figure 1 33 solution of example 1 8

... RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-5 21- 4 310 8- 5) Copyright (C) 19 88 -19 92 by Cambridge University Press.Programs Copyright (C) 19 88 -19 92 by Numerical Recipes Software Permission ... ART OF SCIENTIFIC COMPUTING (ISBN 0-5 21- 4 310 8- 5) Copyright (C) 19 88 -19 92 by Cambridge University Press.Programs Copyright (C) 19 88 -19 92 by Numerical Recipes Software Permission is granted for internet ... Dongarra, J.J., et al 19 79, LINPACK User’s Guide (Philadelphia: S.I.A.M.) Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-5 21- 4 310 8- 5) Copyright (C) 19 88 -19 92 by Cambridge...

Ngày tải lên: 15/12/2013, 04:15

... t ≤ w1 t ≤ β t , on 0, σ T 3 .14 Using 3 .11 and the fact that w1 is a solution of 3 .12 , we obtain ΔΔ w1 t σ σ g t, w1 t , w0 t w1 0, σ ≥ f t, w1 t , w1 σ t ∈ 0, T , m 1 αi w1 ηi , i 3 .15 Advances ... vn 1 Φxx t, 1 σ β − wn 1 t σ σ wn t − wn 1 t σ σ ≥ fx t, wn 1 xσ t − wn t − d vn 1 Φxx t, 1 σ β − wn 1 t σ σ xn t − wn 1 t ≥ −d vn 1 σ − d1 β − wn 1 t σ xσ t − wn 1 t , t ∈ 0, T , 3.24 10 Advances ... Equations which implies that w1 is a lower solution of the problem 1. 1 Similarly, in view of A1 , 3 .11 , and 3 .15 , we can show that w1 and β are lower and upper solutions of the problem xΔΔ t x t...

Ngày tải lên: 21/06/2014, 16:20

Ngày tải lên: 09/05/2016, 09:04

... 10 6, 10 7: threaded cores; 10 8: spme bushing; 11 1: gear; 11 2: pinion shaft; 11 3, 11 4: threaded bushings; 12 3: yoke; 12 5, 12 6: gear racks; 13 2: baffle; 13 6: bushing; 13 8 : hydraulic cylinder Example ... means of injection molding The special features of this part are the thin wall sections of 0.7 11 111 1, some of which taper down to 0.3 11 111 1 As a result of the very slight Fig Fig I Fig Figures ... bosses in the mold Fig 13 6 \ 10 6 12 5 10 711 4 25 10 8 \ \ \ \ I -90 -L -87 30 A- B C 203 Figures and Single-cavity injection mold for a housing base 4: stripper plate; , 10 , 11 , 12 : ejector plates;...

Ngày tải lên: 29/04/2016, 13:51

... 2. 017 2.090 2.220 1. 674 1. 717 1. 780 1. 7 91 1 .80 6 1. 86 4 1. 911 2. 0 18 2.092 2.220 21. 1 20 .1 18. 7 18 .4 18 .1 17.0 16 .2 - - - d0 (25.4 x 10 -4 mm) settlement EOP δ ti δ pi Coefficient of consolidation ... /min -1/ 2 ) (between any two consecutive points) (%) 15 00 14 51 14 08 13 54 13 04 12 48 11 97 11 43 10 93 - - - 0.274 0.254 0. 284 0.259 0.274 - 0.269 4.55 - - - 15 16 15 04 15 28 15 03 15 21 - 15 14 ... 15 14 0.72 Time (min) 20.25 25 30.25 36 42.25 60 10 0 200 400 14 40 Dial Reading (x 10 -4 in) in = 25.4 mm 10 43 999 956 922 89 2 83 0 765 722 693 642 1. 2 01 1. 313 1. 422 1. 509 1. 585 1. 742 1. 9 08 2. 017 ...

Ngày tải lên: 21/03/2013, 14:09

...  =  b 11  b 21  b 31 b 41   b12  b22  b32 b42    x12  x22  x32 x42  x13  x23  x33 x43  b13  b23  b33 b43  0 0 y 11  y 21 y 31 y 41 0 0 y12 y22 y32 y42 y13 y23 y33 y43  y14 y24 ... C1 · C 1 ·x= b A · C1 · C2 · C 1 · C 1 · x = b (A · C1 · C2 · C3 · · ·) · · · C 1 · C 1 · C 1 ·x= b (1) · · · C 1 · C 1 · C 1 · x = b (2 .1. 7) Sample page from NUMERICAL RECIPES IN C: THE ART OF ... RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-5 21- 4 310 8- 5) Copyright (C) 19 88 -19 92 by Cambridge University Press.Programs Copyright (C) 19 88 -19 92 by Numerical Recipes Software Permission...

Ngày tải lên: 15/12/2013, 04:15

... multiplication of two × matrices, a 11 a 21 a12 a22 · b 11 b 21 b12 b22 = c 11 c 21 c12 c22 (2 .11 .1) Eight, right? Here they are written explicitly: c 11 = a 11 × b 11 + a12 × b 21 c12 = a 11 × b12 + a12 × b22 c 21 = ... of formulas was, in fact, discovered by Strassen [1] The formulas are: Q1 ≡ (a 11 + a22 ) × (b 11 + b22 ) Q2 ≡ (a 21 + a22 ) × b 11 Q3 ≡ a 11 × (b12 − b22 ) Q4 ≡ a22 × (−b 11 + b 21 ) Q5 ≡ (a 11 + a12 ... ≡ (−a 11 + a 21 ) × (b 11 + b12 ) Q7 ≡ (a12 − a22 ) × (b 21 + b22 ) (2 .11 .3) Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-5 21- 4 310 8- 5) Copyright (C) 19 88 -19 92...

Ngày tải lên: 15/12/2013, 04:15

... case of a × matrix A, for example, equation (2.3 .1) would look like this:       11  α 21 α 31 α 41 α22 α32 α42 0 33 α43 11   · 0 α44 12 β22 0 13 β23 33 14 β24  β34 β44 a 11 a =  21 ... xi = βij xj  yi − i = N − 1, N − 2, , βii j=i +1 Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-5 21- 4 310 8- 5) Copyright (C) 19 88 -19 92 by Cambridge University ... SCIENTIFIC COMPUTING (ISBN 0-5 21- 4 310 8- 5) Copyright (C) 19 88 -19 92 by Cambridge University Press.Programs Copyright (C) 19 88 -19 92 by Numerical Recipes Software Permission is granted for internet users...

Ngày tải lên: 24/12/2013, 12:16

... (2.3 .13 ) Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-5 21- 4 310 8- 5) Copyright (C) 19 88 -19 92 by Cambridge University Press.Programs Copyright (C) 19 88 -19 92 by ... (equation 2.3 .11 ) are not stored at all.] In brief, Crout’s method fills in the combined matrix of α’s and β’s,  11  α 21  α 31 α 41 12 β22 α32 α42 13 β23 33 α43  14 β24   β34 β44 (2.3 .14 ) by ... RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-5 21- 4 310 8- 5) Copyright (C) 19 88 -19 92 by Cambridge University Press.Programs Copyright (C) 19 88 -19 92 by Numerical Recipes Software Permission...

Ngày tải lên: 24/12/2013, 12:16

... RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-5 21- 4 310 8- 5) Copyright (C) 19 88 -19 92 by Cambridge University Press.Programs Copyright (C) 19 88 -19 92 by Numerical Recipes Software Permission ... RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-5 21- 4 310 8- 5) Copyright (C) 19 88 -19 92 by Cambridge University Press.Programs Copyright (C) 19 88 -19 92 by Numerical Recipes Software Permission ... RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-5 21- 4 310 8- 5) Copyright (C) 19 88 -19 92 by Cambridge University Press.Programs Copyright (C) 19 88 -19 92 by Numerical Recipes Software Permission...

Ngày tải lên: 24/12/2013, 12:16

... and 2.7.25): R1 = Inverse(a 11 ) R2 = a 21 × R1 R3 = R1 × a12 R4 = a 21 × R3 R5 = R4 − a22 R6 = Inverse(R5 ) c12 = R3 × R6 c 21 = R6 × R2 R7 = R3 × c 21 c 11 = R1 − R7 c22 = −R6 (2 .11 .6) Sample page ... RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-5 21- 4 310 8- 5) Copyright (C) 19 88 -19 92 by Cambridge University Press.Programs Copyright (C) 19 88 -19 92 by Numerical Recipes Software Permission ... 2 .11 Is Matrix Inversion an N Process? 10 3 in terms of which c 11 = Q1 + Q4 − Q5 + Q7 c 21 = Q2 + Q4 (2 .11 .4) c12 = Q3 + Q5 What’s the use of this? There is one fewer...

Ngày tải lên: 24/12/2013, 12:16

... RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-5 21- 4 310 8- 5) Copyright (C) 19 88 -19 92 by Cambridge University Press.Programs Copyright (C) 19 88 -19 92 by Numerical Recipes Software Permission ... ART OF SCIENTIFIC COMPUTING (ISBN 0-5 21- 4 310 8- 5) Copyright (C) 19 88 -19 92 by Cambridge University Press.Programs Copyright (C) 19 88 -19 92 by Numerical Recipes Software Permission is granted for internet ... 1 n≤N (2.6.2) Vjk Vjn = δkn 1 k≤N 1 n≤N (2.6.3) i =1 N j =1 Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-5 21- 4 310 8- 5) Copyright (C) 19 88 -19 92 by Cambridge University...

Ngày tải lên: 24/12/2013, 12:16

... RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-5 21- 4 310 8- 5) Copyright (C) 19 88 -19 92 by Cambridge University Press.Programs Copyright (C) 19 88 -19 92 by Numerical Recipes Software Permission ... RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-5 21- 4 310 8- 5) Copyright (C) 19 88 -19 92 by Cambridge University Press.Programs Copyright (C) 19 88 -19 92 by Numerical Recipes Software Permission ... (2.6 .13 ) Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-5 21- 4 310 8- 5) Copyright (C) 19 88 -19 92 by Cambridge University Press.Programs Copyright (C) 19 88 -19 92 by...

Ngày tải lên: 24/12/2013, 12:16

... v) 1 , and is derived briefly as follows: (A + u ⊗ v) 1 = (1 + A 1 · u ⊗ v) 1 · A 1 = (1 − A 1 · u ⊗ v + A 1 · u ⊗ v · A 1 · u ⊗ v − ) · A 1 = A 1 − A 1 · u ⊗ v · A 1 (1 − λ + λ2 − ) = A 1 ... two arrays of length 11 , as follows 10 11 ija[k] 8 10 11 12 sa[k] 5 x (2.7. 28) Here x is an arbitrary value Notice that, according to the storage rules, the value of N (namely 5) is ija [1] -2, and ... = −(S 1 · R) · (P − Q · S 1 · R) 1 (2.7.24) S = S 1 + (S 1 · R) · (P − Q · S 1 · R) 1 · (Q · S 1 ) or else by the equivalent formulas P = P 1 + (P 1 · Q) · (S − R · P 1 · Q) 1 · (R · P 1 ) Q...

Ngày tải lên: 24/12/2013, 12:16

... (i = 1, , M ) (2 .8 .10 ) j =1 (M ) M (M ) Ri−j xj = yi i = 1, , M (2 .8 .11 ) j =1 becomes M (M +1) Ri−j xj (M +1) + Ri−(M +1) xM +1 = yi i = 1, , M + (2 .8 .12 ) i = 1, , M (2 .8 .13 ) j =1 By ... Gj (M +1) = Hj Gj Hj (M ) − GM +1 HM +1 j (M +1) (M ) − HM +1 GM +1 j (M +1) (M ) (M ) (2 .8. 25) Now, starting with the initial values (1) x1 = y1 /R0 (1) G1 = R 1 /R0 (1) H1 = R1 /R0 (2 .8. 26) ... GM +1 j = xj we can substitute the previous order (M +1) − xj (M +1) (2 .8 . 18 ) xM +1 The result of this operation is (M +1) xM +1 = (M ) M − yM +1 j =1 RM +1 j xj (M ) M RM +1 j GM +1 j − R0 j=1...

Ngày tải lên: 21/01/2014, 18:20

... (i = 1, , M ) (2 .8 .10 ) j =1 (M ) M (M ) Ri−j xj = yi i = 1, , M (2 .8 .11 ) j =1 becomes M (M +1) Ri−j xj (M +1) + Ri−(M +1) xM +1 = yi i = 1, , M + (2 .8 .12 ) i = 1, , M (2 .8 .13 ) j =1 By ... Gj (M +1) = Hj Gj Hj (M ) − GM +1 HM +1 j (M +1) (M ) − HM +1 GM +1 j (M +1) (M ) (M ) (2 .8. 25) Now, starting with the initial values (1) x1 = y1 /R0 (1) G1 = R 1 /R0 (1) H1 = R1 /R0 (2 .8. 26) ... GM +1 j = xj we can substitute the previous order (M +1) − xj (M +1) (2 .8 . 18 ) xM +1 The result of this operation is (M +1) xM +1 = (M ) M − yM +1 j =1 RM +1 j xj (M ) M RM +1 j GM +1 j − R0 j=1...

Ngày tải lên: 21/01/2014, 18:20

... 1. 1 → 1. 2 → 1. 3 → 1. 4 → 1. 5 → 1. 6 → 1. 7 → 1. 8 ↓ §5 .1 → §5.2 → §5.3 → §5.4 ↓ §6 .1 → §6.2 → §6.3 ↓ §7 .1 → §7.2 → §7.3 → §7.4 ↓ 8 .1 → 8. 2 → 8. 3 → 8. 4 → 8. 5 → 8. 6 → 8. 8 ↓ 11 .1 → 11 .2 ... 1. 6 → 1. 7 → 1. 8 ↓ Chapter ↓ Chapter ↓ Chapter ↓ §6 .1 → §6.2 → §6.3 ↓ §7 .1 → §7.2 → §7.3 → §7.4 ↓ 8 .1 → 8. 2 → 8. 3 → 8. 4 → 8. 5 → 8. 6 → 8. 8 ↓ Chapter ↓ Chapter 10 ↓ Chapter 11 ↓ 12 .1 ... 8. 3 → 8. 4 → 8. 5 → 8. 6 → 8. 8 ↓ 11 .1 → 11 .2 → 11 .3 → 11 .4 → 11 .5 ↓ 12 .1 → 12 .2 ↓ 13 .1 → 13 .2 → 13 .3 → 13 .4 → 13 .7 ↓ Chapter 14 ↓ 16 .1 XVI Suggestions for the Reader (ii) Engineers,...

Ngày tải lên: 19/02/2014, 22:20

... similar examples Example (e) is special, i.e., idiomatic The condition (Co) in section 3 .1 holds SUCCESS 0.9 r 15 92 /17 90 0 .8 0.7 2 313 7 • 19 /33 • = • 3 516 7 9 511 62 • 74 /14 8 8/24 10 0 / 16 9 0.6 0.5 ... common 11 no of examples (x 10 0) 21 Figure Success Rate per No of Examples 18 9 4.3.3 S U C C E S S RATE PER DISTANCE (2) Because the current distance calculation is inadequate, dissimilar examples ... BtoA 1/ 27 (E l=timei) [place/ (E2=deno) [in/ t.p B freq BonA t.p freq B in A 313 1/ 24 9/24 AB 9/24 B in A 2/24 A's B 11 24 (E3=soudan) [meetings] Figure Weight of the i-th attribute 18 8 In Figure...

Ngày tải lên: 20/02/2014, 21:20

... a 11 ↔ 12 , so we have b = and e = 12 vertices altitude renum a9 a2 a5 a12 a15 4 a4 a3 a6 a7 a1 a8 a 11 11 a14 11 a17 11 a13 15 a10 16 a16 16 10 11 12 13 14 15 16 17 • An optimal tour from to 12 ... a4 and the sink a 11 for Problem A): vertices altitude a1 a2 a3 a4 a5 a6 a7 a8 a9 a10 16 a 11 11 a12 a13 15 a14 11 a15 a16 16 a17 11 We first renumber the vertices in increasing of altitudes We ... a8 - a14 – a13 - a16 - a10 – a17 - a 11 1 π2 π3 with the optimal function value is fopt = (= t16 – t14) • An optimal tour for Problem B is – – – – – 11 – 13 – 15 – 17 – 16 – 14 – 12 – 10 – –...

Ngày tải lên: 14/03/2014, 13:20

... = 1 n≤ω (k, ω) (5, 6) m, ω (3, 6) 16 − R 6 7 a(n) = 1 1 /6 ,δ = 1 n≤ω 16 16 16 h = Let α = , then ϕ(α) = ϕ ≤ 1 16 1 1 16 1 < 1 16 2 < 1 1 16 = 1 a So ϕ(α) ≤ (¯ − 1) (b − 1) α 2 1+ (13 ) ... York (19 88 ) doi :10 .11 86 /16 87 - 18 47-2 011 -56 Cite this article as: Tang and Liu: Positive periodic solution of higher-order functional difference equation Advances in Difference Equations 2 011 2 011 :56 ... Equations 2 011 , 2 011 :56 http://www.advancesindifferenceequations.com/content/2 011 /1/ 56 Let β = Page of If u Î [δb,b], then u ≥ Furthermore, δ 16 =2 1 16 > 1 16 ψ(β) ≥ − 23 2 1 1 1 1 (14 ) So...

Ngày tải lên: 20/06/2014, 22:20