law and order svu closure part 2 recap

Tài liệu RESEARCH AND WRITING SKILLS SUCCESS PART 2 ppt

Ngày tải lên : 24/12/2013, 14:16

... in just 20 short lessons of 20 minutes a day by using basic research and writing tools that you can practice at home. Each lesson is carefully designed to make researching any topic and writing ... Bibliography 95 LESSON 20 Writing an Annotated Bibliography, a Historiography, and an Abstract 99 POST-TEST 105 APPENDIX A A List of Research Topics 119 APPENDIX B Additional Resources 123 viii T his ... & WRITING SKILLS SUCCESS IN 20 MINUTES A DAY LESSON 16 Revising Your Draft 77 LESSON 17 Proofreading and Editing Your Draft 81 LESSON 18 Adding Footnotes, Endnotes, and Parenthetical Citations...

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Power Quality Harmonics Analysis and Real Measurements Data Part 2 docx

Ngày tải lên : 19/06/2014, 08:20

... and  ’s. By using the first two terms in the Taylor series expansion A i e  it ; i = 1 ,2. Equation (22 ) turns out to be                   11 111 22 2 22 2 22 2 22 2 cos ...   2 2 (23 ) where the Taylor series expansion is given by: 1 t et     Making the following substitutions in equation (23 ), equation (26 ) can be obtained, 11 21 1 32 2 422 2 52 2 622 ... equation (21 ) are considered, then the error e(t) can be written as (21 )       12 1 122 2 cos cos tt et Ae wt Ae wt    (21 ) Using the well-known trigonometric identity   22 2 2 2 2 cos...

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Convection and Conduction Heat Transfer Part 2 ppt

Ngày tải lên : 19/06/2014, 10:20

... 1 Heater 2 Re = 100, d = 1 t 24 6810 121 4 NU 5 10 15 20 25 30 Heater 1 Heater 2 Re = 1000, d = 1 t 24 6810 121 4 NU 5 10 15 20 25 30 Heater 1 Heater 2 Re = 10, d = 2 t 5101 520 NU 5 10 15 20 25 30 Heater ... 2 t 5101 520 NU 5 10 15 20 25 30 Heater 1 Heater 2 Re = 100, d = 2 t 5101 520 NU 5 10 15 20 25 30 Heater 1 Heater 2 Re = 1000, d = 2 t 5101 520 NU 5 10 15 20 25 30 Heater 1 Heater 2 Re = 10, d = 3 t 5101 520 NU 5 10 15 20 25 30 Heater ... 1 θ 0,00 0,05 0,10 0,15 0 ,20 0 ,25 d = 1 d = 2 d = 3 Re = 100, Gr = 10 5 Heater 2 θ 0,06 0,08 0,10 0, 12 0,14 0,16 0,18 0 ,20 0 ,22 0 ,24 d = 1 d = 2 d = 3 Re = 1000, Gr = 10 5 Heater 2 θ 0,00 0,05 0,10 0,15 0 ,20 0 ,25 d...

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Indoor and Outdoor Air Pollution Part 2 doc

Ngày tải lên : 19/06/2014, 10:20

... radiation and chlorophyll found in trees, plants, and algae. A product of this process is carbohydrates of the form C n H 2n O n . For example, when n=6, glucose is derived: chlorophyll-l 22 6 126 2 6CO ... M. et al 20 02) . Both the inhabited and uninhabited environment is threatened and one such indication is the changes of the climate (Theophanides, T. et al. 20 02) . Furthermore, as of 20 06, the ... al. 20 03; Filleul L, et al 20 03, Basu R. & Samet J. M., 20 02, Le Tertre A. et al. 20 02, Dominici F., 20 02, Sunyer & Basagana 20 01) of occupational diseases on the working population are...

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Current Trends and Challenges in RFID Part 2 pptx

Ngày tải lên : 19/06/2014, 19:20

...  (8) or   42 2 2 210xm x m m    (9) From this equation one can find that: 2 22 22 2 11 22 mm xm m m m          (10) But:  2 2 22 22 2 2 3 33 1 dB dB dB xm ... 23     22 2 42 2 322 21 2 14 2 2 xxmxmxm xxmxmxm     (21 ) One of possible solutions of this equation is x = 0. Other solutions can be obtained from the equation: 22 22 10xm ... ( 12) to zero, one can obtain:     2 222 22 12 1 22 4mm m mm mm m   (13) Squaring both sides of this equation, then:     2 2 122 11mmm mm        (14) And...

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Designing and Deploying RFID Applications Part 2 pdf

Ngày tải lên : 19/06/2014, 19:20

... of 20 00, and the Privacy and Electronic Communications Directive of 20 02 — do apply to the personal data collected by the use of RFID (Slettemeås, 20 09). By establishing and enforcing the laws ... http://www.ciadvertising.org/studies/stdent/98_fall/theory/hornor/paper1.ht ml,[accessed 21 /2/ 2004]. Das R .and Dr. Harrop P. (20 10) ‘Printed and Chipless RFID Forecasts, Technologies & Players 20 09 -20 19’.Obtained through the internet: ... http://www.idtechex.com/research/reports/printed _and_ chipless_rfid_forecasts _technologies _and_ players _20 09 _20 19_00 022 5.asp.[accessed 11March 20 11]. http://www.idtechex.com/research/reports/printed _and_ chipless_rfid_forecasts _technologies _and_ players _20 09 _20 19_00 022 5.asp...

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Artificial Neural Networks Industrial and Control Engineering Applications Part 2 doc

Ngày tải lên : 20/06/2014, 00:20

... respectively 10 .2% and 8.63% for ANN, 20 .4% and 12. 33% for empirical model and 20 .53% and 13.65% for mathematical model. They also predicted bending rigidity of woven fabric by these three models and ANN ... mispicks, pilling, finger marks, and others. 26 Neural-Fuzzy Classification for Fabric Defects Huang and Chen Textile Research Journal 20 01 71(3), 22 0 -22 4. an image classification ... 20 10, 80(10), 981-990. Huang, C.C. and Chen, I.C. Neural-Fuzzy Classification for Fabric Defects. Textile Research Journal, 20 01, 71(3), 22 0 -22 4. Huang, C.C. and Yu, W.H. Fuzzy Neural Network...

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From Turbine to Wind Farms Technical Requirements and Spin-Off Products Part 2 docx

Ngày tải lên : 20/06/2014, 01:20

... 25 4 de fecha 24 Octubre 20 06. • India – ISTS: “Indian Electricity Grid Code (IEGC)”, April, 20 06 and “Draft Report on Indian Wind Grid Code”, July, 20 09. • France: “Décret no 20 08-386 du 23 ... circumstances can generate opposition (see Gross 20 07; Graham et al. 20 09; Jobert et al. 20 09; Jones & Eiser 20 09; Ladenburg 20 09 and Haggett 20 11 for some of the more recent papers on this ... compared to on-land locations (Ek, 20 05; McCartney, 20 05), minimising the visual impacts from offshore wind farms etc. (Ladenburg & Dubgaard, 20 07; Krueger et al., 20 10 and number and size of...

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Self Organizing Maps Applications and Novel Algorithm Design Part 2 pptx

Ngày tải lên : 20/06/2014, 07:20

... 0, 724 57 -0, 724 57 0 ,20 077 -0 ,27 575 -0, 724 57 -0,35355 -1 ,20 760 1 ,20 760 2, 17410 -0,36094 -0, 724 57 -0,35355 0, 724 57 -0, 724 57 -0, 625 26 -0,41751 1 ,20 760 -0,35355 -1 ,20 760 1 ,20 760 -0,7 629 4 -0,35473 ... -0,35473 1 ,20 760 2, 47490 0, 724 57 -0, 724 57 -0, 625 26 -0,16805 -0, 724 57 -0,35355 Fig. 5. Data matrix sample obtained after pre-processing stage 4 .2 The pruning algorithm In terms of partSOM architecture, ... Networks, LNCS, Vol .21 30, pp. 21 7 -22 4, London: Springer-Verlag Du, W. & Atallah, M. (20 01). Secure multi-party computation problems and their applications: A review and open problems, New...

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SELF ORGANIZING MAPS APPLICATIONS AND NOVEL ALGORITHM DESIGNE Part 2 pptx

Ngày tải lên : 21/06/2014, 05:20

... 0, 724 57 -0, 724 57 0 ,20 077 -0 ,27 575 -0, 724 57 -0,35355 -1 ,20 760 1 ,20 760 2, 17410 -0,36094 -0, 724 57 -0,35355 0, 724 57 -0, 724 57 -0, 625 26 -0,41751 1 ,20 760 -0,35355 -1 ,20 760 1 ,20 760 -0,7 629 4 -0,35473 ... -0,35473 1 ,20 760 2, 47490 0, 724 57 -0, 724 57 -0, 625 26 -0,16805 -0, 724 57 -0,35355 Fig. 5. Data matrix sample obtained after pre-processing stage 4 .2 The pruning algorithm In terms of partSOM architecture, ... x’ 1p y’ 11 y’ 1p x’ 21 x’ 2p y’ 21 y’ 2p x’ 31 x’ 3p y’ 31 y’ 3p x’ 41 x’ 4p y’ 41 y’ 4p x’ m1 x’ mp y’ m1 y’ mp x’ 11 x’ 1p y’ 11 y’ 1p x’ 21 x’ 2p y’ 21 y’ 2p x’ 31 x’ 3p y’ 31 ...

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Mobile and wireless communications network layer and circuit level design Part 2 potx

Ngày tải lên : 21/06/2014, 14:20

... will receive its packets (the first one will 2n-1 2n 2n+1 2n +2 Phase I 2n-1 2n 2n+1 2n +2 Phase II re c co u st a se c su b a n ) de Fi g 3. 2 T h h o vi r a w in t w i O t M o R e h o de co n th u th e li m n u di s Fi g ... will receive its packets (the first one will 2n-1 2n 2n+1 2n +2 Phase I 2n-1 2n 2n+1 2n +2 Phase II re c co u st a se c su b a n ) de Fi g 3. 2 T h h o vi r a w in t w i O t M o R e h o de co n th u th e li m n u di s Fi g ... (ElBatt and Ephremides 20 04; Lim, Leong et al. 20 05; Hou, Shi et al. 20 06; Klein and Viswanathan 20 06; Gomez and Campbell 20 07). Among them routing optimization (ElBatt and Ephremides 20 04; Hou,...

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Advances in Optical and Photonic Devices 2011 Part 2 pptx

Ngày tải lên : 21/06/2014, 18:20

... at 6 and 8 μm correspond to the case of 25 6 25 6 hole arrays without implantation (see the arrows 1 and 2) . 0 30 60 90 120 150 180 21 0 24 0 0.06 0.09 0. 12 0.15 0.18 0 .21 0 .24 15 μ m 12 μ m 10 ... emission LED emission 25 A/cm 2 50A/cm 2 100A/cm 2 25A/cm 2 50A/cm 2 100A/cm 2 12- petals, I th =28 uA 11A/cm 2 T=100% Fig. 21 . Various emission patterns of 4-, 8-, 12- petal flower PQRs As mentioned ... al., 20 09). 25 A/cm 2 50A/cm 2 100A/cm 2 T=1.0% T=1.0% T=1.0% T=1.0% T=1.0% T=1.0% T=1.0% T=1.0% T=0.63% Circle 18um, I=15uA PQR emission LED emission 25 A/cm 2 50A/cm 2 100A/cm 2 25A/cm 2 50A/cm 2 100A/cm 2 12- petals,...

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Micro Electronic and Mechanical Systems 2009 Part 2 pot

Ngày tải lên : 21/06/2014, 18:20

... 100 150 20 0 25 0 300 0 50 100 150 20 0 25 0 300 37.3 6. 32 3.16 Conv. (%) WHSV (mol/g-h) 99.6 98.4 72. 0 Reaction time (sec) Temperature ( o C) 0 1 020 30405060 0 50 100 150 20 0 25 0 300 H 2 O 2 reac ... 0.5 g, volume of 2. 7 cc, active area of 4 cm 2 , and power density of 180 mW/cm 2 . Thus 20 W fuel cell would have a mass of 13.89 g (0.5 g × 20 W / (0.18 W/cm 2 × 4 cm 2 )) and a volume of ... expressed below: 22 2 2 2 a(xH O (1-x)H O)) 0.5axO (1 x ax)H O + →+−+ (10) where symbol a and x are the molal ratio of hydrogen peroxide to methanol (H 2 O 2 /CH 3 OH) and the molal concentration...

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Recent Optical and Photonic Technologies 2012 Part 2 pot

Ngày tải lên : 21/06/2014, 19:20

... 1999; Ryu et al., 20 02; Akahane et al., 20 03; Zhang & Qiu, 20 04; Nozaki & Baba, 20 06; Akahane et al., 20 05; Song et al., 20 05; Asano et al., 20 06; Tanaka et al., 20 08) 3. Photonic ... (Noda et al., 20 00; McNab et al., 20 03; Bogaerts et al., 20 04; Notomi et al., 20 04; Noda et al., 20 00; Jiang et al., 20 05; Aoki et al., 20 08), slow light (Vlasov et al., 20 05; Krauss, 20 07; Baba ... Yamilov A., & Bertino, M. (20 07). “Disorder-immune coupled resonator optical waveguide,” Opt. Lett. 32, 28 3 -28 5. Yamilov, A., Herrera, M. R., and Bertino, M. F. (20 08). “Slow light effect in...

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Sensors, Focus on Tactile, Force and Stress Sensors 2011 Part 2 pdf

Ngày tải lên : 21/06/2014, 20:20

... of gravitational torque vector: ( ) ( ) ()() () () 1 2 2 124 134 123 4 1 1 1 2 12 2 22 124 123 4 11 12 12 3 22 123 4 134 4 2 2 123 4 134 124 () g MM g MM g M g M L m scc ccs ss s s L m Lm sc g Lmcsc ... eigenvalues λ 1 and λ 2 of matrix A as real and unequal λ 1 ≠ λ 2 . By using Cayley-Hamilton method for matrix exponential determination, we have: () ()() 21 12 12 2 1 12 12 12 1 TT TT AT d TT ... characteristics and coefficient for the piezoresistance matrix can be simply converted by Euler coordinates into the following equation: ])[( 2 2 2 1 2 1 2 1 2 2 2 144 121 111 nnmmll T ++−−+= πππππ ...