... discuss them. Scoping the Project 63 05 432210 Ch03.qxd 7/2/03 9:32 AM Page 63 There are several areas where the project can be exposed to factors that may inhibit project success. These are ... Inspection 4.1 .3 Do Finish Work 4.2 Gas 4.2.1 Do Rough-in Work 4.2.2 Get Building Inspection 4.2 .3 Do Finish Work 4 .3 Water 4 .3. 1 Do Rough-in Work 4 .3. 2 Get Building Inspection 4 .3. 3 Do Finish ... 2.1 Erect Forms 2.2 Pour Concrete 2 .3 Remove Forms 3 FRAMING 3. 1 Floor Joists 3. 1.1 Install First-Floor Joists 3. 1.2 Install Second-Floor Joists 3. 2 Subflooring 3. 2.1 Install First-Floor
Ngày tải lên: 14/08/2014, 04:21
... f4 ur 1/8/01 u9 1/3/01 ưj 1/3/01 1p 1/3/01 2/14/01 04 days fz 99 days 3c qi x7 0e b ix9 End gp au 9g vs ic k3 h3 fk s3 5n bp n9 v iư jf vii zv f4 d6 hf m r4 days 2/22/01 2/22/01 lx jg 18 oh ur ... dq la xn yg uv oy 0d 82 9x hq kn p1 kv stq Test pump vu x a1 j j3g Install pump we cy qg hf it cc Spec prefab metal building 12 days 16 2/2/01 2/12/01 2/13/01 zh 9z 34 n8 2v qg Start li 5x c8 ... vg n4 s3 7lư ny x hg Paint 1u hg 17 days 15 days 2/20/01 2/22/01 2/15/01 2/19/01 w xi9 Install lights and panels w itk w m d2 zz cc k8 hn m vs ja r 9t tr 6g gx ih w3 70 5i c1 xn v2 j8 u2 x 9y
Ngày tải lên: 03/02/2024, 23:34
Let's go 6 third edition unit in the future
... expensive 28 The ice cream is delicious Unit 3 29 ascorf 30 anecklace 31 abracelet 32 a box of chocolates 33 a skateboard 34 a cookbook 35 aDVD 36 awatch 37 grandmother 38 grandfather 39 uncle ... Mars 66 off 24 Mayan 68 officer 28 maybe 17 oh 19 meet 37 old 43 message 4 on3 met 38 on the corner 29 Mexican 39 one 6 Mexico 39 only 42 middle 55 opened 3! mine 2 other 2 minute 34 our 2 mirror ... postcard 22 next to 28 potatoes 41 nice 26 practice 10 night 6 practicing 48 no2 prefer 37 noodles 41 present 20 noon 49 press 73 North 73 print 22 not 15 printed 22 note 19 probably 37 now I4
Ngày tải lên: 14/03/2014, 12:03
A HEAT TRANSFER TEXTBOOK - THIRD EDITION Episode 3 Part 1 potx
... Fluid Water Propane R -1 2 R-22 R -3 2 F 1. 0 2 .15 1. 50 2.20 1. 20 Fluid R -1 2 4 R -1 2 5 R- 13 4a R -1 5 2a R- 41 0a F 1. 90 1. 10 1. 63 1. 10 1. 72 so that hfb = fn (Bo, Co) ... = (3, 11 5) (1 − 0.2)0.8 0.66 83 (0 . 31 10 )−0.2 (1) + 10 58 (3. 14 7 × 10 −4 )0.7 (1) = 11 , 950 W/m2 K hfb cbd = (3, 11 5) (1 − 0.2)0.8 1. 13 6 (0 . 31 10 )−0.9 (1) + 667.2 (3. ... × 10 −4 )0.7 (1) = 14 , 620 W/m2 K Since the second value is larger, we use it: hfb = 14 , 620 W/m2 K Then, T w = Tb + qw 18 4, 000 = 220◦ C = 207 + hfb 14 , 620 The Kandlikar correlation
Ngày tải lên: 07/08/2014, 10:20
A HEAT TRANSFER TEXTBOOK - THIRD EDITION Episode 3 Part 3 doc
... − B2 B1 − B3 + = 1 1 1 − ε1 A1 F1 3 ε1 A 1 A1 F1–2 Qnet2 , at node B2 : eb2 − B2 B2 − B1 B2 − B3 = + 1 1 1 − ε2 A1 F1–2 A2 F2 3 ε2 A 2 Qnet3 , at node B3 : eb3 − B3 B3 − B1 B3 − B2 = ... H 2 +W 2 tan −1 H 2 +W 2 −1/2 +H tan −1 1 H + 1 4 ln (1 +W 2 )(1 +H 2 ) 1 +W 2 +H 2 × W 2 (1 +W 2 +H 2 ) (1 +W 2 )(W 2 +H 2 ) W 2 H 2 (1 +H 2 +W 2 ) (1 +H 2 )(H 2 +W 2 ) ... +AF 3–2 2F (1+3)–(4+2) = 2F 1–4 +2F 1–2 F 1–2 = F (1+3)–(4+2) −F 1–4 And F (1+3)–(4+2) can be read from Fig. 10.9 (at φ = 90, w/ = 1/2, and h/ = 1/2) as 0.245 and F 1–4 as 0.20. Thus, F 1–2 =
Ngày tải lên: 07/08/2014, 10:20
A HEAT TRANSFER TEXTBOOK - THIRD EDITION Episode 3 Part 4 potx
... p CO 2 = 0.2 atm, and T = 1200 ◦ C = 2651 ◦ R. Then Fig. 10.23a gives f 1 as 0.098 and Fig. 10.23b gives f 2 1, so ε g = 0.098. Next, we use eqn. (10.53) to obtain α g , with T w = 1031 ◦ R, ... CO 2 and 0.45 for H 2 O. Theory, and more recent work, both suggest using the value 1/2 [10.13]. Figure 10.22 Functions used to predict ε g = f 1 f 2 for water vapor in air. 571 Figure 10.23 Functions ... components of air—N 2 and O 2 —are therefore nonabsorbing; so, too, are H 2 and such monatomic gases as argon. Asymmetrical molecules like CO 2 ,H 2 O, CH 4 ,O 3 ,NH 3 ,N 2 O, and SO 2 , on the other
Ngày tải lên: 07/08/2014, 10:20
A HEAT TRANSFER TEXTBOOK - THIRD EDITION Episode 3 Part 5 pot
... air-water T (K) 276 31 3 276 30 3 31 3 D12 (m2/s) 1.42×10 5 1. 45 6.24 0.86 2.88 argon-helium 2 95 628 1068 8 .3 32.1 81.0 (dilute solute, 1 )-( liquid solvent, 2) T (K) D12 (m2/s) ethanol-benzene ... 0.20, mCO2 ,s = 0. 052 , and ρs = 0.29 kg/m3... pO2 R◦ T = (2.1 23 × 104 Pa) (30 0 K)( 831 4 .5 J/kmol·K) cO2 = = 0.00 851 0 kmol/m3 Finally, eqn (11.4) gives the partial density ρO2 = cO2 ... benzene-ethanol water-ethanol carbon dioxide-water ethanol-water 288 298 298 298 288 2. 25 10−9 1.81 1.24 2.00 1.00 methane-water 2 75 33 3 0. 85 3. 55 ... molecules travel a distance close to one
Ngày tải lên: 07/08/2014, 10:20
A HEAT TRANSFER TEXTBOOK - THIRD EDITION Episode 3 Part 6 docx
... 78.628.96 H 2 O2.655 a 363 a 18.02 Ar 3.542 93.339.95 H 2 O2.641 b 809.1 b Br 2 4.296 507.9 159.8H 2 O 2 4.196 289.334.01 C3.385 30.612.01 H 2 S3.623 301.134.08 CCl 2 F 2 5.25 253 120.9He2.551 ... 91.728.01 NH 3 2.900 558.317.03 CO 2 3.941 195.244.01 N 2 3.798 71.428.01 C 2 H 6 4.443 215.730.07 N 2 O3.828 232.444.01 C 2 H 5 OH 4.530 362.646.07 Ne 2.820 32.820.18 CH 3 COCH 3 4.600 560.258.08 ... 0.35 2.476 2.628 2.80 0.9672 1.058 0.40 2.318 2.492 2.90 0.9576 1.048 0.45 2.184 2.368 3.00 0.9490 1.039 0.50 2.066 2.257 3.10 0.9406 1.030 0.55 1.966 2.156 3.20 0.9328 1.022 0.60 1.877 2.065 3.30
Ngày tải lên: 07/08/2014, 10:20
A HEAT TRANSFER TEXTBOOK - THIRD EDITION Episode 3 Part 7 doc
... (1.424 ×10 9 )(0.2286) 1/5 5 4 +9 √ 0.2286 +10(0.2286) 1/5 = 37.73 From this we calculate m He,s −m He,e = n He,s L ρD He,air Nu m,L = (87.0 ×10 −6 )(0.40) (1.141)(7.119 ×10 −5 )(37.73) ... §11.6 eqn. (11.9), the mass fraction is, with M nap = 128.2 kg/kmol, m nap,s = (1.825 ×10 −4 )(128.2) (1.825 ×10 −4 )(128.2) +(1 −1.825 ×10 −4 )(28.96) = 8.074 ×10 −4 The mass fraction of napthalene ... 11.450−3729.3 (T K). At 303 K, this gives p v = 0.1387 mmHg = 18.49 Pa. The mole fraction of napthalene is thus x nap,s = 18.49/101325 = 1.825 × 10 −4 , and with 10 Thomas K. Sherwood (1903–1976)
Ngày tải lên: 07/08/2014, 10:20
A HEAT TRANSFER TEXTBOOK - THIRD EDITION Episode 3 Part 8 pps
... several months: Date Tdry-bulb Twet-bulb 3/ 15 4/21 5/ 13 5 /31 7/4 15.5◦ C 22.0 27 .3 32.7 39 .0 11.0◦ C 16 .8 25 .8 20.0 31 .2... of a reactant per unit surface area The p’s are partial ... H 2 = 5.7 ×10 21 (molecules/m 3 ) number density of He = 7.2 × 10 20 (molecules/m 3 ) number density of CH 4 = 6.5 ×10 18 (molecules/m 3 ) number density of NH 3 = 1.3 ×10 18 (molecules/m 3 ) ... fluid friction Ind Eng Chem., 26:11 83 1 187 , 1 934 [11.29] A F Mills... the heat transfer relation for spheres in a laminar flow, NuD = 2 + 0 .3 Re0.6 Pr1 /3 (Hint : first estimate the
Ngày tải lên: 07/08/2014, 10:20
A HEAT TRANSFER TEXTBOOK - THIRD EDITION Episode 3 Part 9 pdf
... 0 220 1424 34 4 .9 241 .3 233 .9 12 69 230 1 39 7 32 8.0 235 .2 227.8 1258 240 136 9 30 9. 6 228 .9 221.5 1247 250 133 9 2 89 .3 222.2 215.0 1 235 260 130 7 266.5 215.1 ... 483 420 401 391 389 384 378 366 352 336 DS-C15715 ∗ 8,900 ≈384 365 ≈10.7 367 355 345 335 320 Beryllium copper 8,250 420 103 2.97 117 (2.2% Be) Brass (30% Zn) 8,522 385 109 3.32 73 89 106 133 ... 180.5 2 13. 2 100 161.0 202.6 134 .3 1 89. 7 92 .0 1 73. 7 110 120 30 0.4 130 294 .0 1 53. 1 140 287 .9 125.2 150 281.8 79. 2 160 275 .9 180 264 .3 200 257.4 252 .9 1474 245.7 131 0 220 1424
Ngày tải lên: 07/08/2014, 10:20
A HEAT TRANSFER TEXTBOOK - THIRD EDITION Episode 3 Part 10 ppt
... 0.0274 0.1943 0.876 373 0.5589 2238 12.92 2.31 0.0334 0.2671 0.866 423 0.4920 2326 14.87 3.01 0.0407 0.3554 0.850 473 0.4396 2425 16.82 3.82 0.0487 0.4565 0.838 Carbon dioxide 220 2.4733 783 11.06×10 ... 1.018 393.15 0.5652 2021 13.04 23.07 0.02650 2.320 0.994 413.15 0.5365 1994 13.81 25.74 0.02805 2.622 0.982 433.15 0.5108 1980 14.59 28.56 0.02970 2.937 0.973 453.15 0.4875 1976 15.38 31.55 0.03145 ... 0.934 673.15 0.3266 2070 24.45 74.86 0.05476 8.100 0.924 773.15 0.2842 2134 28.57 100.50.06698 11.04 0.910 873.15 0.2516 2203 32.62 129.70.07990 14.42 0.899 973.15 0.2257 2273 36.55 161.90.09338
Ngày tải lên: 07/08/2014, 10:20
A HEAT TRANSFER TEXTBOOK - THIRD EDITION Episode 3 Part 11 pot
... Turbulence, 313–330 eddy diffusivities, 317–323 friction velocity, 319 internal flow, 355–367 lengthscales of, 315–316, 336 log law, 321 mixing length, 315–321 Reynolds-Colburn analogy, 322–325 transition ... sphere, 207–208 temperature response charts, 208–218 semi-infinite region, 220–235 contact of two, 231–233 convection at surface, 225–228 heat flux to, 228 oscillating surface temperature, 233–235 step-change ... steady, 235–247 transient, 247–251 one-dimensional steady, 58–62, 144–145 one-dimensional transient, 203–235 cylinder, 207–208 heat removal during, 208–212 one-term solutions, 218 slab, 203–208 sphere,
Ngày tải lên: 07/08/2014, 10:20
Building the Data Warehouse Third Edition phần 3 doc
... 2.26 Where the costs and the activities are when a data warehouse is built. Uttama Reddy CHAPTER 2 70 $1,000,000 $500,000 $2,000,000 $2,500,000 $1,000,000 $250 $10,000 $1,000 $2,000 $3,000 $2,000,000 ... tables. Figure 2.29 shows this division of data into tables for the subject area product. The Data Warehouse Environment 69 5 - build the report 1 - find the data 2 - access the data 3 - integrate ... reports (see Figure 2.27). But that expense is a one-time expense, for the most part. (At least the initial establishment of the data warehouse is a one-time expense.) Figure 2.27 shows that indeed
Ngày tải lên: 08/08/2014, 22:20
Beginning JavaScript Third Edition phần 3 pdf
... the following example, you have “31 January 2010”. var theDate3 = new Date(“31 January 2010”); However, you could have written 31 Jan 2010, Jan 31 2010, 01-31-2010, or any of a number of valid ... seconds, and milliseconds. For example: var theDate4 = new Date(2010,0,31,15,35,20,20); This date is actually 31 January 2010 at 15:35:20 and 20 milliseconds. You can specify just the date part if you ... dateNow.getDate(); var daySuffix; switch (dayNow) { case 1: case 21: case 31: daySuffix = “st”; break; case 2: case 22: daySuffix = “nd”; break; case 3: case 23: daySuffix = “rd”; break; default: daySuffix =
Ngày tải lên: 09/08/2014, 14:21
Beginning Perl Third Edition PHẦN 3 docx
... = (1, 2, 3) ; my @array2; @array2 = (@array1, 4, 5, 6); print "@array2\n"; @array2 = (3, 5, 7, 9); @array2 = (1, @array2, 11); print "@array2\n"; $ perl addelem.pl 1 2 3 4 5 6 1 3 5 7 ... to test the expression for the outer while loop This generates the following output: $ 1 1 2 2 3 3 4 4 5 5 $ perl ** 1 ** 1 ** 1 ** 2 ** 1 ** 2 ** 1 ** 2 ** 1 ** 2 looplabel1.pl = 1 = 1 = 2 ... numbers (3. 6) and variables: 30 $ Notice that the print() function prints... number as per the rules in Chapter 2, and got a 0 It’s equivalent to this: print "Going from 3 to z: ", (3 0),
Ngày tải lên: 09/08/2014, 14:21
The C++ Programming Language Third Edition phần 3 doc
... 0-201-88954-4 All rights reserved Section 10.2 .3 D at e Da te D at e Da te D at e Da te D at e Da te Constructors 227 t od ay = D at e(2 3, 6 19 83 ; to da y Da te 23 6,1 98 3) x ma s(2... ... Language, Third Edition by Bjarne Stroustrup. Copyright ©1997 by AT&T. Published by Addison Wesley Longman, Inc. ISBN 0-201-88954-4. All rights reserved. Section 9.2.2 Standard Library Headers 203 ... defined twice in a single translation unit. / / file1.c: s st tr ru uc ct t S S2 2 { i in nt t a a; c ch ha ar r b b; }; / / file2.c: s st tr ru uc ct t S S2 2 { i in nt t a a; c ch ha ar r b bb
Ngày tải lên: 12/08/2014, 19:21
Operating Systems Design and Implementation, Third Edition phần 3 pptx
... [Page 2 03] Figure 2-46 (a) Worst case for reading a block requires eleven messages (b) Best case for reading a block requires... pending for 42 03, 4207, 42 13, 4215, and 4216 Figure 2-49 Simulating ... receiver an opportunity to run (line 7620). If, on the other hand, the receiver is not blocked, or is blocked but waiting for a message from someone else, the code on lines 7623 to 7632 is executed ... example of Fig. 2-42(a) shows what happens when process 3 is unable to send to process 0. If process 4 is subsequently also unable to send to process 0, we get the situation of Fig. 2-42(b). [Page
Ngày tải lên: 12/08/2014, 22:21
Unix Shell Programming Third Edition phần 3 docx
... 5 27 $ sort -n data Sort arithmetically -5 11 2 12 3 33 5 27 14 -9 15 6 23 2 $ Skipping Fields If you had to sort your data file by the ... the -t option must be used. $ sort +1n data Skip the first field in the sort 14 -9 23 2 15 6 -5 11 2 12 5 27 3 33 $ The -t Option As mentioned, if you skip over fields, sort assumes that the fields ... george:*:75:75::/users/george:/usr/lib/rsh steve:*:203:100::/users/steve:/usr/bin/ksh pat:*:300:300::/users/pat:/usr/bin/ksh mail:*:301:301::/usr/mail: $ Here we've emboldened the third field of each line so that
Ngày tải lên: 13/08/2014, 15:21
Statistical Methods for Survival Data Analysis Third Edition phần 3 doc
... 435 8 27 3—4 400 7 22 4—5 371 7 26 5—6 338 28 25 6—7 285 31 20 7—8 234 32 11 8—9 191 24 14 9—10 153 27 13 10—11 113 22 5 11—12 86 23 5 12—13 58 18 5 13—14 35 9 2 14—15 24 7 3 15; 14 11 3 Source: ... G :10.0270 49,103 1,325.78 34,599 934.17 1—4 0.0011 193,644 213.01 132,367 145.60 5—14 0.0005 454,972 227.49 285,830 142.92 15—24 0.0011 329,230 362.15 186,789 205.47 25—34 0.0015 279,327 418.99 ... 169,873 254.81 35—44 0.0030 287,994 863.98 173,029 519.09 45—54 0.0076 269,147 2,045.52 136,573 1,037.95 55—64 0.0174 216,036 3,759.03 92,871 1,615.96 65—74 0.0382 157,385 6,012.11 63,634 2,430.82
Ngày tải lên: 14/08/2014, 09:22
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