cisco ccna 1 chapter 5 test answers

... of _ and an APR of _ A 16 .08%; 15 .00% B 14 .55 %; 16 .08% C 12 .68%; 15 .00% D 15 .00%; 14 .55 % Annually compounded rate = (1. 012 5 )12 - = 16 .08% APR = 1. 25%  12 = 15 .00% AACSB: Reflective Thinking ... $ 15 0,000? By how much would your answer change if you expected 11 % annually? FV = PV (1 + i)n $ 15 0,000 = PV (1. 08 )18 $ 15 0,000 = PV  3.996 $37 ,53 7. 35 = PV If the interest rate increases to 11 %, ... of 10 %? A $10 0.00 B $10 5 .17 C $11 0 .50 D $11 5. 70 37 How much interest will be earned in an account into which $1, 000 is deposited for one year with continuous compounding at a 13 % rate? A $13 0.00

Ngày tải lên: 04/06/2018, 15:18

... A Prince of Sinners E Phillips Oppenheim BOOK CHAPTER THE MARQUIS OF ARRANMORE They had met almost on the steps of his office, and only a few ... luggage came clattering up the street She watched it with darkening face "That is the sort of man I detest," she said, motioning her head towards the window "You know whose carriage it is, don't you?"

Ngày tải lên: 06/07/2014, 02:20

... lion Then it throws its rider, and you have 16 42 in England and 17 89 in France; and sometimes it devours him, and you have in England 16 49, and in France 17 93 That the lion should relapse into the ... that is all that is asked of the sovereign of England He receives for that nothing ? ?1, 250 ,000 a year In 17 05, England which had had but thirteen men of war under Elizabeth, and thirty-six under ... and fifty in her fleet The English had three armies, 5, 000 men in Catalonia; 10 ,000 in Portugal; 50 ,000 in Flanders; and besides, was paying ? ?1, 666,666 a year to monarchical and diplomatic Europe,

Ngày tải lên: 07/07/2014, 05:20

... interference (if codes are “orthogonal”) 5: DataLink Layer 5a -18 CDMA Encode/Decode 5: DataLink Layer 5a -19 CDMA: two-sender interference 5: DataLink Layer 5a-20 Random Access protocols ❒ When node ... [t0 -1, t0 +1] 5: DataLink Layer 5a-24 Pure Aloha (cont.) P(success by given node) = P(node transmits) P(no other node transmits in [p0 -1, p0] P(no other node transmits in [p0 -1, p0] = p (1- p) (1- p) ... ❍ ❍ ❍ ❍ ❍ Ethernet hibs, bridges, switches IEEE 802 .11 LANs PPP ATM 5: DataLink Layer 5a -1 Link Layer: setting the context 5: DataLink Layer 5a-2 Link Layer: setting the context ❒ two physically

Ngày tải lên: 04/12/2015, 20:37

... ch 05 Key B D D C A D B D A 10 C 11 C 12 A 13 A 14 B 15 D 16 A 17 A 18 C 19 A 20 B 21 C 22 A 23 C 24 B 25 D 26 C 27 D 28 D 29 B 30 C 31 C 32 B 33 A 34 D 35 D 36 C 37 D 2) 38 1) 2) 39 1) 2) 40 1) ... A $12 5, 000 B $12 3, 750 C $11 8, 750 D $13 0,000 30 Based on the preceding information, what is the amount of consolidated comprehensive income reported for 20X9? A $14 5, 000 B $13 5, 000 C $13 8, 750 ... $13 8, 750 D $12 8, 750 31 Based on the preceding information, what is the amount of comprehensive income attributable to the controlling interest for 20X8? A $12 3, 750 B $11 8, 750 C $11 9,000 D $10 4,000

Ngày tải lên: 04/06/2018, 15:17

... Option B C Option C D Option D 14 Further audit procedures include: A Option A B Option B C Option C D Option D 5- 3 Chapter 05 - Audit Evidence and Documentation 15 Assertions that have a meaningful ... Understand Difficulty: Medium Learning Objective: 05- 04 List and describe types of audit evidence Source: IIA Topic: Analytical Procedures 5- 51 Chapter 05 - Audit Evidence and Documentation 68 Which ... Learning Objective: 05- 04 List and describe types of audit evidence Topic: Risk, Evidence, and Assertions 5- 54 Chapter 05 - Audit Evidence and Documentation Matching Questions 75 For each of the

Ngày tải lên: 04/06/2018, 15:25

...  several speeds: OC3 = 15 5 .52 Mbps; OC12 = 622.08 Mbps; OC48 = 2. 45 Gbps, OC192 = 9.6 Gbps  TI/T3: transmission frame structure (old telephone hierarchy): 1. 5 Mbps/ 45 Mbps  unstructured: just ... Link-layer Addressing 5. 5 Ethernet CuuDuongThanCong.com  5. 6 Link-layer switches  5. 7 PPP  5. 8 Link virtualization: ATM, MPLS 5: DataLink Layer https://fb.com/tailieudientucntt 5- 4 Link Layer: Introduction ... CuuDuongThanCong.com 5: DataLink Layer https://fb.com/tailieudientucntt 5- 3 Link Layer  5 .1 Introduction and     services 5. 2 Error detection and correction 5. 3 Multiple access protocols 5. 4 Link-layer

Ngày tải lên: 11/01/2020, 00:30

... Chapter 5 .1: Network Design NGUYỄN CAO ĐẠT E-mail:dat@hcmut.edu.vn Hochiminh City University Of Technology Computer Science & Engineering © 2 014 Computer Networks Chapter 5: Network ... © 2 014 Computer Networks Chapter 5: Network Design Systems Development Life Cycles Hochiminh City University Of Technology Computer Science & Engineering © 2 014 Computer Networks Chapter 5: Network ... Server Farm Kbps Kbps Kbps Kbps Kbps 10 -Mbps Metro Ethernet to Internet App App App App App Total 10 8 60 19 2 48 400 808 Kbps Kbps Kbps Kbps Kbps Kbps 25 Macs 50 PCs 50 PCs Arts and Humanities Administration

Ngày tải lên: 26/11/2016, 02:11

... information about the PC hardware. 11 02.book Page 11 Tuesday, May 20, 2003 2 :53 PM 12 Chapter 1: Introduction to Networking Network Interface Cards As shown in Figure 1- 6, a NIC is a printed circuit ... address. 11 02.book Page 15 Tuesday, May 20, 2003 2 :53 PM 16 Chapter 1: Introduction to Networking determine if there is connectivity to a destination. The ping command is used to test the NIC ... did not become widely used until the early 19 80s, and the transfer of 11 02.book Page 14 Tuesday, May 20, 2003 2 :53 PM Testing Connectivity with Ping 15 files and graphics began to be desirable.

Ngày tải lên: 04/07/2014, 18:20

... Chapter - RIP version CCNA Exploration version 4.0 Objectives • • • • • • Describe the functions, characteristics, and operation of the RIPv1 protocol Configure a device for using RIPv1 Verify ... RIPv1 Học viện mạng Bách Khoa - Website: www.bkacad.com RIPv1 • RIP Characteristics - A classful, Distance Vector (DV) routing protocol - Metric = hop count - Routes with a hop count > 15 are ... Verify proper RIPv1 operation Describe how RIPv1 performs automatic summarization Configure, verify, and troubleshoot default routes propagated in a routed network implementing RIPv1 Use recommended

Ngày tải lên: 28/07/2014, 18:21

... Hannah MAC IP 0200 .11 11. 111 1 10 .1. 1 .1 0200 .12 34 .56 78 10 .1. 1.2 0200 .54 32 .11 11 10 .1. 1.3 RARP Reply IP: ?.?.?.? MAC: 0200 .11 11. 111 1 Hey Everybody! My MAC Address Is 0200 .11 11. 111 1 If You Are a RARP ... Address! Your IP Address Is 10 .1. 1.2 BOOTP Configuration MAC IP Gateway 0200 .11 11. 111 1 10 .1. 1 .1 10 .1. 1.200 0200 .12 34 .56 78 10 .1. 1.2 10 .1. 1.200 0200 .54 32 .11 11 10 .1. 1.3 10 .1. 1.200 Hannah BOOTP Broadcast ... Figure 5 -14 Router A Advertising Routes Learned from Router C Router A 16 2 .11 .5. 0 16 2 .11 .8 .1 Routing Update To0 s0 s1 16 2 .11 .9.0 Routing Update 16 2 .11 .10 .0 16 2 .11 .5. 0 16 2 .11 .9.0 16 2 .11 .8.0 16 2 .11 .10 .0

Ngày tải lên: 13/08/2014, 13:21

... B) 10 -K form C) 10 -Q form D) S -1 form Answer: B Te rms: Securities Exchange Act of 19 34 Diff: Challe nging Objective : LO 5- 6 AACSB: Re flective thinking skills 15 ) Section 10 and Rule 10 b -5 of ... Abse nce of causal connection Diff: Mode rate Objective : LO 5- 2, LO 5- 5, LO 5- 5, LO 5- 6 and LO 5- 8 AACSB: Re flective thinking skills 5) Discuss some of the steps individual practicing auditors ... Securities Exchange Act of 19 34 Rule 10 b -5; U.S Supre me Court rule d in 19 76 in Hochfe lde r v Ernst & Ernst Diff: Challe nging Objective : LO 5- 6 AACSB: Re flective thinking skills 17 ) The Sarbanes-Oxley

Ngày tải lên: 11/04/2017, 15:04

... a $ 15 0,000 / 15 ,000 = $10 per purchase order $17 5, 000 /10 ,000 = $17 .50 per receiving report $2 25, 000 /50 ,000 = $4 .50 per phone call Product A 50 purchase orders × $10 10 0 purchase orders × $10 15 0 ... x x x x x x x x x x Multiple Choice Difficulty Level Easy 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 Moderate x x x x x x Learning Objectives Difficult LO ... Produced 1. 5 Total OH $ Total DL Hours 3200 12 000 15 200 800 8000 Proportion Allocated Units OH per OH Produced Unit 780,000 0. 210 52 6 316 $ 16 4, 210 .53 800 $ 2 05. 28 (3,200 / 15 ,200) DIF: Moderate OBJ: 5- 3

Ngày tải lên: 11/04/2017, 15:06

... Routing • Spanning Tree Overview • STP 802.1D, RSTP, PVRST+ … © 2 012 Cisco and/or its affiliates All rights reserved Mitigating Layer Attacks © 2 012 Cisco and/or its affiliates All rights reserved ... the VLANs on the victim switch from the rogue switch © 2 012 Cisco and/or its affiliates All rights reserved 10 MAC Address Spoofing © 2 012 Cisco and/or its affiliates All rights reserved 22 MAC ... address-to-IP address bindings stored in a DHCP snooping database © 2 012 Cisco and/or its affiliates All rights reserved 35 © 2 012 Cisco and/or its affiliates All rights reserved 36

Ngày tải lên: 30/01/2020, 11:54

... of 19 34, most of the litigation against the auditor has been generated because of the auditor’s involvement with the: a 8-K form b 10 -K form c 10 -Q form d S -1 form 68 challenging a Section 10 ... False 10 6 medium a The only parties who can recover from auditors under the Securities Act of 19 33 are original purchasers of securities a True b False 10 7 medium a Under the Securities Act of 19 33, ... fraudulent activity a True b False 11 3 medium b Gross negligence is the existence of extreme or unusual negligence with the intent to deceive a True b False 11 4 challenging b The preferred defense

Ngày tải lên: 11/04/2017, 14:44

... Living in a Network Centric World CCNA Exploration Semester 1 Chapter 1 Overview 2 Remember, we are just beginning to herd the cats. Much of this will ... v=fQKNvPn3V8&mode=related&search= 13 14 Examples of Today’s Popular Communication Tools Instant Messaging:... as: file transfer voice video communication (web cam) chat 15 Weblogs (blogs) Weblogs (Blogs) ... streams Text graphics 11 The Global Community Technology helps to create a world in which national borders, geographic distances, and physical limitations become less relevant 12 Networks are integral

Ngày tải lên: 01/04/2014, 12:20

... number system to another. This chapter corre- sponds to the Module 1 content from the CCNA 1 online curriculum. 11 02.book Page xxviii Tuesday, May 20, 2003 2 :53 PM xxix ■ Chapter 2, “Networking Fundamentals,” ... learning about networking, cabling, and cable testing. This chapter corre- sponds to the Module 4 and 5 content from the CCNA 1 online curriculum. ■ Chapter 5, “Ethernet Fundamentals,” discusses the ... switch port states. This chapter corresponds to the Module 7 and 8 content from the CCNA 1 online curriculum. 11 02.book Page xxix Tuesday, May 20, 2003 2 :53 PM xxx ■ Chapter 7, “TCP/IP Protocol

Ngày tải lên: 04/07/2014, 18:20

... practice. 11 02.book Page xxxiii Tuesday, May 20, 2003 2 :53 PM 11 02.book Page 2 Tuesday, May 20, 2003 2 :53 PM Part I CCNA 1: Networking Basics Chapter 1 Introduction to Networking Chapter 2 Networking ... Finally, this chapter describes how to use a TFTP server as a soft- ware source. This chapter corresponds to the Module 5 content from the CCNA 2 online curriculum. ■ Chapter 15 , “Routing and ... Fundamentals Chapter 3 Networking Media Chapter 4 Cable Testing and Cabling LANs and WANs Chapter 5 Ethernet Fundamentals Chapter 6 Ethernet Technologies and Ethernet Switching Chapter 7 TCP/IP

Ngày tải lên: 04/07/2014, 18:20

... 4 = 16 ), as you will see in Table 1- 6 in a moment. Instead of writing 10 1 010 10 .11 110 000 .11 0000 01. 111 00 010 . 011 1 011 1. 010 100 01 you can write the much-shorter hex equivalent: AA.F0.C1.E2.77. 51 . To ... value 16 8 is 10 1 010 00. For more practice, try converting decimal 255 to binary. The answer should be 11 111 111 . Table 1- 5 Base 16 Number System Number of Symbols 16 Symbols 0, 1, 2, 3, 4, 5, 6, ... 5 2 4 2 3 2 2 2 1 2 0 Place Value 12 8643 216 84 21 Example: 10 110 00 010 110 11 02.book Page 23 Tuesday, May 20, 2003 2 :53 PM 24 Chapter 1: Introduction to Networking Example: 1A2C = (1 ∗ 16 3 = 655 36)

Ngày tải lên: 04/07/2014, 18:20

... 010 0 4 4 010 1 5 5 011 0 6 6 011 1 7 7 10 00 8 8 10 01 9 9 10 10 A 10 10 11 B 11 11 00 C 12 11 01 D 13 11 10 E 14 11 11 F 15 11 02.book Page 29 Tuesday, May 20, 2003 2 :53 PM 30 Chapter 1: Introduction to ... follow. Example 1: 11 111 111 .00000000.00000000.00000000 written in dotted decimal is 255 .0.0.0. Example 2: 11 111 111 .11 111 111 .00000000.00000000 written in dotted decimal is 255 . 255 .0.0. In the first ... Using the second mask ( 255 . 255 .0.0): 000 010 10.0 010 0 010 .00 010 111 .10 00 011 0: IP address 11 111 111 .11 111 111 .00000000.00000000: network mask 000 010 10.0 010 0 010 .00000000.00000000 is the network part

Ngày tải lên: 04/07/2014, 18:20