... 0.2 0.7 0.6 0 .5 0.4 0.3 0.2 real model 0.1 0 10 15 20 25 30 Time (ms) 35 40 45 50 mean demerit 20.00ms 10.2ms 40% 25. 35ms mean simulation 20 25 30 Time (ms) 35 40 45 50 8.9ms 35% demerit 22.08±0.08ms ... fixed 20ms fixed 30ms mean 0.6 0 .5 0.4 0.3 0.2 0.6 0 .5 0.4 0.3 0.2 real model 0.1 real model 0.1 0 10 15 20 25 30 Time (ms) 35 40 45 50 10 15 20 25 30 Time (ms) 35 40 45 50 d Final model; includes ... 0.6 0 .5 0.4 0.3 0.2 real model real model 0.1 0 10 15 20 25 30 Time (ms) 35 40 45 50 a Basic model: includes all of the features in the best C2200A model mean 10 15 20 25 30 Time (ms) 35 40 b...
Ngày tải lên: 12/09/2012, 14:16
... beginning to the end (for now) No backing up to read something again (OK to start over) Just as done from the keyboard Writing to a file Sending output to a file Done from beginning to end ... fails, it is generally best to stop the program The function exit, halts a program exit returns its argument to the operating system exit causes program execution to stop exit is NOT a member ... What if the argument for width is too small? Such as specifying cout.width(3); when the value to print is 3 456 . 45 The entire item is always output If too few spaces are specified, as many...
Ngày tải lên: 12/09/2012, 22:49
Introduction to Digital Signal Processing and Filter Design
... −0.2366 −0.1 251 0 .52 23 0.2462 0.38 75 0 .55 40 0 .52 11 0.2 754 0.19 45 0.1687 0.21 75 Quantized Values of f (n) 0.000 −0. 250 −0.1 25 −0.1 25 0.000 0.1 25 0.3 75 0 .50 0 0 .50 0 0. 250 0.1 25 0.1 25 0.1 25 Binary Number ... −0. 054 307 −0. 253 287 −0.236 654 −0.1 251 01 0 .52 2312 0.246210 0.38 750 8 0 .55 4090 0 .52 1112 0.2 754 32 0.19 450 1 0.168887 0.21 758 8 Values of f (n) Truncated to Four Digits −0. 054 3 −0. 253 2 −0.2366 −0.1 251 ... 0. 750 = 0.6 25 = 0 .50 0 = 0.3 75 = 0. 250 = 0.1 25 0.0 = 0.000 8 8 8 000 −0.0 = −0.000 001 − = −0.1 25 010 − = −0. 250 011 − = −0.3 75 100 − = −0 .50 0 101 − = −0.6 25 110 − = −0. 750 111 − = −0.8 75 DISCRETE-TIME...
Ngày tải lên: 13/09/2012, 10:21
Introduction to Wireless Communications
... software that helps identify other Bluetooth devices Bluetooth and Ultra Wide Band (continued) Bluetooth and Ultra Wide Band (continued) • Bluetooth – Distance: up to 33 feet (10 meters) – Bandwidth: ... 150 feet (50 meters) – Bandwidth: 100 Mbps to Gbps • Piconet – Wireless personal area network (WPAN) – Consists of two or more Bluetooth devices that are exchanging data with each other Bluetooth ... of up to 35 miles – Based on the IEEE 802.16 Fixed Broadband Wireless standard – Uses small custom antennas on the roof of each building – Transmission speeds • 75 Mbps at distances of up to miles...
Ngày tải lên: 13/09/2012, 10:52
An Introduction to Software Engineering
... erfall model 25 Specification 50 Design 100 75 Development Integ ration and testing It erative development 25 Specification Component-based software eng 25 Specification 50 ineering 50 75 System development ... particular customer or may be developed for a general market Software products may be • • Generic - developed to be sold to a range of different customers e.g PC software such as Excel or Word Bespoke ... ©Ian Sommerville 2004 75 Iterative development ems 200 30 400 System evolution Software Engineering, 7th edition Chapter Slide 15 Product development costs 25 Specification 50 Development ©Ian Sommerville...
Ngày tải lên: 14/09/2012, 11:26
A simple introduction to working with LVM
... Segments Allocation Read ahead sectors Block device /dev/skx-vol/test skx-vol J5XlaT-e0Zj-4mHz-wtET-P6MQ-wsDV-Lk2o5A read/write available 1.00 GB 256 inherit 254 :0 We see it is 1Gb in size (no ... LV Size Current LE Segments Allocation Read ahead sectors Block device read/write available 2.00 GB 51 2 inherit 254 :0 The important thing to realise is that although the volume has been resized ... Linux lappy 2.6.8-2-686 #1 Sat Jan 16 :50 :08 EST 20 05 i686 Filesystems When it comes to using LVM effectively it is worth considering the filesystem that you wish to use upon your logical volumes If...
Ngày tải lên: 18/09/2012, 10:12
Cambridge.University.Press.An.Introduction.to.Law.and.Regulation.Text.and.Materials.Apr.2007.pdf
... questions 4 .5 Conclusion 151 151 153 1 75 176 181 193 Regulatory accountability and legitimacy 5. 1 Introduction 5. 2 Levels of theorising 5. 3 Regulatory accountability 5. 3.1 Discussion questions 5. 4 Varying ... print format 2007 eBook (EBL) ISBN-13 978-0 -51 1-284 75- 5 ISBN-10 0 -51 1-284 75- 6 eBook (EBL) paperback ISBN-13 978-0 -52 1-6 856 5-8 paperback ISBN-10 0 -52 1-6 856 5-6 Cambridge University Press has no responsibility ... Understanding regulatory instruments 3.2.1 Command 3.2.2 Competition 3.2.3 Consensus 3.2.4 Communication 79 79 80 80 85 92 96 41 42 43 44 47 51 52 53 53 59 69 74 74 75 ix x Contents 3.2 .5 Code 3.2.6...
Ngày tải lên: 21/09/2012, 10:39
Cambridge.University.Press.An.Introduction.to.the.Philosophy.of.Mind.Jan.2000.pdf
... Cape Town 8001, South Africa http://www.cambridge.org © E J Lowe 2004 First published in printed format 2000 ISBN 0 -51 1-04 054 -7 eBook (netLibrary) ISBN 0 -52 1- 652 85- 5 hardback ISBN 0 -52 1- 654 28-9 ... conceptual schemes 69 70 74 79 82 84 89 92 95 99 100 102 103 107 110 112 114 116 119 121 1 25 126 128 130 131 1 35 137 143 1 45 149 155 158 160 162 164 167 169 1 75 178 183 Contents Knowledge of language: ... 2 35 240 243 246 250 252 257 262 264 266 270 277 282 283 288 291 293 296 297 298 313 Preface At a time when many introductory books on the philosophy of mind are available, it would be fair to...
Ngày tải lên: 21/09/2012, 10:39
Cambridge.University.Press.The.Cambridge.Introduction.to.Modern.British.Fiction.1950-2000.Apr.2002.pdf
... feels obliged to take If to permit the expression of humanity is to tolerate the antisocial expression of youth power, this might also be to allow the rapists into your own home, into the writer’s ... The Cambridge Introduction to Modern British Fiction, 1 950 2000 In this introduction to post-war fiction in Britain, Dominic Head shows how the novel yields a special insight into the important ... literary fashion Indeed, Introduction a turn towards the historical novel has been frequently observed in the 1990s, in marked contrast to the gritty working-class realism of the 1 950 s and 1960s The...
Ngày tải lên: 21/09/2012, 11:00
An introduction to franchising
... abilities Total Current Li ilities – Note Long-Term Liab uity Stockholders’ Eq S AND EQUITY TAL LIABILITIE TO THE IFA EDUCATIONAL FOUNDATION $6 ,50 0 1,200 1,800 $9 ,50 0 $12 ,50 0 $20,600 $33,100 An Introduction ... PROFIT (INCOM TAXES (30%) 1 05 $2 45 ET INCOME) NET PROFIT (N ne”) (“The Bottom Li THE IFA EDUCATIONAL FOUNDATION An Introduction To Franchising 25 Things you want to see on a franchisor’s income ... DuPont, operations coordinator Franchising is a wonderful way to go into business for yourself, but not by yourself Franchising is an example of teamwork at its best, bringing together the talents...
Ngày tải lên: 19/10/2012, 15:42
Introduction to fluid mechanics - P1
... origin of the ship is not clear, but it is easy to imagine the course of progress from log to raft, from manual propulsion to sails, and from river to ocean navigation The Phoenicians and Egyptians ... used by a citizen in those days is said to be approximately 180litres Today, the amount of water used per capita per day in an average household is said to be approximately 240 litres Therefore, ... the history of the city water system is very old But in the development process of city water systems, in order to transport water effectively, the shape and size of the water conduit had to be...
Ngày tải lên: 22/10/2012, 10:59
Introduction to fluid mechanics - P2
... io5) Kinematic viscosity, v (m2/s x106) 10 20 30 40 179.2 130.7 100.2 79.7 65. 3 1.792 1.307 1.004 0.801 0. 658 1.724 1.773 1.822 1.869 1.9 15 13.33 14.21 15. 12 16.04 16.98 Stokes’ equation, to ... only too well known There are so many scientific terms named after Newton (Newton's rings and Newton's law of motion/ viscosity/resistance) that he can be regarded as the greatest contributor to ... p (kg/m') Water Air 10 999.8 1.293 999.7 999.1 998.2 1.247 1.226 1.2 05 15 20 100 40 60 80 992.2 1.128 983.2 1.060 971.8 958 .4 1.000 0.9464 Viscosity As shown in Fig 2.1, suppose that liquid fills...
Ngày tải lên: 22/10/2012, 10:59
Introduction to fluid mechanics - P3
... metre Torr Pa bar mH,O atm mHg torr Pa = N/m2 bar = 0.1 MPa mH,O = 806. 65 Pa atm = 101 325Pa mHg = 1/0.76 atm torr = 1mmHg 3.1.2 Absolute pressure and gauge pressure There are two methods used to ... From eqs (3.12)-(3.14) (3. 15) From eqn (3. 15) (3.16) In aeronautics, it has been agreed to make the combined values of po = 101.3 25 kPa, T, = 288. 15 K and po = 1.2 25 kg/m3 the standard atmos- ... Fig 3. 15 Substitute eqn (3.26) into (3. 25) to calculate y, (3.27) Parallel a x b theorem: The moment of inertia with respect to any axis equals the sum of the moment of inertia with respect to the...
Ngày tải lên: 22/10/2012, 10:59
Introduction to fluid mechanics - P4
... we had to trust mainly to Rankine's text books Occasionally in the higher classes he would forget all about having to lecture and after waiting for ten minutes or so, we sent the janitor to tell ... two-dimensional flow where w = V is an operator which represents a a a ax ay az i-+j-+k- where i,j , k are unit vectors on the x, y z axes 50 Fundamentals of flow Fig 4.11 Tornado movement along the flow ... conducted many experiments using glass tubes of 7, 9, 15 and 27 mm diameter and water temperatures from to 44°C discovered that He a laminar flow turns to a turbulent flow when the value of the...
Ngày tải lên: 22/10/2012, 10:59
Introduction to fluid mechanics - P5
... eqn (5. 49) If the relation of eqn (5. 49) is applied to fluid flow, the torque acting on Conservation of angular momentum 77 Fig 5. 22 Ice skater Fig 5. 23 Flow in curved tube supported so as to turn ... - = Mrv (5. 48) r The torque (rotational couple) on this body is given by Torque = change of angular momentum = moment of inertia x angular acceleration (5. 49) This is equivalent to Newton’s second ... shown in Fig 5. 19 Thus (5. 42) ~ Q ( u V I ) = (PI - ~ M Since Q = Alvl = A2u2,from the above equation, p2 - Q u2 - u1 = u2 (u2 - u l ) p1 (5. 43) PS A2 9 Substituting eqn (5. 43) into (5. 41), (VI...
Ngày tải lên: 22/10/2012, 10:59
Introduction to fluid mechanics - P6
... Navier-Stokes equations (6.12) simplify the following equations: Boundary layer 1 05 ( E g) p u-+u- ap ax = +p- a% a$ (6 .55 ) (6 .56 ) The continuity equation is as follows: (6 .57 ) Equations (6 .55 )+6 .57 ) ... a body and turbulent flow Wrote Aerodynamics: Selected Topics in the Lkht of Their Historical Development U + C) - = 5. 751 0g u* 5. 5 (6 .51 ) This equation is considered applicable only in the neighbourhood ... acting on the moving piston? Assume that the kinematic viscosity of oil v = 50 cSt, specific gravity = 0.9, diameter of cylinder d, = 122mm, diameter of piston d2 = 1 25 mm, piston length = 160mm,...
Ngày tải lên: 22/10/2012, 10:59
Introduction to fluid mechanics - P7
... 0.0 45 0.14 0.19 0.21 0 .51 0.03 0.0 45 0.14 0.12 0.1 35 0 .51 R/d= 0.03 0.0 45 0.03 0.0 45 0.08 0.0 85 0.0 85 0.18 0.03 0.0 45 0.07 0.07 0.1 05 0.20 0.08 0.0 95 0.10 0.23 bend In a bend, in addition to the ... Table 7.2 Loss factor for elbows eo 5" 10" 15" 22 .5" 30" 45" 60" 90" 0.016 0.024 0.034 0.044 0.042 0.062 0.066 0.130 0.1 65 0.236 0.320 0.471 0.687 1.129 1.2 65 ~~~ [ Smooth Coarse 0. 154 7.4.4 Pipe ... Needle valve 0.3 1. 35 a = n(dx tan 012 - x2tan20/2) A x = when x = [ = 0 .5 + O.IS(A/a)* Ball valve a N 0. 751 cdx [ = 0 .5 O.l5(A/a)’ Spool valve At full open position [ = 5. 5 + - 7.4.6 Total loss along...
Ngày tải lên: 22/10/2012, 10:59
Introduction to fluid mechanics - P8
... Bending river with large stones and wild grass 0.010-0.013 0.012-0.018 0.013-0.017 0.0 15- 0.01 0.01&0.020 0.017-0.030 0.028-0.0 35 0.0 25- 0.033 0.030-0.040 0.06 0.0 35- 0. 050 0.46 1.30 2.0 It is also ... Consequently, the total head may be described as follows: u2 (8.12) total head = - + h + zo 29 However, the total head relative to the channel bottom is called the specific energy E , which expresses the ... (8. 15) , which makes the specific energy minimum, is obtained from eqn (8.14) (8. 15) At the critical water depth h,, From eqn (8. 15) q2 = ghz hC E, = + h, = l S h , (8.16) The specific energy (total...
Ngày tải lên: 22/10/2012, 10:59
Introduction to fluid mechanics - P9
... part of the disc to f and the resistance acting on it to F, Ff =r- 2zr0b P(row)2 Torque T2 due to this surface friction is as follows: T2 = z f p o r : b Assumingf = (9.27) ,the torque T needed ... 9 .5, where there is left and right symmetry to the centre line at right angles to the flow Consequently the pressure resistance obtained by integrating this pressure distribution turns out to ... 2.4cm/s, Re= 1 95 separation harder to occur Figure 9.8 shows a flow visualisation of the development process from twin vortices to a Kkrman vortex street The Reynolds number Re = 3.8 x lo5 at which...
Ngày tải lên: 22/10/2012, 10:59