descriptive statistics for explanatory variables 1

... [0. 013 ]** [0. 013 ]* [0. 013 ] 0.435 0.0 21 0. 019 0. 010 0.006 0. 010 [0. 012 ]* [0. 012 ] [0. 012 ] [0. 011 ] [0. 011 ] 1. 886 0.036 0. 018 0. 016 [0 .12 1]*** Education at 16 No of O-levels 0. 011 [0. 010 ] [0.0 41] *** ... 11 82 467 (.499) 965 (1. 298) 19 76 19 76 235 (.424) 266 (.442) 19 75 19 70 0275 19 76 11 76 19 76 19 14 3.328 (3 .17 7) 19 13 420 4 31 1900 19 23 18 3 17 3 19 00 216 1 0323 2024 008 2024 Age 16 Exams Combined English ... months not in education inactive 12 7 (1. 375) -.037 (1. 253) 0003 (1. 038) 035 (1. 004) 206 (.983) 243 (1. 005) 13 7 (.948) Sample Size 216 3 216 3 18 81 1836 19 16 19 16 19 14 19 14 19 70 Cohort Sons Mean (Standard...

Ngày tải lên: 23/03/2014, 03:20

... billion Hurricane Isabel $1. 7 billion 36 US, Canada Storms and hail $1. 6 billion US Cedar fire, urban forest fires Old fire, urban forest fires $1. 1 billion 14 US (CA) $1. 0 billion US(CA) US Cite: ... California storm losses in the 19 97-98 El Niño were $1. 1 billion Cite: Changnon, Stanley A., ed El Niño 19 97 -19 98: The Climate Event of the Century, Oxford University Press, 2000, p 22 notes 15 ... http://marineeconomics.noaa.gov/SCBeach/4Summary_Expenditures.pdf In 19 99-2000, the top three states for beach visitation were Florida (15 .2 million participants and 17 7.2 million days), California (12 .6 million participants and 15 1.4 million days),...

Ngày tải lên: 17/12/2013, 08:40

... 20 10 13 14 18 13 22 38 11 10 10 12 14 15 18 20 29 33 14 11 26 34 38 40 41 18 28 38 23 13 13 9 10 10 10 16 11 11 10 15 47 20 13 28 41 29 29 18 25 18 16 20 15 12 12 12 39 16 14 12 13 15 16 14 18 ... (mg/L) 10 11 12 13 14 15 16 17 3 .11 5 3.08 4.496 3.207 3.8 81 4.769 3.5 5.373 3.779 3 .11 3 4.008 3.455 3 .10 6 3.583 3.889 4.7 21 4.2 41 119 0 12 11 1005 12 08 13 49 12 21 1288 11 93 13 80 11 68 12 50 14 37 11 05 11 55 ... 20 19 28 29 25 28 25 29 36 68 32 24 22 22 31 32 21 24 20 23 24 26 23 22 28 14 28 36 50 24 22 24 26 11 19 21 21 24 26 33 21 21 19 19 15 20 25 11 13 14 26 19 21 16 13 10 10 11 11 14 11 16 13 12 ...

Ngày tải lên: 20/01/2014, 01:20

... 9 .1 9.5 10 .1 11. 9 9.6 9 .1 9.0 10 .4 9.7 9.4 8.9 9.2 11 .2 10 .3 10 .6 12 .1 7.8 10 .4 8.6 11 .6 11 .7 11 .1 10.4 11 .3 10 .6 11 .7 9.0 10 .6 9.2 10 .4 8.4 10 .9 12 .1 11. 2 10 .0 10 .4 9.7 9.3 8.7 9 .1 L1592_Frame_C02 ... 4.2 17 .5 37 .1 25.2 38.5 10 .8 16 .2 10 .4 11 1.8 9.3 0.4 32.4 34.6 3.0 2.7 1. 3 14 .9 14 .7 56.4 2.5 3.4 8.8 7 .1 3.3 28.0 17 .8 13 .9 15 .4 9.7 11 .3 2.4 3.3 26.9 8.4 5.9 20.7 11 .4 2 .15 Standard Error I Calculate ... of t for Several Tail Probabilities and Degrees of Freedom n α = 0 .1 10 20 25 26 27 40 ∞ 1. 886 1. 533 1. 440 1. 372 1. 325 1. 316 1. 315 1. 314 1. 303 1. 282 Tail Area Probability 0.05 0.025 0. 01 0.005...

Ngày tải lên: 20/01/2014, 01:20

... (2.6%) (3 .1% ) Moderate improvement 22 (28.9%) (28.9%) (34.4%) Significant improvement 31 (40.8%) (40.8%) (48.4%) Unable to evaluate impact (11 .8%) (11 .8%) (14 .1% ) N/A 12 (15 .8%) (15 .8%) - B 11. 3 Impact ... groups NB had conflict of interest 33 (43.4%) (43.4%) 12 (15 .8%) (15 .8%) 16 ( 21. 1%) ( 21. 1%) (11 .8%) (11 .8%) Lower quality of service performed by subcontractor or subsidiary of NB Other (please ... (57.9%) % of total number records (76) (57.9%) No 16 ( 21. 1%) ( 21. 1%) I don't know 16 ( 21. 1%) ( 21. 1%) B2 .1 Proportion of non-compliant products for: -single choice reply- (compulsory) These figures...

Ngày tải lên: 19/02/2014, 03:20

... registration form (9) tell one's name and address (10 ) make a registration procedure (11 ) pay by bank transfer (12 ) take part in the party (13 ) be informed about persons who wish to participate DP1 DP2 ... clues for ascertaining illocutionary forces (Wierzbicka 19 86) (2-5) t~rokuydsi o o-okuri negae masu ks? registration form OBJ send-POL desire POL QUEST Can you please send me a registration form7 ... Notes 13 Sanford, D and J Roach, 19 87, "Representing and using metacommunieation to control speakers' relationships in natural-language dialogue", Int J of Man-Machine ,Studies, 28, 3 01- 319 Scoria,...

Ngày tải lên: 09/03/2014, 01:20

... 6 ,17 1 3,646 1, 625 24,739 14 ,039 6,876 289 18 1 *44 1, 608 990 479 4,093 2,558 1, 278 16 7 11 6 *56 240 15 1 *11 5 518 2 51 150 14 1 *62 † 1, 493 2,344 4,565 3,0 41 7, 419 11 ,480 15 ,576 11 ,17 8 13 8 *88 15 2 13 4 ... Yes 11 , 610 17 ,664 26,7 91 18,5 61 249 617 1, 550 1, 225 11 ,3 61 17,036 25,225 17 , 317 1, 656 4,980 4, 816 5,363 9,484 11 , 719 19 ,854 11 ,560 *30 *10 6 16 5 10 1 14 8 13 8 203 17 3 † † *79 *66 † † 10 3 *54 ... taken regularly for at least months1 40,0 71 23,245 11 , 310 4,860 3,4 41 1,7 81 12.3 (0.49) 15 .1 (0. 71) 15 .8 (1. 14) 11 , 610 17 ,664 26,7 91 18,5 61 1,495 2,770 4,225 1, 592 12 .9 15 .7 16 .1 8.7 Excellent...

Ngày tải lên: 14/03/2014, 09:20

... 14 7 15 1 16 1 16 1 16 5 16 7 17 7 17 8 18 0 18 0 18 5 18 5 18 5 18 5 19 0 19 0 19 5 19 5 19 7 200 202 208 209 220 230 235 240 240 265 319 10 2 01 13225 15 625 15 876 16 900 18 225 20736 210 25 210 25 216 09 228 01 259 21 ... 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 10 1 11 5 12 5 12 6 13 0 13 5 14 4 14 5 14 5 ... SAMPLE) 10 0 11 9 11 9 13 9 14 0 15 9 16 0 17 9 18 0 19 9 200– 219 220–239 240–259 260–279 280–299 300– 319 11 1 5 .1 10.3 12 .8 15 .3 28.2 10 .3 7.7 5 .1 2.6 0.0 2.6 Total 39 CUMULATIVE FREQUENCY (CUMULATIVE %) 5.1...

Ngày tải lên: 15/03/2014, 09:20

... parsing forthcoming T Dunning 19 93 Accurate methods for the statistics of surprise and coincidence Computational Linguistics, 19 (1) : 61- 74 W.A Gale, K.W Church, and D Yarowsky 19 92 A method for disambiguating ... Total Valid Total Valid Terms 11 5 338 15 5 90 Terms 24 85 33 35 Terms 90 335 243 14 0 96 Terms 24 11 7 10 3 33 17 Table 5: Valid category terms found by our algorithm for other categories tested senses ... produced 10 6, R&C R&C R&S 12 0 10 0 (MUC) (wsJ) (MUC) , Vhl eie c f ,,t 60 4o 20 50 10 0 15 0 200 Terms Generated r 250 10 0 Weapon 8O 6O 40 2O 0~ I 50 F i g u r e 1: Weapon J I 10 0 i 50 Terms Generated...

Ngày tải lên: 23/03/2014, 19:20

... 99 10 7 10 9 11 2 Non-Governmental Organizations and Power Introduction Global Civil Society Generally Contending Issues and Problems Reconsidering the Framework Conclusion 11 5 11 5 11 7 12 1 12 4 12 8 ... Conclusion 11 5 11 5 11 7 12 1 12 4 12 8 Conclusion 12 9 Bibliography International Documents Judicial Decisions Books Articles Index 13 5 13 5 13 6 13 6 14 1 14 9 Acknowledgements A number of colleagues have ... cancel out any form of objectivity Either international law is too political Stark (2002); Carty (19 91) Stark (2002) Koskenniemi (19 89) Theoretical Grounds for International Law 11 given the reference...

Ngày tải lên: 30/03/2014, 10:20

... DISTRIBUTIONS 6 .1 Bernoulli Trials 6 .1. 1 Binomial D istribution Contents 44 46 49 49 51 55 61 66 67 75 76 76 79 83 86 87 88 92 92 93 98 99 10 1 10 8 11 2 11 2 11 9 11 9 12 0 13 4 13 7 14 5 14 7 15 3 15 4 16 1 16 1 16 2 ... eferences F urther R eading and Comments Problems ix 16 7 16 9 17 2 17 3 18 1 18 2 18 3 18 4 18 5 19 1 19 1 19 3 19 6 19 9 2 01 205 207 209 211 212 215 219 2 21 223 225 226 228 233 234 238 238 238 239 PART B: STATISTICAL ... egression 11 .1. 1 Least Squares Method of Estimation 11 .1. 2 Properties of Least-Square Estimators 11 .1. 3 Unbiased Estimator for 11 .1. 4 Confidence Intervals for R egression Coefficients 11 .1. 5 Significance...

Ngày tải lên: 31/03/2014, 16:23

... p 011 1 p1 010 = p 010 1 p 111 0 , p 011 1 p2 = p1 010 p2 , 11 10 11 11 p2 p 010 1 = p2 p1000 , 0000 00 01 p 011 1 p1000 = p00 01 p 111 0 , p2 p 111 0 = p 010 1 p2 , 011 1 11 11 p2 p3 = p3 p2 , 0000 11 10 10 00 11 11 p 010 1 ... p00 01 p1000 − p0000 p10 01 , p00 01 p 010 0 − p0000 p 010 1 , p0 011 p10 01 − p00 01 p1 011 , p0 011 p1 010 − p0 010 p1 011 , p0 011 p 011 0 − p0 010 p 011 1 , p 011 0 p 110 0 − p 010 0 p 111 0 , p 010 1 p 110 0 − p 010 0 p 110 1 ... + p10 01 )(p 111 0 + p 111 1 ) − (p1 010 + p1 011 )(p 110 0 + p 110 1 ), p0000 p10 01 − p00 01 p1000 , p0 010 p1 011 − p0 011 p1 010 , p 010 0 p 110 1 − p 010 1 p 110 0 , p 011 0 p 111 1 − p 011 1 p 111 0 Statistics 39 The model...

Ngày tải lên: 08/04/2014, 13:10

... 2 .13 2 2.776 3.747 4.604 1. 476 2. 015 2.5 71 3.365 4.032 10 1. 372 1. 812 2.228 2.764 3 .16 9 11 1. 363 1. 796 2.2 01 2. 718 3 .10 6 12 1. 356 1. 782 2 .17 9 2.6 81 3.055 13 1. 350 1. 7 71 2 .16 0 2.650 3. 012 14 1. 345 ... 1. 345 1. 7 61 2 .14 5 2.624 2.977 15 1. 3 41 1.753 2 .13 1 2.602 2.947 30 1. 310 1. 697 2.042 2.457 2.750 40 1. 303 1. 684 2.0 21 2.423 2.704 60 1. 296 1. 6 71 2.000 2.390 2.660 12 0 1. 289 1. 658 1. 980 2.358 2. 617 ... − 0.6 915 ) = 0.3085, or 38.05% of the infusion pumps − = x ± t(a/2, n − 1) SE(x) — = 15 .8 ± t((0. 01) /2; 15 − 1) (2.4 15 ) = 15 .8 ± t(0.005, 14 ) (0. 619 6) = 15 .8 ± 2.977 (0. 619 6) = [13 .96, 17 .64]...

Ngày tải lên: 27/06/2014, 10:20

... exercises 10 1 10 1 10 1 10 2 10 3 10 9 11 6 12 2 12 3 12 6 12 6 12 6 13 1 13 3 13 3 13 4 13 4 13 5 13 8 14 1 14 8 15 3 15 4 15 4 15 6 15 8 15 9 15 9 16 0 16 0 16 7 16 8 16 9 17 4 17 6 17 6 17 7 18 0 18 2 18 2 18 3 18 6 18 7 SFE_A 01. qxd 3/23/07 ... 897.22 14 055.79 72 12 2.92 382 612 .90 872 948.56 228 619 .88 54 630 329.97 16 916 826.55 12 13 9 223.03 335 274. 81 7 51 537 .16 13 8 086.73 18 1 2 41. 95 11 2 411 .42 098 16 2.88 17 457 288.35 62 746 940.35 14 0 ... diagram 8 10 10 10 13 15 15 17 19 23 24 26 26 27 28 29 31 33 34 35 36 37 37 38 39 40 40 41 42 47 50 50 51 52 52 55 SFE_C 01. qxd 3/23/07 12 :15 PM Page 8 Chapter • Descriptive statistics Data transformations...

Ngày tải lên: 28/06/2014, 17:20

... births 1. 0 0.8 CDF 0.6 0.4 0.2 0.00 20 40 60 80 10 0 minutes 12 0 14 0 16 0 Figure 4.2: CDF of interarrival times Time between births Complementary CDF 10 0 10 -1 10-2 20 40 60 80 10 0 minutes 12 0 14 0 16 0 ... check for outliers, and sometimes it is useful and appropriate to discard them In the list of pregnancy lengths for live births, the 10 lowest values are {0, 4, 9, 13 , 17 , 17 , 18 , 19 , 20, 21} Values ... 1. 5 Significance 1. 6 Glossary Descriptive statistics 11 2 .1 Means and averages 11 2.2 Variance ...

Ngày tải lên: 28/06/2014, 20:20

... t) = p 1 = B (s, t) p(t 1) +1 1 τ p(s 1) +1 1 (1 − τ ) dτ 1 [B (p (s − 1) + 1, p (t − 1) + 1) ] p , B (s, t) provided p (s − 1) + 1, p (t − 1) + > 0, namely, s >1 p and t >1 p Now, using Theorem ... (1. 2) We observe that for < p < 1, f (·, p, q) ∞ = sup x∈(0 ,1) xp 1 (1 − x)q 1 B (p, q) = ∞ Assume that p, q ≥ 1, then we find that df (x, p, q) dx = (p − 1) xp−2 (1 − x)q 1 − (q − 1) xp 1 (1 ... f q +1 b−a q = f q +1 p (x − a) q +1 (b − x) q +1 + 1 +1 +1 q q 1 (x − a) q +1 + (b − x) q +1 p (b − a) q x−a b−a +1 q + b−x b−a for all x ∈ [a, b] Since b E (X) = b − F (t) dt a then, by (1. 35)...

Ngày tải lên: 20/07/2014, 18:38

... 2, 12 2, 2, 12 1 A∗ = (1, 1, 2, 3, 2, 1, 1) s A∗ = (1, 2, 3, 2, 1) s A∗ = (1, 2, 3, 2, 1) s A∗ = (1, 1, 2, 3, 2, 1, 1) s A∗ = (1, 3, 4, 4, 4, 2, 1, 1) s A∗ = (1, 2, 4, 4, 4, 2, 1) s A∗ = (1, 1, ... a(2a +1 1b ) (T ) = a(2a 1b+2 ) (T ) and b(2a +1 1b ) (T ) = b(2a +1 1b ) (T ) + If type(2a +1 1b ) (T )a +1 = then a(2a +1 1b ) (T ) = a(2a 1b+2 ) (T ) + (b + 1) and b(2a +1 1b ) (T ) = b(2a +1 1b ) ... t] = (t; t)b eb X 1 t From this we derive X 1 t X (1 − 1/ t)t b +1 X = ( 1) 2b t( )−b (t 1 ; t 1 )b hb (1 − 1/ t) b) = t(2 ωH b [X; t 1 ] b +1 = ( 1) b t( ) (t 1 ; t 1 )b eb − (1 ) So that using the...

Ngày tải lên: 07/08/2014, 06:22

... 000000000 11 111 111 1 000000000 11 111 111 1 000000000 11 111 111 1 000000000 11 111 111 1 000000000 11 111 111 1 000000000 11 111 111 1 000000000 11 111 111 1 000000000 11 111 111 1 000000000 11 111 111 1 000000000 11 111 111 1 ... 0000000000 11 111 111 11 0000000000 11 111 111 11 0000000000 11 111 111 11 0000000000 11 111 111 11 0000000000 11 111 111 11 0000000000 11 111 111 11 0000000000 11 111 111 11 0000000000 C 11 111 111 1 000000000 11 111 111 1 000000000 ... 11 111 111 11 0000000000 11 111 111 11 0000000000 11 111 111 11 0000000000 11 111 111 11 0000000000 C 11 111 111 1 000000000 11 111 111 1 000000000 11 111 111 1 000000000 11 111 111 1 000000000 11 111 111 1 000000000 11 111 111 1...

Ngày tải lên: 07/08/2014, 08:22

... Acta Arith 14 8 (2 011 ), 1 19 [7] H Zhao and Z Zhong, Ramanujan type congreuences for a certain partition function, EJC (2 011 ) (1) , P58 the electronic journal of combinatorics 18 (2 011 ), #P128 ... for λ ∈ P ∗ by 1, if λ ∈ P, λ = 1 , or λ = 1 ∗ , wt(λ) = 1, if λ = 1, and we also define the extended crank c∗ (λ) by  c(λ), if   0, if ∗ c (λ) = 1, if    1, if λ ∈ P, λ = 1, λ = 1 ... ζ 1 q , ζ 2q , ζ −2q ; q )∞ ∞ (q ; q )∞ = (q; q )2 (q 10 ; q 10 )∞ ∞ (q ; q )3 ∞ = (q; q)2 (q 10 ; q 10 )∞ ∞ (q ; q )3 (q; q)3 ∞ ≡ 5 ∞ 10 10 (mod 5) (q ; q )∞ (q ; q )∞ ∞ ∞ n n(n +1) m m(m +1) /2...

Ngày tải lên: 08/08/2014, 14:23