fundamentals of electric circuits solutions manual chapter 9

Solution manual for fundamentals of electric circuits 3rd edition

Solution manual for fundamentals of electric circuits 3rd edition

... https://testbankgo.eu/p/ Chapter 2, Problem For the network graph in Fig 2. 69, find the number of nodes, branches, and loops Chapter 2, Solution n = 9; l = 7; b = n + l – = 15 Chapter 2, Problem In ... determine the number of branches and nodes Chapter 2, Solution n = 12; l = 8; b = n + l –1 = 19 Chapter 2, Problem Determine the number of branches and nodes in the circuit of Fig 2.71 1Ω 12 V ... of a lightbulb rated 60 W, 120 V Chapter 2, Solution p = v2/R → R = v2/p = 14400/60 = 240 ohms Chapter 2, Problem A bar of silicon is cm long with a circular cross section If the resistance of

Ngày tải lên: 26/03/2019, 11:40

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Lecture Fundamentals of business law (7/e): Chapter 9 - M.L Barron

Lecture Fundamentals of business law (7/e): Chapter 9 - M.L Barron

... Discharge of contract— frustration Frustration (i.e impossibility of performance of a contract through no fault of either party) Destruction of subject matter Failure of event to take place Contract of ... Barron, Fundamentals of Business Law 7Rev •2-27 The Franchising Code of Conduct • • • • • • • Disclosure document Cooling-off period Copy of lease Association of franchisees Prohibition of general ... accompany Barron, Fundamentals of Business Law 7Rev 2-1 CONTRACT LAW CHAPTER Copyright â 2014 McGraw-Hill Education (Australia) Pty Ltd PPTs to accompany Barron, Fundamentals of Business Law 7Rev

Ngày tải lên: 02/02/2020, 05:52

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Lecture Fundamentals of operations management (4/e): Chapter 9 - Davis, Aquilano, Chase

Lecture Fundamentals of operations management (4/e): Chapter 9 - Davis, Aquilano, Chase

... Taguchi’s View? ?of? ?the Cost? ?of? ?Variability Taguchi’s View? ?of? ?the Cost? ?of? ?Variability Fundamentals? ?of? ?Operations  Management 4e  © The McGraw­Hill  Companies, Inc., 2003 Exhibit S6.26 S6–48 Fundamentals? ?of? ?Operations  ... Pareto Chart? ?of? ?Factors in an Emergency Room Fundamentals? ?of? ?Operations  Management 4e  © The McGraw­Hill  Companies, Inc., 2003 Exhibit S6.5 S6? ?9 Scatterplot? ?of? ?Customer Satisfaction and  Scatterplot? ?of? ?Customer Satisfaction and  ... Involvement (Homewood, IL: Dow Jones-Irwin, 198 7), p 66 By permission of The McGraw-Hill Companies The Goal? ?of? ?Six Sigma The Goal? ?of? ?Six Sigma Fundamentals? ?of? ?Operations  Management 4e  © The McGraw­Hill 

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fundamentals of heat and mass transfer solutions manual phần 9 ppt

fundamentals of heat and mass transfer solutions manual phần 9 ppt

... J2481450W/m 293 1W/m. =+= Hence 2 2 er 293 1W/m I933W/msr srπ + ==⋅ and ( ) 24268 sd q933W/msr10m0.86610sr8.0810W. −−− − =⋅×=× < PROBLEM 12.81 KNOWN: Small, diffuse, gray block with ε = 0 .92 at 35°C ... in terms of the target... range of the copper property table 1200 1100 Temperature, T(K) 1000 90 0 800 700 600 500 400 300 0 10 20 30 40 50 60 Time, t(s) The rate of change of the rod ... 12 .92 KNOWN: Temperatures of furnace wall and top and bottom surfaces of a planar sample Dimensions and emissivity of sample FIND: (a) Sample thermal conductivity, (b) Validity of

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Solution   fundamentals of corporate finance brealy  4th chapter text solutions   ch 11

Solution fundamentals of corporate finance brealy 4th chapter text solutions ch 11

... the value of ChemCo, for a total of $1, 091 .837 million Weight for ChemCo division = = = 084 = 8.4% Weight for original BigCo = = = 91 6 = 91 .6% New beta of BigCo = 084 × 1.4 + 91 6 × = 94 2 As expected, ... “fair” 9. 25%: = 092 5 = 9. 25% 17 a The expected return of the portfolio is the weighted average of the returns on the TSX and T-bills Similarly, the beta of the portfolio is a weighted average of ... Division B, with a required rate of return of 14.3%, has an expected return of 13% Likewise, Division C has a required rate of return of 6. 89% but its expected rate of return is 6% This means Divisions

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Solution   fundamentals of corporate finance brealy  4th chapter text solutions ch 12

Solution fundamentals of corporate finance brealy 4th chapter text solutions ch 12

... + 95 basis points Required rate of return on 10-year Gov't debt = (1 + 04/2) - =.0404 rB = 0404 + 0 095 = 0.0 499 = 4 .99 % 6-month required rate of return = (1.0 499 )1/2 - = 0246 Face value = 1000 ... Debt $ 21, 690 ,000 126 Before-tax Required Rate of Return 4 .99 % Equity Total $150,000,000 $171, 690 ,000 874 10.3% b After-tax Required Rate of Return Weight × After-tax Return (1-.35)×4 .99 % = 3.24% ... has a yield to maturity of 10% and sells for 93 .86% of face value: n = 10, i = 10%, PMT = 90 , FV = 1000, compute PV = $93 8.55 The market value of the issue is therefore 93 86  $20 million = $18.77

Ngày tải lên: 04/10/2018, 09:03

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Solution   fundamentals of corporate finance brealy  4th chapter text solutions ch 13

Solution fundamentals of corporate finance brealy 4th chapter text solutions ch 13

... = 0.085 2002 - 0 .94 1/13.65 = 0.0 69 2001 - 2. 199 /12.06 = 0.182 Long term debt-to-equity (market value) 2003 - 1.754/ 39. 47= 0.04 2002 - 0 .94 1/24 .95 =0.04 2001 - 2. 199 /24 .94 =0. 09 Note: • Monthly ... 2005 • Book value of common equity 2004 – $ 16.781 billion (2004 Annual ReportBalance Sheet) • Common shares outstanding for 2003 – 92 3 ,98 8,818 and 2004 -92 5 ,93 5,682 (Note 21 of the 2004 Annual ... present value of the net investment cost PV of net savings over years PV of net investment cost NPV of bond refunding $28,648,1 19 - 15 ,97 8,845 $12,6 69, 274 Since the NPV is positive, Universal

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Solution   fundamentals of corporate finance brealy  4th chapter text solutions ch 5

Solution fundamentals of corporate finance brealy 4th chapter text solutions ch 5

... will be $ 490 . 09 (On your calculator, input n = 29, PMT = 40, FV = 1000, and i = 9% .) The rate of return is therefore [40 + ( 490 . 09 – 5 49. 69) ]/5 49. 69 = –.0357 = –3.57% 25 a Annual coupon = 08 × ... Price of bond today = 40 × PVIFA(5%, 3) + 50 × PVIFA(5%,3) × PVIF(5%,3) + 60 × PVIFA(5%,3)×PVIF(5%,6) + 1000 × PVIF(5%, 9) = 108 .93 + 117.62 + 121 .93 + 644.61 = $99 3. 09 31 a., b Price of each ... 7%, the 3% coupon bond's price falls from $94 5 to $92 7.68, a -1.8328% decrease (= (92 7.68 - 94 5) /94 5) The otherwise identical 6% bonds price falls to 98 1 .92 (= 60 × annuity factor(7%, 2) + 1000/(1

Ngày tải lên: 04/10/2018, 09:03

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Solution   fundamentals of corporate finance brealy  4th chapter text solutions ch 6

Solution fundamentals of corporate finance brealy 4th chapter text solutions ch 6

... 20.8] = $31.37 Rate of return if R&D is successful = - = 1.031 = 103.1% Rate of return if R&D is unsuccessful = - = -0. 299 = - 29. 9% Expected rate of return = × 1.031 + × (-. 299 ) = 10 = 10% 55 The ... 3.16 09 DIV15 = (1.05) × DIV14 = 1.05 × 3.16 09 = 3.3 190 Present value of Year 15 and on dividends at the end of Year 14 = = = 47.41 Present value of Year 15 and on dividends today = = × 47.41 = 9. 70 ... million The value of the firm as of today, the end of 20 09, is the present value of this amount Remember, there will be no dividend flows in the years leading up to 2014 Value20 09 = = $153.70 million

Ngày tải lên: 04/10/2018, 09:03

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Solution   fundamentals of corporate finance brealy  4th chapter text solutions ch 10

Solution fundamentals of corporate finance brealy 4th chapter text solutions ch 10

... 552 ,95 0 -3.23% 96 .77 -3.23% -0.24% 540,300 -2. 29% 94 .56 -2. 29% 1.06% 536 ,90 0 -0.63% 93 .96 -0.63% 3.38% 552,050 2.82% 96 .61 2.82% -2 .93 % 546,550 -1.00% 95 .65 -1.00% -0 .93 % 553 ,90 0 1.34% 96 .94 1.34% ... -0.0 893 -0. 098 0 -0. 097 8 -0.0843 0. 092 1 0. 096 4 0. 098 9 -0. 090 0 -0.1008 -0.0841 -0.0408 0. 095 7 0. 097 1 0. 097 3 -0.0323 -0.1000 0.1007 0. 097 6 0.1000 0. 096 0 -0. 096 8 -0. 096 9 -0. 096 0 0.0000 0.0000 0.0000 ... rate of return Standard deviation of return Tonsil Weekly Rates of Return on Stocks Prochnik Krosno Exbud Kable Average -0.1000 -0. 098 0 -0. 094 2 -0. 096 0 -0.0088 0. 098 2 0. 097 6 -0. 096 3 -0.0 893 -0. 098 0

Ngày tải lên: 04/10/2018, 09:03

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Solution   fundamentals of corporate finance brealy  4th chapter text solutions   ch 11

Solution fundamentals of corporate finance brealy 4th chapter text solutions ch 11

... the value of ChemCo, for a total of $1, 091 .837 million Weight for ChemCo division = = = 084 = 8.4% Weight for original BigCo = = = 91 6 = 91 .6% New beta of BigCo = 084 × 1.4 + 91 6 × = 94 2 As expected, ... “fair” 9. 25%: = 092 5 = 9. 25% 17 a The expected return of the portfolio is the weighted average of the returns on the TSX and T-bills Similarly, the beta of the portfolio is a weighted average of ... Division B, with a required rate of return of 14.3%, has an expected return of 13% Likewise, Division C has a required rate of return of 6. 89% but its expected rate of return is 6% This means Divisions

Ngày tải lên: 14/12/2018, 14:21

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Solution   fundamentals of corporate finance brealy  4th chapter text solutions ch 12

Solution fundamentals of corporate finance brealy 4th chapter text solutions ch 12

... + 95 basis points Required rate of return on 10-year Gov't debt = (1 + 04/2) - =.0404 rB = 0404 + 0 095 = 0.0 499 = 4 .99 % 6-month required rate of return = (1.0 499 )1/2 - = 0246 Face value = 1000 ... Debt $ 21, 690 ,000 126 Before-tax Required Rate of Return 4 .99 % Equity Total $150,000,000 $171, 690 ,000 874 10.3% b After-tax Required Rate of Return Weight × After-tax Return (1-.35)×4 .99 % = 3.24% ... has a yield to maturity of 10% and sells for 93 .86% of face value: n = 10, i = 10%, PMT = 90 , FV = 1000, compute PV = $93 8.55 The market value of the issue is therefore 93 86  $20 million = $18.77

Ngày tải lên: 14/12/2018, 14:21

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Solution   fundamentals of corporate finance brealy  4th chapter text solutions ch 13

Solution fundamentals of corporate finance brealy 4th chapter text solutions ch 13

... = 0.085 2002 - 0 .94 1/13.65 = 0.0 69 2001 - 2. 199 /12.06 = 0.182 Long term debt-to-equity (market value) 2003 - 1.754/ 39. 47= 0.04 2002 - 0 .94 1/24 .95 =0.04 2001 - 2. 199 /24 .94 =0. 09 Note: • Monthly ... 2005 • Book value of common equity 2004 – $ 16.781 billion (2004 Annual ReportBalance Sheet) • Common shares outstanding for 2003 – 92 3 ,98 8,818 and 2004 -92 5 ,93 5,682 (Note 21 of the 2004 Annual ... present value of the net investment cost PV of net savings over years PV of net investment cost NPV of bond refunding $28,648,1 19 - 15 ,97 8,845 $12,6 69, 274 Since the NPV is positive, Universal

Ngày tải lên: 14/12/2018, 14:21

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Solution   fundamentals of corporate finance brealy  4th chapter text solutions ch 5

Solution fundamentals of corporate finance brealy 4th chapter text solutions ch 5

... will be $ 490 . 09 (On your calculator, input n = 29, PMT = 40, FV = 1000, and i = 9% .) The rate of return is therefore [40 + ( 490 . 09 – 5 49. 69) ]/5 49. 69 = –.0357 = –3.57% 25 a Annual coupon = 08 × ... Price of bond today = 40 × PVIFA(5%, 3) + 50 × PVIFA(5%,3) × PVIF(5%,3) + 60 × PVIFA(5%,3)×PVIF(5%,6) + 1000 × PVIF(5%, 9) = 108 .93 + 117.62 + 121 .93 + 644.61 = $99 3. 09 31 a., b Price of each ... 7%, the 3% coupon bond's price falls from $94 5 to $92 7.68, a -1.8328% decrease (= (92 7.68 - 94 5) /94 5) The otherwise identical 6% bonds price falls to 98 1 .92 (= 60 × annuity factor(7%, 2) + 1000/(1

Ngày tải lên: 14/12/2018, 14:21

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Solution   fundamentals of corporate finance brealy  4th chapter text solutions ch 6

Solution fundamentals of corporate finance brealy 4th chapter text solutions ch 6

... 20.8] = $31.37 Rate of return if R&D is successful = - = 1.031 = 103.1% Rate of return if R&D is unsuccessful = - = -0. 299 = - 29. 9% Expected rate of return = × 1.031 + × (-. 299 ) = 10 = 10% 55 The ... 3.16 09 DIV15 = (1.05) × DIV14 = 1.05 × 3.16 09 = 3.3 190 Present value of Year 15 and on dividends at the end of Year 14 = = = 47.41 Present value of Year 15 and on dividends today = = × 47.41 = 9. 70 ... million The value of the firm as of today, the end of 20 09, is the present value of this amount Remember, there will be no dividend flows in the years leading up to 2014 Value20 09 = = $153.70 million

Ngày tải lên: 14/12/2018, 14:21

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Solution   fundamentals of corporate finance brealy  4th chapter text solutions ch 10

Solution fundamentals of corporate finance brealy 4th chapter text solutions ch 10

... 552 ,95 0 -3.23% 96 .77 -3.23% -0.24% 540,300 -2. 29% 94 .56 -2. 29% 1.06% 536 ,90 0 -0.63% 93 .96 -0.63% 3.38% 552,050 2.82% 96 .61 2.82% -2 .93 % 546,550 -1.00% 95 .65 -1.00% -0 .93 % 553 ,90 0 1.34% 96 .94 1.34% ... -0.0 893 -0. 098 0 -0. 097 8 -0.0843 0. 092 1 0. 096 4 0. 098 9 -0. 090 0 -0.1008 -0.0841 -0.0408 0. 095 7 0. 097 1 0. 097 3 -0.0323 -0.1000 0.1007 0. 097 6 0.1000 0. 096 0 -0. 096 8 -0. 096 9 -0. 096 0 0.0000 0.0000 0.0000 ... rate of return Standard deviation of return Tonsil Weekly Rates of Return on Stocks Prochnik Krosno Exbud Kable Average -0.1000 -0. 098 0 -0. 094 2 -0. 096 0 -0.0088 0. 098 2 0. 097 6 -0. 096 3 -0.0 893 -0. 098 0

Ngày tải lên: 14/12/2018, 14:21

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fundamentals of electric circuits

fundamentals of electric circuits

... 190 Problems 191 Comprehensive Problems 200 Contents xi Chapter 2 Basic Laws 27 Chapter 3 Methods of Analysis 75 PART 1 DC CIRCUITS 1 Chapter 1 Basic Concepts 3 Chapter 4 Circuit Theorems 1 19 Chapter ... Odd-Numbered Problems 893 Selected Bibliography 92 9 Index 93 3 xiv CONTENTS Chapter 16 The Fourier Series 707 Chapter 17 Fourier Transform 7 59 Chapter 18 Two-Port Networks 795 | | | | ▲ ▲ e-Text ... Menu Textbook Table of Contents Problem Solving Workbook Contents 1 DC CIRCUITS PART 1 Chapter 1 Basic Concepts Chapter 2 Basic Laws Chapter 3 Methods of Analysis Chapter 4 Circuit Theorems Chapter 5 Operational...

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FUNDAMENTALS OF ELECTRIC DRIVERS doc

FUNDAMENTALS OF ELECTRIC DRIVERS doc

... reserved. Any use is subject to the Terms of Use as given at the website. FUNDAMENTALS OF ELECTRIC SYSTEMS FUNDAMENTALS OF ELECTRIC SYSTEMS 1 .9 FIGURE 1 .9 Iron filings around a wire carrying a ... 2.15 55,000 80 10.7 Supermendur 49% Co, V 2.4 15 ,90 0 80,000 8 26 Vanadium Permendur 49% Co, V 2.3 12,700 4 ,90 0 92 40 93 2 Hyperco 27 27% Co 2.36 70,000 2,800 198 19 925 Flake iron Carbonal power ... subject to the Terms of Use as given at the website. FUNDAMENTALS OF ELECTRIC SYSTEMS FUNDAMENTALS OF ELECTRIC SYSTEMS CAPACITORS Figure 1.1 illustrates a capacitor. It consists of two insulated...

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Fundamentals of Corporate Finance 8th edition: Solutions Manual

Fundamentals of Corporate Finance 8th edition: Solutions Manual

... = .5 294 Now we can use the sustainable growth rate equation to get: Sustainable growth rate = (ROE ì b) / [1 (ROE ì b)] Sustainable growth rate = [.1 899 (.5 294 )] / [1 – .1 899 (.5 294 )] ... $10,157 / (1 – 0.34) = $15,3 89. 39 Now, we can add interest to EBT to get EBIT as follows: EBIT = EBT + Interest paid = $15,3 89. 39 + 3,405 = $18, 794 . 39 CHAPTER 4 B-35 10. Below is ... $41,7 69 + 85,000 = $126,7 69 Now we can calculate Tobin’s Q, which is: Tobin’s Q = (Market value of equity + Book value of debt) / Book value of assets Tobin’s Q = ($860,000 + 126,7 69) ...

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Electric Machinery Fundamentals (Solutions Manual) Part 1 pdf

Electric Machinery Fundamentals (Solutions Manual) Part 1 pdf

... limit of the capability curve would be drawn from an origin of 3 V 2 3 ( ) 1328 V 2 Q =  ⎞ =  =  4810 kVAR S X 1.1 & The radius of the ... generate the power by means of a motor-generator set consisting of a synchronous motor driving a synchronous generator. How many poles should each of the two machines have in ... voltage of 200 V, and the maximum I F is 10 A. The resistance of the field circuit is adjustable over the range from 20 to 200 & . The OCC of this generator...

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