bs electronics and communications engineering up diliman curriculum

Ngày tải lên: 15/12/2013, 07:15

Ngày tải lên: 04/07/2014, 06:03

Ngày tải lên: 07/09/2013, 13:45

... obtain the dot product and the vector product of two vectors a and b. Use the function to evaluate the dot and vector products of vectors x and y, where x = (1 5 6) and y = (2 3 8). 1.4 ... sign and the function name. The â 1999 CRC Press LLC â 1999 CRC Press LLC 1.6 M-FILES Normally, when single line commands are entered, MATLAB processes the commands immediately and ... software for engineering and scientific calculations. The name MATLAB stands for MATRIX LABORATORY. MATLAB is primarily a tool for matrix computations. It was developed by John Little and Cleve...

Ngày tải lên: 23/10/2013, 16:15

... electrical and electrical engineering technology students and professionals who want to use MATLAB to explore the characteristics of semiconductor devices and the application of MATLAB for analysis and ... obtain the dot product and the vector product of two vectors a and b. Use the function to evaluate the dot and vector products of vectors x and y, where x = (1 5 6) and y = (2 3 8). 1.4 ... the commands loglog, semilogx, and semilogy. The use of the above plot commands is similar to those of the plot command discussed in the previous section. The description of these commands are...

Ngày tải lên: 27/10/2013, 23:15

... statement groups 1 and 2 will be executed before executing statement group 3. If logical expression 1 is false, we jump to statement group 4 without executing state- ment groups 1, 2 and 3. ã ... expression 2 statement group 2 end statement group 3 end statement group 4 The program control is such that if expression 1 is true, then statement groups 1 and 3 are executed. If the ... statement group1 elseif logical expression 2 statement group2 elseif logical expression 3 statement group 3 elseif logical expression 4 statement group 4 end A statement group is executed...

Ngày tải lên: 27/10/2013, 23:15

... erased. The hold command holds the current plot on the screen, and inhibits erasure and rescaling. Subsequent plot commands will overplot on the original curves. The hold command remains in effect ... effect until the command is issued again. When a graph is drawn, one can add a grid, a title, a label and x- and y-axes to the graph. The commands for grid, title, x-axis label, and y-axis label ... 2.3 LOGARITHMIC AND POLAR PLOTS Logarithmic and semi-logarithmic plots can be generated using the commands loglog, semilogx, and semilogy. The use of the above plot commands is similar...

Ngày tải lên: 27/10/2013, 23:15

... (3+4*j)*I(2); Vcn = (5-12*j)*I(3); Van_abs = abs(Van); Van_ang = angle(Van)*180/pi; Vbn_abs = abs(Vbn); Vbn_ang = angle(Vbn)*180/pi; Vcn_abs = abs(Vcn); Vcn_ang = angle(Vcn)*180/pi; % ... Lowpass Hs k sBsw LP () = ++ 1 2 0 2 (6.54) (ii) Highpass Hs ks sBsw HP () = ++ 2 2 2 0 2 (6.55) (iii) Bandpass Hs ks sBsw BP () = ++ 3 2 0 2 (6.56) (iv) Bandreject â ... power and quadrature power. Three-phase circuits are analyzed by converting the circuits into the frequency domain and by using the Kirchoff voltage and current laws. The un- known voltages and...

Ngày tải lên: 06/11/2013, 09:15

... yt yt yt yt n () () () . . () =                 1 2 and A, B, C , and D are matrices determined by constants of a system. For example, consider a single-input and a single-output system described by ... charging and discharging curves. Figure 5.4 Charging and Discharging of a Capacitor with Different Time Constants â 1999 CRC Press LLC â 1999 CRC Press LLC [] C = 1000 and ... capacitor and the current flowing in an inductor are known at some initial time t , then the capacitor voltage and inductor current will allow the description of system behavior for all subsequent...

Ngày tải lên: 06/11/2013, 09:15

... the current I and the power supplied by the 10-volt source is MATLAB Script diary ex4_3.dat % this program determines the current % flowing in a resistor RB and power supplied by source ... resistor and the current supplied by the source is shown below MATLAB Script diary ex4_4.dat % This program determines the power dissipated by % 8 ohm resistor and current supplied by ... is 0.037 Amps the power supplied by 10V source is 4.7531 watts â 1999 CRC Press LLC â 1999 CRC Press LLC Attia, John Okyere. “DC Analysis.” Electronics and Circuit Analysis using...

Ngày tải lên: 06/11/2013, 09:15

... is required to operate as an engineering department. See Ch. 3 and Appendi- ces A, B, and C for examples of each document type. 8 Developing and Managing Engineering Procedures 1.6.0 ENGINEERING PROCEDURE ... Subsection 4.5.1, Document Ap- proval and Issue: The supplier shall establish and maintain procedures to control all documents and data that relate to the requirements of this international standard. ... can be used for developing and managing engineering procedure documentation and for training new employees or retraining existing employees. 2 Developing and Managing Engineering Procedures ISO...

Ngày tải lên: 09/12/2013, 21:15

... CRC Press LLC and III CFFR =− α (12.3) II I EFRR =− + α (12.4) and ()() III BFFRR =− +− 11 αα (12.5) where I ES and I CS are the base-emitter and base-collector ... reference and output currents for the β F from 40 to 200. Assume that for both figures, VV CC = 10 , RK C = 50 Ω and VV BE = 07 Solution We use Equation (12.50) to calculate I R and ... for the simple current mirror and Wilson current source. Figure 12.12 Percentage Error between Reference and Output Currents for Simple Current Mirror and Wilson Current Source ...

Ngày tải lên: 13/12/2013, 01:15

... Substituting Equations (11.14) and (11.15) into Equation (11.16) we have â 1999 CRC Press LLC â 1999 CRC Press LLC Attia, John Okyere. “Operational Amplifiers.” Electronics and Circuit ... [a(i)]; den = [1 b(i)]; h(i,:) = freqs(num,den,w); end semilogx(f,abs(h(1,:)),'w',f,abs(h(2,:)),'w',f,abs(h(3,:)),'w') title('Op Amp Frequency Characteristics') ... Figure 11.12, if the open-loop gain is 106, R 2 = 24K, and R 1 = 1K, plot the frequency response for a unity gain bandwidth of 10 10 67 ,, and 10 8 Hz. 11.5 For the inverting amplifier,...

Ngày tải lên: 13/12/2013, 01:15

... direct band gap semiconductor. The energy levels of the outer electrons form energy bands. In insulators, the lower energy band (valence band) is completely filled and the next energy band (conduction ... band (conduction band) is completely empty. The valence and conduction bands are separated by a forbidden energy gap. energy of electrons conduction band 1.21 eV gap valence band energy of electrons conduction ... electrons conduction band 0.66 eV gap valence band energy of electrons conduction band 5.5 eV gap valence band Figure 10.1 Energy Level Diagram of (a) Silicon, (b) Germanium, and (c ) Insulator...

Ngày tải lên: 13/12/2013, 01:15

... approaches for solving I D and V D . In one approach, Equations (9.10) and (9.11) are plotted and the intersection of the linear curve of Equation (9.10) and the nonlinear curve of Equation ... 10V, and the reverse saturation current of the diode is 10 -12 A and n = 2.0. (Assume a temperature of 25 o C.) (a) Use MATLAB to plot the diode forward characteristic curve and the ... The diode current and voltage will be related by the diode equation iIe DS vnV DT = (/ ) (9.11) Equations (9.10) and (9.11) can be used to solve for the current I D and volt- age V D . ...

Ngày tải lên: 13/12/2013, 01:15

... T p () ( ) =± (8.1) and in any finite interval gt () has at most a finite number of discontinuities and a finite number of maxima and minima (Dirichlets conditions), and in addition, ... 8.1. If gt () is continuous and non- periodic, then Gf () will be continuous and periodic. However, if g(t) is continuous and periodic, then Gf () will discrete and nonperiodic; that is ... a n and b n of Equations (8.5) and (8.6) by the expression cab b a nnn n n =+∠− − 1 2 22 1 tan ( ) (8.16) In addition, c n relates to A n and φ n of Equations (8.8) and (8.9)...

Ngày tải lên: 13/12/2013, 01:15

... Figure 7.1 General Two-Port Network I 1 and V 1 are input current and voltage, respectively. Also, I 2 and V 2 are output current and voltage, respectively. It is assumed that the ... (7.66) Substituting Equations (7.64) and (7.66) into Equations (7.62) and (7.63), we have VIZVa a Z gg L −= + 1211 12 [] (7.67) IVa a Z L 1221 22 =+ [] (7.68) Substituting Equation ... VaVaI 1 11 2 12 2 =− (7.35) IaVaI 1 21 2 22 2 =− (7.36) where V 2 and I 2 are independent variables and V 1 and I 1 are dependent variables. In matrix form, the above two equations...

Ngày tải lên: 13/12/2013, 01:15

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