en 60 601 1 2 1993

... 4.5 .2 How we get rules? 4.5.3 How we check if the rules are OK? 6 /13 /97, 10 :19 AM 70 73 74 78 78 79 81 83 86 90 93 93 96 98 99 10 5 10 7 10 7 10 7 11 2 11 7 12 1 12 4 12 4 12 6 12 9 13 1 13 1 13 2 13 5 13 6 13 6 ... 15 3 15 4 15 4 15 6 15 8 15 9 16 0 16 0 16 0 16 1 16 3 16 6 16 6 16 7 17 1 17 4 17 5 17 6 17 7 18 0 18 0 18 2 18 4 viii CONTENTS Fuzzy system design software tools 6 .1 Fuzzy technology products classification 6 .2 Main ... to implement a fuzzy controller 8.9 How to test a fuzzy controller 8 .10 How to fix a fuzzy controller 8 .11 How to choose a design package 21 9 21 9 21 9 22 0 22 3 22 3 22 5 22 6 22 6 22 7 22 8 22 9 Problems...

Ngày tải lên: 18/04/2014, 12:28

... 0050 00 51 010 0 010 2 010 4 010 6 010 7 unsigned int Temperature ; B7 51 A1 3C 24 02 4F 81 STA $ 51 CMP #$3C BCC $ 010 8 CLRA RTS < < < < < 010 8 B6 51 LDA $ 51 < > 010 A 010 C 010 E 011 0 011 2 011 3 011 5 CMP ... < < < < A1 22 A0 AE 42 AB 81 50 08 3C 0C 07 011 6 A6 FF 011 8 81 #$50 $ 011 6 #$3C #$0C #$07 LDA #$FF RTS 3 2 > > > > > unsigned int Temperature_HOT (unsigned int CRISP) { if ( CRISP < 60) return(0); ... 0 015 0 017 001A 001D 001F 00 21 AE 93 10 AE 94 9C BC AD 9D 94 8E 0 022 98 0 024 8E LD B,#09 X A,[B] LD A,[B] IFGT A,#03B JP 0000D CLRA RET < < < < < < < LD B,#09 < > LD A,[B] IFGT A,#050 JP 00 022 LD...

Ngày tải lên: 08/03/2016, 11:34

... AT 10 3 H1 Fieldbus Segment # JHC /20 01- 04-03 p LT 11 2 LT 11 1 CV -10 1 A/O FT 11 0 SC 11 0 23 SC 11 2 25 IP 10 4B Cooler 21 TT 10 4 TT 10 5 AT 10 6 AT 10 7A AT 10 7B LT 10 8 SC 10 8 22 OPEN DISTRIBUTED AUTOMATION ... AT103 PID AI AIC106 AT106 RATIO AO FRC103 SC103 AI PID AO FT1 02 AY103 FIC1 02 IP1 02 AC 10 6 AIC 10 7 FRC 10 3 FIC 10 2 FT 10 2 SC 10 3 IP 10 2 CV -10 2 A/O AY 10 3 AT 10 3 HS 10 7 AT 10 6 AT 10 7A AT 10 7B Conductivity ... View) H1 Fieldbus Segment # Control Room PC H1 Fieldbus Segment # Green Liquor Storage Re-Burned Purchased Lime Lime DT 10 9 LT 10 1 19 SC 11 1 24 20 IP 10 2 FT 10 2 IP 10 4A Heater AT 10 3 H1 Fieldbus...

Ngày tải lên: 20/08/2012, 11:15

... 11 .00 ZEIT-EINH 24 h 12 .00 V-ANKUNFT 67,8 km/h 13 Audible signals 13 .00 AUDIO LICHT-WARN BLINKER ZS-WARN 14 Self-diagnostics 14 .00 FSP-Einträge 10 15 I/O ports processor 15 .00 PORT 00 010 1 011 1 ... L R S 24 .5 26 .7 50 07 Current display values 07.00 KTMP-MOM 10 4°C 08 Road speed 08.00 V-EFF 12 3 km/h 09 System voltage 09.00 Ub 13 .3 V 10 Not used 11 Units 12 Calculated time of arrival 10 .00 ... 18 .00 Not used Locking 19 .00 LOCK LOCK: ON LOCK 25 20 Fuel consumption correction 20 .00 KORR-VERBR 10 00 1er KORR 10 er KORR 10 0er KORR 21 Reset (software reset) 21 . 00 Reset? 19 Only the main test...

Ngày tải lên: 19/10/2012, 13:50

... 12 7 4 .1 Context 12 8 4 .1. 1 Formal Analysis 12 8 4 .1. 2 Throughput Time 12 9 4 .2 Analysis of Timed Petri Nets 13 0 4 .2 .1 Deterministic Timing 13 1 4 .2. 2 ... .20 8 6 .1. 2 Task Rules 21 2 6 .1. 3 Routing Rules 21 4 6 .1. 4 Allocation Rules 21 7 6 .1. 5 Resource Rules 22 0 6 .1. 6 Rules for External Parties 22 3 6 .1. 7 ... Communication 32 2 .1. 2 Simulation and Analysis 32 2 .1. 3 Costing and Budgeting 33 2 .1. 4 Documentation, Knowledge Management, and Quality 33 2 .1. 5 Enactment 33 2 .1. 6 System...

Ngày tải lên: 21/07/2013, 09:42

... Annotated Bibliography Further Case Studies 27 8 2 81 2 81 28 6 2 91 29 4 29 4 29 6 29 7 29 9 29 9 300 3 02 303 305 307 308 3 12 3 12 314 317 3 21 322 324 324 325 325 330 3 32 334 336 339 TLFeBOOK TLFeBOOK Foreword ... 14 2 14 3 14 5 14 6 14 7 14 8 14 9 15 2 15 3 15 4 15 5 Designing and Operating a Warehouse 15 7 5 .1 157 15 9 16 0 16 1 16 5 16 5 5 .2 5.3 Introduction 5 .1. 1 Internal warehouse structure and operations 5 .1. 2 Storage ... Inventory Policy Multiple Stocking Point Models Slow-Moving Item Models Policy Robustness Questions and Problems Annotated Bibliography 12 3 12 4 12 8 13 0 13 0 13 2 13 2 13 4 13 6 13 6 13 8 14 1 14 1 14 2 14 3...

Ngày tải lên: 16/08/2013, 08:50

... abortions Vet Parasitol 10 9, 20 3 -11 Dubey, J P., J L Carpenter, C A Speer, M J Topper, and A Uggla (19 88) Newly recognized fatal protozoan disease of dogs J Am Vet Med Assoc 19 2, 12 69-85 Esposito, M., ... Leslie, B McEwen, G Cramer, and A S Peregrine (20 02) Neospora caninum serostatus and milk production of Holstein cattle J Am Vet Med Assoc 2 21 , 1 16 0- 4 Huang, C C., L J Ting, J R Shiau, M C Chen, and ... Med 77, 18 6-98 Bjerkas, I., S F Mohn, J Presthus (19 84) Unidentified cyst-forming sporozoon causing encephalomyelitis and myositis in dogs Z Parasitenkd 2, 2 71- 4 Chi, J., J A VanLeeuwen, A Weersink,...

Ngày tải lên: 29/08/2013, 08:14

... tắt Ta dùng chuột để điều chỉnh công tắt SW1, SW2 để xem trạng thái ngỏ vào, ngỏ Như vậy, ngõ (led D3) sáng trạng thái ngõ vào o mức cao (led D1, led D2 sáng) Để kết thúc mô phỏng, ta click chuột ... vào nút Stop Bạn làm tương tự cho loại cổng logic khác, xem trạng thái Ví dụ a1 Sơ đồ mạch: Bật công tắt SW1, SW2 để xem trạng thái logic ngõ vào ngõ ra, ghi kết vào bảng thật sau: SVTH: PHẠM ... mô phỏng, ta click chuột vào nút Play góc dưới, phía bên trái hình: Mạch số dùng để mô cổng AND -2 INPUT với bảng thật sau: SVTH: PHẠM MINH TIẾN - Trang 64 - HƯỚNG DẨN SỬ DỤNG ISIS Phần 4: Mô số...

Ngày tải lên: 29/09/2013, 20:20

... Usage General Procurement PM PM Procurement EVA CPA EVA Finance Procurement General PM EVA CPA General MOD Procurement Procurement General General Finance PM PM General Finance General General General ... different requirements The principles are, however, fundamentally the same Figure 32 .1 354 Stages and sequence Project stage control techniques Figure 32. 2 355 CPM (11 ) Figure 32. 3 Number in parentheses ... Task Cost table, Figure 31. 10, accessed from View – Table – Cost A Task Summary table 348 MS Project 98 Figure 31. 10 Figure 31. 11 349 Project Planning and Control Figure 31. 12 which shows the status...

Ngày tải lên: 17/10/2013, 21:15

... 22 Q 21 Q 11 + 2Q 22 Q 32 Q 22 Q 21 Q 11 − Q 22 Q 21 Q 11 1 1 1 1 1 1 1 Λ 51 = −3Q 22 Q 32 Q 22 Q 32 Q 22 Q 21 Q 11 + 3Q 22 Q 32 Q 22 Q 21 Q 11 1 1 1 1 1 1 1 + Q 22 Q 32 Q 22 Q 32 Q 22 Q 32 Q 22 ... 1 11 = Q 11 1 1 1 Λ 21 = − Q 22 Q 21 Q 11 = − Q 22 Q 21 11 = − Λ 22 Q 21 11 1 1 1 1 1 Λ 31 = Q 22 Q 32 Q 22 Q 21 Q 11 − Q 22 Q 21 Q 11 1 1 1 1 1 1 1 1 1 Λ 41 = − Q 22 Q 32 Q 22 Q 32 ...  21 1 311 1n1 n1 11 1 11 1 411 811 21 1 511  =  (f 811 − f 711 + f1 011 − f3 21 + f 42 + w 311 ) + (f 611 − f 511 + f 21 2 + f 1 12 + w 411 )    (f 811 − f 711 + f1 011 − f3 21 + f 42 + w 311 ) − (f 611 −...

Ngày tải lên: 18/10/2013, 09:15

... 10 -2 -2 0 .1 0 .1 1.0 1. 0 10 2 10 10 2 10 3 10 2 10 10 3 10 3 Gas Flow Units 10 4 10 4 10 5 cc/min 004 0.04 10 -6 10 -6 0.4 10 -5 10 -5 3.8 10 -4 10 -4 10 -3 38 10 -3 379 10 -2 10 -2 0 .1 0 .1 1.0 1. 0 10 10 10 2 10 3 ... SENSOR FLOW RANGE” 0 .1 1.0 10 2 10 10 3 10 4kgm/hr 20 /5 0 .1 1.0 10 2 10 10 3 10 4 10 5 10 6 Solids Flow Units cc/min 0.05 0.3 10 10 -6 2. 8 -6 10 10 -5 Sm3/hr or Am3/hr 28 .3 -5 10 10 -4 -4 10 10 -3 -3 10 10 -2 ... URV 2- 4% URV 2- 4% URV ±0.5 -1% of rate ±0.5-5% URV ±0.5 -2% URV 1- 2% URV 1. 25 % URV ±3-5% URV 1- 2% URV ±5 -10 % URV 1% of rate R > 10 ,000 D RD > 10 ,000 RD > 10 ,000 RD > 500 RD > 10 ,000 RD > 10 ,000...

Ngày tải lên: 20/10/2013, 01:15

... position 10 4 10 5 10 6 10 6 10 7 10 7 10 8 10 8 10 9 10 9 10 9 11 0 11 0 11 0 11 1 11 1 11 1 11 1 11 2 11 2 11 2 11 3 11 4 11 4 11 5 11 6 11 6 11 6 11 7 11 9 12 1 12 1 12 2 12 2 12 3 12 3 12 3 12 4 12 4 12 4 12 4 12 4 12 5 12 5 12 6 12 6 Polyphase ... 21 7 21 8 21 9 21 9 22 0 22 0 2 21 22 2 22 2 22 2 22 2 22 3 22 3 22 3 22 5 2 31 2 31 10 23 2 23 3 23 3 23 3 23 3 23 4 23 4 23 5 23 5 23 5 23 6 23 6 23 6 23 6 23 6 23 7 23 7 23 7 23 7 23 7 23 7 11 Limits to cable length Example Output ... ix 23 7 24 0 24 0 24 0 24 0 24 0 2 41 2 41 24 2 24 3 24 3 24 3 24 3 24 3 24 3 24 4 24 4 24 4 24 4 24 4 24 5 24 5 24 6 24 6 24 6 24 6 24 6 24 7 24 7 24 8 24 8 24 8 24 9 24 9 24 9 25 0 25 0 25 0 25 2 25 2 25 2 25 3 25 4 25 5 25 5 25 5 25 5 25 6...

Ngày tải lên: 20/10/2013, 02:15

... numbering, 71, 72 Tornado Diagram, 53 US Navy, xvii Updating, 14 9, 15 0, 15 1, 15 8 3 82 Value hour, 22 2, 22 3, 26 5 VDU, 13 0 Vendor, 15 1, 15 2, 15 5 Warehouse, 21 2 Watermeter, 18 2 Weighting, 2 21 , 22 3 Work ... problems, 16 0 Site organization, 25 Slack, see Float, 10 5 Slip chart, 12 0, 12 1, 305 Slippage, 14 8 SMAC, 13 3, 15 1, 2 21 , 2 31, 25 2, 25 3, 27 8, 27 9, 28 0 SMART, 12 0 Software, 55, 13 2 Specialist groups, 15 6 ... (CPI), 2 51, 25 2, 25 4 Cost report, 15 1, 335 Cost variance, 2 51, 25 4 Cost/benefit analysis, CPM, 65, 66, 15 8, 23 8 378 Critical activity, 66, 10 9, 11 6, 13 3 Critical path, 65, 91, 10 1, 10 9, 11 0, 11 2 Critical...

Ngày tải lên: 20/10/2013, 13:15

... display.addCuePoint( "1" , 8); 12 13 display.addCuePoint( "2" , 14 ); 14 15 display.addCuePoint("3", 31) ; 16 17 display.addCuePoint("4", 35); 18 19 display.addCuePoint("5", 53); 20 21 display.addCuePoint("6", 56); 22 ... displayListener:Object = new Object(); displayListener.complete = function(){ 10 getURL("http://www.thebluezone.com"); 11 12 } 13 14 display.addEventListener("complete", displayListener); 15 Here ... display.addCuePoint("6", 56);: 10 var cueTextArray:Array = new Array(); 11 12 cueTextArray[0] = "Potential Fluffy victim"; 13 14 cueTextArray [1] = "Sweet, innocent Fluffy appears"; 15 16 cueTextArray [2] = "Fluffy...

Ngày tải lên: 20/10/2013, 14:15

... that have to be completed early because others are dependent on them  12 2 Managing projects in human resources The project manager is often asked to set the milestones so that regular reviews ... progress of activities is very different from the plan you will need to take some action Action should be taken when there is a danger that Monitoring and control 11 9 the project will not meet its ... information with progress on project and identifying variance Figure 10 .1 A simple project control loop The process of project control is a simple loop (see Figure 10 .1) The four stages in this loop are:...

Ngày tải lên: 24/10/2013, 08:20

... L4 02- 011 (23 .0) L 720 - 0 12 (20 0.0) L 511 - 0 12 (11 0.0) L4 02- 011 (23 .0) R3 01- 011 (11 .0) R3 01- 011 (11 .0) FRS -20 - 16 0 ( 16 0) CSS- 32- 16 0 ( 16 0) CSS- 32- 16 0 ( 16 0) CSS -20 -80 (80) FRS -20 - 16 0 ( 16 0) CSS -20 -50 (50) The ... Thickness (mm) B0 B1 B2 B3 B4 B5 B6 Total 320 .0 320 .0 400.0 28 0.0 12 0.0 12 0.0 40.0 16 00 .0 13 0.0 12 0.0 12 0.0 84.0 84.0 84.0 44.5 9.0 10 .0 2. 0 2. 0 2. 0 2. 0 2. 0 Cylindrical arm element (Duralumin) Source: ... dimensions and machine elements are obtained; then the robot design is terminated 21 . 2. 7 Design Example The design conditions are summarized in Table 21 . 2 and Figures 21 . 22 and 21 . 23 Figure 21 . 24 ...

Ngày tải lên: 25/10/2013, 13:15

... fps 10 10 4 10 4 10 4 10 4 10 4 10 4 10 4 10 5 10 4 10 4 10 4 10 4 10 4 10 4 10 4 10 4 10 4 10 4 10 4 IQ4 1. 09 X 10 3 1. 13 x 10 3 1. 48 X 10 3 8.50 x 10 2 1. 09 X 10 3 6.76 X 10 2 1. 01 x 10 3 1. 04 X 10 3 4 .20 X 10 3 9. 71 X 10 2 ... 1. 41 1 .17 1. 17 6.66 1. 57 1. 70 4 .10 1. 61 1 .26 1. 56 9 .19 8.66 1. 66 1. 10 8.96 1. 41 1 .25 1. 64 x 10 4 x 10 4 X 10 3 X 10 4 X 10 3 x 10 4 x 10 4 X 10 4 x 10 3 X 10 4 X 10 4 X 10 3 X 10 4 x 10 4 x 10 4 X 10 3 x 10 3 ... = 2 .1 x — 7 .15 X 1. 39 X 9 . 12 X 1. 72 x 1. 51 x 1. 56 X 1. 06 x — 1. 92 X 7.87 X — 1. 53 x 1. 84 x 1. 30 X 1. 18 x 2. 00 x — 1. 09 x 1. 79 X 1. 37 x — 10 4 10 3 10 4 10 3 10 4 10 4 10 4 10 4 10 4 10 3 10 4 10 4 10 4 10 4...

Ngày tải lên: 25/10/2013, 13:15

... stability based on: sup © 20 02 by CRC Press LLC e(t ) p (t ) < W(s)(I + G e 1 (s)G t (s)) 1 ∞ 1 (23 . 61) 8596Ch23Frame Page 625 Friday, November 9, 20 01 6 :26 PM FIGURE 23 .22 Performance comparison: ... F x r = x − ∆x f (23 .26 ) ∆x F = G F (s) F Substituting: x − x = G t 1 (s) F © 20 02 by CRC Press LLC (23 .27 ) 8596Ch23Frame Page 607 Friday, November 9, 20 01 6 :26 PM in (23 .26 ), we derive the ... Vol 10 7, 1 24 , 19 85 20 Kazerooni, K.H., Waibel, B.J., and Kim, S., On the stability of robot compliant motion control: Theory and experiments, J Dynam Syst., Meas Control, 11 2, 417 – 426 , 19 90 21 ...

Ngày tải lên: 29/10/2013, 20:15

... r ∑ p∈P ∂Ep ∂s2pi s2pi ∂w 12 ij p ∂E p ∂s3pr ∂o2 j ∂s2pi ∂s3pr ∂o2pi ∂s2pi ∂w 12 ij ∑∑δ p 3r w23ri f2′i (s2pi )u1pj p∈P =− r ∑δ p p 2i j (24 .23 ) w23ri f2′i (s2pi ) (24 .24 ) u p∈P p δ2i = ∑δ p 3τ ... November 6, 20 01 9:43 PM ∆w 12 ij (t ) = − η ∂E = ηδ i (t )u1 j (t ) ∂w 12 ij (24 .28 ) w23ij (t + 1) = w23ij (t ) + ∆w23ij (t ) (24 .29 ) w 12 ij (t + 1) = w 12 ij (t ) + ∆w 12 ij (t ) (24 .30) where ... s2pa )) p s2 εR L1 p a = 1, K, L1 o20 = pT p s3p = W23 o2 o3pb = 1/ (1 + exp( − s3pb )) ycp = o3pc s3p εR Ny b = 1, K, N y c = 1, K, N y (24 .15 ) (24 .16 ) (24 .17 ) (24 .18 ) (24 .19 ) where s2p , s3p are input...

Ngày tải lên: 29/10/2013, 20:15

... 11 b 10 c 11 d 10 e 10 22 13 18 23 28 33 a 39 44 b 38 44 c 38 43 d 37 42 e 33 38 28 12 11 14 13 16 15 a 14 13 b 18 21 c 14 17 d 12 13 e 18 17 23 20 20 17 17 14 14 11 a 8 b 11 11 c 11 14 d e 11 ... 29 34 c 29 31 d 26 31 e 26 32 44 44 41 38 a 10 12 b 35 32 c 34 d 35 10 e 10 52 50 17 14 14 11 11 8 a b c d 5 e 45 32 29 26 23 20 17 14 a 11 b 12 c 11 d 32 29 e 10 51 13 29 15 26 17 23 19 a 21 ... 66 17 a 19 66 b 66 19 c 19 22 d 20 66 e 66 20 58 17 32 19 29 21 26 23 a 25 25 b 20 22 c 23 25 d 25 22 e 27 32 54 35 10 12 35 17 a 22 35 b 35 19 c 19 35 d 19 24 e 22 24 59 10 34 12 31 14 28 16 ...

Ngày tải lên: 02/11/2013, 16:20