fundamentals of structural analysis

... have a direct bearing on the design of the content of a course in structural analysis: the reduction of credit hours to three required hours in structural analysis in most civil engineering curricula ... four DOFs, since each node has two DOFs and there are two nodes for each member We may also use the way each of the DOF is sequenced to refer to a particular DOF For example, the second DOF of member ... truss is composed of relatively slender members often forming triangular configurations An example of a plane truss used in the roof structure of a house is shown below A roof truss called Fink...

Ngày tải lên: 06/07/2014, 11:20

... are changed by the addition of one more diagonal member (9) Concluding remarks If the number of nodes is N and the number of constrained DOF is C, then (a) the number of simultaneous equations ... determined The resulting method of analysis is simple and straightforward and is very easy to be implemented into a computer program As a matter of fact, virtually all structural analysis computer packages ... Truss Analysis: Matrix Displacement Method by S T Mau Kinematic instability resulting from insufficient number of supports or members Problem 4: Discuss the kinematic stability of each of the...

Ngày tải lên: 06/07/2014, 11:20

... have a direct bearing on the design of the content of a course in structural analysis: the reduction of credit hours to three required hours in structural analysis in most civil engineering curricula ... four DOFs, since each node has two DOFs and there are two nodes for each member We may also use the way each of the DOF is sequenced to refer to a particular DOF For example, the second DOF of member ... truss is composed of relatively slender members often forming triangular configurations An example of a plane truss used in the roof structure of a house is shown below A roof truss called Fink...

Ngày tải lên: 05/08/2014, 09:20

... have a direct bearing on the design of the content of a course in structural analysis: the reduction of credit hours to three required hours in structural analysis in most civil engineering curricula ... four DOFs, since each node has two DOFs and there are two nodes for each member We may also use the way each of the DOF is sequenced to refer to a particular DOF For example, the second DOF of member ... truss is composed of relatively slender members often forming triangular configurations An example of a plane truss used in the roof structure of a house is shown below A roof truss called Fink...

Ngày tải lên: 05/08/2014, 09:20

... are changed by the addition of one more diagonal member (9) Concluding remarks If the number of nodes is N and the number of constrained DOF is C, then (a) the number of simultaneous equations ... determined The resulting method of analysis is simple and straightforward and is very easy to be implemented into a computer program As a matter of fact, virtually all structural analysis computer packages ... given at the beginning of this section is obtained For example, the unconstrained global stiffness matrix component k34 is the superposition of (k34)1 of member and (k12)2 of member Note that the...

Ngày tải lên: 05/08/2014, 09:20

... direction of the FBD to the left or right of the cut 52 Truss Analysis: Force Method, Part I by S T Mau (2) Method of joint 16 kN Joints used to solve for vertical web member forces At each of the ... often leads to mistakes Example Find the member forces in bars 4, 5, 6, and of the loaded Fink truss shown 10 3 10 kN 3@2m=6m Fink truss to be solved by the method of joint 39 2m 11 1 Truss Analysis: ... the accuracy of the computation We need not use these three joint equations because we have already used three equations from the equilibrium of the whole structure at the beginning of the solution...

Ngày tải lên: 05/08/2014, 09:20

... direction of the FBD to the left or right of the cut 52 Truss Analysis: Force Method, Part I by S T Mau (2) Method of joint 16 kN Joints used to solve for vertical web member forces At each of the ... often leads to mistakes Example Find the member forces in bars 4, 5, 6, and of the loaded Fink truss shown 10 3 10 kN 3@2m=6m Fink truss to be solved by the method of joint 39 2m 11 1 Truss Analysis: ... the accuracy of the computation We need not use these three joint equations because we have already used three equations from the equilibrium of the whole structure at the beginning of the solution...

Ngày tải lên: 05/08/2014, 09:20

... Truss Analysis: Force Method, Part I by S T Mau Matrix Method of Joint The development of the method of joint and the method of section pre-dates the advent of electronic computer ... deflection is the result of displacements of some or all of the truss nodes and nodal displacements are caused by the change of length of one or more members 2 3 Elongation of member induces nodal ... displacement method of analysis Since we are developing the force method of analysis herein, we shall not explore the application of this principle further at this point (3) Principle of Virtual Force...

Ngày tải lên: 05/08/2014, 09:20

... Truss Analysis: Force Method, Part I by S T Mau Matrix Method of Joint The development of the method of joint and the method of section pre-dates the advent of electronic computer ... deflection is the result of displacements of some or all of the truss nodes and nodal displacements are caused by the change of length of one or more members 2 3 Elongation of member induces nodal ... displacement method of analysis Since we are developing the force method of analysis herein, we shall not explore the application of this principle further at this point (3) Principle of Virtual Force...

Ngày tải lên: 05/08/2014, 09:20

... displacement of node of the loaded truss shown, given E=10 GPa, A=100 cm2 for all bars The magnitude of the pair of loads is 141.4 kN 1 2 3 4m 3@4m=12m Problem 5-2 (3) The lower chord members 1, 2, and of ... a counterclockwise rotation of 9.83mm/4,000mm=0.0025 radian 80 Truss Analysis: Force Method, Part II by S.T.Mau Problem (1) Find the horizontal displacement of node of the loaded truss shown, ... rotation of bar 2, we note that the –9.83 computed represents a relative vertical movement between node and node of 9.83 mm in the opposite direction of what was assumed for the pair of unit loads...

Ngày tải lên: 05/08/2014, 09:20

... displacement of node of the loaded truss shown, given E=10 GPa, A=100 cm2 for all bars The magnitude of the pair of loads is 141.4 kN 1 2 3 4m 3@4m=12m Problem 5-2 (3) The lower chord members 1, 2, and of ... a counterclockwise rotation of 9.83mm/4,000mm=0.0025 radian 80 Truss Analysis: Force Method, Part II by S.T.Mau Problem (1) Find the horizontal displacement of node of the loaded truss shown, ... rotation of bar 2, we note that the –9.83 computed represents a relative vertical movement between node and node of 9.83 mm in the opposite direction of what was assumed for the pair of unit loads...

Ngày tải lên: 05/08/2014, 09:20

... value of the load (4) According to Eq 2, the slope of the moment diagram is equal to the value of the shear, and the integration of the shear function gives the moment diagram 103 Beam and Frame Analysis: ... is an applied load (q≠0), the direction of change of the shear diagram follows the direction of the load and the rate of change is equal to the intensity of the load If a concentrated load is encountered, ... N=2, C=0 M=1, N=2, C=1 R=2 Number of unknowns = 3M+ΣR =8, Number of equations = 3N+ΣC = Indeterminate to the 2nd degree R=1 Number of unknowns = 3M+ΣR =7, Number of equations = 3N+ΣC = Statically...

Ngày tải lên: 05/08/2014, 09:20

... value of the load (4) According to Eq 2, the slope of the moment diagram is equal to the value of the shear, and the integration of the shear function gives the moment diagram 103 Beam and Frame Analysis: ... is an applied load (q≠0), the direction of change of the shear diagram follows the direction of the load and the rate of change is equal to the intensity of the load If a concentrated load is encountered, ... N=2, C=0 M=1, N=2, C=1 R=2 Number of unknowns = 3M+ΣR =8, Number of equations = 3N+ΣC = Indeterminate to the 2nd degree R=1 Number of unknowns = 3M+ΣR =7, Number of equations = 3N+ΣC = Statically...

Ngày tải lên: 05/08/2014, 09:20

... rotation of a section is equal to the rotation of the neutral axis The rate of change of angle of the neutral axis is defined as the curvature The reciprocal of the curvature is called the radius of ... The effect of shear deformation is the distortion of the shape of an element that results in the transverse deflections of a member The effect of flexural deformation is the bending of the element ... length-todepth ratio of a member is greater than ten, as a rule of thumb Consequently, the only effect to be included in the analysis of beam and frame deflection is that of the flexural deformation...

Ngày tải lên: 05/08/2014, 09:20

... Frame Analysis: Force Method, Part III Statically Indeterminate Beams and Frames When the number of force unknowns exceeds that of independent equilibrium equations, the force method of analysis ... and the method of solution is called the method of consistent deformations The procedures of the method of consistent deformations are outlined below (1) Determine the degree(s) of redundancy, ... combination of ∆b’ and Rbδbb is based on the concept of superposition, which states that the displacement of a linear structure due to two loads is the superposition of the displacement due to each of...

Ngày tải lên: 05/08/2014, 09:20

... Frame Analysis: Force Method, Part III by S T Mau The basic concept of the approximate methods is to assume the location of zero internal moments At the point of zero moment, the conditions of construction ... see from the previous examples, the force method of analysis for frames is practical for hand calculation only for cases of one to two degrees of redundancy Although we can computerize the process ... the formulation of the compatibility equation of the rigid frame shown EI is constant for all members P L L A rigid frame with three degrees of redundancy 166 Beam and Frame Analysis: Force Method,...

Ngày tải lên: 05/08/2014, 09:20

... are more than one DOF The above procedures for one DOF problem can still apply if we consider one DOF at a time That is to say that when we concentrate on one DOF, the other DOFs are considered ... Because of symmetry/anti-symmetry, we need to deal with only half of the span The other half is a mirror image of the first half in the case of symmetry and an upside down mirror image in the case of ... with a single degree of freedom (SDOF) Example Find all the member-end moments of the beam shown EI is constant for all members 30 kN-m a c b 5m 10 m Beam problem with a SDOF Solution (1) Preparation...

Ngày tải lên: 05/08/2014, 09:20

... are more than one DOF The above procedures for one DOF problem can still apply if we consider one DOF at a time That is to say that when we concentrate on one DOF, the other DOFs are considered ... Because of symmetry/anti-symmetry, we need to deal with only half of the span The other half is a mirror image of the first half in the case of symmetry and an upside down mirror image in the case of ... with a single degree of freedom (SDOF) Example Find all the member-end moments of the beam shown EI is constant for all members 30 kN-m a c b 5m 10 m Beam problem with a SDOF Solution (1) Preparation...

Ngày tải lên: 05/08/2014, 09:20

... basic unknown of the problem We seek to express the moment equilibrium condition at node b in terms of θb This is achieved in two steps: express moment equilibrium of node b in terms of member-end ... (7) Identify nodal rotations as degrees -of- freedom (DOFs) Identify nodal equilibrium in terms of member-end moments Express member-end moments in term of nodal rotation Solve for nodal rotation ... moments of the beam shown EI is constant for al members 30 kN-m a c b 5m 10 m Beam problem with a SDOF Solution We observe that there is only one DOF, the rotation at b: θb The equation of equilibrium...

Ngày tải lên: 05/08/2014, 09:20

... basic unknown of the problem We seek to express the moment equilibrium condition at node b in terms of θb This is achieved in two steps: express moment equilibrium of node b in terms of member-end ... (7) Identify nodal rotations as degrees -of- freedom (DOFs) Identify nodal equilibrium in terms of member-end moments Express member-end moments in term of nodal rotation Solve for nodal rotation ... moments of the beam shown EI is constant for al members 30 kN-m a c b 5m 10 m Beam problem with a SDOF Solution We observe that there is only one DOF, the rotation at b: θb The equation of equilibrium...

Ngày tải lên: 05/08/2014, 09:20