modelling of aquaporin 2 trafficking
.MODELLING OF MECHANICAL SYSTEMS VOLUME 2..MODELLING OF MECHANICAL SYSTEMS VOLUME 2Structural docx
Ngày tải lên :
22/03/2014, 13:20
... 23 5 23 7 23 8 24 0 24 0 24 3 24 5 24 7 24 8 25 4 25 6 25 9 26 0 26 0 26 0 26 2 26 2 26 2 26 3 26 3 26 3 26 5 26 5 26 5 26 6 26 7 27 0 27 0 27 2 27 3 27 5 27 5 27 7 27 8 27 8 Contents xi 5.3.4.5 In-plane ... 180 186 188 189 190 190 190 193 196 196 20 0 20 0 20 5 20 7 20 7 20 9 21 0 21 0 21 1 21 3 21 3 21 4 21 7 21 8 22 0 22 0 22 1 22 2 22 2 22 4 22 9 23 1 23 1 23 2 x Contents 4.4.1 .2 Truncation stiffness for a free-free ... 1.4 .2 Harmonic solutions of Naviers equations 3 11 13 16 17 18 19 20 20 20 21 21 23 23 24 25 27 28 29 31 31 32 vi Contents 1.4.3 Dilatation...
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MODELLING OF MECHANICAL SYSTEM VOLUME 2 Episode 1 ppt
Ngày tải lên :
13/08/2014, 05:22
... 23 5 23 7 23 8 24 0 24 0 24 3 24 5 24 7 24 8 25 4 25 6 25 9 26 0 26 0 26 0 26 2 26 2 26 2 26 3 26 3 26 3 26 5 26 5 26 5 26 6 26 7 27 0 27 0 27 2 27 3 27 5 27 5 27 7 27 8 27 8 Contents xi 5.3.4.5 In-plane ... 180 186 188 189 190 190 190 193 196 196 20 0 20 0 20 5 20 7 20 7 20 9 21 0 21 0 21 1 21 3 21 3 21 4 21 7 21 8 22 0 22 0 22 1 22 2 22 2 22 4 22 9 23 1 23 1 23 2 x Contents 4.4.1 .2 Truncation stiffness for a free-free ... 1.4 .2 Harmonic solutions of Naviers equations 3 11 13 16 17 18 19 20 20 20 21 21 23 23 24 25 27 28 29 31 31 32 vi Contents 1.4.3 Dilatation...
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MODELLING OF MECHANICAL SYSTEM VOLUME 2 Episode 2 pdf
Ngày tải lên :
13/08/2014, 05:22
... 2 ei 2 ; x sin 2 − z cos 2 cL −iωU2 λ + 2G(cos 2 )2 ei 2 ; cL +iωU2 G sin 2 2 ei 2 ; (σzy )2 ≡ (σzx )2 = cL [1.104] (σzz )2 = Now, the attempt to solve the reflection problem in terms of (P ... 2 sin 2 − (γ cos 2 )2 ; sin 2 sin 2 + (γ cos 2 )2 C= 2 sin 2 cos 2 sin 2 sin 2 + (γ cos 2 )2 [1.114] These functions are plotted in Figure 1.18 for a few values of Poisson’s ratio It ... β )2 ) = γ cos 2 G The system [1.1 12] is thus transformed into: γ cos 2 sin 2 − sin 2 γ cos 2 −γ cos 2 R = sin 2 C [1.113] which has the non-trivial solution: R= sin 2 sin 2 − (γ cos 2 )2...
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MODELLING OF MECHANICAL SYSTEM VOLUME 2 Episode 3 ppt
Ngày tải lên :
13/08/2014, 05:22
... force equation [2. 18], we arrive at: ρS ∂ 2X ∂ − ∂x ∂t ES ∂X ∂x (e) = Fx (x; t) [2. 22] Equation [2. 22] was first established by Navier 1 824 , see [SOE 93] for a short historical survey of the vibration ... case of the longitudinal mode of deformation to the shear case 2. 2 .2. 2 General solution without external loading x Z(x) = a dx +b GS [2. 34] a and b are two arbitrary real constants 2. 2 .2. 3 Elastic ... sin n=1 (2n + 1)πy a sinh (2n + 1)πz a Substitution of the series into the second boundary condition gives: ∂ ∂z ±b /2 = ∞ βn n=0 (2n + 1)π a cosh (2n + 1)πb (2n + 1)πy sin 2a 2a = − 2y This relation...
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MODELLING OF MECHANICAL SYSTEM VOLUME 2 Episode 4 pptx
Ngày tải lên :
13/08/2014, 05:22
... θ (z)dz −a /2 [2. 86] a /2 θ (z) dz −a /2 σxx (z)z dS = −EI ∂ 2Z − αEa ∂x a /2 θ (z)z dz −a /2 a4 12 [2. 87] where I = Figure 2. 37 Beam subjected to a transverse temperature gradient 122 Structural elements ... Figure 2. 27 Loading on a sliding support Figure 2. 28 Equilibrium of the loaded section how, the simplest way is to adapt the Figure 2. 14 to the case of a transverse loading, as shown in Figure 2. 28 ... [2. 70] into the transverse equilibrium equations [2. 18]: 2 ∂x 2 ∂x ∂M(e) (x; t) ∂ 2Y ∂ 2Y z (e) + ρS = Fy (x; t) − ∂x ∂x ∂t 2Z 2Z ∂M(e) (x; t) ∂ ∂ y EIy + ρS = Fz(e) (x; t) + ∂x ∂x ∂t EIz [2. 71]...
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MODELLING OF MECHANICAL SYSTEM VOLUME 2 Episode 5 pptx
Ngày tải lên :
13/08/2014, 05:22
... K13 K23 K33 K43 Using [3.105] the following coefficients are obtained: K11 = 12En In ℓ3 n K 12 = K 22 = 4En In ℓn K23 = − 6En In 2 n K13 = − 12En In ℓ3 n 6En In 2 n K24 = 2En In ℓn 6En In 2 n ... ∂ 2Z ∂x 2 dx ℓn dx + En In K11 K21 ′ K Zk ZJ ] 31 K41 K 51 K61 K 12 K 22 K 32 K 42 K 52 K 62 where the element stiffness matrix [K (n) ] is: En Sn 0 ℓn 6En In 12En In ℓ3 2 ... = 54mn M 12 = −M34 = 22 mn ℓn M14 = −M23 = −13mn ℓn M 22 = M44 = 4mn 2 n M24 = where mn = ρn Sn ℓn 420 −3mn 2 n [3.108] Straight beam models: Hamilton’s principle 177 3.4.3 .2 Stiffness matrix combining...
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MODELLING OF MECHANICAL SYSTEM VOLUME 2 Episode 6 ppsx
Ngày tải lên :
13/08/2014, 05:22
... − 12 −6γ ℓ ⇒ K (1) U2 W2 2 U3 W3 ϕ3 T ⇒ U2 W2 2 ϕ3 T −1 0 −6γ ℓ − 12 −6γ ℓ 4γ 2 6γ ℓ 2 2 0 6γ ℓ 12 6γ ℓ 2 2 6γ ℓ 4γ 2 0 0 12 −6γ ℓ −6γ ℓ = Kℓ 0 −6γ ℓ 12 2 ... W2 2 T 1 82 Structural elements −1 0 −6γ ℓ − 12 −6γ ℓ 4γ 2 6γ ℓ 2 2 0 6γ ℓ 12 6γ ℓ 2 ℓ 6γ ℓ 4γ 2 4γ 2 6γ ℓ 2 2 0 = Kℓ 6γ ℓ 12 6γ ℓ 2 2 6γ ℓ 4γ 2 12 0 ... 2 2 4γ 2 The finite element model of the problem is assembled as: 4γ 2 6γ ℓS 6γ ℓC 2 2 ψ1 6γ ℓS 2( C + 12 S ) 12 ℓS 6γ ℓS X2 6γ ℓC 2( S + 12 C ) −6γ ℓC Z2...
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MODELLING OF MECHANICAL SYSTEM VOLUME 2 Episode 7 pdf
Ngày tải lên :
13/08/2014, 05:22
... 2 2γL + ̟1 − ̟ 2 L 2 L 2 L 2 L 2 L 2 L q1 2 L + 2 − ̟ 2 L 2 L q2 q3 2 L 2 L + ̟3 − ̟ 2 L q4 2 L 2 L 2 L + ̟4 − ̟ 0 = 0 by solving this system, the following values of ... 2( γL + ̟ ) 2 L 2 L 2 L q1 q2 0 2 L 2 L + π − ̟ 2 L 2 L q = 2 2γL 2 L 2 L 2 L 2 L + 4π − ̟ 2 L 2 L 2 L + 9π − ̟ q4 The first row of the modal equation is the projection of the ... energy: ˙ ˙ ˙′ ˙′ M1 X1 + M2 X2 = M1 X1 + M2 X2 2 M1 X1 ′ ′ 1 2 ˙ ˙ + M2 X2 = M1 X 12 + M2 X 22 [4.100] ˙ ˙ ˙′ ˙′ where X1 , X2 and X1 , X2 denote the velocities of the two particles just before and...
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MODELLING OF MECHANICAL SYSTEM VOLUME 2 Episode 8 potx
Ngày tải lên :
13/08/2014, 05:22
... equation leads to: F 2 = 8GI dX0 F y2 νFy + − dy 2GI 2EI + F x(x − 2L) dY0 + dx 2EI 28 2 Structural elements so, (2 + ν)Fy dX0 =a− ; dy 2EI where a + b = dY0 =b− dx F x(x − 2L) 2EI F 2 8GI The resulting ... M × m2 η n + 2 − 2n2 m2 2 (n2 − m2 )2 αn,m = βn,m ′ ωn,m 2 2n2 m2 2 (n2 − m2 )2 n2 2 + m2 η 2 ′ − ωn,m 2 ... Ehπ m2 η m2 n2 + αn,m + n2 η + η 2 otherwise Ehπ m2 η n2 + η 2 αn,m + n2 η + m2 2 βn,m βn,m + 8n2 m2 α β (n2 − m2 )2 n,m n,m π where η = Lx /Ly and the following...
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MODELLING OF MECHANICAL SYSTEM VOLUME 2 Episode 9 pps
Ngày tải lên :
13/08/2014, 05:22
... −z εxx = −z ∂ 2Z + 2 ∂x εxy = −z ∂ 2Z z2 ∂ Z + ∂x∂y ∂x∂y εyy = −z ∂ 2Z + ∂y ∂Z ∂x + z2 ξz = Z ∂ 2Z ∂x + z2 ∂ 2Z ∂x∂y + ∂ 2Z ∂ 2Z + ∂x ∂y 2 ∂Z ∂y ∂Z ; ∂y + ∂Z ∂Z ∂x ∂y ∂ 2Z ∂y 2 ∂ 2Z ∂x∂y + [6.89] ... ∂y ∂y D D ∂ 2Z ∂y +ν ∂ 2Z ∂ 2Z +ν 2 ∂x ∂y ∂ 2Z ∂x y=±ℓ /2 ∂ 3Z ∂ 3Z + (2 − ν) ∂x ∂x∂y x=±L /2 x=±L /2 = = −M(e) y ∂ 2Z ∂x∂y = 0; =0 x=±L /2; y=±ℓ /2 ∂ 3Z ∂ 3Z + (2 − ν) ∂y ∂x ∂y =0 y=±ℓ /2 =0 [6.78] ... Structural elements 2 = β1 [gβ Nαα δXα ] 2 dβ α1 2 + α1 2 − β1 ∂(gβ Nαα ) ∂gα δXα + δXβ ∂α ∂β dα dβ and, 2 2 α1 {Nββ δ[ηββ ]}gα gβ dα dβ β1 2 = 2 α1 Nββ gβ β1 2 = 2 2 2 2 α1 − β1 α1 dα...
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MODELLING OF MECHANICAL SYSTEM VOLUME 2 Episode 10 pdf
Ngày tải lên :
13/08/2014, 05:22
... P )2 = (d r )2 + (dς )2 + ς (d n )2 + 2 d r · d n [7 .28 ] d r is in the tangent plane so 2 (d r )2 = gα (dα )2 + gβ (dβ )2 [7 .29 ] The determination of (d n )2 is obtained from the differentiation of ... included in the model [7 .21 ] 7 .2. 5 .2 Breathing mode of vibration of a circular ring Using [7 .21 ] for n = 0, the modal equations are: − 2 ρSV0 = − 2 ρSU0 + ES U0 = R2 [7 .23 ] There are two solutions ... (ηkm )2 − (kn )2 (−1)n+m ab (ηkm kn )2 (ηkm )2 + (kn )2 (2n + 1)π , n = 0, 1, ; a km = (2m + 1)π , m = 0, 1, a where η = a/b is the aspect ratio of the plate Numerical evaluation of this...
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MODELLING OF MECHANICAL SYSTEM VOLUME 2 Episode 11 potx
Ngày tải lên :
13/08/2014, 05:22
... coefficients of the metrics are given by: (ds )2 =(dx )2 + (dy )2 + (dz )2 (ds )2 = (sin ψ cos θ )2 + (sin ψ sin θ )2 + (cos ψ )2 (dξ )2 + (sin θ )2 + (cos θ )2 (ξ sin ψdθ )2 (ds )2 =(dξ )2 + (ξ sin ψdθ )2 then, ... written as: 2 E= L11 [Wn ] = η 2 n4 + L 22 [Rψn ] = [Wn Rψn ] L11 [Wn ] + L 12 [Rψn ] dθ L21 [Wn ] + L 22 [Rψn ] n2 − ̟ Wn ; 2( 1 + ν) n2 + 2( 1 + ν) L 12 [νn ] = −η 2 n2 Rψn [8.69] − ̟ Rψn ; L 12 [un ] ... f0 2 f0 π f0 t1 = π tn>1 = − f0 π +π /2 −π /2 cos θ dθ = − f0 ; π r1 = − f0 π +π /2 −π /2 k 2f0 (−1) +π /2 cos(nθ) cos θ dθ = π(4k − 1) −π /2 +π /2 −π /2 (cos θ )2 dθ = − f0 if n = 2k if n = 2k...
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MODELLING OF MECHANICAL SYSTEM VOLUME 2 Episode 12 pot
Ngày tải lên :
13/08/2014, 05:22
... terms of the displacement variables Z, ∂Z/∂α, ∂Z/∂β 2 2 − (Mαα δχαα )gα gβ dα dβ α1 β1 2 = 2 β1 + α1 gα gβ 2 = ∂ ∂β 2 β1 α1 2 2 2 2 Mαα gβ α1 2 = 2 − β1 2 = 2 α1 gα gβ Mαα δ gα β1 2 ... Un ; dz2 Eh − 2 (n) Nzz = M(n) = −D zz (n2 − 1) Un ; R2 dUn −n ; n dz (n) (n) R d Un n2 dz2 d Un ν(1 − n2 )Un + dz2 R2 Mθ θ = −D − Mθ z = − − d Un (n2 − 1) Un + ν R2 dz2 D(1 − ν) −n + R 2n dUn ... shells Mzz = −D ∂ 2U ν + ∂z2 R Mθ θ = −D R2 Mθ z where ∂ 2U ∂V − ∂θ ∂θ ∂ 2U ∂V − ∂θ ∂θ −D(1 − ν) = R +ν ∂ 2U ∂z2 [8. 92] ∂V ∂ 2U − ∂θ ∂z ∂z D= 419 Eh3 12( 1 − ν ) 8.3 .2. 2 Equations of vibrations By...
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MODELLING OF MECHANICAL SYSTEM VOLUME 2 Episode 13 ppsx
Ngày tải lên :
13/08/2014, 05:22
... quasi-inertial range 22 5, 22 8 quasi-static correction 22 8, 23 5 mode 22 8 range 22 5, 22 8 Rayleigh minimum principle 29 4, 29 9 Rayleigh–Love model 199 Rayleigh–Ritz method 24 2, 29 3, 29 5, 335, 345, 436 ... axis 118 of beam 141, 20 7 element 174, 21 2 equations 316 mode 51, 21 2 mode of vibration 20 0 20 1, 21 2 moment 73, 125 , 22 2 operator 159 plane 71 and shear modes 20 5 stiffness coefficient 327 strain ... relation of constraint resonant range 22 5, 22 6 response 22 6 response spectrum 22 7 resultant stress 72 rigid body 24 , 26 2 mode 23 6 motion rigid connection mode 25 6 spring 24 4 support 173 roof truss...
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Báo cáo y học: "A prospective observational study of the relationship of critical illness associated hyperglycaemia in medical ICU patients and subsequent development of type 2 diabetes"
Ngày tải lên :
25/10/2012, 10:02
... (43.6%) 20 2 (56.4%) P < 0.001 ACSb Diagnoses (N, %) 322 97 (30.1%) 22 5 (69.9%) - other diagnoses 331 99 (29 .9%) 23 2 (70.1%) Age (years) 58 (19 to 87) 59 (22 to 87) 58 (19 to 86) P = 0 .21 4 Male ... Care 20 09, 13:R27 31 Goran KP: The consensus is clearly needed for the definition of stress hyperglycaemia in acute myocardial infarction Eur Heart J 20 07, 28 :20 42 author reply 20 42- 2043 32 Timmer ... 1.4 (0.9 to 4 .2) 1.3 (0.9 to 4.5) P = 0.106 Cholesterol (umol/l) 4.5 (2. 1 to 7.7) 4.8 (2. 0 to 9.7) 4.9 (2. 1 to 8.0) P = 0.146 Glucose levelsc 6.4 (2. 7 to 23 .5) 7.6 (3.8 to 23 .5) 5 .2 (2. 7 to 7.7)...
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Báo cáo y học: "The association of meat intake and the risk of type 2 diabetes may be modified by body weight"
Ngày tải lên :
31/10/2012, 16:49
... 1659.4 2. 8 2. 2 2. 2 2. 68 38.6 30.9 36.0 33.8 38.8 34.3 33.1 32. 3 23 .7 10.8 11.53 42. 3 30.6 15.5 36.1 34.3 21 .1 8.5 9.9 38.9 33.8 17.3 32. 7 31.8 22 .8 12. 6 18.4 38.3 29 .3 14.1 20 .2 38.8 24 .7 16.3 ... 29 .7 17.9 22 .1 41.4 23 .7 12. 8 12. 3 35.9 30.7 21 .0 23 .8 39.4 24 .1 12. 7 14.7 37.9 28 .9 18.4 14.6 9.6 15.3 60.5 9.7 0.4 2. 3 28 .6 20 .9 14.7 26 .3 38.0 4.4 0.1 1.4 16.8 11.7 9.8 17.5 61.0 8.3 0.3 2. 7 ... 24 .1 23 .9 0.81 0.80 1438.6 1939.7 3.1 2. 3 2. 2 2. 7 Poultry Q1 Q5 54.5 49.7 24 .2 23.7 0.81 0.80 1515.3 1833.8 3.7 1.8 2. 0 2. 9 Processed Meat No Yes 54.7 51.3 23 .9 23 .9 0.81 0.81 1617 .2 1659.4 2. 8...
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The future of English 2
Ngày tải lên :
05/11/2012, 16:27
... British ‘brand’ of English play an important role in the 21 st century? p 57 Figure 29 Composition of Gross World Product 1990 20 50 40 20 1990 20 00 20 10 20 20 20 30 20 40 20 50 The Future of English? ... Three 55% Figure 21 Proportions of world wealth in 1990 (total $25 trillion) Asia 21 % Rest 24 % Rest 28 % Big Three 12% Figure 22 Estimated shares of world wealth in 20 50 (total $25 0 trillion, average ... as a working language of world institutions, although the world position of French has been in undoubted rapid decline Ethnologue 1, 123 322 23 6 26 6 20 2 170 28 8 189 125 98 72 63 47 Table Major world...
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Rate-Distortion Analysis and Traffic Modelling of Scalable Video Coders
Ngày tải lên :
06/11/2012, 10:45
... 10 11 12 16 20 21 21 22 23 23 RATE-DISTORTION ANALYSIS FOR SCALABLE CODERS 25 A Motivation B Preliminaries ... 66 19 22 26 27 28 xiv FIGURE 29 Page Comparison between the logarithmic model (3.58) and other models in FGS-coded (a) CIF Foreman and (b) CIF Carphone, in terms of the average absolute ... (a) The ACF of {εI (n)} and that of {φI (n)} in Star Wars IV (b) The ACF of {εP (n)} and that of {φP (n)} in The Silence of 1 the Lambs 125 63 The ACF of {A3 (ε)}...
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