Ngày tải lên :
13/02/2014, 04:20
... Let
x
0
= (1, 1, 1, 1, 0, 0
, 1
, 1, 1, 1, 1, 0, 0
, 1
)
x
1
= (1, 1, 1, 1, 1, 0, 0
, 1
, 1, 1, 1, 1, 0, 0
, 1
, )
x
2
= (1, 1, 1, 1, 1, 1, 0, 0
, 1
, 1, 1, 1, 1, 0, 0
, 1
, )
x
3
= (1, ... )
x
3
= (1, 1, 0, 1, 1, 1, 1, 0, 0
, 1
, 1, 1, 1, 1, 0, 0
, 1
, )
x
4
= (1, 1, 0, 0, 1, 1, 1, 1, 0, 0
, 1
, 1, 1, 1, 1, 0, 0
, 1
, )
x
5
= (1, 1, 1, 0, 0, 1, 1, 1, 1, 0, 0
, 1
, 1, 1, 1, 1, ... by s = S(x), where
x = (1, 1, 1, 1, 0, 0
, 1
k
1
=6
0, 0, ,0
, 1
k
2
1, 1, 1, 1, 0, 0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 1, 0, 0
, 1
k
3
=18
0, 0, ,0,
, 1
k
4
). (17 )
Note that, for i ∈...