streaming flow past a semi infinite wedge the falkner skan solution

... Plate – The Blasius Solution D Streaming Flow past a Semi- Infinite Wedge – The Falkner Skan Solutions E Streaming Flow past Cylindrical Bodies – Boundary-Layer Separation F Streaming Flow past Axisymmetric ... without addressing the stability of the solutions that are obtained The ideas of linear stability theory are very important both within the transport area and also in a variety of other problem areas ... recognized by a number of awards, including the Dreyfus Foundation Teacher-Scholar Award, a Guggenheim Fellowship, the Allan Colburn and Warren Walker Awards of the AIChE, the Bingham Medal of the Society...

Ngày tải lên: 02/04/2014, 16:45

... can define the set of derivation trees and the language that it generates just as we for a context-free grammar The language and the derivation trees generated by a unification grammar are the ... less than D The parser will eventually reach depth D; at this depth there are no parse trees, and then the parser will halt The essential properties of offline parable grammars are these: Theorem ... or C a contains a pair of the form [A, A] , proving that the grammar is not depth-bounded The algorithm always halts, because the grammar is either depthbounded or it is not; in the first case...

Ngày tải lên: 21/02/2014, 20:20

... Generalization of the Braid Arrangement The classical braid arrangement An in complex n-space is given by the “thick” diagonals Hij : zi = zj for ≤ i < j ≤ n The braid arrangement, also known as the ... Let A be an arrangement of a ne hyperplanes in Cn Assume G ≤ Gln (C) is a finite subgroup that leaves A invariant Let ˆ be an additional element that is larger than any element of LA Then, UA ... called the complement of the arrangement H A A The combinatorial object associated to an arrangement A is the intersection (semi) lattice LA It is the set of subspaces V of Cn such that ∅ = V...

Ngày tải lên: 07/08/2014, 06:20

... proved that the constant term in (1.1) equals the positive square root of a certain determinant, actually of one determinant, namely (2. 2a) , if n is even, and of another determinant, namely (2.2b), ... Taking the limit x → −c in (3.21) then (a) reveals that these denominators cancel in the determinant, so that DB (x, y, y ; n) is ¯ n−1 actually a polynomial in x and y Thus we have shown that ... of another determinant, namely EB (x, y; n), by (4.3)–(4.5), which is a polynomial in x and y, then identify as many factors of the new determinant as possible (as a polynomial in x and y), and...

Ngày tải lên: 07/08/2014, 06:20

... be an injective mapping from A to B Suppose that m + n ≥ q + Then τ √ |A + B| > q − q − In a certain (rather narrow) range of m, n and in the particular case of R induced by an injective mapping, ... mapping, Theorem improves Theorem To deal with the generalization of the most important and most difficult case of Theorem — that of small m + n — we make a simplifying assumption that R satisfies the ... ∈ A, b ∈ B) such that a + b = s, and for any such pair we have (a, b) ∈ R Totally, we have at least |S|(m + n − q) pairs (a, b) ∈ R On the other hand, the number of these pairs is r, whence |S|...

Ngày tải lên: 07/08/2014, 06:20

Ngày tải lên: 27/11/2015, 11:19

... Fellowship Author details Department of Mathematics and Statistics, King Fahd University of Petroleum and Minerals, Dhahran 31261, Saudi Arabia 2Center for Advanced Mathematics and Physics, National ... Science and Technology H-12, Islamabad, Pakistan Authors’ contributions All authors contributed equally to the manuscript and read and approved the final draft Competing interests The authors declare ... literature on these particles) The eBE and eFD functions had been put forward as possible candidates for the anyon function as they interpolate very naturally between the BE and FD functions The above...

Ngày tải lên: 21/06/2014, 02:20

Ngày tải lên: 05/08/2014, 15:20

Ngày tải lên: 05/08/2014, 15:20

... factorial factorization and symbolic summation, J Symbolic Computation, 20 (1995), 235–268 [9] P Paule and A Riese, A Mathematica q-analogue of Zeilberger’s algorithm based on an algebraically motivated ... An indefinite bibasic summation formula and some quadratic, cubic, and quartic summation and transformation formulas, Canad J Math., 42 (1990), 1–27 [5] G Gasper and M Rahman, Basic Hypergeometric ... derivation of a family of q-Lagrange inversion formulas Al-Salam and Verma [2] employed the fact that the n-th q-difference of a polynomial of degree less than n is equal to zero, to show that 1− a...

Ngày tải lên: 07/08/2014, 06:20

... = and b4 (π) = The number am (π) can be read off immediately from the ranked diagram of π Proposition Let π ∈ Sn be a permutation Then am (π) equals the number of diagram squares of rank at least ... of a diagram form Young diagrams For a diagram square, its rank is defined to be the number of dots northwest of it Clearly, connected diagram squares have the same rank In this paper, permutation ... Diagram of a permutation π ∈ S7 satisfying a3 (π) = Consider now the Dyck path that goes from the lower-left corner to the upper-right corner of the array, and travels along the boundary of the...

Ngày tải lên: 07/08/2014, 07:21

... in a family resulting from a more general graph operation Instead of placing copies of the same graph Gi on all the lines parallel to the i-th axis, we may place different graphs from a fixed class ... research was conducted during the DIMACS, DIMATIA and Renyi tripartite workshop “Combinatorial Challenges” held in DIMACS in April 2006; we thank the DIMACS center for its hospitality We also thank ... implies that each graph in S d is d-colorable (when d ≥ 3) Also graphs in S are bipartite, since cycles in such a graph alternate between horizontal and vertical edges In general, graphs in S d are...

Ngày tải lên: 07/08/2014, 21:21

... a special element of order s of the automorphism cyclic graph Gn (Ai ) For an arbitrary a ∈ Ai , let r = |a( k)| If r > 1, then the equivalence class a = {a, a, ka, −ka, , k s− 1a, −k s−1 a} ... First assume that [Ai ] = Then for arbitrary a ∈ M and y ∈ Ai , the element y − a is not in Ai By Definition ℓi (a) = Hence max{ℓi (a) |a ∈ M} = and the equality holds Then assume that [Ai ] If ... that a ∈ Ai ⇔ ka ∈ Ai (i.e a ∈ Si ⇔ |ka| ∈ Si ) Lemma The set P under multiplication in Zn is a group Proof Assume that k, h ∈ P It follows from Lemma that kAi = Ai and hAi = Ai Thus khAi = Ai...

Ngày tải lên: 08/08/2014, 11:20

... − a) −1 = a A b A\ {a} Proof Consider the polynomial f (x) = a A b A\ {a} (x − b) (a − b) Its degree is at most |A| − 1, and for all a ∈ A it takes value of Hence f ≡ and the coefficient of x |A| −1 ... )−1 · a i · i = a2 A2 , ,an ∈An i=2 b∈Ai \{ai }  ·  (b − a1 )−1 a1 A1 b A1 \ {a1 } b∈B1 (a1 − b) The last factor in this product can be simplified to the form (b − a1 )−1 , a1 A1 \B1 b∈ (A1 ... a2 ∈ A2 , , an ∈ An so that h (a2 , , an ) = 0, then we get f (a, a2 , , an ) = h (a2 , , an ) = 0, which proves the assertion Otherwise h |A2 × ×An ≡ By the division algorithm we have...

Ngày tải lên: 08/08/2014, 11:20

... T is the set of diagonal matrices and µ is an arbitrary partition of n In 1982, Tanisaki [14] simplified their ideal; his simplification has since become known as the Tanisaki ideal Iµ For a representation ... construct a row-strict tableau T such that Φ(T ) equals xα In other words the paths on the tree give Ψ First we recall what Garsia and Procesi did Then we give an example that makes this algorithm ... its vertex The branching and edge labelling rules are the same as in the GP-tree The crucial modification from the GP-tree is the diagram at the end of a branching edge • When branching down from...

Ngày tải lên: 08/08/2014, 12:23

... X and y ∈ Ns (x) We call x the head and y the tail of the pair By the remark, the set A ∩ N(x) has at most A N (x) A m elements, and property (2) ensures that |Ns (x)| = |Ns (x)| ≥ qds That ... escaping paths Since there are c cops in the game, the cops control at most 3msds c escaping paths By controlling each escaping path, the cops can decrease the number of free escaping pairs by at ... such that x is the head of at least qds /2 free escaping pairs, because then x would be a safe vertex, and the robber, having speed s, can move to x in her move If (x, y) is an escaping pair, then...

Ngày tải lên: 08/08/2014, 12:23

... classes are not isotopic and the families Fi , for i = 0, 3, 4, are closed under the transpose and the translation dual operations The linear set L associated with a semi eld in class F3 has the ... with Multiplication (15) and the family of their translation duals References [1] A. A Albert: On the collineation groups of certain non–Desarguesian planes, Portugaliae Mathematica, 18 (1959), ... Such a prime is also called the characteristic of the semi eld The additive group of a semi eld of characteristic p is an elementary abelian p–group and it is always possible to choose the support...

Ngày tải lên: 08/08/2014, 12:23

... Proof A 2-balanced orientation of a graph is precisely a realization of that graph as a Hasse diagram So, we consider the posets which have Hasse diagram isomorphic to Km,n No such poset can have ... = As a special k case, if G has a triangle, then g = and so XG = for k > Alternately, if g = ∞ (that is, G is a forest), then the condition that weak cycles are k-balanced is vacuous, so that ... towards the larger element in the covering relation These orientations are necessarily acyclic, but they have the additional property that every weak cycle has at least edges oriented both forward...

Ngày tải lên: 08/08/2014, 12:23

... exp(-lt) if the time t is the time of transition along the given path Since the time to pass an organ has the distribution (2.4) then fraction of oxygen that passes the organ is integral of exp(-lt) ... negligible Main result (2. 8a) is the observation that about fold variation of the demand of oxygen can be satisfied without variation of blood flow by only the changes in intensity of vasomotion Additionally, ... should have the ranges of the variation for all variables of (2.8) It should be noticed that parameters of interest (l, b and μ) have the dimension as [sec-1] = [Hz] Let estimate l, the intensity...

Ngày tải lên: 13/08/2014, 16:20

... that arctan(k/n) ϕ(k) = k(n + k) π arctan x dx 1+x arctan x 1+x dx The 1−t 1+t to obtain Thus we only need to evaluate the integral I = to this is to make the change of variables x ← I= arctan ... U131, Mathematical Reflections (4) (2009) [2] G H Hardy and E M.Wright, An Introduction to the Theory of Numbers (5th ed.), Oxford University Press (1980) Omran Kouba Department of Mathematics ... σ(k) π2 = log(1 + a) n2 + ak 1 2a • Starting from lim n→∞ n n k=1 ϕ(k) = 2, k π which can be proved in the same way as (3), we conclude that, for every α ≥ 0, lim n→∞ Mathematical Reflections (2010)...

Ngày tải lên: 15/08/2014, 16:55