the case where the service ... Example 13.1 Single-class, load-independent open networks A simplification of the BCMP theorem is obtained when only open networks in which there is only a single, load-independent Poisson arrival...

Ngày tải lên: 24/12/2013, 15:15

... Systems: A Model-Based Approach Boudewijn R Haverkort Copyright © 19 98 John Wiley & Sons Ltd ISBNs: 0-471-972 28- 2 (Hardback); 0-470 -84 192-3 (Electronic) Chapter 14 Stochastic I N this chapter Petri ... been further developed 14.6 Exercises 325 by, among others, Lindemann and German [104, 103, 182 , 183 , 184 1, Ciardo et al [52] and Choi et al [49] SPNs are not the only “high-level” formalisms to ... their timed counterparts as well For further details on invariants for SPNs with marking-dependent arc multiplicities, refer to [51] Example 14 .8 Structural properties in SPNs Consider the SPN...

Ngày tải lên: 24/12/2013, 15:15

... chất hóa học: Fe có tính khử trung bình - Khi tác dụng với chất oxi hóa yếu, sắt bị oxi hóa đến số oxi hóa +2: Fe → Fe +2 + 2e - Khi tác dụng với chất oxi hóa mạnh, sắt bị oxi hóa đến số oxi hóa ... C 0 ,81 g D 8, 1g 7/ Cho 5,4 g Al vào 100 ml dung dịch KOH 0,2M sau phản ứng xảy hồn tồn thể tích khí H2(đktc) thu A 4, 48 lít B 0,4 48 lít C 0,672 lít D 0,224 lít 8/ Nung nóng hỗn hợp gồm 10 ,8 g ... HỌC LỚP 12 – THẦY HUY – 09 68 64 65 97 Câu7: Bản chất trình hóa học xảy điện cực điện phân là: A anion bò oxi hóa anot B cation bò khử catot C catot xảy trình oxi hóa D anot xảy trình oxi hóa...

Ngày tải lên: 26/12/2013, 10:45

... 0.5000, 0.3333, 0.1667 ) ( 0. 388 9, 0. 388 9, 0.2222 ) ( 0.5 385 , 0.3077, 0.15 38 ) ( 0.4902, 0.3137, 0.1961 ) ( 0. 583 3, 0. 583 3, 0.2917 ) ( 0.4000, 0.4000, 0.2000 ) ( 0.4167, 0. 388 9, 0.1944 ) ( 0.3796, 0.4213, ... ( 0.3 981 , 0.3 981 , 0.2037 ) ( 0.3979, 0.4023, 0.19 98 ) ( 0.40 28, 0.3 981 , 0.1991 ) ( 0.4001, 0.3999, 0.2000 ) ( 0.3997, 0.3997, 0.2006 ) ( 0.4000, 0.4000, 0.2000 ) ( 0.4005, 0.3997, 0.19 98 ) ( ... Numerical solution of Markov chains 0 .8 0.6 Pi(t) 0.4 0.2 0.0 Figure 15.4: First 0.2 0.4 0.6 1.0 t 0 .8 two seconds in the evolution 1.2 1.4 1.6 of the three-state 1 .8 CTMC computing via uniformisation...

Ngày tải lên: 21/01/2014, 20:20

... 89 95 .89 1 89 93.530 0.015679 0.01 686 4 0.016 983 0.016 985 0.016 985 0.016 985 89 90.796 89 90.056 89 89.9 78 8 989 .9 78 8 989 .9 78 8 989 .9 78 0.0265 0.1039 0.6140 0 2.2475 7.6420 32.153 80 .700 180 .757 481 .430 982 .555 ... 0.657 1.731 1. 580 1.527 126 48 580 56 14 688 675 38 167 28 77016 0.6 48 0.642 0.6 38 1. 482 1.471 1.463 1.499 187 68 0.635 1.457 4 488 65 28 85 68 106 08 485 76 K rl 86 496 Table 16.2: The influence of the ... 364 J TM 92 59 1 78 173 290 3 38 425 550 581 80 5 756 1099 9 48 14 28 1155 1 788 1375 2175 1606 2 585 10 VM q 327 87 3 J TM 11 184 6 3014 12 1650 13 2640 14 382 5 15 5 187 16 67 08 17 83 70 18 10155 19 12045...

Ngày tải lên: 21/01/2014, 20:20

... stability tion 8. 2.3 for PHIPHIl of the modelled system, similar queueing systems; condition trices Ai have been computed remarks in Section 8. 3; details apply as given in Sec- (8. 23) can be validated ... er - second) All these quantities can be 3 98 17 Infinite-state 0.30 I I SPNs I set set 0. 28 0.26 0.24 0.22 Wwl 0.20 0. 18 0.16 0.14 0.12 50 Figure 17 .8: The expected bandwidth 100 x (p/s) 150 200 ... solution matrix of the class of iSPNs Referring Q of the QBD has the following 17 Infinite-state 388 K-l K Bo,o Bl,o s e BO,M BI,,-I row\col Q= K-1 0 K+l K-k2 Now, by the requirements B,pl,,...

Ngày tải lên: 21/01/2014, 20:20